blake chapter1 10
TRANSCRIPT
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Chapter 1: Introduction to
Communication SystemsMULTIPLE CHOICE
1. The theory of radio waves was originated by:
a. Marconi c. Maxwellb. Bell d. HertzANS: C
2. The person who sent the first radio signal
across the Atlantic ocean was:a. Marconi c. Maxwell
b. Bell d. HertzANS: A
3. The transmission of radio waves was firstdone by:
a. Marconi c. Maxwellb. Bell d. HertzANS: D
4. A complete communication system must
include:
a. a transmitter and receiverb. a transmitter, a receiver, and a channelc. a transmitter, a receiver, and a spectrum
analyzerd. a multiplexer, a demultiplexer, and a channel
ANS: B5. Radians per second is equal to:
a. 2Tvfc. the phase angle
b.fz2Td. none of the aboveANS: A6. The bandwidth required for a modulated
carrier depends on:
a. the carrier frequency c. the signal-plus-noise
to noise ratiob. the signal-to-noise ratio d. the baseband
frequency range
ANS: D7. When two or more signals share a common
channel, it is called:a. sub-channeling c. SINAD
b. signal switching d. multiplexingANS: D
8. TDM stands for:
a. Time-Division Multiplexing c. Time DomainMeasurement
b. Two-level Digital Modulation d. none of the
aboveANS: A
9. FDM stands for:a. Fast Digital Modulation c. Frequency-
Division Multiplexing
b. Frequency Domain Measurement d. none of
the aboveANS: C10. The wavelength of a radio signal is:
a. equal tofzc
b. equal to c zP
c. the distance a wave travels in one periodd. how far the signal can travel without
distortionANS: C11. Distortion is caused by:
a. creation of harmonics of baseband frequenciesb. baseband frequencies "mixing" with each
otherc. shift in phase relationships between basebandfrequencies
d. all of the above
ANS: D
12. The collection of sinusoidal frequenciespresent in a modulated carrier is called its:a. frequency-domain representation c. spectrum
b. Fourier series d. all of the aboveANS: D
13. The baseband bandwidth for a voice-grade
(telephone) signal is:a. approximately 3 kHz c. at least 5 kHz
b. 20 Hz to 15,000 Hz d. none of the above
ANS: A
14. Noise in a communication system originatesin:
a. the sender c. the channelb. the receiver d. all of the aboveANS: D
15. "Man-made" noise can come from:
a. equipment that sparks c. staticb. temperature d. all of the aboveANS: A
16. Thermal noise is generated in:
a. transistors and diodes c. copper wireb. resistors d. all of the aboveANS: D
17. Shot noise is generated in:
a. transistors and diodes c. copper wireb. resistors d. none of the above
ANS: A18. The power density of "flicker" noise is:a. the same at all frequencies c. greater at low
frequencies
b. greater at high frequencies d. the same as"white" noise
ANS: C
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19. So called "1/f" noise is also called:
a. random noise c. white noiseb. pink noise d. partition noiseANS: B
20. "Pink" noise has:
a. equal power per Hertz c. constant power
b. equal power per octave d. none of the aboveANS: B
21. When two noise voltages, V1 and V2, arecombined, the total voltage VTis:
a. VT= sqrt(V1vV1 + V2 vV2) c. VT= sqrt(V1
vV2)b. VT= (V1 + V2)/2 d. VT= V1 + V2
ANS: A22. Signal-to-Noise ratio is calculated as:a. signal voltage divided by noise voltage
b. signal power divided by noise power
c. first add the signal power to the noise power,
then divide by noise powerd. none of the aboveANS: B
23. SINAD is calculated as:a. signal voltage divided by noise voltage
b. signal power divided by noise power
c. first add the signal power to the noise power,then divide by noise power
d. none of the above
ANS: D
24. Noise Figure is a measure of:a. how much noise is in a communications
systemb. how much noise is in the channelc. how much noise an amplifier adds to a signal
d. signal-to-noise ratio in dB
ANS: C25. The part, or parts, of a sinusoidal carrier thatcan be modulated are:
a. its amplitude c. its amplitude, frequency, and
directionb. its amplitude and frequency d. its amplitude,frequency, and phase angle
ANS: D
COMPLETION1. The telephone was invented in the year
____________________.ANS: 18632. Radio signals first were sent across the
Atlantic in the year ____________________.
