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  • notes for chapter 3_2017.notebook

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    Atoms, the Building Blocks of Matter

    1

  • notes for chapter 3_2017.notebook

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    Learning objective:The learner will explain :• explain the law of conservation of mass• law of definite proportions• law of multiple proportion

    summarize:• Dalton's atomic theory• and explain how this relates to the above laws

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    atoms: Smallest unit of an element that retains all of the properties of that element

    electron:  A negatively charged, subatomic particle located outside the nucleus of an atom. (in electron cloud)

    nucleus: 

    neutron: Neutrally charged subatomic particle in the nucleus of an atom

    proton: Positively charged subatomic particle in the nucleus of an atom

    center region of an atom that contains the neutrons and protons

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    atomic #

    ion: an atom that has lost or gained 1 or more electrons

    Isotope: are atoms of the same element with different #'s of neutrons

    Gives the position of an element on the periodic table of elements and the number of protons

    atomic mass 

    number:# of protons +neutrons in the nucleus

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    Atom → Greek philosopher: DemocritusAtomus: indivisible

    Aristotle → no, matter is a continuous

    sheet: "Hoyle"

    Early ideas :

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    2.  All atoms of same element are identical in size, mass, and chemical properties

    3. Atoms cannot be subdivided, created, or destroyed 

    John Dalton: English Chemist in the 1700'sDalton's Atomic Theory

    1. All matter is made of very small particles called atoms

    4. Atoms combine in simple, whole number ratios to form compounds5. In chemical reactions, atoms are combined, separated, or rearranged to form new substances

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    Note questionpageNotes

    Where Does Modern Atomic Theory differ from Dalton's Atomic Theory?

    1. WE now know that elements have atoms with  different ______________ which means the number 

    of _______ differs.

    2. We now know that atoms have ____ _________ 

    ________________.  

    massesneutrons

    sub  atomicparticles

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    Early Research in Subatomic Particles

    The first subatomic particle discoveredwere electrons in cathode ray tube experiments

    Low pressure

    gases

    enclosed in

    tube 

    discover,

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    • Thomson conducted a series of experiments with cathode rays and cathode ray tubes • leading him to the discovery of electrons and subatomic

    particles. Thomson used the cathode ray tube and the results of

    experiments conducted by Perin in three different experiments

    http://www.aip.org/history/electron/

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    He found 1. when the rays entered the slit in the cylinders, the electrometer measured a large amount of negative charge.

    2.The electrometer did not register much electric charge if the rays were bent so they would not enter the slit.

    His conclusion: the negative charge and the cathode rays must somehow be connected: you cannot separate the charge from the rays.

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     Rays from the cathode (C) pass through a slit in the anode (A) and through a slit in a grounded metal plug (B). An electrical voltage is established between aluminum plates (D and E), and a scale pasted on the outside of the end of the tube measures the deflection of the rays. 

    Thomson's apparatus in the second experiment.

    conclusion: [cathode rays] are charges of negative electricity carried by particles of matter

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    Robert Milikan

    Discovered the charge on a single electron through his famous oil drop experiment.using this and the ratio of the charge to mass, the massof an electron was calculated to be 1/1837th that of a hydrogen atom.

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    • The original experiment was performed in 1909• balanced the downward gravitational force and the upward electrical forces of charged oil droplets suspended between two metal plates. • The mass of the droplets and the density of the oil was known

    How the Oil Drop Experiment Worked

    http://www.youtube.com/watch?NR=1&v=XMfYHag7Liw&feature=endscreen

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    • measured radii of the oil drops. • the electric field that held the droplets suspended was measured • The value for the charge was calculated for many droplets. • The values were multiples of the value of a charge of a single electron. Millikan and Fletcher calculated the charge of an electron :

        1.5924(17)×10−19 C (coulombs). Their value was within one percent of the currently accepted value for the charge of an electron: 1.602176487(40)×10−19 C

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    Other Questions:1. Atoms are electrically neutral

    *since electrons are negative, what balances that negative charge?2. Atoms have measurable mass

    *electrons are not anywhere near the mass of the atom-what gives the atom its mass?

