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5 Minute CheckComplete in your notes.
1. What is 25% of 60?
2. What is 140% of 60?
3. 27 is 30% of what number?
4. What percent is 6 of 40?
5 Minute CheckComplete in your notes.
2. What is 140% of 60?
𝟏𝟒𝟎
𝟏𝟎𝟎=
?
𝟔𝟎
140 x 60 = 8400 ÷ 100 = 84
5 Minute CheckComplete in your notes.
3. 27 is 30% of what number?
30
100= 27
?
100 x 27 = 2700 ÷ 30 = 90
5 Minute CheckComplete in your notes.
4. What percent is 6 of 40?
?
100=
6
40
100 x 6 = 600 ÷ 40 = 15
The distance between point (2, 2) and point (8, 2) is 6 units on a coordinate plane. Select all the pairs of points that are 6 units apart.
a. (1,7) and (1,1)
b. (3,3) and (-5,3)
c. (-3,4) and (-3,-2)
d. (0,0) and (-2,-4)
e. (-1,5) and (5,5)
f. (-8,3) and (-2,3)
OST Test Prep
The distance between point (2, 2) and point (8, 2) is 6 units on a coordinate plane. Select all the pairs of points that are 6 units apart.
a. (1,7) and (1,1)
OST Test Prep
The distance between point (2, 2) and point (8, 2) is 6 units on a coordinate plane. Select all the pairs of points that are 6 units apart.
a. (1,7) and (1,1)
I7I - I1I 7 - 1
6
OST Test Prep
1 7
6 units
If the unique numbers have the same signs, subtract their absolute values, placing the largest number first.
The distance between point (2, 2) and point (8, 2) is 6 units on a coordinate plane. Select all the pairs of points that are 6 units apart.
b. (3,3) and (-5,3)
OST Test Prep
The distance between point (2, 2) and point (8, 2) is 6 units on a coordinate plane. Select all the pairs of points that are 6 units apart.
b. (3,3) and (-5,3)
I-5I + I3I 5 + 3
8
OST Test Prep
-5 3
8 units
If the unique numbers have opposite signs, add their absolute values together.
The distance between point (2, 2) and point (8, 2) is 6 units on a coordinate plane. Select all the pairs of points that are 6 units apart.
c. (-3,4) and (-3,-2)
OST Test Prep
The distance between point (2, 2) and point (8, 2) is 6 units on a coordinate plane. Select all the pairs of points that are 6 units apart.
c. (-3,4) and (-3,-2)
I4I + I-2I 4 + 2
6
OST Test Prep
-2 4
6 units
If the unique numbers have opposite signs, add their absolute values together.
The distance between point (2, 2) and point (8, 2) is 6 units on a coordinate plane. Select all the pairs of points that are 6 units apart.
d. (0,0) and (-2,-4)
OST Test Prep
The distance between point (2, 2) and point (8, 2) is 6 units on a coordinate plane. Select all the pairs of points that are 6 units apart.
d. (0,0) and (-2,-4)
Since there a two sets of unique numbers, the distance can not be determined.
OST Test Prep
The distance between point (2, 2) and point (8, 2) is 6 units on a coordinate plane. Select all the pairs of points that are 6 units apart.
e. (-1,5) and (5,5)
OST Test Prep
The distance between point (2, 2) and point (8, 2) is 6 units on a coordinate plane. Select all the pairs of points that are 6 units apart.
e. (-1,5) and (5,5)
I5I + I-1I 5 + 1
6
OST Test Prep
-1 5
6 units
If the unique numbers have opposite signs, add their absolute values together.
The distance between point (2, 2) and point (8, 2) is 6 units on a coordinate plane. Select all the pairs of points that are 6 units apart.
f. (-8,3) and (-2,3)
OST Test Prep
The distance between point (2, 2) and point (8, 2) is 6 units on a coordinate plane. Select all the pairs of points that are 6 units apart.
f. (-8,3) and (-2,3)
I-8I – I-2I 8 - 2
6
OST Test Prep
-8 -2
6 units
If the unique numbers have the same signs, subtract their absolute values, placing the largest number first.