ANS: 1901
3. The frequency band used to modulate the
carrier is called the ____________________band.ANS: base
4. The job of the carrier is to get the information
through the ____________________.
ANS: channel5. The bandwidth of an unmodulated carrier is
____________________.ANS: zero
6. The 'B' in Hartley's Law stands for
____________________.ANS: bandwidth7. The more information per second you send,
the ____________________ the bandwidth
required.ANS:
greater
largerwider
8. In ____________________, you split the
bandwidth of a channel into sub-channels tocarry multiplesignals.
ANS: FDM
9. In ____________________, multiple signalstreams take turns using the channel.
ANS: TDM10. VHF stands for the ____________________frequency band.
ANS: very high11. The VHF band starts at
____________________ MHz.ANS: 30
12. The UHF band starts at
____________________ MHz.ANS: 300
13. A radio signal's ____________________ isthe distance it travels in one cycle of the carrier.ANS: wavelength
14. In free space, radio signals travel at
approximately ____________________ meters
per second.ANS: 300 million15. The equipment used to show signals in the
frequency domain is the_________________________.
ANS: spectrum analyzer16. Mathematically, a spectrum is represented
by a ____________________ series.
ANS: Fourier
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17. Disabling a receiver during a burst of
atmospheric noise is called____________________.ANS:
noise blanking
blanking
18. For satellite communications,____________________ noise can be a serious
problem.ANS: solar
19. Thermal noise is caused by the random
motions of ____________________ in aconductor.ANS: electronsSHORT ANSWER
1. Name the five elements in a block diagram ofa communications system.
ANS:
Source, Transmitter, Channel, Receiver,Destination
2. Name five types of internal noise.
ANS:Thermal, Shot, Partition, 1/f, transit-time3. Why is thermal noise called "white noise"?
ANS:
White light is composed of equal amounts oflight at all visible frequencies. Likewise, thermal
noise hasequal power density over a wide range offrequencies.
4. What is "pink noise"?ANS:
Light is pink when it contains more red than itdoes other colors, and red is at the low end of
the visible
spectrum. Likewise, pink noise has higher powerdensity at lower frequencies.
5. Suppose there is 30 QV from one noise source
that is combined with 40 QV from another noisesource.Calculate the total noise voltage.
ANS:
50 QV6. If you have 100 mV of signal and 10 mV ofnoise, both across the same 100-ohm load, what
is the signalto-noise ratio in dB?ANS:
20 dB
7. The input to an amplifier has a signal-to-noise
ratio of 100 dB and an output signal-to-noiseratio of 80dB. Find NF, both in dB and as a ratio.
ANS:
20 dB, NF = 100
8. A microwave receiver has a noise temperatureof 145 K. Find its noise figure.
ANS:1.5
9. Two cascaded amplifiers each have a noise
figure of 5 and a gain of 10. Find the total NFfor the pair.ANS:
5.4
10. Explain why you could use a diode as anoise source with a spectrum close to that of
pure thermal noise.
How would you control the amount of noisegenerated?
ANS:
When current flows through a diode, it generatesshot noise that can be represented as a currentsource,
the output of which is a noise current. The
equation for the noise current is very similar tothe equation for
thermal noise voltage. Since the power in theshot noise is proportional to the diode current,controlling
the diode current controls the noise power.
