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Assignment #3 KEY April 9, 2018 10:18 AM Stoichiometry Page 1

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Page 1: Assignment #3 KEY - misszukowski.weebly.com #3 KEY April 9, ... 124.OgP4 = 8.29g I mol P4 63.5 g cu ... (based on HCI) = 5.00 x ICF3 mol HCI x -5.00 x I mol HCI mol

Assignment #3 KEYApril 9, 2018 10:18 AM

Stoichiometry Page 1

Page 2: Assignment #3 KEY - misszukowski.weebly.com #3 KEY April 9, ... 124.OgP4 = 8.29g I mol P4 63.5 g cu ... (based on HCI) = 5.00 x ICF3 mol HCI x -5.00 x I mol HCI mol

Stoichiometry Page 2

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f1.hcm.edu.vnf1.hcm.edu.vn/Data/hcmedu/gdtrunghoc/Attachments/...cau 73. Hõn X gòm amino axit Y (có H2N-CnH2n-COOH) và 0,02 mol Cho X vào dung dich chúa 0,04 mol HCI, thu dung

hululkitab.b-cdn.net...1 molecule HCI + 1 formula unit KOH —+ 1 formula unit KCI + 1 molecule HO. 1 mol + 1 mol KOH 1 mol KCI+ 1 mol 1120. 36.461 g HCI HCI = 1 mol HCI x = 36.461

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