atoms, the building blocks of matter - niagara.k12.wi.us 3 notes .pdf · john dalton: english...
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notes for chapter 3_2017.notebook
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October 26, 2017
Oct 1211:08 PM
Atoms, the Building Blocks of Matter
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Oct 223:40 PM
Learning objective:The learner will explain :• explain the law of conservation of mass• law of definite proportions• law of multiple proportion
summarize:• Dalton's atomic theory• and explain how this relates to the above laws
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Oct 198:09 AM
atoms: Smallest unit of an element that retains all of the properties of that element
electron: A negatively charged, subatomic particle located outside the nucleus of an atom. (in electron cloud)
nucleus:
neutron: Neutrally charged subatomic particle in the nucleus of an atom
proton: Positively charged subatomic particle in the nucleus of an atom
center region of an atom that contains the neutrons and protons
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Oct 199:27 AM
atomic #
ion: an atom that has lost or gained 1 or more electrons
Isotope: are atoms of the same element with different #'s of neutrons
Gives the position of an element on the periodic table of elements and the number of protons
atomic mass
number:# of protons +neutrons in the nucleus
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Atom → Greek philosopher: DemocritusAtomus: indivisible
Aristotle → no, matter is a continuous
sheet: "Hoyle"
Early ideas :
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2. All atoms of same element are identical in size, mass, and chemical properties
3. Atoms cannot be subdivided, created, or destroyed
John Dalton: English Chemist in the 1700'sDalton's Atomic Theory
1. All matter is made of very small particles called atoms
4. Atoms combine in simple, whole number ratios to form compounds5. In chemical reactions, atoms are combined, separated, or rearranged to form new substances
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Note questionpageNotes
Where Does Modern Atomic Theory differ from Dalton's Atomic Theory?
1. WE now know that elements have atoms with different ______________ which means the number
of _______ differs.
2. We now know that atoms have ____ _________
________________.
massesneutrons
sub atomicparticles
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October 26, 2017
Oct 127:14 PM
Early Research in Subatomic Particles
The first subatomic particle discoveredwere electrons in cathode ray tube experiments
Low pressure
gases
enclosed in
tube
discover,
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October 26, 2017
Oct 127:57 PM
• Thomson conducted a series of experiments with cathode rays and cathode ray tubes • leading him to the discovery of electrons and subatomic
particles. Thomson used the cathode ray tube and the results of
experiments conducted by Perin in three different experiments
http://www.aip.org/history/electron/
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Oct 128:16 PM
He found 1. when the rays entered the slit in the cylinders, the electrometer measured a large amount of negative charge.
2.The electrometer did not register much electric charge if the rays were bent so they would not enter the slit.
His conclusion: the negative charge and the cathode rays must somehow be connected: you cannot separate the charge from the rays.
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Rays from the cathode (C) pass through a slit in the anode (A) and through a slit in a grounded metal plug (B). An electrical voltage is established between aluminum plates (D and E), and a scale pasted on the outside of the end of the tube measures the deflection of the rays.
Thomson's apparatus in the second experiment.
conclusion: [cathode rays] are charges of negative electricity carried by particles of matter
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October 26, 2017
Oct 128:31 PM
Robert Milikan
Discovered the charge on a single electron through his famous oil drop experiment.using this and the ratio of the charge to mass, the massof an electron was calculated to be 1/1837th that of a hydrogen atom.
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• The original experiment was performed in 1909• balanced the downward gravitational force and the upward electrical forces of charged oil droplets suspended between two metal plates. • The mass of the droplets and the density of the oil was known
How the Oil Drop Experiment Worked
http://www.youtube.com/watch?NR=1&v=XMfYHag7Liw&feature=endscreen
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• measured radii of the oil drops. • the electric field that held the droplets suspended was measured • The value for the charge was calculated for many droplets. • The values were multiples of the value of a charge of a single electron. Millikan and Fletcher calculated the charge of an electron :
1.5924(17)×10−19 C (coulombs). Their value was within one percent of the currently accepted value for the charge of an electron: 1.602176487(40)×10−19 C
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October 26, 2017
Oct 1210:18 PM
Other Questions:1. Atoms are electrically neutral
*since electrons are negative, what balances that negative charge?2. Atoms have measurable mass
*electrons are not anywhere near the mass of the atom-what gives the atom its mass?
