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Q.1 A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length

of the train?

A. 120 Meters

B. 150 MetersC. 324 Meters

D. 180 Meters

ANSWER : Option B 150 Meters

SOLUTION :

Speed = (60*5/18)m/Sec. =(50/3) m/Sec.

Length of Train=(Speed * Time)=(50/3*9)m=150 Meters

Q.2 Two trains of equal lengths take 10 seconds and 15 seconds respectively to cross a

telegraph post. If the length of each train be 120 meters, in what time in(seconds) will theycross each other travelling in opposite direction?

A. 10 Sec

B. 12 Sec

C. 15 Sec

D. 20 Sec

ANSWER : Option B 12 Sec

SOLUTION :

Speed of first train = (120/10) m/ sec. = 12m/sec

Speed of second Train =(120/15) m/sec. =8m/secRelative Speed = (12+8)= 20m/sec

Hence required time = (120+120)/20 Sec= 12 Sec.

Q.3 Two trains of equal length are running on parallel lines in the same direction at 46 km/hr

and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each

train is:

A. 50 m

B. 72 m

C. 80 mD. 82 m

ANSWER : Option A 50 m

SOLUTION :

Let the length of each train be X meters.

Then, distance covered = 2x

Relative Speed= (46-36) Km/hr = (10*1000mtr/3600 Sec)= (25/9) m/Sec

Hence, 2X/36 = 25/9 , 2x=100

X= 50.

Q.4 A train passes a station platform in 36 seconds and a man standing on the platform in

20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?

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A. 120

B. 180

C. 220

D. 240

ANSWER : Option D 240

SOLUTION :

Speed= (54*5/18)m/sec.=15m/sec.

Length of the Train = (15*20)m=300mtr.

Let the length of the platform be x metres.

Then,x + 300= 15

36

x + 300 = 540

x = 240 m.

Q.5 A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform

650 m long?

A. 65 sec.

B. 74 sec.

C. 89 sec

D. 96 sec.

ANSWER : Option C 89 secSOLUTION :

Speed=(240/24)m/sec = 10m/sec.

Hence,Required time = (240+650)/10sec. = 89sec.

Q.6 A train 120 m long is running at the speed of 54 km /hr. Find the time taken it to pass a

man standing near the railway track.

A. 8 sec

B. 9 sec

C. 11 sec.D. 10 sec.

ANSWER : Option A 8 sec

SOLUTION :

speed of train = [54 * ( 5 / 18 ) ] = 15 m / sec

length of train = 120 m , So required time :

TimeTaken=(120/15)=8sec

Q.7 A train is moving at a speed of 54 km / hr. If the length of the train is 100 meters, how

long will it take to cross a railway platform 110 meters long ?

A. 12 sec.



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B. 14 sec.

C. 16 sec

D. 18 sec

ANSWER : Option B 14 sec

SOLUTION :

speed of train = [54 * ( 5 / 18 ) ] = 15 m / sec

Distance covered in passing the platform = 100 + 110 = 210 m

time taken=(210/15)=14sec

Q.8 Two trains 125 m and 100 m in length respectively are running in opposite directions,

one at the rate of 50km/hr and the other at the rate of 40km/hr. At what time they will cleareach other from the moment they meet?

A. 7 sec.

B. 8 sec.

C. 9 sec.

D. 10 sec.

ANSWER : Option C 9 sec

SOLUTION :

of trains = (50 + 40) km / hr = [90 * ( 5 / 18 ) ] = 25 m / sec

Total length to be travelled = 125 + 100 = 225 m


Q.9 Two trains 110m and 100m in length respectively are running in same directions, one at

the rate of 100km/hr and the other at the rate of 64km/hr. At what time faster train will clear

other train from the moment they meet ?

A. 15 sec

B. 18 sec.

C. 21 sec.

D. 24 sec.

ANSWER : Option C 21 sec.

SOLUTION :

Since trains are running in same direction, so

relative speed = 100-64 = 36 km / hr = [ 36 * ( 5 / 18 )] = 10 m / sec

Total length to be travelled = 110 + 100 = 210 m

time taken=(210/10)=21 sec

Q.10 A train 125 m in length, moves at a speed of 82 km / hr , In what time the train will

cross a boy who is walking at 8 km / hr in opposite direction ?



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A. 3 sec.

B. 5 sec.

C. 7 sec

D. 9 sec

ANSWER : Option B 5 sec.

SOLUTION :

Relative speed = 82+8 = 90 km / hr = [ 90 * ( 5 / 18 )] = 25 m / sec.


Q.11 A train passes a standing pole on the platform in 5 seconds and passes the platform

completely in 20 seconds. If the length of the platform is 225 meters. Then find the length of

the train ?

A. 75 mB. 80 m

C. 85 m

D. 90 m


SOLUTION :

Let the length of the train is x meter

So speed of train =( x / 5 ) m / sec

Also speed of train = ( 225 + x ) / 20 m/sec

x/5=225+x/20

so x=75m

Q.12 Two trains of length 115 m and 110 m respectively run on parallel rails. When running

in the same direction the faster train passes the slower one in 25 seconds, but when they

are running in opposite directions with the same speeds as earlier, they pass each other in

5 seconds. Find the speed of each train ?

A. 22 m/s & 15 m/s

B. 25 m/s & 17 m/sC. 27 m/s & 18 m/s

D. 30 m/s & 21 m/s

ANSWER : Option C 27 m/s & 18 m/s

SOLUTION :

Let the speed of trains be x m/sec and y m/sec espectively.

When they move in same direction their relative speed is : x - y

When they moves in opposite direction their relative speed is : x + yso x-y=115+110/25,x+y=115+110/5

On solving two equations x=27 m/s and y=18 m/sec



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Q.13 The length of the bridge, which a train 130 meters long and travelling at 45km/hr can

cross in 30 seconds, is:

A. 200

B. 260C. 230

D. 245


SOLUTION :

Speed = 45*5/18 m/sec. 25/2 m/sec.

Time = 30 sec.

Let the length of bridge be xmtr.

Then, (130+x)/30 = 25/2

2(130+x) = 25*30

2(130+x) = 750

X =245

Q.14 A train of length 150 meters takes 40.5 seconds to cross a tunnel of length 300

meters. What is the speed of the train in km/hr?

A. 40 km/hr.

B. 37 km/hr.

C. 42 km/hr.

D. 35 km/hr.

ANSWER : Option A 40 km/hr

SOLUTION :

Speed = (150+300)/40.5 m/sec.

=(450/40.5 *18/5)km/hr.

=40km/hr.

Q.15 A jogger running at 9 km/h alongside a railway track is 240 meters ahead of the

engine of a 120 meters long train running at 45 km/h in the same direction. In how much

time will the train pass the jogger?

A. 3.6 secB. 360 sec

C. 36 sec.

D. None.

ANSWER : Option C 36 sec.

SOLUTION :

Speed of train relative to Jogger = (45 - 9) km/hr. = 36 km/hr.

= 36*5/18 m/sec. =10 m/sec

Distance to be covered = (240+120) m = 360 m.Hence, Time taken = 360/10 sec = 36 sec.

Q.16 A train travelling at 48 km/h completely crosses another train having half its length and

travelling in opposite direction at 42 km/h, in 12 seconds, It also passes a railway platform in



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45 seconds. The length of the platform is.

A. 400 m

B. 450 m

C. 500 mD. 600 m


SOLUTION :

Let, length of the first train is X mtr

Then, length of second train is X/2mtr.

Relative speed = (48+42) km/hr = (90*5/18) m/sec. =25 m/sec.

(x+x/2)/25=12 3x/2 = 300 x = 200m

Length of first train = 200m.

Let, the length of platform be Ymtr.

Speed of thefirs train =(48*5/18)m/sec. =40/3 m/sec.

(200 + Y) x 3/40 = 45

600 + 3Y = 1800

Y = 400 m

Q.17 A train covers a distance of 12 km in 10 minutes. If it takes 6 seconds to pass a

telegraph post, then the length of the train is:

A. 90 mtr.

B. 100 mtr.

C. 120 mtrD. 140 mtr

ANSWER : Option C 120 mtr

SOLUTION :

Speed = 12/10*60 km/hr. = 72*5/18 m/sec. =20 m/sec

Length of the train = (Speed x Time) = (20x6) mtr. =120 mtr

Q.18 A train 800 meters long is running at a speed of 78 km / hr. If it crosses a tunnel in 1

minute, then the length of the tunnel (in meters) is:

A. 130mtr.B. 340 mtr

C. 480mtr

D. 500mtr.

ANSWER : Option D 500mtr.

SOLUTION :

Speed = (78x5/18)m/sec. = (65/3) m/sec;

Let the length of the tunnel be x mtr.

Then, (800+X/60) = 65/3

3(800+X) = 3900X = 500 mtr.



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Q.19 Two trains running in opposite directions cross a man standing on the platform in 27

seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of

their speeds is:

A. 1:3B. 3:2

C. 2:3

D. 3:4

ANSWER : Option B 3:2

SOLUTION :

Let the speed of both trains are X m/sec. & Y m/sec. resp.

Then, the length of first train is = 27X m/sec.

And the length of second train is = 17Y m/sec.

(27X + 17Y)/X+Y = 23

27X + 17Y = 23X + 23Y

4X = 6Y

X/Y = 3/2

Q.20 A train leaves Cairo at 3:00 am, averaging 30 mph.

Another train headed in the same direction leaves Cairo at 6:00 am, averaging 60 mph.

To the nearest tenth, how many hours after the second train leaves will it overtake the first

train?

A. 2 hr.B. 2.5 hr

C. 3 hr.

D. 4 hr.

ANSWER : Option C 3 hr.

SOLUTION :

We begin by noting that the distance travelled by both trains must be the same when the

second train overtakes the first.

Distance = Rate ~A- Time

Therefore, r1t1 = r2t2

Let t2 = time that the second train is travelling.Let t1 = time that the first train is travelling alone + time that it's travelling with the second

train = 3 + t2

r1(3 + t2) = r2t2

30(3 + t2) = 60t2

90 + 30 t2 = 60t2

90 = 30t2

t2 = 3 hr.

