basic electrical & electronics lab department of … · 2013. 10. 6. · q2 2n3904 q1 2n3904 rl...
TRANSCRIPT
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 1
THIRD SEMESTER
ELECTRONICS - II
BASIC ELECTRICAL & ELECTRONICS LAB
DEPARTMENT OF ELECTRICAL ENGINEERING
Prepared By: Checked By: Approved By:
Engr. Saqib Riaz Engr. M.Nasim Khan Dr.Noman Jafri
Lecturer (Lab) Senior Lab Engineer Dean Electrical Department
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 2
Name: ____________________________________________
Registration No: ____________________________________
Semester: _________________________________________
Batch: ____________________________________________
FEDERAL URDU UNIVERSITY OF ARTS, SCIENCE & TECHNOLOGY
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 3
PRACTICAL LIST
S.NO. PRACTICAL NAME
01 Verification of the calculated value of a BJT amplifier
02 Implementation of OR gate using BJT’s
03 Determination of Input-offset voltage of LM-741
04 Implementation of the Buffer/Non-Inverting Amplifier using LM-741
05 Implementation of the Inverting Amplifier using LM-741
06 Implementation of the Summing Amplifier using LM-741
07 Frequency Response of Active Low Pass Filter
08 Frequency Response of Active High Pass Filter
09 Plot the Drain Characteristics of a JFET
10 Plot the Transfer Characteristics of a JFET
11 JFET Self Biased Network
12 JFET Voltage Divider Bias Network
13 Implementation of Common Source Amplifier using JFET
14 Implementation of Common Drain Amplifier using JFET
15 A-stable Operation of a 555 Timer
16 Mono-stable Operation of a 555 Timer
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 4
C2
10uF
1kHz
V2-1m/1mV
+
Vcc
12V
C1
10uF
Q1
2N3904RL 1k
RC 3kRB 57k
Experiment # 01
VERIFICATION OF THE CALCULATED VALUES OF A BJT AMPLIFIER
OBJECTIVE:
Understand and analyze the operation of common-emitter amplifiers.
APPARATUS:
• BJT (2N3904) • AC/DC POWER SUPPLY • BREAD BOARD • CAPACITORS 10UF • RESISTORS 57K, 3K • MULTIMETER • CONNECTING WIRES
INITIAL CONDITIONS:
IC = 2mA & VCE= VCC/2
CIRCUIT DIAGRAM:
Common Emitter Amplifier
PROCEDURE:
1. Connect the circuit as shown in circuit diagram 2. Use the multimeter to find out the type of transistor and the value of beta. 3. Set the initial condition for the circuit and calculate the value of Rc and RB.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 5
4. Use the following relationship RC= (VCC-VCE)/IC
RB= (VCC-VBE)/IB
IC= βIB
5. Measure the Output Voltage Vo (p-p) for different values of input voltage Vin (p-p). 6. All the readings are tabulated and voltage gain in dB is calculated by using the expression
Av=20 log10 (V0/V i)
CALCULATIONS:
Table No. 01:
S. No. Red Wire (+) Black Wire (-) Voltage
1 A B
2 B A
3 A C
4 C A
5 B C
6 C B
From voltage table:
Side A is __________ Side B is _________ Side C is _________
Transistor is __________.
