begin the slide show. an ant walks 2.00 m 25° n of e, then turns and walks 4.00 m 20° e of n....
TRANSCRIPT
An ant walks 2.00 m 25° N of E , then turns and walks 4.00 m 20° E of N.
…can not be found using right-triangle math because WE DON’T HAVE A RIGHT TRIANGLE!
4.00 m
2.00 m
dt
CONSIDER THE FOLLOWING...
The total displacement of the ant…
An ant walks 2.00 m 25° N of E , then turns and walks 4.00 m 20° E of N.
This can’t be solved using our right-triangle math because it isn’t a RIGHT TRIANGLE!
We can add the two individual displacement vectors together by first separating them into pieces, called x- & y-components
The total displacement of the ant…
An ant walks 2.00 m 25° N of E , then turns and walks 4.00 m 20° E of N.
4.00 m
2.00 m
dt
This was the situation...
The total displacement of the ant…
R1 = 2.00 m, 25° N of E
R2 = 4.00 m, 20° E of N
R1 = 2.00 m, 25° N of E
25°
x = R cosθ = (2.00 m) cos 25° = +1.81262 m
y = R sinθ = (2.00 m) sin 25° = +0.84524 m
1.81262 m
0.84524 m
R2 = 4.00 m, 20° E of N
x = R cosθ = (4.00 m) cos 70° = +1.36808 m
y = R sinθ = (4.00 m) sin 70° = +3.75877 m
1.36808 m
3.75877 m
θ = 70˚
So, you have broken the two individual displacement vectors into components.
Now we can add the x-components together to get a TOTAL X-COMPONENT; adding the y-components together will likewise give a TOTAL Y-COMPONENT.
Let’s review first…
R1 = 2.00 m, 25° N of E
25°
x = R cosθ = (2.00 m) cos 25° = +1.81262 m
y = R sinθ = (2.00 m) sin 25° = +0.84524 m
1.81262 m
0.84524 m
R2 = 4.00 m, 20° E of N
x = R cosθ = (4.00 m) cos 70° = +1.36808 m
y = R sinθ = (4.00 m) sin 70° = +3.75877 m
1.36808 m
3.75877 m
Now we have the following information:
x y
R1
R2
+1.81262 m
+1.36808 m
+0.84524 m
+3.75877 m
Adding the x-components together and the y-components together will produce a TOTAL x- and y-component; these are the components of the resultant.
x y
R1
R2
+1.81262 m
+1.36808 m
+0.84524 m
+3.75877 m
+3.18070 m +4.60401 m
x-component of resultant y-component of resultant
Now that we know the x- and y-components of the resultant (the total displacement of the ant) we can put those components together to create the actual displacement vector.
3.18070 m
4.60401 mdT
θ
The Pythagorean theorem will produce the magnitude of dT:
c2 = a2 + b2
(dT)2 = (3.18070 m)2 + (4.60401 m)2
dT = 5.59587 m 5.60 m
A trig function will produce the angle, θ:
tan θ = (y/x)
θ = tan-1 (4.60401 m / 3.18070 m) = 55º
Of course, ‘55º’ is an ambiguous direction. Since there are 4 axes on the Cartesian coordinate system, there are 8 possible 55º angles.
55º
55º55º
55°
…and there are 4 others (which I won’t bother to show you).
To identify which angle we want, we can use compass directions (N,S,E,W)
3.18070 m
4.60401 mdT
θ
From the diagram we can see that the angle is referenced to the +x axis, which we refer to as EAST.
The vector dT is 55° north of the east line; therefore, the direction of the dT vector would be
55° North of East
We started with the following vector addition situation…
4.00 m
2.00 m
dt
…which did NOT make a right triangle.
dt
Then we broke each of the individual vectors ( the black ones) into x- and y-components…
…and added them together to get x- and y-components for the total displacement vector.
And now we have a right triangle we can analyze!
Yeah, baby! Let’s give it a try!
Complete #16 on your worksheet. (Check back here for the solution to the problem when you are finished.)