Q.21 A train leaves Pune at 8:00 pm, averaging 60 m/h.Another train headed in the same direction leaves Pune at 12:00 am, averaging 90 m/h.To

the nearest tenth, how many hours after the second train leaves will it overtake the first



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train?

A. 6 hr.

B. 7 hr.C. 7.5 hr.

D. 8 hr

ANSWER : Option D 8 hr

SOLUTION :

Distance = Rate Time

Therefore, the total head start that the first train has is 4 hours 60 m/h = 240 miles.

The second train travels at a relative rate of 30m/h faster than the first train and it starts 240

miles behind the first train.

Thus we can find the time it will take to overtake the first train by relating distance rate and

time once again.

Time = Distance Rate

Time = 240.30 = 8 hr.

Q.22 A train leaves Venice at 7:00 pm, averaging 80 mph.

Another train headed in the same direction leaves Venice at 10:00 pm, averaging 100 mph.

To the nearest minute, at what time will the second train overtake the first train?

A. 10 pm

B. 10 am

C. 12 pm

D. 12 am

ANSWER : Option B 10 am

SOLUTION :





Let t2 = time that the second train is travelling.

Let t1 = time that the first train is travelling alone + time that it's travelling with the second

train = 3 + t2

r1(3 + t2) = r2t2

80(3 + t2) = 100t2

240 + 80t2 = 100t2

240 = 20t2

t2 = 12

Now we must use that to determine the time the second train overtakes the first.



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Adding the time passed to 10:00 pm we get 10:00 am

Q.23 A train leaves Taipei at 3:00 am, averaging 50 m/h. Another train headed in the samedirection leaves Taipei at 4:00 am, averaging 70 m/h.To the nearest minute, at what time

will the second train overtake the first train?

A. 6.30 am

B. 6.30 pm

C. 7 am

D. 7.30 am

ANSWER : Option A 6.30 am

SOLUTION :

Distance = Rate-TimeTherefore, the total head start that the first train has is 1 hour 50 m/h = 50 miles.

The second train travels at a relative rate of 20m/h faster than the first train and it starts 50



time once again.

Time = Distance - Rate

Time = 50. 20 = 2.5


2.5 hrs can be converted to hours and minutes. It should be 2 hrs and 0.5 ??? 60 =

30 min.

Adding the time passed to 4:00 am we get 6:30 am

Q.24 A train leaves Los Angeles at 6:45 pm, averaging 85 m/h.Another train headed in the

same direction leaves Los Angeles at 9:30 pm, averaging 105 mph.To the nearest minute,

at what time will the second train overtake the first train?

A. 9.06 amB. 9.11 am

C. 9.25 am

D. 9.37 am

ANSWER : Option B 9.11 am

SOLUTION :



Distance = Rate ? Time


Let t2 = time that the second train is travelling.



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Let t1 = time that the first train is travelling alone + time that it's travelling with the

second train = 2.75 + t2

r1(2.75 + t2) = r2t285(2.75 + t2) = 105t2

233.75 + 85t2 = 105t2

233.75 = 20t2

t2 = 11.6875


11.6875 hrs can be converted to hours and minutes. It should be 11 hrs and 0.6875

? 60 = 41 min.

Adding the time passed to 9:30 pm we get 9:11 am

Q.25 A train leaves Cairo at 2:45 pm, averaging 30 mph.

Another train headed in the same direction leaves Cairo at 3:15 pm, averaging 45 mph.

To the nearest minute, at what time will the second train overtake the first train?

A. 4 am

B. 4 pm

C. 4.15 am

D. 4.15 pm

ANSWER : Option D 4.15 pmSOLUTION :


Therefore, the total head start that the first train has is 0.5 hours~A- 30 mph = 15 miles.

The second train travels at a relative rate of 15mph faster than the first train and it starts 15



time once again.

Time = Distance ~A. Rate

Time = 15 ~A. 15 = 1


Adding the time passed to 3:15 pm we get 4:15 pm

Q.26 A train leaves Rome at 7:15 am, averaging 95 m/h.

Another train headed in the opposite direction leaves Rome at 8:30 am, averaging 115

m/h.To the nearest mile, how far are the two trains from each other at 10:30 am?

A. 537B. 539

C. 542



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D. 547

ANSWER : Option B 539

SOLUTION :Since both trains are travelling in opposite directions, their total distance apart is the sum of

the distances they each traveled.

Distance = Rate-Time

Therefore, dtotal = r1t1 + r2t2

Let t1 = time between 7:15 am and 10:30 am = 3.25

Let t2 = time between 8:30 am and 10:30 am = 2

dtotal = 95t1 + 115t2

dtotal = 95.3.25 + 115.2

dtotal = 308.75 + 230

dtotal = 538.75

dtotal = 539 (rounded)

Q.27 A train leaves Geneva for a nearby city at 3:04 pm, averaging 37 mph.

Another train leaves the nearby city for Geneva at 7:30 pm, averaging 55 mph.

If the nearby city is 624.03333333333 miles from Geneva, to the nearest minute, at what

time will the two trains pass each other?

A. 12 pmB. 12 am

C. 12.30 pm

D. 12.30 am

ANSWER : Option C 12.30 pm

SOLUTION :

Note that the total distance travelled between the two trains must equal the distance

between the two cities.


Therefore d = r1t1 + r2t2.

Let t2 = Time travelled by the second train.

Let t1 = Time travelled by the first train alone + Time travelled with second train =

4.4333333333333 + t2

d = r1(4.4333333333333 + t2) + r2t2

624.03333333333 = 37(4.4333333333333 + t2) + 55t2

624.03333333333 = 164.03333333333 + 37t2 + 55t2

460 = 92t2

t2 = 5

We must use the amount of time that passes after the second train leaves to determine the

time at which the trains pass by each other.



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Adding this amount of time to 7:30 pm yields 12:30 pm as the time.

Q.28 A train 150 m long is running with a speed of 68 km/ph. In what time will itpass a manwho is running at 8 kmph in the same direction in which the train isgoing?

A. 6 sec.

B. 7 sec.

C. 8 sec.

D. 9 sec.

ANSWER : Option D 9 sec

SOLUTION :

Speed of the train relative to man = (68 - 8) kmph

= (60 x 5/18)m/see = 50/3 m/sec

Time taken by the train to cross the man = Time taken by it to cover 150 m at(50/3)m/sec = (150 x 3/50)sec = 9 sec.

Q.29 A boat takes 90 minutes less to travel 36 miles downstream than to travel the

samedistance upstream. If the speed of the boat in still water is 10 mph, the speed of

thestream is:(ACCENTURE 2007)

A. 2 mph

B. 2.5 mph

C. 3 mph

D. 4 mph

ANSWER : Option A 2 mph

SOLUTION :

Let the speed of the stream x mph. Then,

Speed downstream = (10 + x) mph,

Speed upstream = (10 - x) mph.

36/(10-X)-36/(10+X) =90/60

72X x 60 = 90 (100 ^aEUR" X2)

X2+ 48X - 100 = 0

(X+ 50)(X - 2) = 0

X = 2 mph.

Q.30 A man can row at 5 km/h in still water. If the velocity of current is 1 km/h and it take

shim 1 hour to row to a place and come back, how far is the place?

A. 2.4 km

B. 2.5 km

C. 3 km

D. 3.6 km



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ANSWER : Option A 2.4 km

SOLUTION :

Speed downstream = (5 + 1) km/h = 6 km/h.

Speed upstream = (5 - 1) km/h = 4 km/h.Let the required distance be x km.

Then, x/6 + x/4 =1

2x + 3x = 12

5x = 12

x = 2.4 km.

Q.31 A boat covers a certain distance downstream in 1 hour, while it comes back in 1

hours.If the speed of the stream be 3 kmph, what is the speed of the boat in still water?

A. 12 kmph

B. 13 kmphC. 14 kmph

D. 15 kmph

ANSWER : Option D 15 kmph

SOLUTION :

Let the speed of the boat in still water be x kmph. Then,

Speed downstream = (x + 3) kmph,

Speed upstream = (x - 3) kmph.

(x + 3) x 1 = (x - 3) x 3/2

2x + 6 = 3x - 9x = 15 kmph.

Q.32 A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along

the current in 10 minutes. How long will it take to go 5 km in stationary water?(CSC 2008)

A. 40 minutes

B. 1 hour

C. 1 hr 15 min

D. 1 hr 30 min

ANSWER : Option C 1 hr 15 minSOLUTION :

Rate downstream = (1/10x60) km/hr =6 km/hr.

Rate upstream = 2 km/hr.

Speed in still water = 1/2(6 + 2) km/hr = 4 km/hr.

Required time = 5/4 hr. = 1/14hr. = 1 hr. & 15 min.

Q.33 A man can row three-quarters of a kilometre against the stream in 11 minutes and

down the stream in 7 minutes. The speed (in km/hr) of the man in still water is: (SBI P.O

2001

A. 2

B. 3



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C. 4

D. 5

ANSWER : Option D 5SOLUTION :

We can write three-quarters of a kilometre as 750 metres,

and 11x1/4 minutes as 675 seconds.

Rate upstream = 750/675 m/sec = 10/9 m/sec.

Rate downstream = 750/450 m/sec = 5/3 m/sec.

Rate in still water = ^A 1/2 (10/9+5/3) m/sec.

= (25/18x18/5) km/hr.

= 5 km/hr.

Q.34 Speed of a boat in standing water is 9 kmph and the speed of the stream is 1.5 kmph.Aman rows to a place at a distance of 105 km and comes back to the starting point.

Thetotal time taken by him is.(S.S.C 2005)

A. 16 hours

B. 18 hours

C. 20 hours

D. 24 hours

ANSWER : Option D 24 hours

SOLUTION :

Speed upstream = 7.5 kmph.Speed downstream = 10.5 kmph.

