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    Los Angeles Trade Technology College

    Chemical Technology Program

    Courses: Chemical Technology 131- 142

    Project Team

    Group: No2

    Clarence McKelry

    Dynicia Braxton

    Rodney Pujada

    Robert Thomas

    Submission Date: Monday 10th, 2010

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    Contents

    1. pH Analysis 3

    2. Total Dissolved Solid Dried at 180 C 4

    3. Total Suspended Solids Dried at 103-105 C 6

    4. Chlorine Analysis 8

    5. Determination of Sulfate 11

    6. Oil & Grease Analysis 17

    7. Hardness Analysis 19

    8. Sewage Water Analysis 20

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    1. Title : pH Analysis

    1.1. Method#: 4500-H+ A. pH Value

    1.2. Analytes:

    Sample ID#: A-7543-b

    Sample ID#: B - 1500

    Sample ID#: B 1214-0

    Sample ID#: F 882-3

    Sample ID#: C 222-4

    1.3. Date Due: Wednesday, April 14th, 2010

    1.4. Prepared by: Dynicia and Clarence

    1.5. Objective: To determine pH liquid unknown sample.

    1.6. Data Analysis:

    Sample

    ID# pH Color

    A-7543

    -b 2.56

    Colorle

    ss

    B-1500 5.58

    Colorle

    ss

    B-1214-0 2.56

    Colorle

    ss

    F-882-3 6.99

    Colorle

    ss

    C-222-4 3.12

    Colorle

    ss

    duplicate

    1.7. Conclusion

    All of samples are acid and colorless

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    2. Title: Total Dissolved Solid Dried at 180 C

    2.1 Method#: 2540 C. Total Dissolved Solid Dried at 180 C

    2.2 Analytes:

    Sample ID#: A-7543-b

    Sample ID#: B - 1500

    Sample ID#: B 1214-0

    Sample ID#: F 882-3

    Sample ID#: C 222-4

    Sample ID#: A 3614

    2.3 Date Due: Wednesday, April 21th, 2010

    2.4 Prepared by: Rodney and Clarence

    2.5 Objective: Determine the concentration of total suspended solid in

    each samples.

    2.6 The Sample Handling and Preservation

    a) Preserve by refrigeration at 4 C

    b) The maximum holding for samples is 28 days

    2.7 Data Analysis

    Table No 1: Experimental Data

    4/19/201

    0

    4/19/201

    0

    4/19/20

    10

    4/20/20

    10

    4/21/20

    10 Sample

    ID# Dish empty 7:30 AM 9:45 AM 9:00 AM 9:00 AM

    Dish with

    sample

    grams

    reference(

    gr) W1(gr) W2 (gr) W3 (gr)Average(W1,W2,W

    3)

    A-7543-b 58.9607 58.9649 58.9640 58.9637 58.9638 58.9638

    B-1500 58.4378 58.4427 58.4405 58.4399 58.4393 58.4399

    B-1214-0 73.3920 73.3945 73.3910 73.3911 73.3901 73.3907

    F-882-3 72.5863 72.5627 72.5618 72.5620 72.5642 72.5627

    C-222-4 66.4562 66.4721 66.4709 66.4682 66.4671 66.4687A-3614 68.1818 66.1852 66.1835 66.1830 66.1830 66.1832

    A-7543-b

    Duplicat

    e 68.1215 68.1221 68.1200 66.1198 68.1193 67.4530

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    Table No 2: Result of gravimetric measures

    B A (A-B) mg/LtSample

    ID#

    Dish

    empty

    Dish with

    sampleGravimetric

    Difference to 25 mL

    mg

    Average(W1,W2,W3

    ) mg (B-A)/0.025A-7543-b 58960.7 58963.8 3.1333 125.3

    B-1500 58437.8 58439.9 2.1000 84.0

    B-1214-0 73392.0 73390.7 -1.2667 -50.7

    F-882-3 72586.3 72562.7 -23.6333 -945.3

    C-222-4 66456.2 66468.7 12.5333 501.3

    A-3614 68181.8 66183.2

    -

    1998.6333 -79945.3

    A-7543-b

    Duplicate 68121.5 67453.0 -668.4667 -26738.7

    2.8 Calculations

    a) Calculating total dissolved solids concentration:

    A = weight of dried residue + dish, mg

    B = weight of dish, mg

    For Sample ID#: A-7543-b

    A = 58.9638

    B = 58.9607

    mg Dissolved solids/L = (58.9638 - 58.9607)x1000

    25 mL sample

    mg Dissolved solids/L = 125.3

    2.9 Conclusion

    We made a mistakes in samples:

    Sample ID#: B 1214-0

    Sample ID#: F 882-3

    Sample ID#: A 3614

    5

    mg Dissolved solids/L = ( A B )x1000mL sample

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    A-7543-b

    Duplicat

    e 17.0224 17.3989 17.3989 17.3985 17.3988

    A-3614 18.8490 18.8482 18.8479 18.8491 18.8484

    B-1214-0 18.5200 18.5206 18.5206 18.5204 18.5205

    Table No 2: Result of gravimetric measures

    B A (A-B) mg/Lt

    Sample ID

    Dish

    empty

    Dish with

    sampleGravimetric

    Difference to 25 mL

    mgAverage(W1,W2,

    W3) mg (B-A)/0.025

    A-7543-b 19056.3 19047.7 -8.6 -344.0

    F-882-3 18516.4 18514.8 -1.6 -64.0

    B-1500 17650.3 17638.4 -11.9 -477.3

    C-222-4 17232.9 17233.0 0.1 2.7

    A-7543-b

    Duplicate 17022.4 17398.8 376.4 15054.7

    A-3614 18849.0 18848.4 -0.6 -24.0

    B-1214-0 18520.0 18520.5 0.5 21.3

    3.8 Calculationa) Calculating total suspended solids concentration:

    A = weight of dried residue + gooch crucible, mg

    B = weight of gooch crucible, mg

    For Sample ID#: A-7543-b

    A = 58.9638

    B = 58.9607

    mg Dissolved solids/L = (19047.7 -19056.3)x1000

    25 mL sample

    mg Dissolved solids/L = -344.0

    7

    mg suspended solids/L = ( A B )x1000

    mL sample

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    3.9 Conclusion

    We made a mistake in sample

    Sample ID#: A-7543-b and duplicate

    Sample ID#: B - 1500

    Sample ID#: F 882-3

    Sample ID#: A 3614

    4. Title: Chlorine Analysis

    4.1 Method#: 4500-Cl-C. Mercuric Nitrate Method

    4.2 Analytes:

    Sample ID#: A-7543-bSample ID#: B - 1500

    Sample ID#: B 1214-0

    Sample ID#: C 222-4

    Sample ID#: A 3614

    4.3 Prepared by: Clarence and Robert

    4.4 Date Due: Wednesday, April 21th, 2010

    4.5 Objective: Chloride determination by titration with mercury4.6 The Sample Handling and Preservation

    a) Preserve by refrigeration at 4 C

    b) The maximum holding for samples is 28 days

    4.7 Data Analysis

    Table No 1 : Volume of Mercuric Nitrate

    Sample IDTitrantVolume

    (mL)

    A-7543-b 0.70

    B - 1500 3.30

    B 1214-0 4.30

    C 222-4 2.00

    A 3614 0.70

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    C 222-4Duplicate 2.00

    Table No2: Calculating chloride concentration in samples

    Sample IDTitrantVolume

    (mL)

    Titrant(MercuricNitrate)

    Concentration(N)

    TitratedVolumen

    (mL)

    ChlorideConcentrati

    on (g/L)

    A-7543-b 0.70 0.0141 50 7.00

    B - 1500 3.30 0.0141 50 32.99

    B 1214-0 4.30 0.0141 50 42.99

    C 222-4 2.00 0.0141 50 19.99

    A 3614 0.70 0.0141 50 7.00

    C 222-4Duplicate

    2.00 0.0141 50 19.99

    4.8 Calculation

    Prepared Hg(NO3)2 Concentration = 0.0141 N

    Where:

    A = mL of titrant (mercuric nitrate) for sample

    B = mL of titrant (mercuric nitrate) for blank

    N = normality of mercuric nitrate titrated concentration = 0.0141 N

    For sample A- 7543-b

    mg/L Cl = (0.70 0.01) x 0.0141 x 35.450

    50 mL samplemg/L Cl = 7.00 mg/Cl

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    mg/L Cl = (A B) x N x 35.450

    mL sample

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    5. Title: Determination of Sulfate

    5.1 Method# : 4500-SO42- E. Turbidimetric Method

    5.2 Analytes:

    Sample ID#: F 882-3

    Sample ID#: A 3614

    Sample ID#: B 1214-0

    5.3 Prepared by: Rodney

    5.4 Date Due: Tuesday, April 27th, 2010

    5.5 Objective: To determine the sulfate concentration by comparison by

    reading with a standard curve.

    5.6 Summary of Method:

    a) Sulfate ion is converted to a barium sulfate suspension under

    controlled conditions.

    b) The resulting turbidity is determined by spectrophotometer and

    compared to a calibration curve prepared from standard sulfate

    conditions.

    5.7 The Sample Handling and Preservation

    a) Preserve by refrigeration at 4 C

    b) The maximum holding for samples is 28 days

    5.8 Data Analysis

    Table No 1 Sulfate Calibration Curve

    Concentrati

    on

    Absorbanc

    e

    mg/L

    0 0

    10 0.06

    20 0.1230 0.18

    40 0.25

    Table No 2 Sample Calibration Curve

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    Sample ID Absorbance

    F-882-3 0.01

    F-882-3

    Duplicate 0.01A-3614 0.56

    B-1214-0 0.75

    5.9 Graphic

    a) Standard Calibration Curve

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    b) Sample Calibration Curve

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    5.10 Calculation

    a) Calculating volumes (mL) for standard concentration:

    Prepared Na2SO4 149.7 mg/1LPrepared dilution of 10, 20, 30, 40 mg/L

    Where:

    C1 = sulfate concentration = 149.7 mg/LV1 = unknown volume in mLC2 = sulfate dilution concentration = 10 mg/1LV2 = volume of dilution concentration (10 mg/L) = 100 mL

    V1 = (C2*V2) / C1

    V1 = 6.68 mL

    b) Calculating sample concentration by Calibration Curve

    Sample

    ID Concentration

    Absorbanc

    e

    mg/L

    0 0

    F-882-3 1.64 0.01

    10 0.06

    20 0.12

    30 0.18

    40 0.25

    A-3614 91.80 0.56

    B-1214-0 122.95 0.75

    5.11 Conclusion

    13

    Concentrat

    ion

    volume for

    dilution

    mg/L mL

    10 6.68

    20 13.36

    30 20.04

    40 26.7

    C1*V1 = C2*V2

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    We need to prepared new concentration of standard near to the

    concentrations of samples. 100mg/L and 90mg/L

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    6. Title : Oil & Grease Analysis

    6.1 Method#: 5520 B. Partition Gravimetric Method

    6.2 Analytes:

    Sample ID#: A 41202

    Sample ID#: A 41201

    6.3 Prepared by: Robert and Rodney

    6.4 Date Due: Thursday, May 6th, 2010

    6.5 Objective: To determine the dissolved or emulsified oil and grease

    in unknown samples by using partition gravimetric method.

    6.6 The Sample Handling and Preservation

    a) Preserve by refrigeration at 4 C

    b) If analysis is delayed for more than a few days, the sample is

    acidified with 5 mL of 1:1 HCl

    c) Do not exceed the recommended holding time of 28 days

    6.7 Data Analysis

    Table No 1Gravimetric difference of Standard

    IDSample Date

    Sample

    AmountUsed(L)

    Wt of

    emptyflask(g)

    wt of

    flaskw/sample(g)

    (Wt offlask

    w/sample-Wt. ofempty

    flask) (mg)

    Concentrat

    ion Oil &Grease(mg/L)

    %Recovery

    Standard

    4/24/2010

    1.0080.453

    4 81.2052 751.80751.80 75 %

    Standard

    4/26/2010

    1.00102.59

    27 103.5560 963.30963.30 96 %

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    Table No 2 Gravimetric difference for samples