Chapter 2: Radio-Frequency CircuitsMULTIPLE CHOICE
1. The time it takes a charge carrier to crossfrom the emitter to the collector is called:
a. base time c. charge time
b. transit time d. Miller timeANS: B2. A real capacitor actually contains:
a. capacitance and resistance only c. capacitance,
inductance, and resistanceb. capacitance and inductance only d. reactance
onlyANS: C3. Bypass capacitors are used to:
a. remove RF from non-RF circuits c. neutralize
amplifiers
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b. couple RF around an amplifier d. reduce the
Miller effectANS: A4. A resonant circuit is:
a. a simple form of bandpass filter c. both a and
b
b. used in narrowband RF amplifiers d. none ofthe above
ANS: C5. Loading down a tuned-circuit amplifier will:
a. raise the Q of the tuned circuit c. "multiply"
the Qb. lower the Q of the tuned circuit d. have noeffect on Q
ANS: B
6. The "Miller Effect" can:a. cause an amplifier to oscillate c. reduce the
bandwidth of an amplifier
b. cause an amplifier to lose gain d. all of theabove
ANS: D
7. The Miller Effect can be avoided by:a. using a common-emitter amplifier c.increasing the Q of the tuned circuit
b. using a common-base amplifier d. it cannot be
avoidedANS: B
8. In a BJT, the Miller Effect is due to:a. inductance of collector lead c. base-to-emittercapacitance
b. collector-to-emitter capacitance d. base-to-collector capacitance
ANS: D9. In RF amplifiers, impedance matching is
usually done with:
a. RC coupling c. direct couplingb. transformer coupling d. lumped reactance
ANS: B10. Neutralization cancels unwanted feedback
by:
a. adding feedback out of phase with the
unwanted feedback
b. bypassing the feedback to the "neutral" orground planec. decoupling it
d. none of the aboveANS: A
11. For a "frequency multiplier" to work, itrequires:a. a nonlinear circuit
b. a linear amplifier
c. a signal containing harmonics
d. an input signal that is an integer multiple ofthe desired frequencyANS: A
12. A sinusoidal oscillation from an amplifier
requires:
a. loop gain equal to unityb. phase shift around loop equal to 0 degrees
c. both a and b, but at just one frequencyd. none of the above
ANS: C
13. The conditions for sinusoidal oscillationfrom an amplifier are called:a. the loop-gain criteria c. the Bode criteria
b. the Hartley criteria d. the Barkhausen criteria
ANS: D14. The Hartley oscillator uses:
a. a tapped inductor c. an RC time constant
b. a two-capacitor divider d. a piezoelectriccrystal
ANS: A
15. The Colpitts VFO uses:a. a tapped inductor c. an RC time constant
b. a two-capacitor divider d. a piezoelectric
crystal
ANS: B16. The Clapp oscillator is:
a. a modified Hartley oscillator c. a type ofcrystal-controlled oscillator
b. a modified Colpitts oscillator d. only built
with FETsANS: B
17. A varactor is:a. a voltage-controlled capacitor c. used in tuner
circuits
b. a diode d. all of the aboveANS: D
18. Crystal-Controlled oscillators are:a. used for a precise frequency
b. used for very low frequency drift (parts per
million)
c. made by grinding quartz to exact dimensions
d. all of the aboveANS: D
19. If two signals, Va = sin([at) and Vb=
sin([bt), are fed to a mixer, the output:
a. will contain [1 = [a + [b and [2 = [a[b
b. will contain[1 = [a / [b and [2 = [b / [a
c. will contain [= ([a + [b ) / 2d. none of the above
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ANS: A
20. In a balanced mixer, the output:a. contains equal (balanced) amounts of all inputfrequencies
b. contains the input frequencies
c. does not contain the input frequencies
d. is a linear mixture of the input signalsANS: C
21. "VFO" stands for:a. Voltage-Fed Oscillator c. Varactor-Frequency
Oscillator
b. Variable-Frequency Oscillator d. Voltage-Feedback OscillatorANS: B
22. A "frequency synthesizer" is:
a. a VCO phase-locked to a reference frequencyb. a VFO with selectable crystals to change
frequency
c. a fixed-frequency RF generatord. same as a mixer
ANS: ACOMPLETION
1. Generally, conductor lengths in RF circuitsshould be ____________________.
ANS: short
2. At UHF frequencies and above, elementsmust be considered as ____________________
instead of asbeing "lumped".ANS: distributed
3. When one side of a double-sided pc board isused for ground, it is called a
____________________.ANS: ground-plane
4. Interactions between parts of an RF circuit
can be reduced by using ____________________ between
them.ANS: shielding5. In high-frequency RF circuits, the placement
of wires and ____________________ can be
critical.
ANS: components6. A ____________________ circuit is used toremove RF from the DC voltage bus.