Objective: To understand how to solve algebraic equations.
6.EE.7 I can solve real-world and mathematical problems by writing and solving equations of the form x + p = q and px = q (where p, q and x are all nonnegative rational numbers).
Algebraic Equations
Term: a single number or variable or numbers and variables multiplied together and separated by addition or subtraction.
2r² + 3 = 21
Algebraic Equations
terms
Variable : a symbol, usually a letter, used to represents a number.
2r² + 3 = 21
Algebraic Equations
In this term r is a variable.
Coefficient: A number used to multiply a variable.
2r² + 3 = 21
Algebraic Equations
This term has a coefficient of 2.
In algebra, if no operation is written it is assumed to be multiplication.
2r² + 3 = 21
Algebraic Equations
In this term 2 is multiplied by r².
Exponent: tells how many times a number or variable is multiplied by itself.
2r² + 3 = 21
Algebraic Equations
r² = r ∙ r
Solution: is the numeric value that can be substituted in place of the variable to make the equation true.
There will be a value for r that makes this equation true.
2r² + 3 = 21
Algebraic Equations
Algebraic Expression: An expression that contains at least one variable and at least one operation.
e.g.
x + 6
Algebraic Expression
Algebraic Equations
In an algebraic expression something is being done to the variable.
e.g.
x + 6
6 is being added to the variable
Algebraic Equations
In an algebraic expression something is being done to the variable.
e.g.
x + 6
6 is being added to the variable
To undo adding 6, you would subtract 6.
Algebraic Equations
In this algebraic expression, what is being done to the variable and how is it undone?
x + 2
Algebraic Equations
In this algebraic expression, what is being done to the variable and how is it undone?
x + 2
2 is being added to the variable.
To undo adding 2, you would subtract 2.
Use the inverse operation to undo.
Algebraic Equations
In this algebraic expression, what is being done to the variable and how is it undone?
r + 15
Algebraic Equations
In this algebraic expression, what is being done to the variable and how is it undone?
r + 15
15 is being added to the variable.
To undo adding 15, you would subtract 15.
Algebraic Equations
In this algebraic expression, what is being done to the variable and how is it undone?
y - 5
Algebraic Equations
In this algebraic expression, what is being done to the variable and how is it undone?
y - 5
5 is being subtracted from the variable.
To undo subtracting 5, you would add 5.
Algebraic Equations
Solve the equation.
a + 2 = 8
How to Solve Algebraic Equation - Use the inverse operation to undo whatever is being done to the variable.
Algebraic Equations
Solve the equation.
a + 2 = 8
How to Solve Algebraic Equation - Use the inverse operation to undo whatever is being done to the variable.
Algebraic Equations
Yes, I know you already know the solution.
Solve the equation.
a + 2 = 8
To solve algebraic equations undo whatever is done to the variable.
What is being done to the variable?
Algebraic Equations
Solve the equation.
a + 2 = 8
To solve algebraic equations undo whatever is done to the variable.
Algebraic Equations
Adding 2. How can adding 2 onto something be undone?
Solve the equation.
a + 2 = 8
To solve algebraic equations undo whatever is done to the variable.
Algebraic Equations
By subtracting 2 from both sides.
Solve the equation.
a + 2 = 8
To solve algebraic equations undo whatever is done to the variable.
Algebraic Equations
By subtracting 2 from both sides.
Why both sides?
Solve the equation. a + 2 = 8
-2 -2
To solve algebraic equations undo whatever is done to the variable.
Algebraic Equations
Write this down.
Solve the equation. a + 2 = 8
-2 -2
a = 6
To solve algebraic equations undo whatever is done to the variable.
Algebraic Equations
Write this down.
Since 2 - 2 is zero, you do not have to write the zero.
Solve the equation. a + 2 = 8
-2 -2
a = 6
To solve algebraic equations undo whatever is done to the variable.
Algebraic Equations
The solution to this algebraic equation is 6.
Solve the equation. a + 2 = 8
Algebraic Equations
The solution to this algebraic equation is 6.
a 2
8
Solve the equation.
456 + k = 1004-456 = -456
k = 548
This is work that needs to be shown on today’s assignment.
