benchmark test with oktavian data and comment on kerma factor
DESCRIPTION
3nd RCM of CRP on FENDL-3, 6-10 December 2011. Benchmark test with OKTAVIAN data and Comment on kerma factor. Yukinobu Watanabe Department of Advanced Energy Engineering Science, Kyushu University. Contents. Action assignment in 2 nd RCM : Si and Sn - PowerPoint PPT PresentationTRANSCRIPT
Benchmark test with OKTAVIAN data and
Comment on kerma factor
Yukinobu Watanabe
Department of Advanced Energy Engineering Science,
Kyushu University
3nd RCM of CRP on FENDL-3, 6-10 December 2011
Contents
• Action assignment in 2nd RCM : Si and Sn
• Benchmark test using OKTAVIAN data (by C. Konno)
• Comment on KERMA factor in FENDL/MC-2.1 & FENDL/MG-2.1 (from C. Konno)
Assignment-1: Si isotopes
Keep from ENDF/B-VII, but check and consider using the new JENDL evaluation due to unsatisfactory benchmark results.
In summary report from the 2nd RCM; INDC(NDS)-0567 (2010)
C. Konno et al., “Benchmark Test of JENDL-4.0 Based on Integral Experiments at JAEA/FNS” presented at Joint Int. Conf. on Supercomputing in Nuclear Applications + Monte Carlo 2010, October 17-21, 2010, Tokyo, Japan.
JAEA/FNS
FNS SiC TOF Experiment - (1)
10-7
10-6
10-5
10-4
10-6 10-5 10-4 10-3 10-2 10-1 100 101
Expt.ENDF/B-VII.0JEFF-3.1FENDL-2.1JENDL-3.3JENDL-4
Neutron spectra at depth of 279 mm
Neu
tro
n F
lux
[n
/cm
2/L
eth
arg
y/S
ou
rce]
Neutron Energy [MeV]
JAEA/FNS
FNS SiC TOF Experiment - (2)
0.4
0.6
0.8
1.0
1.2
1.4
0 200 400 600
ENDF/B-VII.0JEFF-3.1FENDL-2.1JENDL-3.3JENDL-4
Ca
lc. /
Ex
pt.
Depth in the assembly [mm]
En > 10 MeV
Expt. Error
0.4
0.6
0.8
1.0
1.2
1.4
0 200 400 600
ENDF/B-VII.0JEFF-3.1FENDL-2.1JENDL-3.3JENDL-4
Ca
lc. /
Ex
pt.
Depth in the assembly [mm]
0.1 < En < 1 MeV
Expt. Error
0.4
0.6
0.8
1.0
1.2
1.4
0 200 400 600
ENDF/B-VII.0JEFF-3.1FENDL-2.1JENDL-3.3JENDL-4
Ca
lc. /
Ex
pt.
Depth in the assembly [mm]
10 < En < 100 keV
Expt. Error
0.4
0.6
0.8
1.0
1.2
1.4
0 200 400 600
ENDF/B-VII.0JEFF-3.1FENDL-2.1JENDL-3.3JENDL-4
Ca
lc. /
Ex
pt.
Depth in the assembly [mm]
10 < En < 100 eV
Expt. Error
JAEA/FNS
FNS SiC In-situ Experiment - (3)
0.4
0.6
0.8
1.0
1.2
1.4
0 200 400 600
ENDF/B-VII.0JEFF-3.1FENDL-2.1JENDL-3.3JENDL-4
Ca
lc. /
Ex
pt.
Depth in the assembly [mm]
93Nb(n,2n)92mNb
Expt. Error
0.4
0.6
0.8
1.0
1.2
1.4
0 200 400 600
ENDF/B-VII.0JEFF-3.1FENDL-2.1JENDL-3.3JENDL-4
Ca
lc. /
Ex
pt.
Depth in the assembly [mm]
27Al(n,)24Na
Expt. Error
0.4
0.6
0.8
1.0
1.2
1.4
0 200 400 600
ENDF/B-VII.0JEFF-3.1FENDL-2.1JENDL-3.3JENDL-4
Ca
lc. /
Ex
pt.