ANS: decoupling7. A ____________________ capacitor is used
to short unwanted RF to ground.ANS: bypass
8. The bandwidth of a tuned-circuit amplifier
depends on the ____________________ of thetuned circuit.ANS: Q
9. A value of ____________________ or more
for Q is required for the approximate tuned
circuit equationsto be valid.
ANS: 1010. In a class C RF amplifier, the
____________________ extracts one frequency
from all the harmonicscontained in the device current (e.g. collectorcurrent).
ANS: tuned circuit
11. Using additional feedback to compensate for"stray" feedback is called
____________________.
ANS: neutralization12. A Colpitts oscillator uses a
____________________ voltage divider to
provide feedback.ANS: capacitive13. Electrically, a piezoelectric crystal has both a
____________________ and a
____________________resonant frequency.
ANS: series, parallel14. To produce sum and difference frequencies,a mixer must be a non-____________________
circuit.ANS: linear
15. At some bias point, a diode or a transistorcan act as a ____________________-law mixer.
ANS: squareSHORT ANSWER
1. What inductance would you use with a 47-pF
capacitor to make a tuned circuit for 10 MHz?ANS:
5.4 QH
2. What value of Q is required for a 10-MHztuned circuit to have a bandwidth of 100 kHz?
ANS:1003. A tuned-circuit amplifier with a gain of 10 is
being used to make an oscillator. What should
be the value
of the feedback ratio to satisfy the Barkhausencriteria?
ANS:0.1
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4. What is the advantage of a Clapp oscillator
compared to a Colpitts oscillator?ANS:It is more stable because it "swamps" the device
capacitance with large value capacitors in the
feedback
divider.5. If a varactor has a capacitance of 90 pF at
zero volts, what will be the capacitance at 4volts?
ANS:
30 pF6. An oscillator has a frequency of 100 MHz at20C, and a tempco of +10 ppm per degree
Celsius. What
will be the shift in frequency at 70C? Whatpercentage is that?
ANS:
50 kHz, 0.05%7. Two sinusoidal signals, V1 and V2, are fed into
an ideal balanced mixer. V1 is a 20-MHz signal;
V2 is a 5-MHz signal. What frequencies would you expectat the output of the mixer?
ANS:
15 MHz and 25 MHz8. Suppose the phase-locked-loop frequency
synthesizer of Figure 2.39 has a referencefrequency of 1 MHzand a fixed-modulus divider of 10. What should
be the value of the programmable divider to getan output
frequency of 120 MHz?ANS:
12
Chapter 3: Amplitude ModulationMULTIPLE CHOICE
1. AM stands for:
a. Audio Modulation c. Angle Modulationb. Amplitude Modulation d. Antenna
ModulationANS: B
2. The "envelope" of an AM signal is due to:a. the baseband signal c. the amplitude signal
b. the carrier signal d. none of the aboveANS: A
3. If the audio Va sin([at) modulates the carrier
Vc sin([ct), then the modulation index, m, is:
a. m= [a / [c c. m= (Va / Vc)2
b. m= Va / Vc d. m= Va / [aANS: B
4. The equation for full-carrier AM is:
a. v(t) = (Ec +Em) vsin([ct) c. v(t) = (EcvEm)
vsin([mt) vsin([ct)
b. v(t) = (Ec +Em) vsin([mt) + sin([ct) d. v(t) =
(Ec +Emsin([mt)) vsin([ct)ANS: D5. Overmodulation causes:
a. distortion c. both a and bb. splatter d. none of the above
ANS: C6. The peak voltage of an AM signal goes from
Emax toEmin. The modulation index, m, is:a. m=Emin/Emax c. m= (EmaxEmin) / (Emax +
Emin)
b. m=Emax /Emind. m= (Emax +Emin) / (EmaxEmin)ANS: C
7. IfVa sin([at) amplitude modulates the carrier
Vc sin([ct), it will produce the frequencies:
a. [c + [a and [c[a c. [c + [a and 2[c + 2[a
b. ([c + [a)/2 and ([c[a)/2 d. none of theabove