Total time taken = (105/7.5+105/10.5) hrs. = 24 hrs.

Q.35 A man takes twice as long to row a distance against the stream as to row the same

distance in favor of the stream. The ratio of the speed of the boat

(in still water) and the stream is:

A. 2 : 1

B. 3 : 1

C. 3 : 2

D. 4 : 3

ANSWER : Option B 3 : 1

SOLUTION :

Let man's rate upstream be x kmph.

Then, his rate downstream = 2x kmph.

(Speed in still water) : (Speed of stream) = (2x + x/2) : (2x ?? x/2)

= 3x/2 : x/2

= 3 : 1

Q.36 A man rows to a place 48 km distant and come back in 14 hours. He finds that he can

row 4 km with the stream in the same time as 3 km against the stream. The rate of the

stream is.(BANK PO 2008)



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A. 1 km/hr

B. 1.5 km/hr

C. 2 km/hr

D. 2.5 km/hr

ANSWER : Option A 1 km/hr

SOLUTION :

Suppose he move 4 km downstream in x hours. Then,

Speed downstream = (4/x) km/hr.

Speed upstream =(3/x) km/hr.

48/(4/x) +48/(3/x) = 14 or x = 1/2

So, Speed downstream = 8 km/hr, Speed upstream = 6 km/hr.

Rate of the stream =1/2(8 - 6) km/hr = 1 km/hr

Q.37 A boat can travel with a speed of 13 km/hr in still water. If the speed of the stream is 4

km/hr, find the time taken by the boat to go 68 km downstream. (WIPRO 2007

A. 2 hours

B. 3 hours

C. 4 hours

D. 5 hours

ANSWER : Option C 4 hours

SOLUTION :

Speed downstream = (13 + 4) km/hr = 17 km/hr.Time taken to travel 68 km downstream = 68/17 hrs = 4 hrs.

Q.38 A man's speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr.

The man's speed against the current is: (IGATE 2009)

A. 8.5 km/hr

B. 9 km/hr

C. 10 km/hr

D. 12.5 km/hr

ANSWER : Option C 10 km/hrSOLUTION :

Man's rate in still water = (15 - 2.5) km/hr = 12.5 km/hr.

Man's rate against the current = (12.5 - 2.5) km/hr = 10 km/hr.

Q.39 A boat running upstream takes 8 hours 48 minutes to cover a certain distance, while

ittakes 4 hours to cover the same distance running downstream. What is the ratiobetween

the speed of the boat and speed of the water current respectively?(TCS 2004)

A. 2 : 1

B. 3 : 2

C. 8 : 3

D. Cannot be determined



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ANSWER : Option C 8 : 3

SOLUTION :

Let the man's rate upstream be x kmph and that downstream be y kmph. Then, distance

covered upstream in 8 hrs 48 min = Distance covered downstream in 4 hrs.(X x 8x4/5) = (Y x 4)

44/5X = 4Y

1Y = 11/5X

Required ratio = (y + x)/2 : (y ^aEUR" x)/2

= (16x/5 x 1/2) : (6x/5 x ^A 1/2 )

= 8/5 :3/5

= 8 : 3

Q.40 A motorboat, whose speed in 15 km/hr in still water goes 30 km downstream and

comesback in a total of 4 hours 30 minutes. The speed of the stream in(km/hr) is:A. 4

B. 5

C. 6

D. 10

ANSWER : Option B 5

SOLUTION :

Let the speed of the stream be X km/hr. Then,

Speed downstream = (15 + X) km/hr,

Speed upstream = (15 - X) km/hr.30/(15+X) + 30/(15+X) = 4x1/2

900/225 ?? X2 = 9/2

9X2 = 225

X2 = 25

X = 5 km/hr.

Q.41 In one hour, a boat goes 11 km/hr along the stream and 5 km/hr against the

stream.The speed of the boat in still water (in km/hr) is.(HCL 2008)

A. 3 km/hr

B. 5 km/hrC. 8 km/hr

D. 9 km/hr

ANSWER : Option C 8 km/hr

SOLUTION :

Speed in still water = 1/2(11 + 5) kmph = 8 kmph.

Q.42 A boat running downstream covers a distance of 16 km in 2 hours while for

coveringthe same distance upstream, it takes 4 hours. What is the speed of the boat in

stillwater?

A. 4 km/hr

B. 6 km/hr



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C. 8 km/hr

D. Data inadequate

ANSWER : Option B 6 km/hrSOLUTION :

Rate downstream = (16/2)kmph = 8 kmph.

Rate upstream = (16/4)kmph = 4 kmph.

Speed in still water = 1/2(8 + 4) kmph = 6 kmph.

Q.43 The speed of a boat in still water in 15 km/hr and the rate of current is 3 km/hr. The

distance travelled downstream in 12 minutes is:

A. 1.2 km

B. 1.8 km

C. 2.4 kmD. 3.6 km

ANSWER : Option D 3.6 km

SOLUTION :

Speed downstream = (15 + 3) kmph = 18 kmph.

Distance travelled = (18 x 12/60) km = 3.6 km

Q.44 A train 100 m long is running at the speed of 30 km / hr. Find the time taken by

it to pass a man standing near the railway line. (S.S.C. 2001

A. 10 sec.

B. 12 sec.

C. 14 sec.

D. 16 sec.


SOLUTION :

Speed of the train = (30 x 5/18_) m / sec = (25/3) m/ sec.

Distance moved in passing the standing man = 100 m.

Required time taken = 100/(25/3) = (100 *(3/25)) sec = 12 sec

Q.45 A train is moving at a speed of 132 km/br. If the length of the train is110 metres, how

long will it take to cross a railway platform 165 metres long?(Bank P.O.2004)

A. 7.5 sec.

B. 8 sec

C. 8.5 sec.

D. 9 sec.

ANSWER : Option A 7.5 sec

SOLUTION :

Speed of train = 132 *(5/18) m/sec = 110/3 m/sec.

Distance covered in passing the platform = (110 + 165) m = 275 m.



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Time taken =275 *(3/110) sec =15/2 sec = 7 ^A 1/2 sec

Q.46 A man is standing on a railway bridge which is 180 m long. He finds that atrain crosses the bridge in 20 seconds but himself in 8 seconds. Find the length of thetrain

and its speed? (SASKEN 2003)

A. 37 km.

B. 45 km

C. 54 km

D. 61 km

ANSWER : Option C 54 km

SOLUTION :

Let the length of the train be x metres,Then, the train covers x metres in 8 seconds and (x + 180) metres in 20 sec

x/8=(x+180)/20

20x = 8 (x + 180)

x = 120.

Length of the train = 120 m.

Speed of the train = (120/8) m / sec

= (15 *18/5) kmph

= 54 km

Q.47 A train 150 m long is running with a speed of 68 km/h. In what time will it pass aman

who is running at 8 km/h in the same direction in which the train is going?(WIPRO 2008)

A. 8 sec.

B. 9 sec.

C. 10 sec.

D. 11 sec.


SOLUTION :

Speed of the train relative to man = (68 - 8) kmph

= (60* 5/18) m/sec = (50/3)m/secTime taken by the train to cross the man I

= Time taken by It to cover 150 m at 50/3 m / sec

= 150 *3/ 50 sec = 9sec.

Q.48 A train 220 m long is running with a speed of 59 km/h. In what will-it pass a man who

is running at 7 km/h in the direction opposite to that in which the train's going?

A. 12 sec.

B. 14 sec.

C. 16 sec.

D. 18 sec.

ANSWER : Option A 12 sec.



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SOLUTION :

Speed of the train relative to man = (59 + 7) kmph

= 66 *5/18 m/sec = 55/3 m/sec.

Time taken by the train to cross the man = Time taken by it to cover 220 m at (55/3) m / sec= (220 *3/55) sec = 12 sec

Q.49 A train 100 meters long takes 6 seconds to cross a man walking at 5 km/h in the

direction opposite to that of the train. Find the speed of the train

A. 47 km/hr.

B. 49 km/hr.

C. 53 km/hr.

D. 55 km/hr.

ANSWER : Option D 55 km/hr.

SOLUTION :

Let the speed of the train be x kmph.

Speed of the train relative to man = (x + 5) kmph = (x + 5) *5/18 m/sec.

100/((x+5)*5/18)=6

30 (x + 5) = 1800

x = 55 km/hr.

Q.50 A train running at 54 km/h takes 20 seconds to pass a platform. Next it takes.12 sector

pass a man walking at 6 km/h in the same direction in which the train is going. Find the

length of the train and the length of the platform. (CAT 2006)

A. 140 m

B. 150 m

C. 145 m

D. 155 m


SOLUTION :

Let the length of train be x metres

and length of platform be y metres.Speed of the train relative to man = (54 - 6) kmph = 48 kmph

= 48*(5/18) m/sec = 40/3 m/sec.

In passing a man, the train covers its own length with relative speed.

Length of train (x) = (Relative speed * Time) = ( 40/3)*12 m = 160 m.

Also, speed of the train = 54 *(5/18)m / sec = 15 m / sec.

(x+y)/15 = 20

x + y = 300

Y = (300 - 160) m = 140 m.

Q.51 A man sitting in a train which is traveling at 50 km/h observes that a goods

train,traveling in opposite direction, takes 9 seconds to pass him. If the goods train is 280 m

long,find its speed.?



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A. 57 km/hr.

B. 62 km/hr.

C. 67 km/hrD. 72 km/hr

ANSWER : Option B 62 km/hr.

SOLUTION :

Relative speed = 280/9 m / sec = ((280/9)*(18/5)) km/h = 112 km/h.

Speed of goods train = (112 - 50) km/h = 62 km/h.

Q.52 A train X speeding with 120 km/h crosses another train Y, running in the same

direction, in 2 minutes. If the lengths of the trains X and Y be 100 m and 200 m respectively,

what is the speed of train Y?A. 109 km/hr.

B. 113 km/hr

C. 117 km/hr.

D. 111 km/hr.

ANSWER : Option D 111 km/hr.

