ECE 6616PD Fall 2013

Assignment #2 Solution A1. (30 marks) Slides 5 to 6 & Slides 8 to 10 & Slides 29 to 31. Examples in slides 51-53. A2. (30 marks) Slides 33 to 39. A3. (40 marks) If=10 kA Rj=0.001 ohm Rw=500 ohm tclearing= 0.1s

1

ECE 6616PD Fall 2013

a)

N A B C

Rj

Rj Rj

RB

If

If

Rj

Rj

Rj

RB

IB

2

ECE 6616PD Fall 2013

b) Using the equivalent circuit of part (a),

mARR

RII

Bj

jfB 40500001.03

001.0210000

3

2 =+=+=

c) ( ) JtRIE BB 08.01.05001010 232 === d) IB=10 mA, we will use the same equation of part (b)

Bj

newjf RR

RI

new+=

3

21010 3

Thus,

5003

2100001010 3 +

= newj

newj

RR

Rearranging,

ohmRnewj

00025.03102

5006

==

jnewjRR 25.0=

3