ANS: A
8. At 100% modulation, the total sidebandpower is:a. equal to the carrier power c. half the carrier
powerb. twice the carrier power d. 1.414 vcarrierpowerANS: C
9. If a 5-kHz signal modulates a 1-MHz carrier,the bandwidth of the AM signal will be:
a. 5 kHz c. 1.005 MHzb. 10 kHz d. none of the above
ANS: B
10. If an AM radio station increases itsmodulation index, you would expect:a. the audio to get louder at the receiver c. the
signal-to-noise ratio to increaseb. the received RF signal to increase d. all of the
aboveANS: D
11. The modulation index can be derived from:a. the time-domain signal c. both a and b
b. the frequency-domain signal d. none of the
aboveANS: C
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12. The main problem in using quadrature AM
would be:a. requires too much bandwidth c.incompatibility with ordinary AM radios
b. requires too much power d. all of the above
ANS: C
13. As compared to plain AM, SSB AM:a. is more efficient
b. requires a more complex demodulator circuitc. requires less bandwidth
d. all of the above
ANS: D14. The SC in SSB SC stands for:a. single-carrier c. sideband-carrier
b. suppressed-carrier d. none of the above
ANS: B15. PEP stands for:
a. Peak Envelope Power c. Peak Envelope
Productb. Peak Efficiency Power d. none of the above
ANS: A
16. If an SSB transmitter radiates 1000 watts atpeak modulation, what will it radiate with nomodulation?
a. 1000 watts c. 250 watts
b. 500 watts d. 0 wattsANS: D
17. Music on AM radio stations is "low-fidelity"because:a. AM is susceptible to noise
b. commercial AM stations use low powerc. commercial AM stations have a narrow
bandwidthd. all of the above
ANS: C
18. The type of information that can be sentusing AM is:
a. audio c. digital datab. video d. all of the aboveANS: D
19. Two tones modulate an AM carrier. One
tone causes a modulation index ofm1 and the
other tone causes amodulation index ofm2. The total modulationindex is:
a. m1 + m2 c. sqrt(m1vm2 + m2vm1)
b. (m1 + m2) / 2 d. sqrt(m1vm1 + m2vm2)ANS: D
20. To demodulate a USB SSB signal, thereceiver must:
a. be set to USB mode c. both a and b
b. reinsert the carrier d. none of the above
ANS: CCOMPLETION
1. An advantage of AM is that the receiver can
be very ____________________.
ANS: simple
2. A disadvantage of AM is its____________________ use of power.
ANS: inefficient3. The ____________________ of an AM signal
resembles the shape of the baseband signal.
ANS: envelope4. In AM, modulating with a single audio tone
produces ____________________ sidebands.
ANS: two
5. Compared to the USB, the information in theLSB is ____________________.
ANS: the same
6. Compared to the USB, the power in the LSBis ____________________.
ANS: the same
7. In AM, total sideband power is always____________________ than the carrier power.ANS: less
8. In AM, as the modulation index increases, the
carrier power _________________________.ANS: remains constant
9. The power in an AM signal is maximumwhen the modulation index is
____________________.
ANS: one10. In AM, a voice-band signal of 300 Hz to
3000 Hz will require a bandwidth of____________________.
ANS: 6000 Hz
11. With a 1-MHz carrier, if the LSB extendsdown to 990 kHz, then the USB will extend up
to____________________.ANS: 1010 kHz
12. If an AM transmitter puts out 100 watts with
no modulation, it will put out
____________________ wattswith 100% modulation.ANS: 150SHORT ANSWER
1. An AM transmitter generates 100 watts with
0% modulation. How much power will itgenerate with 20%modulation?