SOLUTION :

And the speed of train x relative to y

= (120-x )5/18 m/sec.

= (600-5x)/18 m/sec.300/(600-5x)/18 = 120 5400 = 120(600-5x)

x = 111 km/hr.

Q.53 A train 800 meters long is running at a speed of 78 km/hr. If it crosses a tunnel in 1

minute, then the length of the tunnel (in meters) is

A. 500

B. 525

C. 550

D. 600

ANSWER : Option A 500

SOLUTION :

Speed =(78x5/18)m/sec. = 65/3 m/sec.

Let length of the tunnel is x mtr.

Then, (800+x)/60 sec. = 65/3

3(800+x) = 3900

2400 + 3x = 3900

X = 500

Q.54 If 12 man can finish a piece of work in 36 days in how many days 18 men can finish

the same work?

A. 30



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B. 26

C. 24

D. 21

ANSWER : Option C 24

SOLUTION :

12 men can finish a work in 36 days.

18 men can finish the work in = (12/18)x36=24

Q.55 Two pipes can fill a tank in 20 and 24 minutes respectively and a waste pipe can

empty 3 gallons per minute. All the three pipes working together can fill the tank in 15

minutes. The capacity of the tank in gallons is.

A. 100

B. 115C. 120

D. 125


SOLUTION :

Work done by the waste pipe in 1 minute

1/15 ^aEUR" (1/20 + 1/24)

1/15 ^aEUR" 11/120 = -1/40

Volume of 1/14 part = 3 gallons.

Therefore, Volume of whole =(3~A-40)gallons = 120 gallons.

Q.56 A man can do a piece of work in 5 days, but with the help pf his son, he can do it in 3

days. In what time can the son do it alone?

A. 7 days

B. 7.5 days

C. 8 days

D. 8.5 days

ANSWER : Option B 7.5 days

SOLUTION :Son's 1 day's work = (1/3-1/5)

= 2/15.

The son alone can do the work in = 15/2 = 7.5 days

Q.57 A can do a work in 15 days and B in 20 days. If they work on it together for 4 days,

then the fraction of the work that is left is :

A. 1/5

B. 1/15

C. 6/15

D. 8/15

ANSWER : Option D 8/15



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SOLUTION :

A's 1 day's work = 1/15;

B's 1 day's work = 1/20;

(A + B)'s 1 day's work = (1/15 + 1/20) = 7/60.(A + B)'s 4 day's work = 7/60x4 =7/15.

Therefore, Remaining work = (1-7/15) = 8/15.

Q.58 A is thrice as good a workman as B and therefore is able to finish a job in 60 days less

than B. Working together, they can do it in:

A. 21.5 days

B. 22 days

C. 22.5 days

D. 23 days

ANSWER : Option C 22.5 days

SOLUTION :

Ratio of times taken by A and B = 1 : 3.

If difference of time is 2 days, B takes 3 days.

If difference of time is 60 days, B takes = 3/2x60 = 90 days.

So, A takes 30 days to do the work.

A's 1 day's work = 1/30 ; B's 1 day's work = 1/90;

(A + B)'s 1 day's work = (1/30+1/90) = 4/90= 2/45.

Therefore, A and B together can do the work in 45/2 = 22.5 days.

Q.59 39 persons can repair a road in 12 days, working 5 hours a day. In how many days will

30 persons, working 6 hours a day, complete the work?

A. 14

B. 12

C. 17

D. 13


SOLUTION :

Let's calculate how much time it takes to repair the road if just 1 person were working on it.5 hours a day for 12 days makes it 60 hours per person.

39 people working 60 hours each makes it 39~A-60=2340 hours in total.

Now we have 30 people working 6 hours a day

That means 30~A-6=180 hours are spent each day.

We need a total of 2340 hours.

With 180 hours every day,

that's going to take 2340/180 = 13 days to complete...

Or

you could just do it in one step... :-

39~A-12~A-5 = 30~A-X~A-62340 = 180X

X = 2340/180



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X = 13.

Q.60 Sakshi can do a piece of work in 20 days. Tanya is 25% more efficient than Sakshi.The number of days taken by tanya to do the same piece of work is

A. 15

B. 16

C. 17

D. 18


SOLUTION :

Ratio of times taken by Sakshi and Tanya = 125:100 = 5:4

Suppose Tanya takes x days to do the work. = 5 : 4 ::20 : X

X = 4~A-20/5 X = 16 days.

Q.61 A piece of work can be done by 6 men and 5 women in 6 days or 3 men and 4 women

in 10 days. It can be done by 9 men and 15 women in :

[Assistant Grade]

A. 4

B. 1

C. 2

D. 3

ANSWER : Option D 3

SOLUTION :

Let 1 mans 1 days work = x and 1 womans 1 days work = y.

Then, 6x+5y = 1/6 , 3x+4y = 1/10

On solving, we get x = 1/54 and y = 1/90

(9 men + 15 women)s 1 days work = (9/54) + (15/90) = 1/3

They will finish the work in 3 days.

Q.62 A and B can complete a work in 12 days. B and C can complete the same work in 18days. C and A can complete in 24 days. How many days will take for A, B and C combined

together to complete the same amount of work?

A. 11

B. 11(1/2)

C. 11(1/3)

D. 12

ANSWER : Option C 11(1/3)

SOLUTION :

A and B can complete the work in 12 days.

(A+B) Can complete(1/12) part of the work in 1 day

(B+C) can complete (1/18) part of the work in 1 day

(A+C) can complete (1/24) part of the work in 1 day



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By adding the three equations, we get,

(A+B) + (B+C) + (A+C) = 1/12+1/18+1/24

2A+2B+2C = (6+4+3)/72

2(A+B+C)=13/72(A+B+C) can complete 13/144 part of the work in 1 day

Therefore (A+B+C) can together complete the work in 144/13 days

That is 11(1/3) days

Q.63 A and B together can do a piece of work in 30 days. A having worked for 16 days, B

finishes the remaining work alone in 44 days. In how many days shall B finish the whole

work alone?

A. 40

B. 60

C. 55D. 75


SOLUTION :

Let A's 1 day's work = x and B's 1 day's work = y.

Then, x + y = 1/30 and 16x + 44y = 1.

Solving these two equations, we get: x = 1/60 & y = 1/60

B's 1 day's work = 1/60

Hence, A alone shall finish the whole work in 60 days.

Q.64 A can lay railway track between two given stations in 16 days and B can do the same

job in 12 days. With help of C, they did the job in 4 days only. Then, C alone can do the job

in:

A. 9(1/5)

B. 9(2/5

C. 9(3/5)

D. 9(4/5)

ANSWER : Option C 9(3/5)

SOLUTION :(A + B + C)'s 1 day's work = 1/4,

A's 1 day's work = 1/16,

B's 1 day's work = 1/12,

C's 1 day's work = 1/4 ^aEUR" (1/16 + 1/12)

= 1/4 ^aEUR" 7/48 = 5/48.

So, C alone can do the work in 48/5 = 9(3/5)days.

Q.65 Water flows into a reservoir which is 200 m long and 150 m wide, through a pipe of

cross-section (0.3m X 0.2m) at 20km/h. In what time will the water level be 8?

A. 150 hr.

B. 170 hr.

C. 185 hr.



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D. 200 hr.

ANSWER : Option D 200 hr.

SOLUTION :Volume of water collected in the tank in 1 hour

0.3?0.2?20?1000=1200 m cubic

If after t hours, the water is at height of 8m,

1200t=200?150?8

t = 200 Hours.

Q.66 A man can do a job in 15 days. His father takes 20 days and his son finishes it in 25

days. How long will they take to complete the job if they all work together?

A. 6 days

B. 6.4 daysC. 6.8 days

D. 7 days

ANSWER : Option B 6.4 days

SOLUTION :

1 day's work of the three persons= (1/15+1/20+1/25)

= 47/300.

So, all the three together will complete the work in = 300/47

= 6.4 days.

Q.67 A and B can dO a Piece of work in 5 days ;B and c can do it in 7 day; A and C can do

it in 4 days. Who among these will take the least time if put to do it alone? . [Hotel

Managemen]

A. A

B. C

C. B

D. Data inadequate

ANSWER : Option A A

SOLUTION :(A+B)s 1 days work = 1/4

and (A+C)^aEURTMs 1 day^aEURTMs work = 1/4

2(A+B+C)s 1 days work = (1/5 + 1/7 + 1/4) = 83/140

(A+B+C)s 1 days work = 83/280

Cs 1 days work = (83/280 - 1/5) = 27/280

As 1 days work = (83/280 - 1/7) = 43/280

Bs 1 days work = (83/280 - 1/4) = 13/280

Thus time taken by A, B, C is 280/43 days, 280/13 days, 280/27 days respectively.

Clearly, the time taken by A is least.

Q.68 A and B together can complete a work in 12 days. A alone can complete it in 20 days.

If B does the work only for half a day daily, then in how many days A and B together will



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complete the work?

A. 11 days

B. 13 days

C. 15 daysD. 17 days

ANSWER : Option C 15 days

SOLUTION :

B's 1 day's work = (1/12 - 1/20) = 2/60 = 1/30

Now, (A + B)'s 1 day's work = (1/20+1/60) = 4/60 = 1/15.

[B works for half day only]

So, A and B together will complete the work in 15 days.

Q.69 A, B and C can do a piece of work in 20, 30 and 60 days respectively. In how manydays can A do the work if he is assisted by B and C on every third day?

A. 11 days

B. 15 days

C. 17 days

D. 19 days

ANSWER : Option B 15 days

SOLUTION :

A's 2 day's work = 1/20x2 =1/10

(A + B + C)'s 1 day's work = (1/20 + 1/30 + 1/60) = 6/60 = 1/10

Work done in 3 days = (1/10 +1/10) = 1/5

Now, 1/5 work is done in 3 days.

Therefore, Whole work will be done in (3 x 5) = 15 days.