Table No. 02:
Calculated Values Actual Values
RB RC RB RC
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 6
Table No. 03:
Input Signal
Output Signal
Gain
AV=(V0/V i)
Gain in dB
Av=20log10 (V0/V i)
Input Signal 01
Output Signal 01
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 7
Input Signal 02
Output Signal 02
Input Signal 03
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 8
Output Signal 03
OBSERVATIONS:
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 9
+VBB2 0/5V
+VBB1 0/5V
+VCC 5V
Q22N3904
Q12N3904
RL 10k
RE2 100RE1 100
RC2 1k
RBB2
100k
RC1 1k
RBB1
100k
Experiment # 02
IMPLEMENTATION OF OR GATE USING BJT’S
OBJECTIVE:
Understand the working of digital OR gate. See how the truth table is constructed & also understand the outputs of the OR gate. APPARATUS:
• BJT (2N3904) • DC POWER SUPPLY • BREAD BOARD • LED’s (Red & Green) • RESISTORS 10K, 1K, 10K & 3.3K • MULTIMETER • CONNECTING WIRES
CIRCUIT DIAGRAM:
OR Gate using BJT’s
PROCEDURE:
1. Construct the circuit as shown above. 2. Clearly mark the inputs and outputs of the circuit 3. Apply the different possible combinations of the inputs to the circuit. 4. Construct the truth table for the inputs as well as for the outputs. 5. Verify the operation of the lab circuit.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 10
Truth Table for an OR gate:
Input A Input B Output Y
Table of results from the circuit:
Vin1 Vin2 Vout
Question: Draw the circuit diagram of AND gate using BJT’s? Also make truth table for it.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 11
OBSERVATIONS:
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
_______________________.
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 12
EXPERIMENT # 03
DETERMINATION OF INPUT-OFFSET VOLTAGE OF OPAMP
LM 741
OBJECTIVE:
To sketch and briefly explain an operational amplifier circuit symbol and identify all terminals. To understand the pin configurations, specifications & functioning of LM741 opamp used in the practical applications. To reduce the offset voltage zero at the output.
APPARATUS:
• OPAMP LM741 • RESISTORS 100K • DC POWER SUPPLY (+15,-15) • MULTIMETER • CONNECTING WIRES
PIN CONFIGURATION OF LM741 OPAMP:
SPECIFICATIONS:
1. Supply voltage:
µA 741A, µA 741, µA 741E ---------------- ±22V
µA 741C ---------------- ±18 V
2. Internal power dissipation
DIP package ----------------- 310 mw.
3. Differential input voltage ---------------- ±30 V.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 13
Vout
+V2 15V
+V1 15V
+U1
UA741
R3
100k
R2100k
R1100k
4. Operating temperature range
Military (µA 741A, µA 741) --------------- -550 to +1250 C.
Commercial (µA 741E, µA 741C) --------- 00 C to +700 C.
5. Input offset voltage ------------ 1.0 mV.
6. Input Bias current ------------ 80 nA.
7. PSSR --------------30µV/V.
8. Input resistance -------------2MΩ.
9. CMMR --------------90dB.
10. Output resistance ---------------75Ω.
11. Bandwidth --------------1.0 MHz.
12. Slew rate ---------------0.5 V/µ sec.
CIRCUIT DIAGRAM 1:
PROCEDURE:
1. Connect the circuit as shown in the figure (1). 2. Make both the inputs inverting as well as non-inverting to ground. 3. Make sure that you have powered the chip with the dual power supply. 4. Measure the DC output voltage at pin 6 using multimeter and record the result in table 1. 5. Calculate the input offset voltage using the formula and record the value in table 1.
Vin = Vout/Av
6. Replace the 100 K resistance with 220 K and repeat the above steps.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 14
Vout
+V
R4 10k 40%
+U2
UA748
+V2 15V
+V1 15V
R3
100k
R2100k
R1100k
R4 10k 40%
Table 1:
Resistance Vout Vin
100 K
220 K
Elimination of the OFFSET voltage:
1. Connect the circuit as shown in the figure (2). 2. To eliminate this offset voltage connects the stationary ends of 5K potentiometer between pin 1 & 5. 3. Use the pot, to zero the output of the amplifier this is how the offset voltage is eliminated. 4. In your experiment due to pot sensitivity, you may not get a full zero volt output. A 10
mV at the output will be sufficient. 5. Record the reading of voltage drop across the variable resistance that makes output zero
in the following table 2.
