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Page 1: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Aula #03

Page 2: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Dalton’s Atomic Theory

2

Page 3: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

8 X2Y16 X 8 Y+Proportion /relation between matter

Page 4: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

atomic radius ~ 100 pm = 1 x 10-10 m

nuclear radius ~ 5 x 10-3 pm = 5 x 10-15 m

Rutherford’s Model of the Atom

What made by Rutherford and his

assistants Geiger and Marsden is perhaps one of the most important experiments of nuclear physics.

Page 5: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

1. atoms positive charge is concentrated in the nucleus

2. proton (p) has opposite (+) charge of electron (-)

3. mass of p is 1840 x mass of e- (1.67 x 10-24 g)

particle velocity ~ 1.4 x 107 m/s(~5% speed of light)

(1908 Nobel Prize in Chemistry)

Page 7: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

- Neutron, n - Protons, He2+

- Electrons, e

Page 8: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Atomic number, Mass number and Isotopes

Atomic number (Z) = number of protons in nucleus

Mass number (A) = number of protons + number of neutrons

= atomic number (Z) + number of neutrons

Isotopes are atoms of the same element (X) with

different numbers of neutrons in their nuclei

XA

Z

H1

1H (D)

2

1H (T)

3

1

U235

92U238

92

Mass Number

Atomic NumberElement Symbol

Page 9: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Isotopes are atoms of the same element (X)

with different numbers of neutrons in their nuclei

XA

Z

Mass Number

Atomic NumberElement Symbol

U235

92

92 protons, 92 electrons

143 (235 - 92) neutrons,

Atomic number, Mass number and Isotopes

Page 10: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

Atomic/Nano/Micro Worldatoms & molecules

Macro WorldGrams; tons

The mole (mol) is the amount of a substance that contains as many elementary entities as there

6.022140857 × 1023

are atoms in exactly 12.00 grams of 12C

Avogadro’s number (NA) 6.022 140 76 × 1023

Page 11: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

The mole (mol) is the amount of a substance that contains as many elementary entities as 6.022 140 76 × 1023

there are atoms in exactly 12.00 grams of 12C …IUPAC 2018

http://physics.nist.gov/cgi-bin/cuu/Value?na

Lorenzo Romano Amedeo Carlo Avogadro

Page 12: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

On this scale

1H = 1.008 amu

16O = 16.00 amu

Atomic mass is the mass of an atom in atomic mass units (amu)

Natural abundance of lithium:

6Li (6.015 amu) 7.42%

7Li (7.016 amu) 92.58%

Average atomic mass of lithium:

7.42 x 6.015 + 92.58 x 7.016

100= 6.941 amu

Li

Page 13: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Average atomic mass (6.941)

= 6.941 amu

Li

Page 14: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

Atomic/Nano/Micro Worldatoms & molecules

Macro WorldGrams; tons

Avogadro’s number (NA) 6.022140857 × 1023 mol-1

1 mole (mol) Li MW=6.941 g/mol 6.941 gram

1 mole (mol) C MW=12.0107 g/mol 12.0107 gram

Page 15: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

Carbon 12.0107 gSulfur 32.065 gMercury 200.59 gCopper 63.546 gIron 55.845 g

One Mole of:

Page 16: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

6x (12.0107) + 12x(1.00794) + 6x(15.9994)

180.1559 gmol-1

Page 17: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

How many molecules are in 5.0 g of Saccharose ?

342.2965 gmol-1

Formula: C12H22O11

Molar mass: 342.2965 g/mol

5.0 g

Avogadro’s number (NA)

x 6.022140857 × 1023 mol-1

mol

= 12 x 8.8 × 1021 atoms of C

= 8.8 × 1021 molecules of Saccharose

= 22 x 8.8 × 1021 atoms of H

= 11 x 8.8 × 1021 atoms of O

Page 18: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

5.0 g of Saccharose ?