Q.70 12 men can complete a work in 18 days. Six days after they started working, 4 men

joined them. How many days will all of them take to finish the remaining work? (Central

Excise & I. Tax 1993)

A. 9

B. 10C. 11

D. 12

ANSWER : Option A 9

SOLUTION :

(12 * 18) men can complete the work in 1 day.

1 mans 1 days work = 1/216

12 men^aEURTMs 6 days work = (1/18)*6 = 1/3

remaining work = 1 - (1/3) = 2/3

16 mens 1 days work = 16/216 = 2/272/27 work is done by them in 1 day.

2/3 work is done by them in (27/2)*(2/3) = 9 days.



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Q.71 A takes twice as much time as B or thrice as much time as C to finish a piece of work.

Working together, they can finish the work in 2 days. B can do the work alone in:

A. 4

B. 6C. 8

D. 12

ANSWER : Option B 6

SOLUTION :

Suppose A, B and C take x, x/2, & x/3 hours respectively to finish the work.

Then, (1/x + 2/x + 3/x) = 1/2

6/x = 1/2

X = 12

So, B takes 6 hours to finish the work.

Q.72 A alone can do a piece of work in 6 days and B alone in 8 days. A and B undertook to

do it for Rs. 3200. With the help of C, they completed the work in 3 days. How much is to be

paid to C?

A. 400

B. 550

C. 600

D. 725

ANSWER : Option A 400SOLUTION :

C's 1 day's work = 1/3 ^aEUR" (1/6 + 1/8) = 1/3 ^aEUR" 7/24 = 1/24.

A's wages : B's wages : C's wages = 1/6 : 1/8 : 1/24 = 4 : 3 : 1

C's share (for 3 days) = Rs. (3 x 1/24 x 3200)

Rs. = 400.

Q.73 A work is done by three person A,B and C. A alone takes 10 hours to complete a

single product but B and C working together takes 4 hours, for the completion of the same

product. If all of them worked together and completed 14 products, then how many hours

have they worked?A. 30

B. 38

C. 40

D. 47


SOLUTION :

1/A = 10 & 1/B + 1/C = 1/4

1/A + 1/B + 1/C = 1/4 + 1/10 = 7/20

In 20 hours, working together they will complete 7 products.Thus in 40 hours they will complete 14 products



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Q.74 A tyre has punctures. The first puncture alone would have made the tyre flat in 9

minutes and the second alone would have done it in 6 minutes. If air leaks out at a constant

rate, how long does it take both the punctures together to make it flat?

A. 4.5 min.B. 5.7min

C. 3.6 min.

D. 2.9 min.

ANSWER : Option C 3.6 min.

SOLUTION :

1 minute's work of both the punctures = (1/9+1/6) = 5/18

So, both the punctures will make the tyre flat in = 18/5 = 3.6 min.

Q.75 A father can do. a job as fast as his two sons working together. If one son does the jobin 3 hours and the other in 6 hours, how many hours does it take the father to do the

job^aEURTM? ssistant Grade 1994]

A. 1

B. 2

C. 3

D. 4

ANSWER : Option B 2

SOLUTION :

Fathers 1 hours work= (1/3) + (1/6) = 1/2Time taken by father to complete the work = 2 hours.

Q.76 A completes a work in 12 days and B complete the same work in 24 days. If both of

them work together, then the number of days required to complete the work will be

A. 8

B. 6

C. 7

D. 5

ANSWER : Option A 8SOLUTION :

If A can complete a work in x days and B can complete the same work in y days,

then, both of them together can complete the work in x y/ x+ y days.

Therefore, here, the required number of days = 12 ~A- 24/ 36 = 8 days.

Q.77 39 men can repair a road in 12 days working 5 hours a day. In how many days will 30

men working 6 hours peer day complete the work?

A. 10



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B. 13

C. 14

D. 15


SOLUTION :

1 work done = 39 ~A- 12 ~A- 5

39 ~A- 12 ~A- 5 = 30 ~A- 6 ~A- ?days

? days = 39 ~A- 12 ~A- 5/ 30 ~A- 6 = 13 days.

Q.78 A and B together can plough a field in 10 hours but by himself A requires 15 hours.

How long would B take to plough the same fieldA. 10

B. 20

C. 30

D. 40


SOLUTION :

If A and B together can do a piece of work in x days and A alone can do the same work in y

days, then B alone can do the same work in x y/ y âEUR" x days.

Therefore, the No. of hours required by B = 10 ~A- 15/ 15 âEUR" 10 = 150/5 = 30 hours.

Q.79 A group of workers accepted to do a piece of work in 25 days. If 6 of them did not turn

for the work and the remaining workers did the work in 40 days, then the original number of

workers was

A. 22

B. 20

C. 18

D. 16

ANSWER : Option D 16SOLUTION :

Let the original number of workers be âEUR~xâEURTM

Then, x ~A- 25 = (x âEUR" 6) ~A- 40

25x = 40x -240

240 = 40x -25x

Q.80 A can do a work in 4 days, B can do it in 5 days and C can do it in 10 days. A, B and C

together can do the work in

A. 1 (3/5) days

B. 1 (9/11) days

C. (5/6) days

D. 3 days



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ANSWER : Option B 1 (9/11) days

SOLUTION :

When A, B and C can do a work in x, y and z days respectively. Then, the three of themtogether can finish the work in xyz/ x y + y z + x z days

That is, A, B and C together can do the work in 4 ~A- 5 ~A- 10/ 20 + 50 + 40

= 4 ~A- 5 ~A- 10/110 = 20/11 = 1 9/11 days

Q.81 3 men or 5 women can do a work in 12 days. How long will 6 men and 5 women take

to finish the work?

A. 4 days

B. 10 days

C. 15 days

D. 20 days

ANSWER : Option A 4 days

SOLUTION :

3 men = 5 women

1 woman = 3/5 men

So, 5 women = 3/5 ~A- 5 = 3 men

6 men and 5 women = 6 + 3 = 9 men

1 work done = 3 men ~A- 12 days

3 ~A- 12 = 9 ~A- x days

x days = 3 ~A- 12/9 = 4 days.

Q.82 Kamal can do a work in 15 days. Bimal is 50% more efficient than Kamal. The number

of days, Bimal will take to do the same piece of work,

A. 9

B. 10

C. 12

D. 14


SOLUTION :Kamal^aEURTMs 15 days is 150% of No. days taken by Bimal to finish the job.

Therefore, the No. of days taken by Bimal = 15/150 ~A- 100 = 10 days.

Q.83 Ram and Shyam together can finish a job in 8 days. Ram can do the same job on his

own in 12 days. How long will Shyam take to do the job by himself?

A. 16 days

B. 20 days

C. 24 days

D. 30 days


SOLUTION :



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If A and B together can do a piece of work in x days and A alone can do the same work in y

days, then B alone can do the same work in x y/ y âEUR" x days.

Therefore, the No. of days Shyam take to finish the job alone = 8 ~A- 12/12 âEUR" 8

= 8 ~A- 12/4 = 24 days.

Q.84 The rates of working of A and B are in the ratio 3 : 4. The number of days taken by

them to finish the work are in the ratio:

A. 3 : 4

B. 9 : 16

C. 4 : 3

D. 3 : 2

ANSWER : Option C 4 : 3

SOLUTION :The No. of days taken by them = inverse ratio = 4 : 3.

Q.85 A certain number of men complete a piece of work in 60 days. If there were 8 men

more, the work could be finished in 10 days less. How many men were originally there?

A. 30

B. 40

C. 32

D. 36


SOLUTION :

Let âEUR~xâEURTM be the original number of men

Then 1 work done = x ~A- 60

Then, 60x = (x + 8) 50

60x = 50x + 400

10 x = 400

x = 40.

Q.86 A does half as much work as B in three- fourth of the time. If together they take 18days to complete the work, how much time shall B take to do it?

A. 30 days

B. 35 days

C. 40 days

D. 42 days


SOLUTION :

Let ??x?? be the number of days taken by B alone to finish the whole work

Then, A alone will finish the whole work in 3x/4 ? 2 days = 3x/2 days.

Then, working together,

3x/2 ? x/3x/2 + x = 18 days

3x ? x/5x = 18



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3x/5 = 18

Therefore, the number of days taken by B = x = 18 ? 5/3 = 30 days.

Q.87 A and B can finish a piece of work in 12 days and 18 days respectively. A begins to do

the work and they work alternately one at a time for one day each. The whole work will be

completed in

A. 14 1/3 days

B. 15 2/3 days

C. 16 1/3 days

D. 18 2/3 days

ANSWER : Option A 14 1/3 days

SOLUTION :

Both of them together can finish the work (daily working) in12 ~A- 18/30 days = 36/5

= 7 (1/5) days.

By working in alternate days, their 2 dayâEURTMs work = 5/36

Their, 14 dayâEURTMs work (because they take more than double of 7 days) = 5/36 ~A- 7

= 35/36

Remaining work = 1 âEUR" 35/36 = 1/36

Because A started the work, the remaining work is finished by A

AâEURTMs 1 dayâEURTMs work = 1/12

Therefore, the No. of days taken by A to finish 1/36 work = 1/36/1/12 = 1/3 days.Therefore, the total work is completed in 14 + 1/3 = 14 1/3 days.

Q.88 A can do a piece of work in 14 days which B alone can do in 21 days. They begin

together but 3 days before the completion of the work, A leaves off. The total number of

days for the work to be completed is

A. 6 3/5 days

B. 8 A 1/2 days

C. 10 1/5 days

D. 13 A 1/2 days

ANSWER : Option C 10 1/5 days

SOLUTION :

BâEURTMs 1 dayâEURTMs work = 1/21

BâEURTMs 3 dayâEURTMs work = 1/21 ~A-3 = 1/7

The remaining work finished by both of them = 1 âEUR" 1/7 = 6/7

Both together can finish it in 14 ~A- 21/35 days = 42/5 days

Their, 1 dayâEURTMs work = 5/42

Therefore, the No. of days taken by them together to finish 6/7 work

= 6/7/5/42 = 6/7 ~A- 42/5 = 36/5 = 7 1/5 days

Therefore,the total No. of days for the work to be completed = 3 + 7 1/5 = 10 1/5 days.