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    Thomson's model, based on these resultsis known as the "plum pudding" model.The atom, he hypothesized, is a sphere of positive charge to counter the electrons. The electrons were free to move around in this charge as though it were a kind of liquid.

    http://www.ukastronomy.com/atom.htm

    http://www.uk-astronomy.com/atom.htm

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    Rutherford and associates did investigations with radioactive particles and gold foil.

    http://www.mhhe.com/physsci/chemistry/essentialchemistry/flash/ruther14.swf

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    • Considered this phenomenon for 2 years •  finally concluded that the alpha particles•  must have encountered a very densely packed, positive       charge •  very small or more would have deflected.  • He called this the nucleus

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    Composition of the nucleus

    Must account for the positive chargeMust account for the high mass

    We know: protons account for the positive charge Neutrons account for the mass

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    The model of the atom at that point was known asthe planetary model:

    the electrons were believed to orbit the nucleusthe way the planets orbit the sun.

    http://www.uk-astronomy.com/atom.htm

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    Now: explain why so many positive charges can exist in the same

    place????• Proton-proton attractive forces don‛t obey the “opposites attract” when in close proximity!• They do just the opposite- so do neutronsThe short range proton- proton, proton-neutron, neutron-neutron attractive forces are known as nuclear forces

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    Li36.94

    Chemical symbol

    Atomic #: whole #= # protons

    Atomic mass # = # protons + # neutrons: weighted atomic mass

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    Nuclear Symbols

    Z##

    # nuclear particles

    # protons

    #+/-

    charge on the atom

    protons+ neutrons

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    summary of hydrogen isotopes:

    Isotope NuclearSymbol

    # ofprotons

    # ofneutrons

    # ofelectrons

    hydrogen - 1 H-1

    hydrogen-2 H-2hydrogen-3 H-3

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    Isotope # of protons# of neutrons

    Nuclear Symbol

    carbon-12

    carbon-13

    carbon-14

    C12

    C13

    C14

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    Relative Atomic Masses*The actual mass of an atom of an element is so small, that it is not convenient to expressthem in grams.*Therefore: choose the mass of one key atom, and

    call that "one atomic unit."

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    • The standard : the carbon atom• The unit: one atomic mass unit, written:

    a.m.u.> is 1/12 of the actual mass of a carbon-12

    atom.

    Relative Atomic Masses, continued

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    weighted atomic averages.The weighted average atomic mass is the weighted average of all of the naturally occurring isotopes of a particular element.

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    Let's do this with isotopes

    Summing the process:1. we multiply the atomic mass of each isotope by it's relative

    abundance 2. Then add the results and 3. divide by 100 to find the weighted average.

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    Step 1: multiply the amu by the abundance .005%  x   234. 040 947 =     001.17020235.720 %x    235.043 924  =      169.2316252899.275% x 238.050 784  = 23632.4915816                                           

    amuamuamuamu

    round to hundredths place AT The End

    1. Isotopes of Uranium occur naturally in the following percentages:

    Isotope name % abundance Atomic massa. Uranium 234:    .005% 234. 040 947 a.m.u.b. Uranium 235   .720% 235.043 924  a.m.u.c. Uranium 238      99.275%  238.050 784  a.m.u.

    Calculate the weighted average of the atomic mass of Uranium.

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    5.  A certain element exists as three natural isotopes as shown in the table below.Percent naturalIsotope  Mass (amu)  abundance  Mass number1  19.99 244   90.51  % 202  20.99395      0.27  %          213              21.99138      9.22 %           22

    Calculate the average atomic mass of this element.

     19. 99244 ×  90.51 =1809.5157 amu 20.99395  × 00.27 =      05.668   amu    21.99138 ×    9.22 =   202.32      amu

       2017.9

    divide by 100 and round to 100ths: 20.18 amu

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    Counting Atoms1 AMU is based on the mass of an atom of C12

    We can determine how many atoms we haveby relating it to this number and a unit called the MOLE

    THE MOLE1 mole is the amount of a substance that contains the same number of particles as exactly 12 grams of Carbon12

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    AVOGADRO'S NUMBER OR AVOGADRO'S CONSTANT

    THE NUMBER OF PIECES IN ONE MOLE :

    THIS IS EQUAL TO 6.022 X 1023 NO MATTER WHAT YOU ARE TALKING ABOUT!!!!DONUTS, EGGS, CARROTS...ELEPHANTS!

