assignment cbcp2103 semsept 1012
DESCRIPTION
This is the assignment about computer programming which is using C languageTRANSCRIPT
SEPTEMBER SEMESTER 2012
CBCP2103
COMPUTER PROGRAMMING
TUTOR: YUZERY BIN YUSOFF
MATRICULATION NO : R336825001
IDENTITY CARD NO. : A1031320
TELEPHONE NO. : 012-2856722
E-MAIL : [email protected]
LEARNING CENTRE : BANGI
CBCP2103
TABLE OF CONTENT page
1.0 Question 1 (Bills for the City Water Company)……………………………………..2
1.1 Coding for Question 1………………………………………………………..2
1.2 Screenshots for Question 1…………………………………………………...5
1.3 Flowchart for Question 1…………………………………………………......9
2.0 Question 2 (Table of Engineering
Properties for Bunyan Lumber Company)………………………………………….10
2.1 Coding for Question 2………………………………………………………10
2.2 Screenshots for Question 2………………………………………………….12
2.3 Flowchart for Question 2…………………………………………………....13
References……………………………………………………………………………….14
1
CBCP21031.0 Question 1 (Bills for the City Water Company)
1.1 Coding for Question 1
/* CBCP2103 Computer Programming Assignment : Question 1 */
/* Name: Dewa Putu Teja Laksana */
/* Matric No.: R336825001 */
/* Semester: September 2012 */
#include <stdio.h> /* Defining Standard Input and Output routines */
int main()
{
printf("\nWATER COMPANY BILLING SYSTEM\n"); /* Heading of the system */
printf("=============================\n\n");
int accountNo;
char codeType;
double waterAmount, bill;
printf("Please enter your account no: "); /* Enter user's account number */
scanf("%d", &accountNo);
printf("\ncode type usage");
printf("\n---------------\n");
printf("h = home use \nc = commercial use \ni = industry use\n");
2
CBCP2103 printf("\nPlease enter your code type (h/c/i): "); /* Enter usage code of the user */
scanf("\n%c", &codeType);
printf("Now enter water amount (gallons): "); /* Enter the quantity of water used */
scanf("%lf", &waterAmount);
/* Calculation of the bill according to the code type */
switch (codeType) {
case ('h'): bill = 5.00 + (0.0005 * waterAmount);
break;
case ('c'): if (waterAmount <= 4000000)
bill = 1000.00;
else if (waterAmount > 4000000)
bill = (((waterAmount - 4000000) * 0.00025) + 1000);
break;
case ('i'): if (waterAmount <= 4000000)
bill = 1000;
else if ((waterAmount > 4000000) && (waterAmount <= 10000000))
bill = 2000;
else if (waterAmount > 10000000)
bill = 3000;
break;
default : printf("\nERROR!! You entered wrong code!!\n\n"); /* If the code type entered other than h or c or i */
}
3
CBCP2103 printf("bill = %lf\n", bill);
printf("=============================\n\n");
printf("You need to pay: RM %.2lf", bill);
getch();
return 0;
}
4
CBCP21031.2 Screenshots for Question 1
Picture 1.2.1. Screenshot for displaying bill of home type usage.
Picture 1.2.2. Screenshot for displaying bill of commercial type usage for the first 4 million gallons used.
5
CBCP2103
Picture 1.2.3. Screenshot for displaying bill of commercial type usage with water quantity exceeds 4 million gallons.
Picture 1.2.4. Screenshot for displaying bill of industry type usage with water quantity does not exceed 4 million gallons.
6
CBCP2103
Picture 1.2.5. Screenshot for displaying bill of industry type usage with water used is more than 4 million gallons but does not exceed 10 million gallons.
Picture 1.2.6. Screenshot for displaying bill of industry type usage with water used is more than 10 million gallons.
7
CBCP2103
Picture 1.2.7. Screenshot for displaying when user input code type other than h / c /i.
8
CBCP21031.3 Flowchart for Question 1
bill = 3000
no
bill = 2000yes
no no
bill = 1000yes yes
bill = ((water amount – 4million) x 0.00025) + 1000
no no
bill = 1000yes yes
no
bill = 5.00 + (0.0005 x water amount)
end
default: other than h/c/i
Display the bill that need to be paid by user
Display “ERROR! You entered wrong code”
case ‘i’(industry)
start
Prompt user to input account number
Input code type of water usage (h/c/i)
Input water amount
if water amount <= 4million
gallons
else-if water amount >
4million gallons
if water amount <= 4million
gallons
else-if 4million<water
amount>=10million
else water amount
>10million
case ‘c’(commercial)
yescase ‘h’
(home usage)
9
CBCP21032.0 Question 2 (Table of the Engineering Properties for Bunyan Lumber Company).
2.1 Coding for Question 2
/* CBCP2103 Computer Programming Assignment : Question 2 */
/* Name: Dewa Putu Teja Laksana */
/* Matric No.: R336825001 */
/* Semester: September 2012 */
/* This program creates value of Engineering Properties of Lumber */
#include <stdio.h> /* Defining Standard Input Output routines */
int main()
{
printf("\n\t\t\tBUNYAN LUMBER COMPANY\n"); /* Heading for the system */
printf("\n\t\t Engineering Properties of Lumber\n");
printf("\t\t====================================\n\n");
printf("\n");
printf("Lumber Size(Inch) | Cross-Sectional | Moment of Inertia | Section Modulus |"); /* Engineering properties */
printf("\n(BasexHeight) | Area | | |\n");
printf("------------------------------------------------------------------------------\n");
/* Nested Loop used to create the table of value*/
float base, height, csa, I, Z;
10
CBCP2103 for (base=2; base<=10; base+=2){
for (height=2; height<=12; height+=2){
csa=base*height; /* csa = Cross Sectional Area */
I=(base*pow(height,3))/12; /* I = Moment of Inertia */
Z=(base*pow(height,2))/6; /* Z = Section Modulus */
printf(" %2.f x %2.f | %3.f | %10.2f | %10.2f |\n", base, height, csa, I, Z);
}
}
getch();
return 0;
}
11
CBCP2103
2.2 Screenshots for Question 2
Picture 2.2.1. Screenshot for displaying lumber size and its engineering properties.
12
CBCP2103
2.4 Flowchart for Question 2
Calculation:
csa = base x height
I =
base x h eig ht 3
12
base+=2
height+=2
True
False
height = 2
True
base = 2
False
height<=1
start
base<=10
13
CBCP2103
3.0 REFERENCE
Bakar, M. A. et al. (2011). CBCP2103 Computer Programming (2nd ed.). Centre for Instructional Design and Technology: Open University Malaysia.
Compiler used: Dev-C++ version 4.9.9.2 (provided by Open University Malaysia). Available: http://download.oum.edu.my/fitmc/m.php?p=compilers/devcpp-4.9.9.2_setup.exe
Cprogramming .com-Your resources for C and C++ [online]. Available: http://www.cprogramming .com
C programming tutorial [online]. Available: http://thenewboston.org/list.php?cat=14.
OPEN UNIVERSITY MALAYSIA online forum [online]. Available: http://lms.oum.edu.my.
14