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Automation and Drives
SIRIUS SCSolid StateSwitching DevicesSIRIUS SC
Solid State Switching Devices
How Do I Select the Right Heat Sink for my Solid State Relay?
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Starting conditions
Solid state relay selection
Power loss and permissible RthHS
1
2
3
4
Theoretical ApproachTheoretical Approach
Load current
Max. ambient temperature
Heat sink assembly conditions
Selection of the solid state relay on the basis of the load current.
Determination of the power loss Ploss and the permissible thermal resistance RthHS on the basis of the diagram contained in the solid state relay‘s data sheet.
Determination of the total power loss Ploss total and the permissible RthHS total for cases where several relays are applied on a single heat sink.
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Actual RthHS
smaller than perm. RthHS
Heat sink selection
Determination of the actual RthHS
4
5
YES
4
NO
Completed
6
Theoretical ApproachTheoretical Approach
Heat sink selection from a heat sink manufacturer‘s data sheet on the basis of the total power loss and the permissible RthHS total.
Determination of the actual RthHS on the basis of the diagram contained in the heat sink‘s data sheet with a given power loss.
Verification whether the heat sink‘s actual RthHS is smaller than the permissible thermal resistance. If this value is not smaller, continue with the selection to verify a different heat sink. If no suitable heat sink is available, continue with step to try a larger solid state relay.2
The heat sink for this application has been correctly dimensioned.
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1
2
3
4
5
6
1 2 3 4 5 6
6 x 5 K/W 1 x 0.83 K/W
Theoretical ApproachTheoretical Approach
Capacity of heat sinks
The RthHS value reflects the heat sink‘s capacity, i.e. the heat sink‘s Kelvin temperature increase per power loss in Watt.
Example: One heat sink with 4 K/W increases its temperature by 80 K at 20 Watt.One heat sink with 1 K/W increases its temperature by 20 K at 20 Watt.
High RthHS value = inferior heat sink Small RthHS value = superior heat sink
Application of several solid state relays on one heat sink
If, for example, six relays are to be mounted on one heat sink, a heat sink which provides the capacity of six small heat sinks is required.
E.g.: Per relay: Ploss = 14 W, RthHS = 5 K/W = 14 W x 5 K/W = 70 K.With 6 relays: = 70 K, Ploss total = 84 W RthHS = 70 K / 84 W = 0.83 K/W. Or more simple: RthHS divided by the number of relays = 5 K/W / 6 = 0.83 K/W.
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11stst Example Example
Starting conditions
Solid state relay selection
1
2
3
6 heating cartridges 230 V / 8 A each
24 V DC control voltage
Max. ambient temperature of 45°C
Space for heat sinks:Height: max. 120 mm = long heat sinksDepth: max. 80 mm = tall heat sinks
Width: any
On the basis of the given conditions, six 3RF2120-1AA02 items are selected.
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11stst Example Example
Power loss and permissible RthHS
3
2 6 10 14 18 22Ie in A
1,0 K/W
1,3 K/W
1,7 K/W
2,4 K/W
3 K/W
4 K/W5 K/W6 K/W8 K/W10 K/W
0
5
10
15
20
25
30
35
40
0 10 20 30 40 50 60Ta in °C
PM
in W
approx. 8,5 K/W
4
3RF2020-.
On the basis of the diagram, a power loss of 8 W per solid state relay is determined at 8 A.
With this power loss and a maximum ambient temperature of 45°C, a maximum thermal resistance RthHS of 8.5 K/W per relay can be determined.
Ploss total: 6 x 8 = 48 W
RthHS total: 8.5 / 6 = 1.41 K/W
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Heat sink selection
Determination of the actual RthHS
4
5
6
11stst Example Example
Heat sink selected from www.alutronic.de: PR131/100/SE (100x100x50)at Ploss = 40 W RthHS of 1.49 K/W
Based on the diagram contained on the heat sink‘s data sheet, a of 70 K can be determined at Ploss = 48 W. This results in:RthHS = 70 K / 48 W = 1.46 K/W
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Actual RthHS
smaller than perm. RthHS
4
NO6
Heat sink selection
4
5
11stst Example Example
The actual RthHS of 1.46 K/W is higher than the permissible RthHS of 1.41 K/W.
Heat sink not suitable!!
Selection of new heat sink
Heat sink selected from www.alutronic.de: PR211/100/SE (100x111.5x67.5 sw anodized)at Ploss = 40 W RthHS of 1.07 K/W
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Determination of the actual RthHS
Actual RthHS
smaller than perm. RthHS
5
YES
Completed
6
11stst Example Example
Based on the diagram contained on the heat sink‘s data sheet, a of 50 K can be determined at Ploss = 48 W. This results in: RthHS = 50 K / 48 W = 1.04 K/W
The actual RthHS of 1.04 K/W is smaller than the permissible RthHS of 1.41 K/W.