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    MolarMass

    amount of mass in one

    Mole of a substance.

    OR_

    http://www.hcc.mnscu.edu/chem/V.13/page_id_15835.html

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    Examples:

    Carbon: 1 atom of carbon is 12.01 a.m.u 1 mol of carbon is 12.01 g

    Magnesium: 1 atom is 24.31 a.m.u. 1 mole is 24.31 g

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    Compounds:

    one molecule of water: H2O 2.02 + 16.00

    18.02 a.m.u.

    one mole of water: 18.02 g/mol

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    Types of conversions we will be doing:1. Moles to mass2. Mass to moles3. # moles to # atoms4. # atoms to # of moles5. # atoms to mass6. Mass to # atoms

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    mass

    Determine the given (known) in your problemGo to the box that has the given in it.Determine which box has your unknownperform the operations in the arrow.

    # moles # atoms÷ molar mass of element x 6.022 x1023

    mass # moles # atoms÷ 6.022 x1023

    xmolar mass of element

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    CuGiven

    3.50 mole Cu = amount

    ?

    mass = ?

    # moles x molar mass = mass

    3.50mol x 63.55 g/mole  = mass

    = 222.425 g Cumass = 222. g

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    Givenamount = 0.375mol K

    mass = ?

    # Moles x Molar mass = mass

    mass=14.7g K

    molar mass K: 39.10 g/mole

    ?

    0.375 mole K. x 39.10 g/mo| = mass K

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    Givenamt= 0.0135 mol Na

    ?mass=?

    amount in moles x Molar mass = mass

    0.0135 mol Na x 22.99 g/mol =0.310g Na

    molar mass Na = 22.99 g/mo|

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    Given

    4.00 moles Al

    ?

    # atoms

    x 6.022. 1023 atoms/mole4.00 mol Al = # atoms24.088 x 1023 atoms Al

    2.41 x 1024 atoms Al

    = # atoms

    6.022. 1023 atoms in one mol

    # moles  x  atoms per mole = # atoms

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    # label # Label# label # Label

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    Known

    3.01 x 1023 atoms Ag

    ?# moles

    0.500 mole Ag

    # atoms ÷ # atommole = # moles

    3.01 x 1023 atoms 1 mole

    6.022 x 1023 atoms

    3.01. 1023 atoms Ag ÷ 6.022.1023 atoms/mole = # moles

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    known       ?# atoms = 3.0x 1023 atoms F  mass

    3.0 x 1023 atoms F ÷ 6.022 x 1023 atoms F x 18.99 g/mole =mass     

    # atoms ÷ # atoms in one mole x molar mass = mass

    3.0 x 1023 atoms F   mole         18.99      g     =mass F                6.022x 1023 atoms    mole

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    Dimensional analysis: do the math with only the units;

    Determine the equationset up with units

    grams moles

    grams= grams

    if the units match what you are after, plug in the numbers

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    • Mass to # atoms• # atoms to mass

    2 step conversions:

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    What is the mass, in grams, of 1.20x108 atoms of Cu?

    Atoms to moles to mass

    # atoms ÷ # atoms in one mole x the molar mass = mass of Cu

    Pg. 86 Sample problem E

    Given ?1.20 x 108 atoms Cu mass of Cu

    1.20 x 108 atoms Cu ÷ 6.022 x 1023atoms/mole x 63. 55g/mol = massCu

    .199 x 10 -15 mol Cu x 63.55 g/mol = mass Cu

    1.27 x 10-14 g Cu

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    #mol →  mass#mol . molar mass = mass

    mass →  Mol#g ÷ molar mass = mol

    1

    # atoms →# moles   4 #atoms ÷ 6.022 x 1023 atoms/mole = # moles

    # moles →  # atoms# atoms x 6.022 x 1023 = # atoms

    2

    3

    Move me to see notes

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    summary slide2

    5 # atom --> mass# atoms ÷ 6.022 x 1023 x molar mass = mass (g)

    6mass --> # atomsmass ÷ molar mass x 6.022 x 1023 atom/mole = # atoms

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    Law of conservation of mass

    Law of Definite Proportions

  • Attachments

    PP CHEM107.ppt

    Atomic Structure

    Chemistry 1

    Chapter 7

    I. Early Atomic Theory

    A. The Greeks

    Democritus 400 BC

    1. Coined the word atom

    2. Different atoms for each material

    Aristotle

    1. Taught that all matter was composed of a continuous material called “hyle”.

    ALCHEMISTS LAB

    ALCHEMY

    B. Europeans

    1. Newton and Robert Boyle –

    proposed atomic theory but had no proof.