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Thomson's model, based on these resultsis known as the "plum pudding" model.The atom, he hypothesized, is a sphere of positive charge to counter the electrons. The electrons were free to move around in this charge as though it were a kind of liquid.
http://www.ukastronomy.com/atom.htm
http://www.uk-astronomy.com/atom.htm
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Rutherford and associates did investigations with radioactive particles and gold foil.
http://www.mhhe.com/physsci/chemistry/essentialchemistry/flash/ruther14.swf
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• Considered this phenomenon for 2 years • finally concluded that the alpha particles• must have encountered a very densely packed, positive charge • very small or more would have deflected. • He called this the nucleus
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Oct 243:35 PM
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Composition of the nucleus
Must account for the positive chargeMust account for the high mass
We know: protons account for the positive charge Neutrons account for the mass
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Oct 188:00 PM
The model of the atom at that point was known asthe planetary model:
the electrons were believed to orbit the nucleusthe way the planets orbit the sun.
http://www.uk-astronomy.com/atom.htm
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Oct 1211:00 PM
Now: explain why so many positive charges can exist in the same
place????• Proton-proton attractive forces don‛t obey the “opposites attract” when in close proximity!• They do just the opposite- so do neutronsThe short range proton- proton, proton-neutron, neutron-neutron attractive forces are known as nuclear forces
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Li36.94
Chemical symbol
Atomic #: whole #= # protons
Atomic mass # = # protons + # neutrons: weighted atomic mass
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Nov 510:56 AM
Nuclear Symbols
Z##
# nuclear particles
# protons
#+/-
charge on the atom
protons+ neutrons
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summary of hydrogen isotopes:
Isotope NuclearSymbol
# ofprotons
# ofneutrons
# ofelectrons
hydrogen - 1 H-1
hydrogen-2 H-2hydrogen-3 H-3
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Isotope # of protons# of neutrons
Nuclear Symbol
carbon-12
carbon-13
carbon-14
C12
C13
C14
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Oct 188:47 PM
Relative Atomic Masses*The actual mass of an atom of an element is so small, that it is not convenient to expressthem in grams.*Therefore: choose the mass of one key atom, and
call that "one atomic unit."
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Oct 188:56 PM
• The standard : the carbon atom• The unit: one atomic mass unit, written:
a.m.u.> is 1/12 of the actual mass of a carbon-12
atom.
Relative Atomic Masses, continued
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weighted atomic averages.The weighted average atomic mass is the weighted average of all of the naturally occurring isotopes of a particular element.
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Let's do this with isotopes
Summing the process:1. we multiply the atomic mass of each isotope by it's relative
abundance 2. Then add the results and 3. divide by 100 to find the weighted average.
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Step 1: multiply the amu by the abundance .005% x 234. 040 947 = 001.17020235.720 %x 235.043 924 = 169.2316252899.275% x 238.050 784 = 23632.4915816
amuamuamuamu
round to hundredths place AT The End
1. Isotopes of Uranium occur naturally in the following percentages:
Isotope name % abundance Atomic massa. Uranium 234: .005% 234. 040 947 a.m.u.b. Uranium 235 .720% 235.043 924 a.m.u.c. Uranium 238 99.275% 238.050 784 a.m.u.
Calculate the weighted average of the atomic mass of Uranium.
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5. A certain element exists as three natural isotopes as shown in the table below.Percent naturalIsotope Mass (amu) abundance Mass number1 19.99 244 90.51 % 202 20.99395 0.27 % 213 21.99138 9.22 % 22
Calculate the average atomic mass of this element.
19. 99244 × 90.51 =1809.5157 amu 20.99395 × 00.27 = 05.668 amu 21.99138 × 9.22 = 202.32 amu
2017.9
divide by 100 and round to 100ths: 20.18 amu
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Oct 1911:16 PM
Counting Atoms1 AMU is based on the mass of an atom of C12
We can determine how many atoms we haveby relating it to this number and a unit called the MOLE
THE MOLE1 mole is the amount of a substance that contains the same number of particles as exactly 12 grams of Carbon12
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Oct 239:58 AM
AVOGADRO'S NUMBER OR AVOGADRO'S CONSTANT
THE NUMBER OF PIECES IN ONE MOLE :
THIS IS EQUAL TO 6.022 X 1023 NO MATTER WHAT YOU ARE TALKING ABOUT!!!!DONUTS, EGGS, CARROTS...ELEPHANTS!