CIRCUIT DIAGRAM 2:
Table 2:
Vin Vr Vout
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 15
OBSERVATIONS:
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
_______________________.
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 16
1kHz
V3-2/2V
+V2 15V
+V1 15V
+U1
UA741
RL 10k
EXPERIMENT # 04
IMPLEMENTATION OF NON-INVERTING/BUFFER AMPLIFIER BY USING LM741
OBJECTIVE:
Understand the op-amp as a voltage follower or buffer. Analyze the non-inverting configuration & understand the closed loop gain.
APPARATUS:
• OP-AMP IC LM741 • RESISTOR 22K & 100K • AC/DC POWER SUPPLIES • OSCILLOSCOPE • CONNECTING WIRES
CIRCUIT DIAGRAM:
PROCEDURE:
1. Construct the buffer amplifier circuit as shown in the figure. 2. Connect AC input signal at the non-inverting end of the amplifier i.e +ve end. 3. Use the oscilloscope to observe the input as well as the output signal. 4. Compute the voltage gain by the following formula.
AV = VOUT/V IN = 1 + RF/RIN
5. Sketch the observed input & output waveforms.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 17
Calculations:
Table
Input Signal (VP-P)
Output Signal (VP-P)
Calculated Voltage Gain
AV
Measured Voltage Gain
AV
Difference
Calculation of the waveform:
input Signal
Output Signal
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 18
1kHz
V3-2/2V
+V2 15V
+V1 15V
+U1
UA741
RL 10k
Rf
100kRin 22k
CIRCUIT DIAGRAM:
PROCEDURE:
1. Construct the non-inverting amplifier circuit as shown in the above figure. 2. Connect AC input signal at the non-inverting end of the amplifier i.e +ve end. 3. Use the oscilloscope to observe the input as well as the output signal. 4. Compute the voltage gain by the following formula.
AV = VOUT/V IN = 1 + RF/RIN
5. Sketch the observed input & output waveforms. Calculations:
Table
Input Signal (VP-P)
Output Signal (VP-P)
Calculated Voltage Gain
AV
Measured Voltage Gain
AV
Difference
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 19
Input Signal
Output Signal
OBSERVATIONS:
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 20
1kHz
V3-2/2V
+V2 15V
+V1 15V
+U1
UA741
Rin
22k
RL 10k
Rf
100k
Rin
22k
EXPERIMENT # 05
IMPLEMENTATION OF INVERTING AMPLIFIER BY USING LM741
OBJECTIVE:
Analyze the inverting configuration & understand the voltage gain.
APPARATUS:
• OP-AMP IC LM741 • RESISTOR 22K & 100K • AC/DC POWER SUPPLIES • OSCILLOSCOPE • CONNECTING WIRES
CIRCUIT DIAGRAM:
PROCEDURE:
1. Construct the inverting amplifier circuit as shown in the figure. 2. Connect AC input signal at the inverting end of the amplifier i.e -ve end. 3. Use the oscilloscope to observe the input as well as the output signal. 4. Compute the voltage gain by the following formula.
AV = VOUT/V IN = - RF/RIN
5. Sketch the observed input & output waveform
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 21
Calculations:
Table:
Input Signal (VP-P)/Freq.
Output Signal (VP-P)/Freq.
Calculated Voltage Gain
AV
Measured Voltage Gain
AV
Difference
Input Signal
Output Signal
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 22
Input Signal
Output Signal
OBSERVATIONS:
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 23
1kHz
V4-1/1V
1kHz
V3-1/1V
+V2 15V
+V1 15V
+U1
UA741
RL 10k
Rin1
22k
Rf
50k
Rin
22k
EXPERIMENT # 06
IMPLEMENTATION OF SUMMING INVERTING AMPLIFIER BY USING LM741
OBJECTIVE:
Analyze the operation of summing amplifiers & how to achieve any specified gain
greater than unity
APPARATUS:
• OP-AMP IC LM741 • RESISTOR 10K, 22K & 100K • AC/DC POWER SUPPLIES • OSCILLOSCOPE • CONNECTING WIRES
CIRCUIT DIAGRAM:
Summing Inverting Amplifier
PROCEDURE:
1. Construct the summing inverting amplifier circuit as shown in the figure. 2. Connect at least two AC input signal at the inverting end of the amplifier i.e -ve end. 3. Use the oscilloscope to observe the input as well as the output signal. 4. Compute the voltage gain by the following formula.