Depth in the assembly [mm]
115In(n,n')115mIn
Expt. Error
0.4
0.6
0.8
1.0
1.2
1.4
0 200 400 600
ENDF/B-VII.0JEFF-3.1FENDL-2.1JENDL-3.3JENDL-4
Ca
lc. /
Ex
pt.
Depth in the assembly [mm]
197Au(n,)198Au
Expt. Error
JAEA/FNS
FNS SiC In-situ Experiment - (4)
0.4
0.6
0.8
1.0
1.2
1.4
0 200 400 600
ENDF/B-VII.0JEFF-3.1FENDL-2.1JENDL-3.3JENDL-4
Ca
lc. /
Ex
pt.
Depth in the assembly [mm]
235U(n,fission)
Expt. Error
0.0
0.5
1.0
1.5
2.0
0 200 400 600
ENDF/B-VII.0JEFF-3.1FENDL-2.1JENDL-3.3JENDL-4
Ca
lc. /
Ex
pt.
Depth in the assembly [mm]
-Ray Heating Rate
Expt. Error
Reference : C. Konno et al., “Benchmark Test of JENDL-4.0 Based on Integral Experiments at JAEA/FNS” presented at Joint Int. Conf. on Supercomputing in Nuclear Applications + Monte Carlo 2010, October 17-21, 2010, Tokyo, Japan.
Conclusion on Si
From the result of this benchmark, I cannot find a reasonable reason to adapt JENDL-4.0 instead of ENDF/B-VII. Therefore, it would be better to keep ENDF/B-VII for Si isotopes in FENDL-3.0.
By YW Jan. 18, 2011
Si
FENDL-3 (SLIB2) :ENDF/B-VII.0
0.6
0.8
1.0
1.2
10-1 100 101
Ca
lc. /
Ex
pt.
Neutron Energy [MeV]
10-2
10-1
100
101
OKTAVIAN Si 60cm
Expt.JEFF-3.1ENDF-B/VII.0JENDL-3.3JENDL-4.0
Ne
utr
on
Flu
x [
1/le
tha
rgy
/so
urc
e]
JENDL-4 is slightly better than the others.
Assigment-2: Sn isotopes
Isotopic evaluations from RUSFOND files (or JENDL-4 if available) to be joined to TENDL at E > 20 MeV. Otherwise use TENDL only. Action on Watanabe to justify switch to JENDL-4.
In summary report from the 2nd RCM; INDC(NDS)-0567 (2010)
The data of Sn isotopes in RUSFOND are taken from ENDF/B-VII and both data are same.
Sn isotopes
Since there is no integral benchmark test for Sn isotopes, our optimum selection of evaluated library should be based on only comparison of differential data.
Here we focus on g-ray production cross sections, because they are important to estimate the influence of g-ray heating on superconducting coil (Nb3Sn) for nuclear fusion technology.
ENDF/B-VII.0, RUSFOND, TENDL-2010, and JENDL-4.0 are compared with available experimental data.
114Sn(n,g)
115Sn(n,g)
116Sn(n,g)
117Sn(n,g)
118Sn(n,g)
119Sn(n,g)
120Sn(n,g)
122Sn(n,g)
124Sn(n,g)
g-ray emission spectra of natural Sn
g-ray emission spectra of natural Sn
Results
JENDL-4.0 is in slightly better agreement with the experimental (n,g) data of 112,114,116Sn than the other evaluations.
All the evaluations for 118,120Sn reproduce the measurements to similar extent.
As for 122,124Sn, JENDL-4.0 is better than RUSFOND (i.e., ENDF/B-VII.0). Thus, as far as the (n,g) cross sections are concerned, the JENDL-4.0 looks superior to RUSFOND and TENDL-2010.
Gamma-ray emission spectra of natural Sn at 4.75 and 13.05 MeV incident energies are shown with JENDL-4 data and measurements. A comparison with TENDL-2010 is also presented. The data of JENDL-4 agrees with the measurements better than that of TENDL-2010.