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Oct 2310:07 AM
MolarMass
amount of mass in one
Mole of a substance.
OR_
http://www.hcc.mnscu.edu/chem/V.13/page_id_15835.html
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Examples:
Carbon: 1 atom of carbon is 12.01 a.m.u 1 mol of carbon is 12.01 g
Magnesium: 1 atom is 24.31 a.m.u. 1 mole is 24.31 g
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Compounds:
one molecule of water: H2O 2.02 + 16.00
18.02 a.m.u.
one mole of water: 18.02 g/mol
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Oct 261:40 PM
Types of conversions we will be doing:1. Moles to mass2. Mass to moles3. # moles to # atoms4. # atoms to # of moles5. # atoms to mass6. Mass to # atoms
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mass
Determine the given (known) in your problemGo to the box that has the given in it.Determine which box has your unknownperform the operations in the arrow.
# moles # atoms÷ molar mass of element x 6.022 x1023
mass # moles # atoms÷ 6.022 x1023
xmolar mass of element
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CuGiven
3.50 mole Cu = amount
?
mass = ?
# moles x molar mass = mass
3.50mol x 63.55 g/mole = mass
= 222.425 g Cumass = 222. g
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October 26, 2017
Oct 2112:51 PM
Givenamount = 0.375mol K
mass = ?
# Moles x Molar mass = mass
mass=14.7g K
molar mass K: 39.10 g/mole
?
0.375 mole K. x 39.10 g/mo| = mass K
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October 26, 2017
Oct 2112:57 PM
Givenamt= 0.0135 mol Na
?mass=?
amount in moles x Molar mass = mass
0.0135 mol Na x 22.99 g/mol =0.310g Na
molar mass Na = 22.99 g/mo|
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October 26, 2017
Oct 2811:13 AM
Given
4.00 moles Al
?
# atoms
x 6.022. 1023 atoms/mole4.00 mol Al = # atoms24.088 x 1023 atoms Al
2.41 x 1024 atoms Al
= # atoms
6.022. 1023 atoms in one mol
# moles x atoms per mole = # atoms
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Oct 3011:11 AM
# label # Label# label # Label
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Known
3.01 x 1023 atoms Ag
?# moles
0.500 mole Ag
# atoms ÷ # atommole = # moles
3.01 x 1023 atoms 1 mole
6.022 x 1023 atoms
3.01. 1023 atoms Ag ÷ 6.022.1023 atoms/mole = # moles
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October 26, 2017
Oct 2612:59 PM
known ?# atoms = 3.0x 1023 atoms F mass
3.0 x 1023 atoms F ÷ 6.022 x 1023 atoms F x 18.99 g/mole =mass
# atoms ÷ # atoms in one mole x molar mass = mass
3.0 x 1023 atoms F mole 18.99 g =mass F 6.022x 1023 atoms mole
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October 26, 2017
Nov 710:34 AM
Dimensional analysis: do the math with only the units;
Determine the equationset up with units
grams moles
grams= grams
if the units match what you are after, plug in the numbers
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Nov 1210:25 AM
• Mass to # atoms• # atoms to mass
2 step conversions:
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Nov 35:29 PM
What is the mass, in grams, of 1.20x108 atoms of Cu?
