basic water properties ii

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  • 8/11/2019 Basic Water Properties II

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    MATERIAL/APPARATUS

    Gloves and goggles

    DPD Total Chlorine powder Pillow

    FerroVer Iron Reagent Powder Pillow

    DPD Free Chlorine Powder Pillow

    PhosVer 3 phosphate Powder Pillow

    ChromaVer 3 Reagent Powder Pillow

    SulfaVer 4 Reagent Powder Pillow

    Water sample

    Spectrophotometer

    Round Sample Cell Bottle

    PROCEDURES

    Total Chlorine:

    1. Fill a sample cell with 10 mL of sample. The contents of one DPD Total Chlorine Powder

    Pillow is added to the sample cell.

    2.

    The sample was swirling for 20 seconds.

    3. After that the instrument timer is started for three minutes. The blank preparation is

    perform at this time period.

    4.

    Blank Preparation:

    a.

    Fill a second sample cell with 10-mL of sample. Wipe the blank sample cell and insert

    it into the cell holder.

    b. ZERO the instrument. The display will show: 0.00 mg/L Cl2

    5. Within three minutes after the timer expires, wipe the prepared sample and insert it into the

    cell holder.

    6. The results are reading in mg/L Cl2.

    Free Chlorine:

    1.

    Fill a sample cell with 10 mL of sample.

    2. Blank Preparation:

    a. Fill a second sample cell with 10-mL of sample. Wipe the blank sample cell and insert

    it into the cell holder.

    b.

    ZERO the instrument. The display will show: 0.00 mg/L Cl2.

    3.

    Fill a second sample cell with 10-mL of sample. Add one 0.1 gram spoon of DPD Free

    Chlorine Powder Reagent to the sample cell. The sample was swirling to 20 seconds and a

    pink colour will form if chlorine is present.

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    4.

    Within one minute after the timer expires, wipe the prepared sample and insert it into the

    cell holder.

    5. The results are reading in mg/L Cl2.

    Total Iron:

    1. Fill a sample cell with 10 mL of sample. The content of one FerroVer Iron Reagent Powder

    Pillow is added to the sample cell.

    2.

    The sample was swirled for a seconds.

    3.

    After that the instrument timer is started for three minutes. An orange colour will form if

    iron is present. The blank preparation is perform at this time period.

    4. Blank Preparation:

    a.

    Fill a second sample cell with 10-mL of sample. Wipe the blank sample cell and insert

    it into the cell holder.

    b.

    ZERO the instrument.

    c. The display will show: 0.00 mg/L Fe.

    5. Within three minutes after the timer expires, wipe the prepared sample and insert it into the

    cell holder.

    6.

    The results are reading in mg/L Fe.

    Reactive Phosporus:

    1.

    Fill a sample cell with 10 mL of sample. The content of one PhosVer 3 phosphate Powder

    Pillow is added to the sample cell.

    2. The sample was immediately stopper and shaking vigorously for 30 seconds.

    3. After that the instrument timer is started for two minutes. The blank preparation is perform

    at this time period.

    4.

    Blank Preparation:

    a. Fill a second sample cell with 10-mL of sample. Wipe the blank sample cell and insert

    it into the cell holder.

    ZERO the instrument.

    b.

    The display will show: 0.00 mg/L PO4 3-.

    5.

    Within three minutes after the timer expires, wipe the prepared sample and insert it into the

    cell holder.

    6. The results are reading in mg/L PO4 3-.

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    Sulfate:

    1. Fill a sample cell with 10 mL of sample. The content of one SulfaVer 4 Reagent Powder Pillow

    is added to the sample cell.

    2.

    The sample was immediately swirled vigorously to dissolve the powder.

    3.

    After that the instrument timer is started for five minutes. The blank preparation is perform

    at this time period.

    4. Blank Preparation:

    a.

    Fill a second sample cell with 10-mL of sample. Wipe the blank sample cell and insert

    it into the cell holder.

    b. ZERO the instrument.

    c. The display will show: 0 mg/L SO4 2.

    5.

    Within three minutes after the timer expires, wipe the prepared sample and insert it into the

    cell holder.

    6.

    The results are reading in mg/L SO4 2.

    RESULTS

    The concentration of heavy metals in various water samples:

    Reagents

    Sample Water

    Drain Water Lake Water Tap Water Deionized Water

    Total Chlorine

    (0.02 mg/L2.0 mg/L)0.26 1.27 0.04 0.05

    Free Chlorine

    (0.02 mg/L2.0 mg/L)0.23 0.25 0.04 0.02

    Iron

    (0.02 mg/L-3.0 mg/L)1.43 0.10 0.02 0.15

    Sulfates

    (2.0 mg/L-7 mg/L)1.90 8.00 2.00 7.00

    Phosporus

    (0.02 mg/L- 2.50 mg/L)0.66 0.30 0.02 0.09

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    CALCULATION

    Total Chlorine:

    Sample Water Calculation

    Drain Water

    Concentration of Total Chlorine = 0.26 mg/LVolume of drain water = 10 mL /1000 = 0.01 L

    Mass of Total Chlorine = 0.26 mg/L x 0.01 L

    = 2.6 x 10-3mg

    Lake Water

    Concentration of Total Chlorine = 1.27 mg/L

    Volume of lake water = 10 mL /1000 = 0.01 L

    Mass of Total Chlorine = 1.27 mg/L x 0.01 L

    = 0.0127 mg

    Tap Water

    Concentration of Total Chlorine = 0.04 mg/L

    Volume of tap water = 10 mL /1000 = 0.01 L

    Mass of Total Chlorine = 0.04 mg/L x 0.01 L

    = 4.0 x 10-4

    mg

    Deionized Water

    Concentration of Total Chlorine = 0.05 mg/L

    Volume of deionized water = 10 mL /1000 = 0.01 L

    Mass of Total Chlorine = 0.05 mg/L x 0.01 L

    = 5.0 x 10-4mg

    Free Chlorine:

    Sample Water Calculation

    Drain Water

    Concentration of Free Chlorine = 0.23 mg/L

    Volume of drain water = 10 mL /1000 = 0.01 LMass of Free Chlorine = 0.23 mg/L x 0.01 L

    = 2.3 x 10-3

    mg

    Lake Water

    Concentration of Free Chlorine =0.25 mg/L

    Volume of lake water = 10 mL /1000 = 0.01 L

    Mass of Free Chlorine = 0.25 mg/L x 0.01 L

    = 2.5 x10-3

    mg

    Tap Water

    Concentration of Free Chlorine = 0.04 mg/L

    Volume of tap water = 10 mL /1000 = 0.01 L

    Mass of Free Chlorine = 0.04 mg/L x 0.01 L

    = 4.0 x 10-4

    mg

    Deionized Water

    Concentration of Free Chlorine = 0.02 mg/LVolume of deionized water = 10 mL /1000 = 0.01 L

    Mass of Free Chlorine = 0.02 mg/L x 0.01 L

    = 2.0 x 10-4

    mg

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    Iron:

    Sample Water Calculation

    Drain Water

    Concentration of Iron= 1.43 mg/L

    Volume of drain water = 10 mL /1000 = 0.01 L

    Mass of Iron = 1.43mg/L x 0.01 L= 0.0143 mg

    Lake Water

    Concentration of Iron = 0.10 mg/L

    Volume of lake water = 10 mL /1000 = 0.01 L

    Mass of Iron= 0.10 mg/L x 0.01 L

    = 0.001 mg

    Tap Water

    Concentration of Iron = 0.02 mg/L

    Volume of tap water = 10 mL /1000 = 0.01 L

    Mass of Iron= 0.02 mg/L x 0.01 L

    = 2.0 x 10-4

    mg

    Deionized Water

    Concentration of Iron = 0.15 mg/L

    Volume of deionized water = 10 mL /1000 = 0.01 LMass of Iron = 0.15 mg/L x 0.01 L

    = 1.5 x 10-3

    mg

    Sulfates:

    Sample Water Calculation

    Drain Water

    Concentration of Sulfates = 1.90 mg/L

    Volume of drain water = 10 mL /1000 = 0.01 L

    Mass of Sulfates = 1.90 mg/L x 0.01 L

    = 0.019 mg

    Lake Water

    Concentration of Sulfates = 8.00 mg/L

    Volume of lake water = 10 mL /1000 = 0.01 L

    Mass of Sulfates = 8.00 mg/L x 0.01 L

    = 0.08 mg

    Tap Water

    Concentration of Sulfates = 2.00 mg/L

    Volume of tap water = 10 mL /1000 = 0.01 L

    Mass of Sulfates = 2.00 mg/L x 0.01 L

    = 0.02 mg

    Deionized Water

    Concentration of Sulfates = 7.00 mg/L

    Volume of deionized water = 10 mL /1000 = 0.01 L

    Mass of Sulfates = 7.00 mg/L x 0.01 L= 0.07 mg

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    Phosporus:

    Sample Water Calculation

    Drain Water

    Concentration of Phosporus = 0.66 mg/L

    Volume of drain water = 10 mL /1000 = 0.01 L

    Mass of Phosporus = 0.66 mg/L x 0.01 L= 6.6 x 10

    -3mg

    Lake Water

    Concentration of Phosporus = 0.3 mg/L

    Volume of lake water = 10 mL /1000 = 0.01 L

    Mass of Phosporus = 0.3 mg/L x 0.01 L

    = 3 x 10-3

    mg

    Tap Water

    Concentration of Phosporus = 0.02 mg/L

    Volume of tap water = 10 mL /1000 = 0.01 L

    Mass of Phosporus = 0.02 mg/L x 0.01 L

    = 2.0 x 10-4

    mg

    Deionized Water

    Concentration of Phosporus= 0.09 mg/L

    Volume of deionized water = 10 mL /1000 = 0.01 LMass of Phosporus = 0.09 mg/L x 0.01 L

    = 9.0 x 10-4

    mg

    CONCLUSION

    At the end of this experiment, we had managed to determine the concentration of heavy

    metals; chlorine (free and total), phosphorus, iron, and phosphorus in different water samples; lake

    water, deionized water, tap water, and drain water. The concentration for total chlorine in drain

    water, lake water, tap water and deionized water are 0.26 mg/L, 1.27 mg/L, 0.04 mg/L and 0.05mg/L respectively. For the concentration for free chlorine in drain water, lake water, tap water and

    deionized water are 0.23 mg/L,0.25 mg/L,0.04 mg/L and 0.02 mg/L respectively. Besides, the

    concentration of Iron in drain water, lake water, tap water and deionized water are 1.43 mg/L,0.10

    mg/L,0.02 mg/L and 0.15 mg/L respectively. As for sulphates, their concentration in drain water, lake

    water, tap water and deionized water are 1.90 mg/L, 8.00 mg/L,2.00 mg/L and 7.00 mg/L

    respectively and lastly the concentration of phosphorus in drain water, lake water, tap water and

    deionized water are 0.66 mg/L,0.30 mg/L,0.02 mg/L and 0.09 mg/L respectively. According to the

    Malaysian Water Standard,

    Thus, it can be concluded that all the objectives of the experiment had been reached.