Conclusion on Sn
I recommend that we should adapt JENDL-4.0 instead of RUSFOND at energies below 20 MeV. Since there is no high energy data of JENDL for Sn isotopes, TENDL-2010 should be connected with JENDL-4.0 at 20 MeV.
By YW Jan. 18, 2011
Contents
• Action assignment in 2nd RCM : Si and Sn
• Benchmark test using OKTAVIAN data (by C. Konno)
• Comment on KERMA factor in FENDL/MC-2.1 & FENDL/MG-2.1 (from C. Konno)
Benchmark Test using OKTAVIAN data
Benchmark test was done by FNS/JAEA using MCNP-5.14 code Presented at 2011 symposium on nuclear data, 16-17 Nov. 2011, Tokai, Japan
Measurement of leakage neutron spectrum from a spherical pile with incident 14 MeV neutrons
Si
FENDL-3 (SLIB2):ENDF/B-VII.0
0.6
0.8
1.0
1.2
10-1 100 101
Ca
lc. /
Ex
pt.
Neutron Energy [MeV]
10-2
10-1
100
101
OKTAVIAN Si 60cm
Expt.JEFF-3.1ENDF-B/VII.0JENDL-3.3JENDL-4.0
Ne
utr
on
Flu
x [
1/le
tha
rgy
/so
urc
e]
Cu
10-1
100
100 101
Cu 61cm
Expt.JEFF-3.1ENDF-B/VII.0JENDL-3.3JENDL-4.0N
eutr
on
Flu
x [1
/leth
arg
y/s
ou
rce]
0.80.91.01.11.21.3
10-1 100 101
Cal
c. /
Exp
t.
Neutron Energy [MeV]
FENDL-3 (SLIB2)ENDF/B-VII
Zr
FENDL-3 (SLIB2):JENDL/HE
10-1
100
100 101
Zr 61cm
Expt.JEFF-3.1ENDF-B/VII.0JENDL-3.3JENDL-4.0
Neu
tro
n F
lux
[1/le
thar
gy/
sou
rce]
0.8
1.0
1.2
1.4
10-1 100 101
Cal
c. /
Exp
t.
Neutron Energy [MeV]
Nb
FENDL-3 (SLIB2):JENDL/HE
10-1
100
101
100 101
Nb 28cmExpt.JEFF-3.1ENDF-B/VII.0JENDL-3.3JENDL-4.0
Neu
tro
n F
lux
[1/le
thar
gy/
sou
rce]
0.8
1.0
1.2
1.4
10-1 100 101
Cal
c. /
Exp
t.
Neutron Energy [MeV]
Mo
FENDL-3 (SLIB2):JENDL/HE
10-1
100
101
100 101
Mo 60cmExpt.JEFF-3.1ENDF-B/VII.0JENDL-3.3JENDL-4.0
Neu
tro
n F
lux
[1/le
thar
gy/
sou
rce]
0.8
0.9
1.0
1.1
10-1 100 101
Cal
c. /
Exp
t.
Neutron Energy [MeV]
W
FENDL-3 (SLIB2):IAEA
10-1
100
101
100 101
W 40cmExpt.JEFF-3.1ENDF-B/VII.0JENDL-3.3JENDL-4.0
Neu
tro
n F
lux
[1/le
thar
gy/
sou
rce]
0.60.70.80.91.01.1
10-1 100 101
Cal
c. /
Exp
t.
Neutron Energy [MeV]
Contents
• Reply to assignments in 2nd RCM : Si and Sn
• Benchmark test using OKTAVIAN data
• KERMA factor in FENDL/MC-2.1 & FENDL/MG-2.1
JAEA/FNS
KERMA factor in FENDL/MC-2.1
and FENDL/MG-2.1
JAEA C. Konno
JAEA/FNSNeutron KERMA in FENDL-2.1
Neutron KERMA factors are stored in FENDL/MC-2.1 (ACE file) and FENDL/MG-2.1 (MATXS file), not in FENDL/E-2.1.
Pointwise neutron KERMA factors in FENDL/MC-2.1 are deduced with the energy balance method in the heatr module of the NJOY code. They are used for tally F6 in MCNP.