AV = VOUT/V IN = - Rf/Rin1+Rf/Rin2
5. Sketch the observed input & output waveforms.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 24
Calculations:
Table:
Input Signal (VP-P)/Freq.
Output Signal (VP-P)/Freq.
Calculated Voltage Gain
AV
Measured Voltage Gain
AV
Difference
Vin1
Vin2
Calculation of the waveform:
Input Signal 1
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 25
Input Signal 2
Output Signal
OBSERVATIONS: ______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 26
C1 .1uF
1kHz
V4-1/1V
+V2 15V
+V1 15V
+U1
UA741
Rin 22k
RL 10k
R1
10k
Rf
100k
1kHz
V4-1/1V
EXPERIMENT # 07
FREQUENCY RESPONSE OF ACTIVE LOW PASS FILTER OBJECTIVE:
Describe the gain-versus-frequency responses of the basic filters & explain the low-pass
response.
APPARATUS:
• OP-AMP IC LM741 • RESISTOR 10K, 22K & 100K • AC/DC POWER SUPPLIES • OSCILLOSCOPE • CONNECTING WIRES
CIRCUIT DIAGRAM:
Active Low Pass Filter
PROCEDURE:
1. Construct the active low pass filter circuit as shown in the figure. 2. Connect AC input signal at the non-inverting end of the amplifier i.e +ve end. 3. Use the oscilloscope to observe the input as well as the output signal. 4. Increase the input signal frequency in steps from 1KHz to 1MHz & Observe the
corresponding output voltage of the filter and tabulate the results. 5. Compute the voltage gain by the following formula.
AV = VOUT/V IN = (AF)/√1+(f/fc)2
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 27
Where, AF= the pass band gain of the filter (1+Rf/Rin) f = the frequency of the input signal fc = the cut-off frequency (fc=1/2πRC)
6. Plot the frequency response curve of the low pass filter with the experimental results
obtained & compare it with the expected waveform.
Table:
Input Frequency(Fin)
in Hz
V in
Input volatage in volts
Vout
Output Voltage
in volts
GAIN
Vout / Vin 20 Log (Vout / Vin) Magnitude in dB
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 28
Calculation of the waveform:
Output Signal Frequency vs Gain in dB
OBSERVATIONS: ______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 29
C1.1uF
10 Hz
V4-1/1V
+V2 15V
+V1 15V
+U1
UA741
Rin 22k
RL 10kR1 10k
Rf
100k
EXPERIMENT # 08
FREQUENCY RESPONSE OF ACTIVE HIGH PASS FILTER OBJECTIVE:
Explain the high-pass response & determine the critical frequency of a high-pass filter.
APPARATUS:
• OP-AMP IC LM741 • RESISTOR 10K, 22K & 100K • AC/DC POWER SUPPLIES • OSCILLOSCOPE • CONNECTING WIRES
CIRCUIT DIAGRAM:
Active High Pass Filter
PROCEDURE:
1. Construct the active high pass filter circuit as shown in the figure. 2. Connect AC input signal at the non-inverting end of the amplifier i.e +ve end. 3. Use the oscilloscope to observe the input as well as the output signal. 4. Increase the input signal frequency in steps from 1KHz to 1MHz & Observe the
corresponding output voltage of the filter and tabulate the results. 5. Compute the voltage gain by the following formula.