ANS:
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102 watts
2. If the carrier power is 1000 watts, what is thepower in the USB at 70.7% modulation?ANS:
125 watts
3. A carrier is modulated by three audio tones. If
the modulation indexes for the tones are 0.3, 0.4,and 0.5,
then what is the total modulation index?ANS:
0.707
4. You look at an AM signal with anoscilloscope and see that the maximum Vpp is100 volts and the
minimum Vpp is 25 volts. What is the modulation
index?ANS:
0.6
5. A SSB transmitter is connected to a 50-ohmantenna. If the peak output voltage of the
transmitter is 20
volts, what is the PEP?ANS:4 watts
Chapter 4: Angle ModulationMULTIPLE CHOICE
1. The FM modulation index:a. increases with both deviation and modulation
frequency
b. increases with deviation and decreases withmodulation frequencyc. decreases with deviation and increases with
modulation frequency
d. is equal to twice the deviationANS: B
2. One way to derive FM from PM is:a. integrate the modulating signal beforeapplying to the PM oscillator
b. integrate the signal out of the PM oscillator
c. differentiate the modulating signal beforeapplying to the PM oscillator
d. differentiate the signal out of the PMoscillator
ANS: A3. The bandwidth of an FM signal is considered
to be limited because:a. there can only be a finite number of sidebands
b. it is equal to the frequency deviation
c. it is band-limited at the receiver
d. the power in the outer sidebands is negligible
ANS: D
4. Mathematically, the calculation of FMbandwidth requires the use of:a. ordinary trigonometry and algebra c. Taylor
series
b. Bessel functions d. fractals
ANS: B5. FM bandwidth can be approximated by:
a. Armstrong's Rule c. Carson's Ruleb. Bessel's Rule d. none of the above
ANS: C
6. NBFM stands for:a. National Broadcast FM c. Near Band FM
b. Non-Broadcast FM d. Narrowband FM
ANS: D
7. When FM reception deteriorates abruptly dueto noise, it is called:
a. the capture effect c. the noise effect
b. the threshold effect d. the limit effectANS: B
8. An FM receiver switching suddenly between
two stations on nearby frequencies is called:a. the capture effect c. the "two-station" effect
b. the threshold effect d. none of the above
ANS: A
9. Pre-emphasis is used to:a. increase the signal to noise ratio for higher
audio frequenciesb. increase the signal to noise ratio for loweraudio frequencies
c. increase the signal to noise ratio for all audiofrequencies
d. allow stereo audio to be carried by FMstations
ANS: A
10. A pre-emphasis of 75 Qs refers to:a. the time it takes for the circuit to work
b. the "dead time" before de-emphasis occurs
c. the time delay between the L and R channelsd. the time-constant of the filter circuits used
ANS: D11. FM stereo:
a. uses DSBSC AM modulation c. has a higherS/N than mono FM
b. is implemented using an SCA signal d. is notcompatible with mono FM
ANS: A
12. An SCA signal:a. can use amplitude modulation c. is monaural
b. can use FM modulation d. all of the aboveANS: D
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13. The modulation index of an FM signal can