Atoms to moles to mass
# atoms ÷ # atoms in one mole x the molar mass = mass of Cu
Pg. 86 Sample problem E
Given ?1.20 x 108 atoms Cu mass of Cu
1.20 x 108 atoms Cu ÷ 6.022 x 1023atoms/mole x 63. 55g/mol = massCu
.199 x 10 -15 mol Cu x 63.55 g/mol = mass Cu
1.27 x 10-14 g Cu
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October 26, 2017
Nov 912:22 PM
#mol → mass#mol . molar mass = mass
mass → Mol#g ÷ molar mass = mol
1
# atoms →# moles 4 #atoms ÷ 6.022 x 1023 atoms/mole = # moles
# moles → # atoms# atoms x 6.022 x 1023 = # atoms
2
3
Move me to see notes
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October 26, 2017
summary slide2
5 # atom --> mass# atoms ÷ 6.022 x 1023 x molar mass = mass (g)
6mass --> # atomsmass ÷ molar mass x 6.022 x 1023 atom/mole = # atoms
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Law of conservation of mass
Law of Definite Proportions
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Attachments
PP CHEM107.ppt
Atomic Structure
Chemistry 1
Chapter 7
I. Early Atomic Theory
A. The Greeks
Democritus 400 BC
1. Coined the word atom
2. Different atoms for each material
Aristotle
1. Taught that all matter was composed of a continuous material called “hyle”.
ALCHEMISTS LAB
ALCHEMY
B. Europeans
1. Newton and Robert Boyle –
proposed atomic theory but had no proof.
2. Joseph Proust –
determined the Law of Definite Proportions.
3. Lavosier –
closed system reactions showed no mass changes.
DALTON’S ATOMIC THEORY
JOHN DALTON
II. Dalton’s Hypothesis
All matter is composed of extremely small particles called atoms
Atoms of a given element are identical in size, mass, and other properties. Atoms of different elements differ is size, mass, and other properties.
Atoms cannot be subdivided, created, or destroyed
Atoms of different elements combine in simple whole number rations to form chemical compounds
In chemical reactions, atoms are combined, separated, or rearranged.
This explains the conservation of mass- along with #3
LAW OF DEFINITE PROPORTIONS
LAW OF MULITPLE PROPORTIONS
Law of multiple proportions
C. Part 2 of the proposal is not entirely correct.
It was discovered that some atoms of an element are heavier than other atoms of the same element.
D. Law of Multiple Proportions - for elements that form more than 1 compound with each other.
SnO 119 to 16 1 to 1
SnO2 119 to 32 1 to 2
III. Early Research on Atomic Particles
A. Atoms consist of smaller particles
B. Cathode Ray Tube
1. + electrode (anode)
2. - electrode (cathode)
3. Rays moved from cathode to the anode.
CATHODE RAY TUBE
CRT
4. J.J. Thomson discovered they were electrons and calculated charge to mass ratio.
CRT IN MAGNETIC FIELD
CRT IN MAGNETIC FIELD
C. Robert Milikan-
Discovered the charge of a single electron through his famous oil drop experiment.
Mass was calculated to be 1/1837th that of a hydrogen atom.
MILIKAN OIL DROP EXPERIMENT
D. Goldstein -
Discovered protons using a modified cathode ray tube.
1. Thomson showed they were particles.
2. Their mass was calculated to be 1836 times the mass of an electron.
GOLDSTEIN’S CRT
E. Chadwick discovered neutrons.
IV. Isotopes and Atomic Number
A. If all atoms of an element were the same, the atomic mass of the element should have a whole number value. It did not.
B. J.J. Thomson observed two kinds of neon atoms, chemically alike but with different masses.
ISOTOPES OF HYDROGEN
ISOTOPES OF LITHIUM
ISOTOPE CHART
C. Henry Moseley -
Discovered the cause of the mass differences in atoms of the same element.
1. X-rays produced by all the atoms of an element had a characteristic wavelength
2. All atoms of an element had the same number of protons.
3. Atomic Number (Z) equals the number of protons.
4. Since atoms are neutral, the number of electrons must equal the number of protons.
5. That left the neutron as the cause of the mass differences in atoms of a given element.
6. It is the number of protons that give an element it’s characteristics.
D. New Atomic Theory
Takes into account the mass differences between atoms of a given element.
1. Nuclide - particular kind of atom containing a definite number of protons and neutrons.
2. Nucleon – particles that make up the nucleus.
3. Mass Number – (A) total number of nucleons.
A – Z = Neutrons
NUCLIDE CHART
V. The Nuclear Atom
A. Gold Foil Experiment
Was designed by Rutherford to determine how atoms were constructed.