Two neutron KERMA factors of 175 groups, “heat” and “kerma”, are stored in FENDL/MG-2.1. “heat” is deduced with the energy balance method in NJOY heatr, while “kerma” is deduced with the kinematic method in NJOY heatr. Note that “kerma” is an upper limit of KERMA and that “heat” should be less than “kerma”. They are extracted with the TRANSX code and are used as response data for heating calculation with Sn codes.
JAEA/FNSProblem in Neutron KERMA in FENDL-2.1
As well known, the energy balance method gives inadequate KERMA, e.g. negative KERMA, if the total energy is not conserved inside nuclear data. In this case the kinematic method should be adopted.
This problem appears in 28 nuclei of FENDL/MC-2.1 (see next slides). - Au-197, Bi-209, Fe-56, Ga-nat, Mn-55, Mo-92, Mo-
94, Mo-95, Mo-96, Mo-97, Mo-98, Mo-100, N-14, Nb-93, P-31, Sn-nat, Ta-181, Ti-46, Ti-47, Ti-48, Ti-49, Ti-50, V-nat, W-182, W-183, W-184, W-186, Zn-96
We would like to propose that this problem should be resolved in FENDL/MC-3.0.
JAEA/FNS
Inadequate KERMA in FENDL-2.1 -(1)
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Au-19710-7
10-6
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Bi-209
10-6
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Fe-5610-5
10-3
10-1
101
103
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Ga-nat
JAEA/FNS
Inadequate KERMA in FENDL-2.1 -(2)
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Mn-5510-7
10-5
10-3
10-1
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Mo-92
10-7
10-6
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Mo-9410-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Mo-95
JAEA/FNS
Inadequate KERMA in FENDL-2.1 -(3)
10-6
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Mo-9610-6
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Mo-97
10-6
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Mo-9810-6
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Mo-100
JAEA/FNS
Inadequate KERMA in FENDL-2.1 -(4)
10-3
10-2
10-1
100
101
102
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
N-1410-6
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Nb-93
10-6
10-5
10-4
10-3
10-2
10-1
100
101
102
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
P-3110-6
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Sn-nat
JAEA/FNS
Inadequate KERMA in FENDL-2.1 -(5)
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Ta-18110-5
10-4
10-3
10-2
10-1
100
101
102
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Ti-46
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Ti-4710-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Ti-48
JAEA/FNS
Inadequate KERMA in FENDL-2.1 -(6)
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Ti-4910-6
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Ti-50
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
V-nat10-5
10-4
10-3
10-2
10-1
100
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
W-182
JAEA/FNS
Inadequate KERMA in FENDL-2.1 -(7)
10-5
10-4
10-3
10-2
10-1
100
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
W-18310-6
10-5
10-4
10-3
10-2
10-1
100
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
W-184
10-6
10-5
10-4
10-3
10-2
10-1
100
101
102
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
W-18610-6
10-5
10-4
10-3
10-2
10-1
100
101
10-11 10-9 10-7 10-5 10-3 10-1 101
Energy balance (MATXS)Kinematic (MATXS)ACE
KE
RM
A f
acto
r [M
eV b
arn
]
Neutron energy [MeV]
Zr-nat
JAEA/FNSProposal concerning neutron KERMA
The energy balance method gives inadequate KERMA, e.g. negative KERMA, if the total energy is not conserved inside nuclear data. In this case the kinematic method should be adopted.
This problem appears in 28 nuclei of FENDL/MC-2.1 :
- Au-197, Bi-209, Fe-56, Ga-nat, Mn-55, Mo-92, Mo-94, Mo-95, Mo-96, Mo-97, Mo-98, Mo-100, N-14, Nb-93, P-31, Sn-nat, Ta-181, Ti-46, Ti-47, Ti-48, Ti-49, Ti-50, V-nat, W-182, W-183, W-184, W-186, Zn-96
This problem should be resolved in processing of FENDL/MC-3.0.
Appendix
114Sn(n,tot)
118Sn(n,tot)
120Sn(n,tot)