beam strength weight cost models s12

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1 Whitney Rectangular Stress Distribution The computation of flexural strength M n based on the approximately parabolic stress distribution shown in Figure 1 may be done using given values of k 2 /(k 1 k 3 ). However, it is desirable to have a simple method in which basic static equilibrium is used. Figure 1. Definition of Whitney Rectangular Stress Distribution In the 1930s, Whitney (1937) proposed the use of a rectangular compressive stress distribution to replace the parabolic stress distribution. As shown in Figure 1, an average stress of 0.85f' c is used with a rectangle of depth a = 1 c. Whitney determined that 1 should be 0.85 for concrete with f' c > 4,000 psi, and 0.05 less for each 1,000 psi of f' c in excess of 4,000 psi. The value of 1 may not be taken less than 0.65 (ACI 2008). The concrete below the neutral axis is ignored and the total tension force T is due the reinforcing steel. The Whitney stress block is used to esti- mate the compression force C. The bending strength M n using the equivalent rectangle is obtained from Figure 1 as follows: 0.85 c C f ba (1) sy T Af (2) where the use of f y is the yield stress of the steel reinforcement (assumes that the steel yields prior to crushing of the concrete). Equating C = T gives: 0.85 sy c Af a fb (3) The bending strength is computed as the tensile force multiplied by the distance between the forces, or: 2 n sy a M Af d (4) b h d A s T C c k 3 f’ c k 2 x T 0.85f’ c a C 0.5a

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  • 1

    Whitney Rectangular Stress Distribution The computation of flexural strength Mn based on the approximately parabolic stress distribution shown in Figure 1 may be done using given values of k2/(k1k3). However, it is desirable to have a simple method in which basic static equilibrium is used.

    Figure 1. Definition of Whitney Rectangular Stress Distribution In the 1930s, Whitney (1937) proposed the use of a rectangular compressive stress distribution to replace the parabolic stress distribution. As shown in Figure 1, an average stress of 0.85f'c is used with a rectangle of depth a = 1c. Whitney determined that 1 should be 0.85 for concrete with f'c > 4,000 psi, and 0.05 less for each 1,000 psi of f'c in excess of 4,000 psi. The value of 1 may not be taken less than 0.65 (ACI 2008). The concrete below the neutral axis is ignored and the total tension force T is due the reinforcing steel. The Whitney stress block is used to esti-mate the compression force C. The bending strength Mn using the equivalent rectangle is obtained from Figure 1 as follows:

    0.85 cC f ba (1)

    s yT A f (2) where the use of fy is the yield stress of the steel reinforcement (assumes that the steel yields prior to crushing of the concrete). Equating C = T gives:

    0.85s y

    c

    A fa

    f b (3)

    The bending strength is computed as the tensile force multiplied by the distance between the forces, or:

    2n s yaM A f d (4)

    b

    h d

    As

    T

    C c

    k3fc k2x

    T

    0.85fc

    a C

    0.5a

  • 2

    Combining the above equations gives:

    0.59 s yn s yc

    A fM A f d

    f b

    (5)

    The ACI Code explicitly accepts the Whitney rectangle (ACI 2008). For the loading conditions in this reinforced concrete beam competition, the ultimate force due to tensile would be:

    0.594s y s y

    tensionc

    A f A fP d

    f b

    (6)

    Shear Model The design of shear reinforcement is based on the assumption that the shear force must not exceed the total shear capacity of the beam (ACI 2008). When shear reinforcement is used, the shear capacity of a beam cross-section can be estimated as:

    n s cV V V (7) where Vn is the shear force in the beam, Vs is the shear capacity supplied by the reinforcement, and Vc is the shear strength of the concrete. The shear capacity of the reinforcement, which is assumed uniformly spaced across the diagonal crack, is:

    2 'v yn cA f d

    V f bds

    (8) where Av is the area of steel reinforcement in shear for each stirrup crossing the diagonal crack and s is spacing of the stirrups. For the loading conditions in this reinforced concrete beam competition, the ultimate force due to shear would be:

    2 2 'v yshear cA f d

    P f bds

    (9)

    Reinforcement Ratio for Rectangular Beams The reinforcement ratio (often called reinforcement percentage), may be conveniently used to represent the relative amount of tension reinforcement in a beam. Thus using the dimensions of Figure 1, the reinforcement ratio is:

    sAbd

    (10) Rewriting Equation (3) expresses the reinforcement ratio in terms of the c/d ratio.