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Q.89 A and B can finish a piece of work in 30 days. They worked at it for 20 days and then

B left. The remaining work was done by A alone in 20 more days. A alone can finish the

work in

A. 48 daysB. 50 days

C. 54 days

D. 60 days

ANSWER : Option D 60 days

SOLUTION :

(A + B)âEURTMs 1 dayâEURTMs work = 1/30

Their 20dayâEURTMs work = 1/30 ~A- 20 = 2/3

Remaining 1/3 work is done by A in 20 days

Therefore, A alone can finish the work in 3 ~A- 20 = 60 days.

Q.90 9 children can complete a piece of work in 360 days; 18 men can complete the same

piece of work in 72 days and 12 women can complete it in 162 days. In how many days can

4 men, 12 women and 10 children together complete the piece of work?

A. 68 days

B. 81 days

C. 96 days

D. 124 days

ANSWER : Option B 81 daysSOLUTION :

1 childâEURTMs 1 dayâEURTMs work = 1/360 ~A-9 = 1/3240

10 childrenâEURTMs 1 dayâEURTMs work = 1/324

1 manâEURTMs 1 dayâEURTMs work = 1/72 ~A- 18 = 1/1296

4 menâEURTMs 1 dayâEURTMs work = 1 ~A-4/1296 = 1/324

12 womenâEURTMs 1 dayâEURTMs work = 1/162 given

Then,

(4 men+12 women+10 children)âEURTMs 1 dayâEURTMs work = 1/324 + 1/162 + 1/324

= 1/324 + 2/324 + 1/324

= 4/324 = 1/81

Therefore, the required No. of days = 81 days.

Q.91 9 men working 7 hours a day can complete a piece of work in 15 days. How many

days can 6 men working for 9 hours a day, complete the same piece of work?

A. 15 A 3/4 days

B. 16 days

C. 16 Â 3/4 days

D. 17 A 1/2 days

ANSWER : Option D 17 Â 1/2 daysSOLUTION :

1 work done = 9 ~A- 7 ~A- 15



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9 ~A- 7 ~A- 15 = 6 ~A- 9 ~A- ?days

? days = 9 ~A- 7 ~A- 15/6 ~A- 9

= 35/2 = 17 Â 1/2 days.

Q.92 A man, a woman and a boy can together complete a piece of work in 3 days. If a man

alone can do it in 6 days and a boy alone in 18 days, how long will a woman take to

complete the work?

A. 9 days

B. 21 days

C. 24 days

D. 27 days


SOLUTION :(1 Man + 1 woman + 1 boy)âEURTMs 1dayâEURTMs work = 1/3

1 manâEURTMs 1 day work = 1/6

1boyâEURTMs 1 dayâEURTMs work = 1/18

(1 Man + 1 boy) âEUR~s 1 dayâEURTMs work = 1/6 + 1/18 = 2/9

Therefore, 1 womanâEURTMs 1 dayâEURTMs work = 1/3 âEUR" 2/9 = 3-2/9 = 1/9

Therefore, the woman alone can finish the work in 9 days.

Q.93 8 men can do a piece of work in 12 days. 4 women can do it in 48 days and 10

children can do it in 24 days. In how many days can 10 men, 4 women and 10 children

together complete the piece of work?

A. 5 days

B. 15 days

C. 28 days

D. 6 days

ANSWER : Option D 6 days

SOLUTION :

1 manâEURTMs 1 dayâEURTMs work = 1/8 ~A- 12 = 1/96

10 menâEURTMs 1 dayâEURTMs work = 1 ~A- 10/96 = 5/48

1 womanâEURTMs 1 dayâEURTMs work = 1/1924 womenâEURTMs 1 dayâEURTMs work = 1/192 ~A- 4 = 1/48

1 childâEURTMs 1 dayâEURTMs work = 1/240

10 childrenâEURTMs 1 dayâEURTMs work = 1/24

Therefore,

(10 men + 4 women + 10 children)âEURTMs 1 dayâEURTMs work = 5/48 + 1/48 + 1/24

= 8/48 =1/6

The required No. of days = 6 days.

Q.94 8 men can dig a pit in 20 days. If a man works half as much again a s a boy, then 4

men and 9 boys can dig a similar pit in

A. 10 days

B. 12 days



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C. 15 days

D. 16 days

ANSWER : Option D 16 daysSOLUTION :

1 work done = 8 ~A- 20

1 man = 3/2 Boys

1 boy = 2/3 men

Then, 9 boys = 9 ~A- 2/3 men = 6 men

Then, 4 men + 9 boys = 10 men

Then, 8 ~A- 20 = 10 ~A- ?days

days = 8 ~A- 20/10 = 16 days.

Q.95 A man and a boy complete a work together in 24 days. If for the last 6 days man alonedoes the work then it is completed in 26 days. How long the boy will take to complete the

work alone?

A. 72 days

B. 20 days

C. 24 days

D. 36 days


SOLUTION :

(man + boy)âEURTMs 1 dayâEURTMs work = 1/24Their 20 dayâEURTMs work = 1/24 ~A- 20 = 5/6

The remaining 1/6 work is done by the man in 6days

Therefore, the man alone will finish the work in 6 ~A- 6 days = 36 days

ManâEURTMs 1 dayâEURTMs work = 1/36

Therefore, boyâEURTMs 1 dayâEURTMs work = 1/24 âEUR" 1/36 = 3 âEUR" 2 /72 =

1/72

Therefore, the Boy alone will finish the work in 72 days.

Q.96 A, B and C completed a piece of work costing Rs.1800. A worked for 6 days, B for 4

days and C for 9 days. If their daily wages are in the ratio 5 : 6 : 4, how much amount will bereceived by A?

A. Rs.800

B. Rs. 600

C. Rs.900

D. Rs.750

ANSWER : Option B Rs. 600

SOLUTION :

The new ratio = wages ratio ~A- No. of days

A = 5 ~A- 6 = 30B = 6 ~A- 4 = 24

C = 4 ~A- 9 = 36



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Therefore,

the ratio of the amount received = 30 : 24 : 36 = 5 : 4 :6

Total ratio = 15

1 unit of ratio = 1800/15 = Rs. 120Therefore,

amount received by A = 5 units = 5 ~A- 120 = Rs.600.

Q.97 12 men take 36 days to do a work while 12 women complete 3/4th of the same work in

36 days. In how many days 10 men and 8 women together will complete the same work?

A. 6 days

B. 12 days

C. 27 days

D. Data inadequate


SOLUTION :

1 manâEURTMs 1 dayâEURTMs work = 1/ 36 ~A- 12 = 1/432

10 menâEURTMs 1 dayâEURTMs work = 10/432

12 women can finish the whole work in 4 ~A- 36/3 = 48 days

1 womanâEURTMs 1 days work = 1/ 48 ~A- 12 = 1/576

8 womenâEURTMs 1 dayâEURTMs work = 8/572 = 1/72

(10 men + 8 women)âEURTMs 1 dayâEURTMs work = 10/432 + 1/72

= 10 + 6/432 = 16/432

= 1/27Therefore, the required No. of days = 27 days.

Q.98 A is thrice as good a workman as B and therefore is able to finish a job in 60 days less

than B. working together, they can do it in

A. 20 days

B. 22 A 1/2 days

C. 25 days

D. 30 days

ANSWER : Option B 22 Â 1/2 daysSOLUTION :

B = 3A

3A âEUR" A =60 days

A = 30days

Then, B = 90 days

(A + B) = 30 ~A- 90/ 120 = 45/2 = 22 Â 1/2 days

Q.99 A works twice as fast as B. if both of them can together finish a piece of work in 12

days, then B alone can do it in

A. 24 days

B. 27 days

C. 36 days



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D. 48 days


SOLUTION :B = 2A

2A ~A- A/3A = 12

2A/3 = 12

A = 18 days

B = 2 ~A- 18 = 36 days

Therefore, B alone can finish the work in 36 days.

Q.100 A man, a woman and a boy can complete a job in 3 days, 4 days and 12 days

respectively. How many boys must assist 1 man and 1 woman to complete the job in 1/4th

of a day?A. 10

B. 14

C. 19

D. 41


SOLUTION :

1 manâEURTMs 1 dayâEURTMs work = 1/3, Â 1/4 dayâEURTMs work = 1/3 ~A- Â

1/4 = 1/12

1 womanâEURTMs 1 dayâEURTMs work = Â 1/4 , Â 1/4 dayâEURTMs work = Â1/4 ~A- Â 1/4 = 1/16

1 boyâEURTMs 1 dayâEURTMs work = 1/12, Â 1/4 dayâEURTMs work = 1/12 ~A-

Â 1/4 = 1/48

Let âEUR~xâEURTM be the No. of boys required.

Then, (1man+ 1woman+xboy)âEURTMs Â 1/4 dayâEURTMs work (1/12+1/16+x)/48 =

1

(4 + 3 + x)/48 = 1

i.e. 7 + x= 48 and

x =41.

Q.101 A does 4/5th of a work in 20 days. He then calls in B and they together finish the

remaining work in 3 days. How long B alone would take to do the whole work?

A. 23 days

B. 37 days

C. 37^ Â 1/2 days

D. 40 days

ANSWER : Option C 37 Â 1/2 days

SOLUTION :

A can finish the whole work in 20 ~A- 5/4 days = 25 daysA and B together finish the whole work in 5 ~A- 3 days = 15 days

Therefore, B can finish the whole work in 25 B/ 25 + B = 15



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25 B = 15 (25+B)= 375 + 15B

10B = 375 and

B = 375/10 = 37^ ^A 1/2 days.

Q.102 A can do 1/4th part of the work in 10 days, B can do 40% of the work in 40 days and

C can do 1/3rd of the work in 13 days. Who will complete the work first?