AV = VOUT/V IN = AF(f/fc)/√1+(f/fc)2
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 30
Where, AF= the pass band gain of the filter (1+Rf/Rin) f = the frequency of the input signal fc = the cut-off frequency (fc=1/2πRC)
6. Plot the frequency response curve of the low pass filter with the experimental results
obtained & compare it with the expected waveform.
Table:
Input Frequency(Fin)
in Hz
V in
Input volatage in volts
Vout
Output Voltage
in volts
GAIN
Vout / Vin 20 Log (Vout / Vin) Magnitude in dB
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 31
Calculation of the waveform:
Output Signal Frequency vs Gain in dB
OBSERVATIONS: ______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 32
Rs 470 ohm
+VDD10V
+VGS 0V,-2V
Rd
1k
Rg
1M
Q12N5457
EXPERIMENT # 09
PLOT THE DRAIN CHARACTERISTICS OF JFET OBJECTIVE:
Explain ohmic area, constant current area and breakdown. Also explain pinch-off voltage.
APPARATUS:
• JFET KS-192 • RESISTOR 1K & 1M • DC POWER SUPPLIES • MULTIMETER • CONNECTING WIRES
CIRCUIT DIAGRAM:
PROCEDURE:
1. Construct the circuit diagram as shown above. 2. Set VGS=0V & measured ID=VRD/RD. 3. As VGS=0V, therefore the resulting drain current is IDSS with VGS=0V. 4. Slowly increase VDD to 3V & measure VDS and ID. 5. Increase VDD to 6V & measure VDS and ID. 6. Take couple of more measurements by increasing the value of VDD. 7. Plot the resulting curve between VDS & ID. 8. Repeat the same procedure with VGS = -2V.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 33
Table for VGS = 0V:
VDD(V)
Calculated
ID(mA)
Measured
ID(mA)
VDS(V)
03
06
09
12
15
Table for VGS = -2V:
VDD(V)
Calculated
ID(mA)
Measured
ID(mA)
VDS(V)
03
06
09
12
15
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 34
Calculations:
VDS vs ID
OBSERVATIONS: ______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 35
Rs 470 ohm
+VDD10V
+VGS 0V,-2V
Rd
1k
Rg
1M
Q12N5457
EXPERIMENT # 10
PLOT THE TRANSFER CHARACTERISTICS OF JFET OBJECTIVE:
Analyze a JFET transfer characteristic curve & Use the equation for the transfer
characteristic to calculate ID also calculate transconductance.
APPARATUS:
• JFET KS-192 • RESISTOR 1K & 1M • DC POWER SUPPLIES • MULTIMETER • CONNECTING WIRES
CIRCUIT DIAGRAM:
PROCEDURE:
1. Construct the circuit diagram as shown above. 2. Set VGS=0V & VDD = 10V at this point measure the drain current ID. 3. Slowly increase VGS to -1V & VDD = 10V measure ID. 4. Take couple of more measurements by increasing the value of VGS. 5. Measures drain current & transconductance by using following equation.
ID = IDSS (1 – VGS/VGS (off)) 2……………. (1) gm = ∆ID/∆VGS ……………. (2)
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 36
Table for VDD = 10V:
VGS(V) Measured
ID(mA)
0
-1
-2
-3
-4
-5
Calculations:
VGS vs ID
OBSERVATIONS: ______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 37
+ VDD15VQ1
2N5457
RS220
RD1k
RG 10M
EXPERIMENT # 11
JFET SELF BIASED NETWORK OBJECTIVE:
Analyze JFET bias circuits & self-biased JFET circuit. Set the self-biased Q-point
APPARATUS:
• JFET KS-192 • RESISTOR 1K, 220Ω & 10M • DC POWER SUPPLIES • MULTIMETER • CONNECTING WIRES
CIRCUIT DIAGRAM:
PROCEDURE:
1. Construct the circuit diagram as shown above. 2. Set VGS=0V & VDD = 15V at this point measure the drain current ID. 3. Slowly decrease the value of VDD = 10V measure ID. 4. Take couple of more measurements by decreasing the value of VDD. 5. Calculate VS by the following formula:
VS = IDRS
6. Calculate drain-source voltage by the following formula. VDS = VDD – ID (RD+RS)
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 38
Table at VGS = 0V:
Drain Voltage
VDD
Drain Current
Measured
ID
Calculated Source Voltage
VS
Calculated Drain-Source
Voltage
VDS
Measured Drain-Source Voltage
VDS
15
10
5
3
Calculations:
VGS vs ID
OBSERVATIONS:
______________________________________________________________________________
______________________________________________________________________________
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 39
+ VDD15VQ1
2N5457
RS2.2k
RD3.3k
R2 1M
R1 6.8M
EXPERIMENT # 12
JFET VOLTAGE DIVIDER BIASED NETWORK OBJECTIVE:
Analyze JFET bias circuits & the effect of parallel resistance on JFET circuit.