The heat sink is suitable !!As the actual RthHS is considerable smaller than the permissible value, the heat sink manufacturer can be consulted to determine whether he recommends a bare heat sink or whether a special length of 80 mm is also sufficient.
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22ndnd Example Example
Starting conditions
Solid state relay selection
1
2
3
30 heating cartridges 230 V / 4.5 A each
3 heating cartridges each are switched via one solid state relay
Control voltage 24 V DC
Max. ambient temperature 40°C
Space for heat sinks:Height max. 120 mm = long heat sinksDepth max. 100 mm = tall heat sinks
Width min. 230 mm
On the basis of the given conditions, ten 3RF2120-1AA02 items are selected.
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22ndnd Example Example
Power loss and permissible RthHS
3
2 6 10 14 18 22Ie in A
1,0 K/W
1,3 K/W
1,7 K/W
2,4 K/W
3 K/W
4 K/W5 K/W6 K/W8 K/W10 K/W
0
5
10
15
20
25
30
35
40
0 10 20 30 40 50 60Ta in °C
PM
in W
approx. 4,0 K/W
4
3RF2020-.
On the basis of the diagram, a power loss of 16.5 W per solid state relay is determined at 13.5 A.
With this power loss and a maximum ambient temperature of 40°C, a maximum thermal resistance RthHS of 4.0 K/W per relay can be determined.
Ploss total : 10 x 16.5 = 165 W
RthHS total : 4.0 / 10 = 0.40 K/W
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Heat sink selection
Determination of the actual RthHS
4
5
6
22ndnd Example Example
Heat sink selected from www.alutronic.de: PR237/100/SE (100x250x83)at Ploss 160 W RthHS of 0.46 K/W
Based on the diagram contained on the heat sink‘s data sheet, a of 78 K can be determined at Ploss = 165 W. This results in: RthHS = 78 K / 165 W = 0.47 K/W
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Actual RthHS
smaller than perm. RthHS
4
NO6
22ndnd Example Example
Solid state relay selection
2
3
The actual RthHS of 0.47 K/W is higher than the permissible RthHS of 0.40 K/W.
The heat sink is not suitable !!
Selection of new heat sink?
As a heat sink with an increased capacity cannot be applied due to spatial reasons, solid state relays with increased capacity should be selected as they can cope with poorer RthHS values.
On the basis of the given conditions, ten 3RF2130-1AA02 items are selected.
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6 10 14 18 22 26 30 34Ie in A
0,3 K/W
0,5 K/W
0,79 K/W
1,25 K/W
2 K/W
3 K/W4 K/W5 K/W7 K/W10 K/W
0
10
20
30
40
50
60
0 10 20 30 40 50 60Ta in °C
PM
in W
22ndnd Example Example
Power loss and permissible RthHS
3
approx. 5,0 K/W
4
3RF2030-.
On the basis of the diagram, a power loss of 14 W per solid state relay is determined at 13.5 A.
With this power loss and a maximum ambient temperature of 40°C, a maximum thermal resistance RthHS of 5.0 K/W per relay can be determined.
Ploss total : 10 x 14 = 140 W
RthHS total : 5.0 / 10 = 0.50 K/W
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Heat sink selection
Determination of the actual RthHS
4
5
6
22ndnd Example Example
The same heat sink is once more selected from www.alutronic.de: PR237/100/SE (100x250x83)at Ploss 160 W RthHS of 0.46 K/W
Based on the diagram contained on the heat sink‘s data sheet, a of 68 K can be determined at Ploss = 140 W. This results in:RthHS = 68 K / 140 W = 0.485 K/W
Automation and Drives
SIRIUS SC Solid State Switching Devices A&D CD CC PM4 14.05.04 16
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Actual RthHS
smaller than perm. RthHS
6
22ndnd Example Example
YES
Completed
The actual RthHS of 0.485 K/W is smaller than the permissible RthHS of 0.50 K/W.
The heat sink is suitable!!
Caution:Caution:It must be assured that the power loss emitted to the ambient It must be assured that the power loss emitted to the ambient air by the heat sink in the form of heat is transported out of the air by the heat sink in the form of heat is transported out of the control cabinet. Otherwise, the temperature within the control control cabinet. Otherwise, the temperature within the control cabinet would exceed the maximum value and the solid state cabinet would exceed the maximum value and the solid state switching devices would be destroyed.switching devices would be destroyed.