angular momentum
DESCRIPTION
Angular Momentum. Angular momentum of rigid bodies Newton’s 2 nd Law for rotational motion Torques and angular momentum in 3-D. Text sections 11.1 - 11.6. m I v w F t p L (“angular momentum”). “Angular momentum” is the rotational analogue of linear momentum. - PowerPoint PPT PresentationTRANSCRIPT
Physics 1D03 - Lecture 31
Make-up Labs
Arrange with Victor in BSB-117
Physics 1D03 - Lecture 31
Angular Momentum IIAngular Momentum II
• General motion of a rigid body• Collisions involving rotation
Text Section 11.1-11.6
Physics 1D03 - Lecture 31
Recall:
• Angular momentum” is the rotational analogue of linear momentum.
m Iv F p L (“angular momentum”)
L = I
Idt
dLexternal
|L| = mrvt = mvr sin
Physics 1D03 - Lecture 31
)( vrprL m
L = I
Angular momentum of a particle:
of a rotating rigid body:
In general, for a moving, rotating rigid body,
ωvrL CMCMm I)(
The first term is called the “orbital” angular momentum and the second term is the “spin” angular momentum.
Example: angular momentum of a planet about the sun.
Physics 1D03 - Lecture 31
Example:
The earth (m = 6.0 x 1024 kg, R = 6400 km) moves at speed v = 30 km/s in an orbit of radius r = 150 x 106 km around the sun. It also spins on its axis once per day (ω = 7.3 x 10-5 rad/s).
The angular momentum of the earth relative to the centre of the sun is L = mvr + ICM ω. The “orbital” part is calculated as if the earth were a particle orbiting the sun; then we add a the angular momentum or the spinning earth relative to its own centre of mass.
Physics 1D03 - Lecture 31
Collisions: Collisions can conserve angular momentum as well as linear momentum.
Total linear momentum is conserved if there is no external force during the collision (or if the external forces are small compared to the forces the colliding bodies exert on each other).
Total angular momentum is conserved if there is no external torque during the collision (or if the external torques are small).
Angular momentum may be calculated about any axis. Usually it is convenient to use an axis through the centre of mass, unless one of the colliding objects actually rotates about some other fixed axis.
Physics 1D03 - Lecture 31
A metre stick (mass M, length L= 1m, moment of inertia I ) is suspended from one end by a frictionless pivot at P. A ball of mass m, velocity v0, strikes the other end of the (stationary) stick at right angles, and stops (final velocity of the ball is zero).
v0
P
Question: Which of the following describe the motionof the stick after the collision? (Answer True, False, or Maybe for each one.)
A) ICM = mv0 L/2B) IP = mv0 LC) MvCM = mv0 D) ½ IP 2= ½ mv0
2
Physics 1D03 - Lecture 31
P
When the ball collides with the stick, there are two forces on the stick which momentarily are large: one from the ball (internal, if the system is ball plus stick); and one from the hinge at P (external force). So we should not expect momentum or angular momentum about the CM to be conserved. So A) and C) are false.
However there is no external torque about P, so angular momentum about P is conserved (so B is true).
D) represents conservation of kinetic energy. It may be true, depending on whether the collision is elastic.
FP
Fball
Physics 1D03 - Lecture 31
v0
CM
P
Quiz
A stick (uniform thin rod) is lying on the ice. A hockey puck hits the stick, at right angles, and the stick starts to slide. Point P is on the end farthest from where the puck hits. Immediately after the collision, the end P will start to move:
A) in the same direction as v0 B) in a direction opposite to v0
C) at an angle (not 0o or 180o) to v0
D) It depends where the puck hits
Physics 1D03 - Lecture 31
Answer: B)
After it is hit, the stick will move forward parallel to v0 (CM motion!), while rotating counterclockwise.
But, if the stick is hit near the middle, the rotation will be slow, and all parts of the stick will move forwards.
If it is hit on the end, the rotation will be fast enough that some parts (including P) will initially be moving backwards.
CM
P
vCM
Physics 1D03 - Lecture 31
Example:
A 2.0kg disk moving at 3.0m/s hits a 1.0kg stick lying flat on a frictionless surface.The moment of inertia of the stick isI=1.33kg m2.
Assuming an elastic collision, find thespeeds of the disk and stick after thecollision and the rotational speed ofthe stick.
v0
2m
Physics 1D03 - Lecture 31
Example: Sticky clay of mass m and velocity v hits a cylinder of mass M and radius R. Find the angular speed of the system after the collision. Is energy conserved?
Physics 1D03 - Lecture 31
Summary
ωvrL CMCMm I)( In general, for a rigid body,
In collisions, angular momentum will be conserved it there is no external torque.