APPARATUS:
• JFET KS-192 • RESISTOR 1M, 2.2K, 3.3K & 10M • DC POWER SUPPLIES • MULTIMETER • CONNECTING WIRES
CIRCUIT DIAGRAM:
PROCEDURE:
1. Construct the circuit diagram as shown above. 2. Set VGS=0V & VDD = 15V at this point measure the drain current ID. 3. Calculate VS by the following formula:
VS = IDRS
4. Calculate gate voltage VG & VGS by the following formula: VG = (R2/ (R1 + R2)) * VDD
VGS = VG - VS
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 40
Table at VGS = 0V:
Gate-Source Voltage
VGS
Drain Voltage
VDD
Drain Current
Measured
ID
Calculated Source Voltage
VS
Calculated Gate Voltage
VDS
Calculated Gate-Source
Voltage
VGS
0 15
OBSERVATIONS: ______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 41
+ V210V
1kHz
V1-1/1V
C3 10uF
C2
1uF
C1
0.01uF
Q12N5457
RL 10k
RS 1k
RD 2.2k
R11k
EXPERIMENT # 13
COMMON SOURCE AMPLIFIER OF JFET OBJECTIVE:
Explain and analyze the operation of common-source FET amplifiers.
APPARATUS:
• JFET KS-192 • RESISTOR 1M, 2.2K, 1K & 10K • CAPACITOR 0.01uF, 1uF & 10uF • AC/DC POWER SUPPLIES • MULTIMETER • CONNECTING WIRES
CIRCUIT DIAGRAM:
PROCEDURE:
1. Construct the circuit diagram as shown above. 2. Set VIN=1Vp-p & VDD = 12V. 3. Measure the Output Voltage Vo (p-p) for different values of input voltage Vin (p-p). 4. Voltage gain of the common source amplifier is given by:
AV = gm RD 5. The output signal voltage VDS at the drain is:
Vout = VDS = AVVGS
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 42
Table :
Input Signal
Output Signal
Gain
AV=(V0/V i)
Gain in dB
Av=20log10 (V0/V i)
Calculation of the waveform:
Input Signal 01
Output Signal 01
Output Signal 01
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ELECTRONICS-II 43
Input Signal 02
Output Signal 02
OBSERVATIONS:
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 44
+ V210V
100kHz
V1-1/1V
C3
1uF
C1
0.01uF
Q12N5457
RL 10k
RS 1k
RD 2.2k
R11k
EXPERIMENT # 14
COMMON DRAIN AMPLIFIER OF JFET OBJECTIVE:
Explain and analyze the operation of common-drain FET amplifiers.