GOLD FOIL APPARATUS
2. Some bullets were deflected, 1 in 8000 bounced back.
3. With a diameter of an atom between 100 – 500 pm, the diameter of the nucleus was calculated at 0.0012 to 0.0075pm.
4. Nucleus is about 1 trillionth the volume of the atom.
VI. Radioactivity
A. Becquerel discovered radioactivity. How??
B. Radioactivity – rays being produced spontaneously by unstable atomic nuclei.
C. Energy Released
1. 1 mol U-235 in chemical reaction releases 7.64*102 kj (764 kj)
2. 1 mol U-235 in nuclear change releases 1.90*1010 kj (19 000 000 000 kj)
VII. Atomic Structure
A. The Nucleus
1. Composed of Protons and Neutrons.
2. What holds the nucleus together?
3. Strong Nuclear Force over 1x10-15m.
4. Has a property that corresponds to spinning on an axis.
ATOMIC NUCLEUS
5. Electrons do not exist in the nucleus but can be emitted by one.
n -> p + e- and an anti-neutrion
B. Subatomic Particles
1. Leptons – light particles
2. Hadrons – heavy particles composed of quarks
a. Baryons (3)
b. Mesons (2)
3. antiparticles
4. Quarks
Proton’s Quark make up (UUD)
U quarks = (+2/3), D quarks = (-1/3)
(+2/3) + (+2/3) + (-1/3) = +1 Charge
Neutron (UDD)
(+2/3) + (-1/3) + (-1/3) = 0 Charge
Quarks are held together by exchanging gluons
ATOMIC STRUCTURE
PARTICL IDENTIFIER
FERMILAB
VIII. Radiation
A. Definition
B. Types
1. Alpha 42He
2. beta
3. gamma
VIII. Radiation
A. Unstable nuclei will eject a particle or energy to reach a more
stable state.
B. Types:
1. Alpha particle are helium nuclei 42 He
2. Beta particles are electrons
3. gamma rays are high energy X rays.
C. Transuranic elements are produced by bombarding stable nuclei
with accelerated particles.
1. these radioactives decay by particle or energy
emission or by capturing an electron from outside
the nucleus.
C. Transuranic elements – After Uranium
Are produced by bombarding stable nuclei with accelerated particles.
Seaborgium named after an Upper Peninsula native who became a famous scientist
IX. The Rutherford Bohr Atom
A. The electron and the nucleus
B. Planetary orbits
Orbital Motion
ELECTRON ORBITAL
LIGHT ABSORPTION
ORBIT JUMPING
C. Energy changes in electrons
The Photoelectric Effect
Electrons moving to higher orbits
Electrons falling to lower orbits
D. Definitions
1. spectroscopy
2. electromagnetic energy
3. frequency
4. wavelength
5. hertz
6. spectrum
7. amplitude
WAVE PARTS
X. Planck’s Hypothesis
A. Quantum Theory
B. Quanta – packets of energy
C. E = hf (6.63 x 10-34j/Hz)(frequency)
QUANTUM VESSEL
XI. Quantum Theory and Hydrogen
A. Absorption of light at specific wavelengths corresponded to definite energy changes.
B. Quanta - packets of energy- energy could be absorbed or emitted in whole numbers of quanta 1,2,3 etc.
C. Electrons had orbitals with definite energy levels.
D. Orbital Sizes
1. electrons move between orbitals by absorbing or releasing quanta of energy.
2. ground state – when all electrons are at the lowest possible energy levels.
3. H is about 53pm in radius.
E. Disagreement with other atoms-
Calculations that worked for hydrogen did not work for more complicated atoms.
XII. Atomic Mass
A.Protons and Neutrons – equal in mass
B.Electrons – almost massless
C.The Nucleus – most of atoms mass
D.Atomic Mass Units (amu)
Carbon 12 has a mass of 12 amu.
E.Isotopes
XIII. Average Atomic Mass
A. Mass Spectrometer – device used to find the masses of all the isotopes of an element.
CALCULATIONS
B. Calculations:
Si92.21% = 27.972 amu
4.70% = 28.976 amu
3.09% = 29.974 amu
(27.972 x 92.21)
+
(28.976 x 4.70)
+
(29.974 x 3.09)
100
= 28.08
CALCULATIONS
CALCULATION
LLA SI TAHT
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