A. A

B. B

C. C

D. A and C both

ANSWER : Option C C

SOLUTION :

The whole work is done by A in 4 ~A- 10 = 40 daysB can do the whole work in 40/40 ~A- 100 days = 100 days

C can do the whole work in 3 ~A- 13 = 39 days.

Therefore, the 1st person to complete the work is C.

Q.103 A alone can finish a work in 10 days which B alone can finish in 15 days. If they work

together and finish it, then out of a total wages of Rs.3000, A will get:

A. Rs.1200

B. Rs.1500

C. Rs.1800

D. Rs.2000

ANSWER : Option C Rs.1800

SOLUTION :

Ratio of working days of A : B = 10 : 15

Therefore, their wages ratio = reverse ratio = 15 : 10

Therefore, A will get 15 units of ratio

Total ratio = 25

1 unit of ratio =3000/25 = 120

So, A^aEURTMs amount = 120 ~A- 15 = Rs.1800.

Q.104 The present age of a father is 3 years more than three times

the age of his son. After three years hence, fathers age will be 10 years more than twice the

age of the son. Find the present age

of the father.

A. 33

B. 34

C. 35

D. 36


SOLUTION :



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Let the present age be 'x' years.

Then father's present age is 3x+3 years.

Three years hence,

(3x+3)+3=2(x+3)+10 x=10

Hence, father's present age = 3x+3 = 33 years.

Q.105 Mr. James is three times as old as his son.Five years before, Mr.James was four

times as old as his son.Find the present ages of Mr. James and his son.

A. 39

B. 45

C. 50

D. 56


SOLUTION :

Let "x" be the present age of the son.

Then the age of Mr.James is 3x

Five years before, age of the son = (x-5) years.

Mr. James's age = 3x-5 years

Given, five years before, Mr.James's age is four times his son's age

Therefore 3x-5 = 4(x-5)

3x-5 = 4x-20

-5+20 = 4x-3x

15 = x

or x = 15

Hence, age of son = 15 years

age of Mr. James = 3(15)= 45 years

Q.106 One year ago Jaya was four times as old as her daughter Nikitha. After Six years

hence, Mrs.Jaya's age will exceed her daughter's age by 9 years. The ratio of the present

ages of Jaya and her daughter is :

A. 9 : 2B. 11: 3

C. 12: 5



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D. 13: 4

ANSWER : Option D 13: 4

SOLUTION :Let Nikitha's age 1 year ago = x

Then Jaya's age 1 year ago = 4 x

(4x+6)-(x+6)=9 or x = 3

Present age of Jaya = (12+1) years = 13 years

Present age of Nikitha = (3+1) years = 4 years

Ratio of their ages = 13 : 4

Q.107 Rabert's age after 15 years will be 5 times his age 5 years back. What is the present

age of Rajeev?

A. 22

B. 17

C. 10

D. 7

ANSWER : Option C 10SOLUTION :

Let Rabert's present age be x years. Then,

Rabert's age after 15 years = (x + 15) years.

Rabert's age 5 years back = (x - 5) years.

x + 15 = 5 (x - 5) ? x + 15 = 5x - 25

4x = 40 x = 10.

Hence, Rabert^aEURTM present age = 10 years.

Q.108 Present ages of Sameer and Anand are in the ratio of 5 : 4 respectively. Three years

hence, the ratio of their ages will become 11 : 9 respectively. What is Anand's present age

in years ?

A. 16

B. 24

C. 38

D. 47




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SOLUTION :

Let the present ages of sameer and anand be 5x years and 4x years respectively.

Then, 5x+3/4x+3=11/9

9(5x+3)=11(4x+3)X = 6.

Anands's present age = 4x = 24 yrs.

Q.109 The ratio between the present ages of P and Q is 6 : 7. If Q is 4 years old than P.

What will be the ratio of the ages of P and Q after 4 years?

A. 7 : 8

B. 6 : 12

C. 9 : 12

D. 10 : 8

ANSWER : Option A 7 : 8

SOLUTION :

Let P's age and Q's age be 6x years and 7x years respectively

Then, 7x - 6x = 4, X= 4

Required ratio = (6x + 4) : (7x + 4) = 28 : 32 = 7 : 8

Q.110 Raju age after 15 years will be 5 times his age 5 years back, What is the present age

of Raju

A. 22

B. 17

C. 12

D. 10


SOLUTION :

x+15 = 5(x-5)

4x = 40 => x = 10

Q.111 Father is aged three times more than his son Ronit. After 8 years, he would be twoand a half times of Ronit's age. After further 8 years, how many times would he be of Ronit's

age?

A. 2 times

B. 2.5 times

C. 3 times

D. 4 times

ANSWER : Option A 2 times

SOLUTION :

Let Ronit's present age be x years. Then, father's present age =(x + 3x) years = 4x years.

(4x + 8) = 5/2(x + 8)

8x + 16 = 5x + 40

3x = 24



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X = 8

Hence, required ratio = (4x + 16)/(x + 16) = 48/24 = 2

Q.112 One year ago the ratio of Ramu&Sonu age was 6:7respectively.

Four years hence their ratio would become 7:8. How old is Sonu.

A. 24

B. 32

C. 36

D. 47


SOLUTION :

Let us assume Ramu&Sonu ages are x &y respectively.One year ago their ratio was 6:7

i.e x-1 / y-1 = 7x-6y=1

Four years hence their ratios,would become 7:8

i.e x-4 / y-4 = 7 / 8

8x-7y=4

From the above two equations we get y= 36 years.

i.eSonu present age is 36 years.

Q.113 The total age of A &B is 12 years more than the total age of

B&C. C is how many year younger than A.

A. 11

B. 12

C. 13

D. 14


SOLUTION :

From the given data:A+B = 12+(B+C)

A+B-(B+C) = 12 A-C=12 years.

C is 12 years younger than A

Q.114 Sachin is younger than Rahul by 7 years. If the ratio of their ages is 7:9, find the age

of Sachin

A. 22.5

B. 25.5

C. 24.5

D. 23.5

ANSWER : Option C 24.5

SOLUTION :



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If Rahul age is x, then Sachin age is x-7,

so (x-7)/x = 7/9

=> 9x-63 = 7x

=> 2x = 63=> x = 31.5

So Sachin age is 31.5 - 7 = 24.5

Q.115 The sum of ages of 5 children born at the intervals of 3 years each is 50

years. What is the age of the youngest child?

A. 4

B. 7

C. 9

D. 15

ANSWER : Option A 4

SOLUTION :

Let the ages of children be x, (x + 3), (x + 6), (x + 9) and (x + 12) years.

Then, x + (x + 3) + (x + 6) + (x + 9) + (x + 12) = 50

5x = 20

x = 4.

Age of the youngest child = x = 4 years.

Q.116 A father is twice as old as his son. 20 years ago the age of the father was 12 times

the age of the son. The present age of the father is :

A. 44 years

B. 32 years

C. 22 years

D. 45 years

ANSWER : Option A 44 years

SOLUTION :

Let son's age = x. Then, father's age = 2x.

12(x-20)=(2x-20), x=22Father's present age = 44 years

Q.117 The ratio of the ages of Jaya and Ravi is 2:5. After 8 years, their ages will be in the

ratio of 1:2. The difference in their present ages is : ( in years )

A. 24

B. 26

C. 29

D. 32


SOLUTION :

Let Jaya's age = 2x or Ravi's age = 5x.



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= (5x+8), x = 8

Jaya's age = 16 years

Ravi's age = 40 years

Difference of their ages = 24 years

Q.118 The present age of a father is 3 years more than three times the age of his son.

Three years hence, fatherâEURTMs age will be 10 years more than twice the age of the

son. Find the present age of the father.

A. 24

B. 31

C. 33

D. 46

ANSWER : Option C 33SOLUTION :

Let the sonâEURTMs present age be x years.

Then, fatherâEURTMs present age = (3x + 3) years.

? (3x + 3 + 3) = 2 (x + 3) + 10 ? 3x + 6 = 2x + 16 ? x = 10.

Hence,

fatherâEURTMs present age = (3x + 3)

= (3 * 10 + 3) years

= 33 years.

Q.119 The ratio between the present ages of P and Q is 5 : 7 respectively. If the difference

between Q's present age and P's age afler 6 years is 2, what is the total of P's and Q's

present ages ?

A. 44

B. 48

C. 52

D. 57


SOLUTION :

Let the present ages of P and Q be 5x years and 7x years respectively.Then, 7x- (5x+6) = 2

2x = 8, x = 4

total of P's and Q's present ages = 5x + 7x

= 20 + 28 = 48 yrs.

Q.120 The Average age of a class of 22 students in 21 years. The average increases by 1

when the teacherâEURTMs age also included. What is the age of the teacher?

A. 39

B. 42

C. 44

D. 48



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SOLUTION :

Avg x Number = Total

21 years x 22 nos = 462 years âEUR|âEUR|âEUR|.(1)22 years x 23 nos = 506 years âEUR|âEUR|âEUR|.(2)

TeacherâEURTMs age = (2) - (1) = 506 âEUR" 462 = 44 Years

Q.121 The ratio of the age of a man & his wife is 4:3.After 4 years this

ratio will be 9:7. If the time of marriage the ratio was 5:3,

then how many years ago were they married.

A. 12

B. 15

C. 17D. 20


SOLUTION :

The age of a man is 4x .

The age of his wife is 3x.

After 4 years their ratio's will be 9:7

i.e4x+4 /3x+4 = 9 / 7

28x-27x=36-28

x = 8.Age of a man is 4x = 4*8 = 32 years.

Age of his wife is 3x = 3*8 = 24 years.

Let us assume 'y' years ago they were married ,

the ratio was 5:3 ,

i.e32-y /24-y = 5/ 3

y = 12 years

i.e 12 years ago they were married

Q.122 Sneh's age is 1/6th of her father's age.Sneh's father's age will

be twice the age of Vimal's age after 10 years. If Vimals8birthday was celebrated two years before,then what is Sneh's

present age.

A. 6 2/3 years

B. 5 years

C. 3 years

D. None of the above

ANSWER : Option B 5 years

SOLUTION :Assume Sneh's age is 'x' years.