APPARATUS:
• JFET KS-192 • RESISTOR 1M, 2.2K, 1K & 10K • CAPACITOR 0.01uF & 10uF • AC/DC POWER SUPPLIES • MULTIMETER • CONNECTING WIRES
CIRCUIT DIAGRAM:
PROCEDURE:
1. Construct the circuit diagram as shown above. 2. Set VIN=1Vp-p & VDD = 12V. 3. Measure the Output Voltage Vo (p-p) for different values of input voltage Vin (p-p). 4. Voltage gain of the common source amplifier is given by:
AV = gm RS / 1 + gm RS
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Table :
Input Signal
Output Signal
Gain
AV=(V0/V i)
Gain in dB
Av=20log10 (V0/V i)
Calculation of the waveform:
Input Signal 01
Output Signal 01
Input Signal 01
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ELECTRONICS-II 46
IntPut Signal 02
Output Signal 02
Output Signal 02
OBSERVATIONS:
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
Federal Urdu University of Arts, Science & Technology Islamabad – Pakistan Electrical Engineering
ELECTRONICS-II 47
EXPERIMENT # 15
A-STABLE OPERATION OF 555 TIMER OBJECTIVE:
To investigate the operation of 555 timer in the A-Stable mode
APPARATUS:
• LM 555 • RESISTORS • CAPACITORS • DC POWER SUPLLY • DIGITAL MULTIMETER • OSCILLOSCOPE
OPERATION:
A-stable circuit produces a 'square wave’; this is a digital waveform with sharp transitions between low (0V) and high (+Vs). Note that the durations of the low and high states may be different. The circuit is called an A-stable because it is not stable in any state the output is continually changing between 'low' and 'high'.
The time period (T) of the square wave is the time for one complete cycle, but it is usually better to consider frequency (f) which is the number of cycles per second.
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T = time period in seconds (s) f = frequency in hertz (Hz) R1 = resistance in ohms (Ω)
T = 0.7 × (R1 + 2R2) × C1 and f = 1.4 (R1 + 2R2) × C1 R2 = resistance in ohms ( ) C1 = capacitance in farads (F) The time period can be split into two parts: T = Tm + Ts
Mark time: (output high): Tm = 0.7 × (R1 + R2) × C1 Space time: (output low): Ts = 0.7 × R2 × C1
Many circuits require Tm and Ts to be almost equal; this is achieved if R2 is much larger than R1. For a standard a-stable circuit Tm cannot be less than Ts, but this is not too restricting because the output can both sink and source current. For example an LED can be made to flash briefly with long gaps by connecting it (with its resistor) between +Vs and the output.
This way the LED is on during Ts, so brief flashes are achieved with R1 larger than R2, making Ts short and Tm long. Tm must be less than Ts a diode can be added to the circuit as explained under duty cycle below.
Choosing R1, R2 and C1:
R1 and R2 should be in the range 1k to 1M. It is best to choose C1 first because capacitors are available in just a few values.
Choose C1 to suit the frequency range you require (use the table as a guide). Choose R2 to give the frequency (f) you require. Assume that R1 is much smaller than
R2 (so that Tm and Ts are almost equal), then you can use:
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ELECTRONICS-II 49
R2 = 0.7 f × C1
Choose R1 to be about a tenth of R2 (1k min.) unless you want the mark time Tm to be
significantly longer than the space time Ts. If you wish to use a variable resistor it is best to make it R2. If R1 is variable it must have a fixed resistor of at least 1k in series (this is not required for R2 if it is variable). A-stable operation With the output high (+Vs) the capacitor C1 is charged by current flowing through R1 and R2. The threshold and trigger inputs monitor the capacitor voltage and when it reaches 2/3Vs (threshold voltage) the output becomes low and the discharge pin is connected to 0V.
The capacitor now discharges with current flowing through R2 into the discharge pin. When the voltage falls to 1/3Vs (trigger voltage) the output becomes high again and the discharge pin is disconnected, allowing the capacitor to start charging again.
This cycle repeats continuously unless the reset input is connected to 0V which forces the output low while reset is 0V. A-stable can be used to provide the clock signal for circuits such as counters.
