ansys mechanical apdl lecture 4 by haydar alsalami from iraq - hilla, studied in jntuh - india
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Ansys Mechanical APDL lecture 4 by Haydar Alsalami from IRAQ - Hilla, studied in JNTUH - INDIA . [email protected] - mobile : 00919059070644 - 009647801518389TRANSCRIPT
1 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
Combination of Link and Beam:
2 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
Preprocessor:
Choosing structural to
update all mechanical
and physical properties
such as Loads, stresses ..
etc.
3 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
First choose LINK: 2D
if available for easy
solution, if not choose
3D
4 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
Second choose BEAM:
2D if available for easy
solution, if not choose 2
node 188.
5 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
Add Real Constants: Enter cross sectional
Area for LINK as in the problem figure.
For BEAM, if we use version 11 and below,
we can Add constants and enter Area of
BEAM, but here in version 14 , there are NO
constants for BEAM so we can Add constants
in Sections.
6 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
e: means exponential
2e11: means 200000000000
PRXY : start from 0 and less than 1,
here take it 0
If we have DENSITY we have to
enter it in the material properties.
This must be 2e11 in this example
7 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
Sections used with BEAMS and Lines.
We can’t use Sections with SOLIDS and
Areas.
Set ID=1 then choose Sub-type as in the problem, then
fill in the dimensions below.
B = 2.5e-3 , we know that after divide Area by h in the
figure.
H = 2.54e-3 directly from figure.
Nb and Nh mean number of
divisions for section, they give
smoothness and flexibility for
section, we assumed about 30,
they are same Segments in 3D
max.(it’s important).
8 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
New method for drawing by
using COMMAND LINE:
K : keypoint
NPT : number of point
X,Y,Z : coordinates
Then press ( Enter )
9 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
It will be like this.
10 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
New method for drawing by
using COMMAND LINE:
L : Line
1 : keypoint 1
2 : keypoint 2
This means connection
between 1 and 2
Then press (ENTER)
11 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
It will be like this.
12 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
From Mesh Attribute:
Choose Picked Lines,
then pick BEAM Lines
as in the fig. below, then
Apply.
13 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
Since we use version 14 , we have to choose
Element type as 2 BEAM188 as in the fig.
and left Real constant set number as 1 , this
means that we want BEAM with number 2 for
Lines that already picked , and LINK with
number 1 to the remaining Lines.
Press OK
ANSYS now understand
that picked lines as a
BEAM, and other lines as
a LINK.
Note: in version 11 and below we can choose from window
above BEAM as a number 2 in the Element type and number
2 in the Real constant for a picked lines, then Apply ….. then
pick remaining lines and choose LINK as a number 1 in the
Element type and number 1 in the Real constant.
14 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
Apply Meshing:
For BEAM let us say ( 10 )
For LINK enter ( 1 ) compulsory
Then Mesh: Pick All Lines.
15 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
All DOF
All DOF
Press UX, UY, UZ, ROTX,
ROTY.
And left only ROTZ , because
we have rotation about Z.
16 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
Apply force ( -3000 )
17 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
18 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
19 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
After choosing (By Sequence )
From left table, then choose
(SMISC) from right table, then in
the rectangle below enter number
2 as in the figure, it will be
(SMISC, 2) this code relate to
find (Shear Force at ith node)
20 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
SMISC, 2 Shear force at ith node
SMISC, 8 Shear force at jth node
SMISC, 6 Bending moment at ith node
SMISC, 12 Bending moment at jth node
NMISC, 1 Maximum stress at ith node
NMISC, 2 Minimum stress at ith node
NMISC, 3 Maximum stress at jth node
NMISC, 4 Minimum stress at jth node
21 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
It should be like this
22 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
Choose any code to Plot
element as in the figure.
23 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
Choose any code to
show in the List, or
choose many codes in
one time to show in the
List.
Attention: these results for
Elements not for Nodes.
24 | Haydar Alsalami \ JNTUH \ India mobile: 00919059070644 – Iraq mobile: 009647801518389 E-Mail: [email protected]
In this window we select different
codes one for node I and another for
node J to see the difference Plot
between them a in the figure.
In this fig. we chose SMISC2 and
SMISC8 to see the difference
between the shear force at ith node
and shear force at jth node. Note: there must be a relationship between chosen codes for
I and j for example:
SMISC2 & SMISC8 or SMISC6 & SMISC12
NMISC1 & NMISC2 or NMISC3 & NMISC4