Formula: C12H22O11

Molar mass: 342.2965 g/mol

Avogadro’s number (NA)

6.022140857 × 1023 mol-1

20 milhões x 20 milhões x 20 milhões

= 8.8 × 1021 molecules of Saccharose

Page 19: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

Page 20: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

%C =2 x (12.01 g)

46.07 gx 100% = 52.14%

%H =6 x (1.008 g)

46.07 gx 100% = 13.13%

%O =1 x (16.00 g)

46.07 gx 100% = 34.73%

52.14% + 13.13% + 34.73% = 100.0%

C2H6O

Ethanol

Percent composition of an element in a compound =

n x molar mass of element

molar mass of compoundx 100%

Page 21: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

nK = 24.75 g K x = 0.6330 mol K1 mol K

39.10 g K

nMn = 34.77 g Mn x = 0.6329 mol Mn1 mol Mn

54.94 g Mn

nO = 40.51 g O x = 2.532 mol O1 mol O

16.00 g O

Empirical formula of a compound that has the following percent composition by mass:

K= 24.75% , Mn= 34.77%, O= 40.51%

Base ..100 g

K : ~~ 1.00.6330

0.6329

Mn : 0.6329

0.6329= 1.0

O : ~~ 4.02.532

0.6329

nK = 0.6330, nMn = 0.6329, nO = 2.532

KMnO4

Page 22: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

Combustion 11.5 g ethanol

Collect 22.0 g CO2 and 13.5 g H2O

g CO2 mol CO2 mol C g C

g H2O mol H2O mol H g H

g of O = g of sample – (g of C + g of H)

6.0 g C = 0.5 mol C

1.5 g H = 1.5 mol H

4.0 g O = 0.25 mol O

C0.5H1.5O0.25

Divide by smallest subscript (0.25)

Empirical formula C2H6O

Page 23: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Ethane reacts with oxygen to form carbon dioxide and water

C2H6 + O2 2 CO2 + 3 H2O

Balancing Chemical Equations

C2H6 + O2 CO2 + H2O

multiply O2 by 72

C2H6 + 7/2O2 2 CO2 + 3 H2O

2C2H6 + 7O2 4CO2 + 6H2O

Balancing, C & H

Page 24: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

2NO + 2O2 2NO2

NO is the limiting reagent

O2 is the excess reagent

limiting reagent

Page 25: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

In one process, 124 g of Al are reacted with 601 g of Fe2O3

2Al + Fe2O3 Al2O3 + 2Fe

Calculate the mass of Al2O3 formed.

g Al mol Al mol Fe2O3 needed g Fe2O3 needed

OR

g Fe2O3 mol Fe2O3 mol Al needed g Al needed

Page 26: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

In one process, 124 g of Al are reacted with 601 g of Fe2O3

2Al + Fe2O3 Al2O3 + 2Fe

Calculate the mass of Al2O3 formed.

g Al mol Al mol Fe2O3 needed g Fe2O3 needed

OR

g Fe2O3 mol Fe2O3 mol Al needed g Al needed

124 g /26.98 gmol-1

= 4.60 mol

601 g /159.688 gmol-1

= 3.76 mol

4.60/2 = 2.30 mol

3.76x2 = 7.52 mol

Page 27: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Mass Relationships in Chemical Reactions

Theoretical Yield is the amount of product that wouldresult if all the limiting reagent reacted.

Actual Yield is the amount of product actually obtainedfrom a reaction.

% Yield = Actual Yield

Theoretical Yield

x 100

Page 28: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Glass transition

Page 29: Aula #03 · Aula #03. Dalton’s Atomic Theory 2. 16 X + 8 Y 8 X 2 Y Proportion /relation between matter . atomic radius ~ 100 pm = 1 x 10-10 m nuclear radius ~ 5 x 10-3 pm = 5 x

Liquid Nitrogen

Liquid nitrogen is

nitrogen in a liquid state at an extremely low temperature.

It is a colorless liquid with a density of 0.807 g/ml at

its boiling point (−195.79 °C (77 K; −320 °F))

Liquid nitrogen

liquid nitrogen can be stored and transported,

for example in vacuum flasks.