A low frequency A-stable (< 10Hz) can be used to flash an LED on and off, higher frequency flashes are too fast to be seen clearly. Driving a loudspeaker or piezo transducer with a low frequency of less than 20Hz will produce a series of 'clicks' (one for each low/high transition) and this can be used to make a simple metronome. An audio frequency A-stable (20Hz to 20 kHz) can be used to produce a sound from a loudspeaker or piezo transducer. The sound is suitable for buzzes and beeps. The natural (resonant) frequency of most piezo transducers is about 3 kHz and this will make them produce a particularly loud sound.
OBSERVATIONS:
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.
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ELECTRONICS-II 50
EXPERIMENT # 16
MONOSTABLE OPERATION OF 555 TIMER OBJECTIVE:
To investigate the operation of 555 timer in the Mono-Stable mode
APPARATUS:
• LM 555 • RESISTORS • CAPACITORS • DC POWER SUPLLY • DIGITAL MULTIMETER • OSCILLOSCOPE
OPERATION:
A Mono-stable circuit produces a single output pulse when triggered. It is called a Mono-stable because it is stable in just one state: 'output low'. The 'output high' state is temporary. The duration of the pulse is called the time period (T) and this is determined by resistor R1 and capacitor C1: time period,
T = 1.1 × R1 × C1 T = time period in seconds (s) R1 = resistance in ohms (Ω) C1 = capacitance in farads (F) The maximum reliable time period is about 10 minutes. Why 1.1? The capacitor charges
to 2/3 = 67% so it is a bit longer than the time constant (R1 × C1) which is the time taken to charge to 63%.
Choose C1 first (there are relatively few values available). Choose R1 to give the time period you need. R1 should be in the range 1k to 1M, so use a
fixed resistor of at least 1k in series if R1 is variable. Beware that electrolytic capacitor values are not accurate; errors of at least 20% are common. Beware that electrolytic capacitors leak charge which substantially increases the time period if you are using a high value resistor - use the formula as only a very rough guide!
For example the Timer Project should have a maximum time period of 266s (about 4½ minutes), but many electrolytic capacitors extend this to about 10 minutes!
The timing period is triggered (started) when the trigger input (555 pin 2) is less than 1/3 Vs, this makes the output high (+Vs) and the capacitor C1 starts to charge through resistor R1. Once the time period has started further trigger pulses are ignored. The threshold input (555 pin 6) monitors the voltage across C1 and when this reaches 2/3 Vs the time period is over and the output becomes low. At the same time discharge (555 pin 7) is connected to 0V, discharging the capacitor ready for the next trigger. The reset input (555 pin 4) overrides all other inputs and the timing may be cancelled at any time by connecting reset to 0V, this instantly makes the output low and discharges the capacitor. If the reset function is not required the reset pin should be connected to +Vs.
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Power-on reset or trigger: It may be useful to ensure that a mono-stable circuit is reset
or triggered automatically when the power supply is connected or switched on. This is achieved by using a capacitor instead of (or in addition to) a push switch as shown in the diagram. The capacitor takes a short time to charge, briefly holding the input close to 0V when the circuit is switched on. A switch may be connected in parallel with the capacitor if manual operation is also required. This arrangement is used for the trigger in the Timer Project.
Edge-triggering: If the trigger input is still less than 1/3 Vs at the end of the
time period the output will remain high until the trigger is greater than 1/3 Vs. This situation can occur if the input signal is from an on-off switch or sensor. The Mono-stable can be made edge triggered, responding only to changes of an input signal, by connecting the trigger signal through a capacitor to the trigger input. The capacitor passes sudden changes (AC) but blocks a constant (DC) signal. For further information please see the page on capacitance. The circuit is 'negative edge triggered' because it responds to a sudden fall in the input signal. The resistor between the trigger (555 pin 2) and +Vs ensures that the trigger is normally high (+Vs).
OBSERVATIONS:
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
______________________________________________________________________________
Teacher’s Signature: ________________. Date: ___________________.
Teacher’s Name: Engr Saqib Riaz.