    IDSample

    Sample

    Amount

    Used(L)

    Wt ofempty

    flask (g)

    wt offlask

    w/sample(g)

    wt of flask

    w/sample (g)Average

    (Wt offlask

    w/sample-Wt. ofemptyflask)

    (mg)

    Concentration Oil &Grease(mg/L)

    W1 W2 W3Average(W1,W

    2,W3)

    Standard

    1.00102.59

    27103.55

    60103.55

    60 103.5560 963.30963.3

    A-41202

    0.97105.22

    65106.63

    34106.63

    34106.63

    34 106.6334 1406.951450.5

    A-41201

    0.97106.83

    00107.20

    46107.20

    46107.20

    46 107.2046 374.60386.2

    6.8 Calculation

    For Sample A- 41202

    Grease and oil, mg/L = (R-B) x 1000

    mL sample

    R = 106.6334 g = 106633.4 mg

    B = 105.2265 g= 105226.5 mg

    Grease and oil, mg/L = (106633.4 mg - 105226.5 mg ) x 1000

    970 mL sample

    Grease and oil, mg/L = 1450.5 mg/L

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    7. Title: Hardness Analysis

    7.1 Method#: 2340 C. EDTA Titrimetric Method

    7.2 Analytes:

    Sample ID#: A-7543-b

    Sample ID#: B - 1500

    Sample ID#: B 1214-0

    Sample ID#: F 882-3

    Sample ID#: C 222-4

    Sample ID#: A 3614

    7.3 Prepared by: Dynicia

    7.4 Date Due: Thursday, April 22th, 2010

    7.5 Objective: To determine hardness by EDTA titrimetric method.

    7.6 The Sample Handling and Preservation

    a) Preserve by refrigeration at 4 C

    b) The maximum holding for samples is 28 days

    7.7 Data Analysis

    Table No 1

    Sample ID

    Titrant

    Volume

    (mL)

    Titrant

    Volume (mL)

    Titrant (EDTA)

    Concentration(M)

    Titrated

    Volumen(mL)

    CaCO3

    Concentration (mg/L)

    CaCO3

    Concentration (mg/L)

    RunN1

    RunN2

    A-7543-b 1.80 1.80 0.01 0.025 0.7200 0.7200

    B - 1500 3.61 13.40 0.01 0.025 1.4440 5.3600

    B 1214-0 5.00 4.90 0.01 0.025 2.0000 1.9600

    F-882-3 0.01 0.61 0.01 0.025 0.0040 0.2440

    C 222-4 3.20 4.51 0.01 0.025 1.2800 1.8040

    A 3614 7.81 28.50 0.01 0.025 3.1240 11.4000

    A-7543-bDuplicate

    2.41 4.60 0.01 0.025 0.9640 1.8400

    Blank 0.01 0.01 0.01 0.025 0.0040 0.0040

    Table No 2

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    Sample IDCaCO3

    Concentration(mg/L)

    A-7543-b 0.7200

    B - 1500 5.3600B 1214-0 1.9600

    F-882-3 0.2440

    C 222-4 1.8040

    A 3614 11.4000

    A-7543-bDuplicate

    1.8400

    Blank 0.0040

    7.8 Calculation

    Hardness (EDTA),as mg CaCO3/L = A x B x 1000

    mL sample

    Where

    A = mL titration for sample and

    B = mg CaCO3, equivalent to 1.00 mL EDTA titrant

    For sample A-7543-b

    Hardness (EDTA),as mg CaCO3/L = 1.80 mL x 0.01 x 1000

    25 mL sample

    Hardness (EDTA),as mg CaCO3/L = 0.72 mg CaCO3/L

    8. Title : Setteable Solids

    8.1 Method#: 2540 F Settleable Solids

    8.2 Analyte: Filtrated water from w

    8.3 Prepared by: Robert

    8.4 Date Due: Thursday, April 22th, 2010

    8.5 Objective: To determine settleable solids in water.

    8.6 Data Analysis: Volume = 31mL

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