    2. Joseph Proust –

    determined the Law of Definite Proportions.

    3. Lavosier –

    closed system reactions showed no mass changes.

    DALTON’S ATOMIC THEORY

    JOHN DALTON

    II. Dalton’s Hypothesis

    All matter is composed of extremely small particles called atoms

    Atoms of a given element are identical in size, mass, and other properties. Atoms of different elements differ is size, mass, and other properties.

    Atoms cannot be subdivided, created, or destroyed

    Atoms of different elements combine in simple whole number rations to form chemical compounds

    In chemical reactions, atoms are combined, separated, or rearranged.

    This explains the conservation of mass- along with #3

    LAW OF DEFINITE PROPORTIONS

    LAW OF MULITPLE PROPORTIONS

    Law of multiple proportions

    C. Part 2 of the proposal is not entirely correct.

    It was discovered that some atoms of an element are heavier than other atoms of the same element.

    D. Law of Multiple Proportions - for elements that form more than 1 compound with each other.

    SnO 119 to 16 1 to 1

    SnO2 119 to 32 1 to 2


    III. Early Research on Atomic Particles

    A. Atoms consist of smaller particles

    B. Cathode Ray Tube

    1. + electrode (anode)

    2. - electrode (cathode)

    3. Rays moved from cathode to the anode.

    CATHODE RAY TUBE

    CRT

    4. J.J. Thomson discovered they were electrons and calculated charge to mass ratio.

    CRT IN MAGNETIC FIELD

    CRT IN MAGNETIC FIELD

    C. Robert Milikan-

    Discovered the charge of a single electron through his famous oil drop experiment.

    Mass was calculated to be 1/1837th that of a hydrogen atom.

    MILIKAN OIL DROP EXPERIMENT

    D. Goldstein -

    Discovered protons using a modified cathode ray tube.

    1. Thomson showed they were particles.

    2. Their mass was calculated to be 1836 times the mass of an electron.

    GOLDSTEIN’S CRT

    E. Chadwick discovered neutrons.

    IV. Isotopes and Atomic Number

    A. If all atoms of an element were the same, the atomic mass of the element should have a whole number value. It did not.

    B. J.J. Thomson observed two kinds of neon atoms, chemically alike but with different masses.

    ISOTOPES OF HYDROGEN

    ISOTOPES OF LITHIUM

    ISOTOPE CHART

    C. Henry Moseley -

    Discovered the cause of the mass differences in atoms of the same element.

    1. X-rays produced by all the atoms of an element had a characteristic wavelength

    2. All atoms of an element had the same number of protons.

    3. Atomic Number (Z) equals the number of protons.

    4. Since atoms are neutral, the number of electrons must equal the number of protons.

    5. That left the neutron as the cause of the mass differences in atoms of a given element.

    6. It is the number of protons that give an element it’s characteristics.

    D. New Atomic Theory

    Takes into account the mass differences between atoms of a given element.

    1. Nuclide - particular kind of atom containing a definite number of protons and neutrons.

    2. Nucleon – particles that make up the nucleus.

    3. Mass Number – (A) total number of nucleons.

    A – Z = Neutrons

    NUCLIDE CHART

    V. The Nuclear Atom

    A. Gold Foil Experiment

    Was designed by Rutherford to determine how atoms were constructed.