Algebraic Equations
456 k
1004
Solve the equation.
3.5 + x = 12.75-3.5 = -3.50 annex zero
x = 9.25
This is work that needs to be shown on today’s assignment.
Algebraic Equations
Solve the equation.
4.6 = e + 3.2-3.2 = -3.2 1.4 = e
This is work that needs to be shown on today’s assignment.
Algebraic Equations
Solve the equation.
y + 45.76 = 53.53-45.76 =-45.76
y = 7.77
This is work that needs to be shown on today’s assignment.
Algebraic Equations
Solve the equation.
21 = h + 21-21 = -21
0 = h
This is work that needs to be shown on today’s assignment.
Algebraic Equations
You have $40 in your checking account. You write a check for $7.99 and $11.45. Write an algebraic equation that represents this situation where c is how much money is left in your checking account.
____ = ____ + ____ + _____
Do this on your own.
Algebraic Equations
You have $40 in your checking account. You write checks for $7.99 and $11.45. Write an algebraic equation that represents this situation where c is how much money is left in your checking account.
40 = 7.99 + 11.45 + c
How much money is left in your checking account?
Algebraic Equations
You have $40 in your checking account. You write checks for $7.99 and $11.45. Write an algebraic equation that represents this situation where c is how much money is left in your checking account.
40.00 = 7.99 + 11.45 + c
40.00 = 19.44 + c
-19.44 -19.44
20.56 = c
Algebraic Equations
A hot air balloon is 200 feet in the air. A few minutes later it ascends to 450 feet. Write and solve an algebraic equation that represents this situation where h is the change in altitude of the balloon.
____ = ____ + ____
Do this on your own.
Algebraic Equations
A hot air balloon is 200 feet in the air. A few minutes later it ascends to 450 feet. Write and solve an algebraic equation that represents this situation where h is the change in altitude of the balloon.
450 = 200 + h
Algebraic Equations
A hot air balloon is 200 feet in the air. A few minutes later it ascends to 450 feet. Write and solve an algebraic equation that represents this situation where h is the change in altitude of the balloon.
450 = 200 + h-200 -200250 = h
Algebraic Equations
In the equation x + y = 5, the value for x is a whole number greater than 2 but less than 6. Determine the possible solutions for y.
Algebraic Equations
In the equation x + y = 5, the value for x is a whole number greater than 2 but less than 6. Determine the possible solutions for y.
x = 3 x = 4 x = 5
3 + y = 5 4 + y = 5 5 + y = 5
y = 2 y = 1 y = 0
Algebraic Equations
Practice Skills EE7.1
Due Wednesday, Jan 23
#3 Daily Assignment should be g + 6 = 21
When complete, work on the EE1 assignment on Delta Math
until 100% is reached.
EE7 Assessment
Thursday, Jan 31
Retakes on Jan 31 during class.
Algebraic Equations
Solve the equation. a + 2 = 8
Algebraic Equations
We can also solve this with a tape diagram.Step 1 – Make two tape diagrams the same length.
Solve the equation. a + 2 = 8
Algebraic Equations
We can also solve this with a tape diagram.Step 1 – Make two tape diagrams the same length.
Solve the equation. a + 2 = 8
Algebraic Equations
We can also solve this with a tape diagram.Step 2 – Label the first diagram with the side of the equation that only has a number.
Solve the equation. a + 2 = 8
Algebraic Equations
We can also solve this with a tape diagram.Step 2 – Label the first diagram with the side of the equation that only has a number.
8
Solve the equation. a + 2 = 8
Algebraic Equations
We can also solve this with a tape diagram.Step 3 – Label the second diagram with the other side of the equation.
8
Solve the equation. a + 2 = 8
Algebraic Equations
We can also solve this with a tape diagram.Step 3 – Label the first diagram with the side of the equation that only has a number.
8
a 2
It doesn’t matter where this line is.
Solve the equation. a + 2 = 8
Algebraic Equations
We can also solve this with a tape diagram.Step 4 – Use both diagrams to determine the value of the variable.
8
a 2
It doesn’t matter where this line is.
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