Assume her fathers age is 'y' years.



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Snehas age is 1/6 of her fathers age i.e x = y /6.

Fathers age will be twice of Vimal's age after 10years.

i.e y+10 = 2( V+10)( where 'V' is the Vimal's age)

Vimal's eight birthday was celebrated two years before,Then theVimal's present age is 10 years.

Y+10 = 2(10+10)

Y=30 years.

Sneh's present age x = y/6

x = 30/6 = 5 years.

Sneh's present age is 5 years.

Q.123 Ages of two persons differ by 16 years. If 6 year ago, the elder one be 3 times as

old the younger one, find their present age

A. 14, 30B. 16, 28

C. 18, 35

D. 22, 42

ANSWER : Option A 14, 30

SOLUTION :

Let the age of younger person is x,

Then elder person age is (x+16)

=> 3(x-6) = (x+16-6) [6 years before]

=> 3x-18 = x+10

=> x = 14.

So other person age is x + 16 = 30

Q.124 A father said to his son, "I was as old as you are at the present at the time of your

birth". If the father's age is 38 years now, the son's age five years back was:A. 8

B. 6

C. 12

D. 14


SOLUTION :

Let the son's present age be x years. Then, (38 - x) = x

2x = 38.

x = 19.Son's age 5 years back (19 - 5) = 14 years.



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Q.125 The ages of Ravi Rani are in the ratio of 3:5. After 9 years, the ratio of their ages will

become 3:4. The present age of Rani is : (in years )

A. 9

B. 15C. 18

D. 24


SOLUTION :

Let Ravi's age = 3x or Rani's age = 5x

Rani's age = 15 years

Q.126 The ratio of the ages of Meena and Meera is 4:3. The sum of their ages is 28 years.

The ratio of their ages after 8 years will be :A. 4:3

B. 12:11

C. 7:4

D. 6:5

ANSWER : Option A 4:3

SOLUTION :

Let Meena's age = 4x or Meera's age = 3x. Then,

4x+3x=28, x = 4

Meena'sage = 16 years or Meera's age=12 years

Ratio = 16:12 = 4 : 3

Q.127 Peter got married 8 years ago. His present age is 6/5 times his age at the time of his

marriage. PeterâEURTMs sister was 10 years younger to him at the time of his marriage.

The age of PeerâEURTMs sister is:

A. 35

B. 38

C. 44D. 52


SOLUTION :

Let PeterâEURTMs present age be x years. Then, his age at the time of marriage

= (x - 8) years.

-> x = 6/5 (x - 8) -> 5x = 6x - 48 -> x = 48.

Peter's sister's age at the time of his marriage = (x - 8) âEUR" 10

= (x - 18) = 30 years.

Peter's sisterâEURTMs present age = (30 + 8) years = 38 years.

Q.128 The age of a man is three times the sum of the ages of his two sons. Five years



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hence, his age will be double of the some of the ages of his sons. The fatherâEURTMs

present age is :

A. 26

B. 32C. 39

D. 45


SOLUTION :

Let the sum of present ages of the two sons be x years.

Then, faherâEURTMs present age = 3x years.

(3x + 5) = 2 (x + 10) -> 3x + 5 = 2x + 20 -> x = 15.

Hence, fatherâEURTMs present age = 45 years.

Q.129 Eighteen years ago, a father was three times as old as his son. Now the father is

only twice as old as his son. Then the sum of the present ages of the son and the father is

A. 72

B. 84

C. 108

D. 128


SOLUTION :

Let the present ages of Father and Son be 2x years and x years respectively.Then, (2x-18) = 3(x-18)

2x-18 = 3x-54

X = 36.

Required sum: = 2x + x =3x

= 3 x 36 = 108

Q.130 At present, the ratio between the ages of Arun and Deepak is 4 : 3. After 6 years,

ArunâEURTMs age will be 26 years. What is the age of Deepak at present

A. 9

B. 15C. 27

D. 31


SOLUTION :

Let the present ages of Arun and Deepak be 4x years and 3x years respectively. Then,

->4x + 6 = 26

->4x = 20

->X = 5

Deepak's age = 3x = 15 years.

Q.131 A father is twice as old as his son. 20 years ago, the age of the father was 12 times



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the age of the son. The present age of the father (in years) is

A. 44

B. 57

C. 64D. 79


SOLUTION :

Let son's age = x. Then father's age = 2x

->12 (x - 20) = (2x - 20)

->10x = 220

->X = 22

Father's present age = 44 years.

Q.132 The sum of the ages of a father and son is 45 years. Five years ago, the product of

their ages was four times the fathers age at that time. The present age of father and son

A. 36 & 12

B. 48 & 12

C. 36 & 9

D. 48 & 9

ANSWER : Option C 36 & 9

SOLUTION :

Let sons age = x years. Then fathers age = (45 - x)years.(xâEUR"5)(45âEUR"xâEUR"5) = 4(45- x - 5)

hence (xâEUR"5) = 4 so x = 9

Their ages are 36 yrs and 9 yrs.

Q.133 The present ages of three persons in proportions 4 : 7 : 9. Eight years ago, the sum

of their ages was 56. Find their present ages (in years).

A. 16, 28, 36

B. 16, 32, 38

C. 16, 34, 42

D. 18, 28, 40

ANSWER : Option A 16, 28, 36

SOLUTION :

Let their present ages be 4x, 7x and 9x years respectively.

Then, (4x - 8) + (7x - 8) + (9x - 8) = 56

2x = 80

X = 4

Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years

respectively.

Q.134 Ayesha's father was 38 years of age when she was born while her mother was 36

years old when her brother four years younger to her was born. What is the difference



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between the ages of her parents?

A. 3

B. 4

C. 6D. 8

ANSWER : Option C 6

SOLUTION :

Mother's age when Ayesha's brother was born = 36 years.

Father's age when Ayesha's brother was born = (38 + 4) years = 42 years.

Required difference = (42 - 36) years = 6 years.

Q.135 A person's present age is two-fifth of the age of his mother. After 8 years, he will be

one-half of the age of his mother. How old is the mother at presentA. 40

B. 45

C. 49

D. 56


SOLUTION :

Let the mother's present age be x years.

Then, the person's present age = (2/5 x) years.

-> (2/5 x + 8/2) = 1 (x + 8)

->2(2x + 40) = 5(x + 8)

->x = 40 years.

Q.136 The ages of A, B and C together total 185 years. B is twice as old as A and C is !7

years older than A. Then, the respective ages of A, B and C are

A. 42, 65, 44B. 42, 84, 59

C. 44, 85, 62

D. 51, 74, 55

ANSWER : Option B 42, 84, 59

SOLUTION :

Let A's age be x years

B's age be 2x years

C's age = (x + 17) years



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According to the question,

x + 2x + (x + 17) = 185

4x = 185 - 17 = 168

-> x = 42

A's age = 42 Years

B's age = 84 Years

C's age = 42 + 17 = 59 years.

Q.137 Rajan got married 8 years ago. His present age is 6 / 5 times his age at the time ofhis marriage. Rajan's sister was 10 years younger to him at the time of his marriage. The

age of Rajan's sister is

A. 38

B. 39

C. 42

D. 45


SOLUTION :

Let Rajan's present age be x years.Then, his age at the time of marriage = (x ^aEUR" 8)

x= 6/5(x-6)

5x = 6x-48, x = 48

Rajan's sister's age at the time of his marriage = (x-8)-10 = 48 - 18 = 30

Rajan's sister's present age = 30 + 8 = 38 years.

Q.138 One year age, Promila was four times as old as her daughter Jenilia. Six years

hence, Promilas age will exceed her daughter^aEURTMs age by 9 years. The ratio of the

present ages of Promila and her daughter is :

A. 12:5B. 12:6

C. 13:4

D. 13:5

ANSWER : Option C

SOLUTION :

Let the ages of Promila and Jenilia 1 yr ago be 4x and x yrs resp.

Then, [(4x + 1) + 6] - [(x + 1) + 6] = 9 -> 3x = 9 x = 3.

-> Required ratio = (4x + 1) : (x + 1) = 13:4.

Q.139 The sum of the ages of a son and father is 56 years. After 4 years, the age of the

father will be three times that of the son. Their ages respectively are:



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A. 12 years, 44 years

B. 16 years, 42 years

C. 16 years, 48 years

D. 18 years, 36 years

ANSWER : Option A 12 years, 44 years

SOLUTION :

Let the present ages of son and father be x yearsand (56-x) years respectively.

Then, (56-x+4) = 3(x+4)

or 4x = 48 or x = 12

So their ages are 12 years, 44 years respectively.

Q.140 The sum of the ages of a mother and daughter is 50 years. Also, 5 years ago, the

mother's age was 7 times the age of the daughter. The present ages of the mother anddaughter respectively are :

A. 35 years, 15 years

B. 38 years, 12 years

C. 40 years, 10 years

D. 42 years, 8 years

ANSWER : Option C 40 years, 10 years

SOLUTION :

Let the daughter's present age be x years. Then, mother's present age = (50-x) years.

Now, 7(x-5)=(50-x-5) or x = 10So, their present ages are 40 years and 10 years.

Q.141 If 6 years are subtracted from the present age of Gagan and

the remainder is divided by 18,then the present age of his

grandson Anup is obtained. If Anup is 2 years younger to Madan

whose age is 5 years,then what is Gagan's present age.

A. 48 years

B. 60 years

C. 84 yearsD. 65 years

ANSWER : Option B 60 years

SOLUTION :

Let us assume Gagan present age is 'x' years.

Anup age = 5-2 = 3 years.

(x-6) /18 = 3

x-6 = 54

x = 60 years

Q.142 My brother is 3 years elder to me. My father was 28 years of

age when my sister was born while my father was 26 years of age



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when i was born. If my sister was 4 years of age when my brother

was born, then what was the age my father and mother respectively

when my brother was born.

A. 32 yrs, 23yrs

B. 32 yrs, 29yr

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