    GOLD FOIL APPARATUS

    2. Some bullets were deflected, 1 in 8000 bounced back.

    3. With a diameter of an atom between 100 – 500 pm, the diameter of the nucleus was calculated at 0.0012 to 0.0075pm.

    4. Nucleus is about 1 trillionth the volume of the atom.

    VI. Radioactivity

    A. Becquerel discovered radioactivity. How??

    B. Radioactivity – rays being produced spontaneously by unstable atomic nuclei.

    C. Energy Released

    1. 1 mol U-235 in chemical reaction releases 7.64*102 kj (764 kj)

    2. 1 mol U-235 in nuclear change releases 1.90*1010 kj (19 000 000 000 kj)

    VII. Atomic Structure

    A. The Nucleus

    1. Composed of Protons and Neutrons.

    2. What holds the nucleus together?

    3. Strong Nuclear Force over 1x10-15m.

    4. Has a property that corresponds to spinning on an axis.

    ATOMIC NUCLEUS

    5. Electrons do not exist in the nucleus but can be emitted by one.

    n -> p + e- and an anti-neutrion

    B. Subatomic Particles

    1. Leptons – light particles


    2. Hadrons – heavy particles composed of quarks

    a. Baryons (3)

    b. Mesons (2)

    3. antiparticles

    4. Quarks

    Proton’s Quark make up (UUD)

    U quarks = (+2/3), D quarks = (-1/3)

    (+2/3) + (+2/3) + (-1/3) = +1 Charge

    Neutron (UDD)

    (+2/3) + (-1/3) + (-1/3) = 0 Charge

    Quarks are held together by exchanging gluons

    ATOMIC STRUCTURE

    PARTICL IDENTIFIER

    FERMILAB

    VIII. Radiation

    A. Definition

    B. Types

    1. Alpha 42He

    2. beta

    3. gamma

    VIII. Radiation

    A. Unstable nuclei will eject a particle or energy to reach a more

    stable state.

    B. Types:

    1. Alpha particle are helium nuclei 42 He

    2. Beta particles are electrons

    3. gamma rays are high energy X rays.

    C. Transuranic elements are produced by bombarding stable nuclei

    with accelerated particles.

    1. these radioactives decay by particle or energy

    emission or by capturing an electron from outside

    the nucleus.

    C. Transuranic elements – After Uranium

    Are produced by bombarding stable nuclei with accelerated particles.

    Seaborgium named after an Upper Peninsula native who became a famous scientist

    IX. The Rutherford Bohr Atom

    A. The electron and the nucleus

    B. Planetary orbits

    Orbital Motion

    ELECTRON ORBITAL

    LIGHT ABSORPTION

    ORBIT JUMPING

    C. Energy changes in electrons

    The Photoelectric Effect

    Electrons moving to higher orbits

    Electrons falling to lower orbits

    D. Definitions

    1. spectroscopy

    2. electromagnetic energy

    3. frequency

    4. wavelength

    5. hertz

    6. spectrum

    7. amplitude

    WAVE PARTS

    X. Planck’s Hypothesis

    A. Quantum Theory

    B. Quanta – packets of energy

    C. E = hf (6.63 x 10-34j/Hz)(frequency)

    QUANTUM VESSEL

    XI. Quantum Theory and Hydrogen

    A. Absorption of light at specific wavelengths corresponded to definite energy changes.

    B. Quanta - packets of energy- energy could be absorbed or emitted in whole numbers of quanta 1,2,3 etc.

    C. Electrons had orbitals with definite energy levels.

    D. Orbital Sizes

    1. electrons move between orbitals by absorbing or releasing quanta of energy.

    2. ground state – when all electrons are at the lowest possible energy levels.

    3. H is about 53pm in radius.

    E. Disagreement with other atoms-

    Calculations that worked for hydrogen did not work for more complicated atoms.

    XII. Atomic Mass

    A.Protons and Neutrons – equal in mass

    B.Electrons – almost massless

    C.The Nucleus – most of atoms mass

    D.Atomic Mass Units (amu)

    Carbon 12 has a mass of 12 amu.

    E.Isotopes

    XIII. Average Atomic Mass

    A. Mass Spectrometer – device used to find the masses of all the isotopes of an element.

    CALCULATIONS

    B. Calculations:

    Si92.21% = 27.972 amu

    4.70% = 28.976 amu

    3.09% = 29.974 amu

    (27.972 x 92.21)

    +

    (28.976 x 4.70)

    +

    (29.974 x 3.09)

    100

    = 28.08

    CALCULATIONS

    CALCULATION

    LLA SI TAHT

    SMART Notebook

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