    '

    10.85 cy

    fcd f

    (11) For beams controlled by tensile failure, c/d < 0.375 (ACI 2008).

  • 3

    Compression Model If the c/d > 0.6 then beam failure is controlled by compression (ACI 2008). For an overly rein-forced beam, the stress in the tensile steel fsteel when the concrete reaches its ultimate strain is:

    87,000steeld cf psi

    c (12)

    If fsteel < fy or c/d > 0.6, then the maximum moment in compression is:

    87,0002compression s

    d c aM A d psic (13)

    For the loading conditions in this reinforced concrete beam competition, the ultimate force due to compression would be:

    87,0004 2

    scompression

    A d c aP d psic (14)

    Estimation of Ultimate Beam Strength The ultimate strength, S, of the reinforced concrete beam may be estimated based the value of c/d as follows (ACI 2008):

    If 0.375 ,

    0.375 0.6 , ,

    0.6 ,

    tensile shear

    tension shear compression

    compression shear

    c S Minimun P Pd

    c S Minimun P P Pd

    c S Minimun P Pd

    (15)

    Estimation of Beam Weight and Cost The estimated weight W of a simply reinforced rectangular concrete beam is:

    beam concrete s steel concreteW V A L (16) where Vbeam is the volume of the beam, L is the length of the beam, concrete is the unit weight of concrete (typically 145 lb./ft.3), and steel is the unit weight of steel (490 lb./ft.3). The total cost estimate for a reinforced concrete beam Cbeam is:

    beam steel concreteC C C (17) where Csteel is the cost of the steel reinforcement and Cconcrete is the cost of the concrete. Table 1 lists the unit cost for a reinforced concrete beam for this competition.

  • 4

    Table 1. Reinforced Concrete Material Cost

    Material Cost Portland Type I cement $106/ton Coarse aggregate $14/ton Fine aggregate $7/ton Steel reinforcement $990/ton Admixtures - water reducer $15/gal Admixture - silica flume $500/ton

    To compute the cost of a reinforced concrete beam using the information in Table 1, use the following estimates (there is no cost associated with shear reinforcement). The cost of the steel, Csteel, may be estimated as:

    3lb. $990 ton490

    ton 2,000 lb.ft.steel sC A L (18)

    The total cost of concrete, Cconcrete, is estimated from the mix design as:

    concrete cement CA FAC C C C (19) where Ccement is the cost of the cement, CCA is the cost of the coarse aggregate, and CFA is the cost of the fine aggregate. The cost of each of these components can be computed as:

    3lb. $106 ton

    ton 2,000 lb.ft.cement beam cementC V W (20)

    3

    lb. $14 tonton 2,000 lb.ft.CA beam CA

    C V W (21)

    3

    lb. $7 tonton 2,000 lb.ft.FA beam FA

    C V W (22)

    where Wcement is the weight of cement, WCA is the weight of coarse aggregate, and WFA is the weight of fine aggregate (each weight is per ft.3 of concrete). Estimation of Cost-Adjusted SWR The predicted value of the cost-adjusted SWR (ASWR) may be computed as:

    If cost $3

    $3$3Beam

    SASWRWSASWRW C

    (23)

    References American Concrete Institute (2008). Building Code Requirements for Structural Concrete (ACI

    31808) and Commentary.

    Whitney, C.S. (1937) "Design of Reinforced Concrete Members Under Flexure and Combined Flexure and Direct Compression." ACI Journal, March-April; 33, 483-498.