be determined readily:a. using measurements at points whereJ0 equalsone
b. using measurements at points whereJ0 equals
zero
c. using measurements at points where thedeviation equals zero
d. only by using Bessel functionsANS: BCOMPLETION
1. FM and PM are two forms of ____________________ modulation.ANS: angle
2. PM is extensively used in
____________________ communication.ANS: data
3. Compared to AM, the signal-to-noise ratio of
FM is usually ____________________.ANS: better
4. Compared to AM, the bandwidth of FM is
usually ____________________.ANS:wider
greater
5. FM transmitters can use Class____________________ amplifiers since
amplitude linearity is notimportant.ANS: C
6. Both the power and amplitude of an FMsignal ____________________ as modulation is
applied.ANS: stay constant
7. In FM, the frequency deviation is proportional
to the instantaneous ____________________ ofthe
modulating signal.ANS: amplitude8. The frequency deviation of an FM signal
occurs at a rate equal to the
____________________ of the
modulating signal.ANS: frequency9. Mathematically, the number of sidebands in
an FM signal is ____________________.ANS: infinite
10. As FM sidebands get farther from the centerfrequency, their power ____________________.ANS: decreases
11. Mathematically, the value of an FM
modulation index can be as high as____________________.ANS: any number
12. In FM, as the modulating frequency
decreases, the modulation index
____________________.ANS: increases
13. In FM, as the frequency deviation decreases,the modulation index ____________________.
ANS: decreases
14. As the FM modulation index increases, thenumber of significant sidebands
____________________.
ANS: increases
15. For certain values ofmf, such as 2.4, theamplitude of the carrier frequency
____________________.
ANS:disappears
goes to zero
16. The bandwidth of an FM signal can beapproximated using ____________________rule.
ANS: Carson's
17. FM bandwidth can be calculated preciselyusing ____________________ functions.
ANS: Bessel18. The ____________________ effect ischaracteristic of FM reception in a noisy
environment.ANS: threshold
19. The ____________________ effect is seenwhen an FM receiver is exposed to two FM
signals that are
close to each other in frequency.ANS: capture
20. Rest frequency is another name for an FM ____________________ frequency.ANS: carrierSHORT ANSWER
1. If a 2-volt instantaneous value of modulating
signal amplitude causes a 10-kHz deviation incarrierfrequency, what is the deviation sensitivity of
the modulator?ANS:
5 kHz / volt2. If a 2-kHz audio tone causes a frequencydeviation of 4 kHz, what is the modulation
index?
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ANS: C
8. With low-level AM:a. the RF amplifiers must be Class A c. the RFamplifiers must be linear
b. the RF amplifiers must be Class B d. the RF
amplifiers must be low-power
ANS: C9. Power amplifiers must be linear for any signal
that:a. is complex c. has variable frequency
b. has variable amplitude d. all of the above
ANS: B10. In high-level AM, "high-level" refers to:a. the power level of the carrier c. the power
level of the final RF amplifier
b. the power level of the modulation d. none ofthe above
ANS: D
11. In high-level AM, the power in thesidebands comes from:
a. the modulating amplifier c. the driver stage
b. the RF amplifier d. the carrierANS: A12. In an AM transmitter with 100% modulation,
the voltage of the final RF stage will be:
a. approximately half the DC supply voltageb. approximately twice the DC supply voltage
c. approximately four times the DC supplyvoltaged. none of the above
ANS: C13. Practical transmitters are usually designed to
drive a load impedance of:a. 50 ohms resistive c. 300 ohms resistive
b. 75 ohms resistive d. 600 ohms resistive
ANS: A14. Which of the following can be used for
impedance matching?a. pi network c. both a and b
b. T network d. a bridge circuit
ANS: C
15. When a transmitter is connected to a resistor
instead of an antenna, the resistor is called:a. a heavy load c. a temporary load
b. a dummy load d. a test load
ANS: B16. When a transmitter is connected to a resistor
instead of an antenna, the resistor must be:a. wire-wound c. 1% tolerance or better
b. noninductive d. all of the above
ANS: B
17. A Class D amplifier is:
a. very efficient c. essentially pulse-durationmodulation
b. essentially pulse-width modulation d. all of
the above
ANS: D
18. To generate a SSB signal:a. start with full-carrier AM c. start with a
quadrature signalb. start with DSBSC d. all of the above
ANS: B
19. The carrier is suppressed in:a. a balanced modulator c. a frequency multiplier
b. a mixer d. none of the above
ANS: A
20. To remove one AM sideband and leave theother you could use:
a. a mechanical filter c. both a and b
b. a crystal filter d. none of the aboveANS: C
21. A direct FM modulator:
a. varies the frequency of the carrier oscillatorb. integrates the modulating signalc. both a and b
d. none of the above
ANS: A22. An indirect FM modulator:
a. requires a varactor in the carrier oscillatorb. varies the phase of the carrier oscillatorc. both a and b
d. none of the aboveANS: B
23. AFC stands for:a. Amplitude to Frequency Conversion c.
Automatic Frequency Control
b. Automatic Frequency Centering d. AudioFrequency Control
ANS: C24. Frequency multipliers are:a. essentially balanced modulators c. essentially
mixers
b. essentially Class C amplifiers d. none of the
aboveANS: B25. With mixing:
a. the carrier frequency can be raisedb. the carrier frequency can be lowered
c. the carrier frequency can be changed to anyrequired valued. the deviation is altered
ANS: C
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COMPLETION
1. The accuracy and stability of a transmitterfrequency is fixed by the
____________________ oscillator.
ANS: carrier
2. In the USA, the ____________________ sets
requirements for accuracy and stability of atransmitter's
frequency.ANS: FCC
3. In Canada, _________________________
sets requirements for accuracy and stability of atransmitter'sfrequency.
ANS: Industry Canada
4. Frequency ____________________ is theability of a transmitter to change frequency
without a lot of
retuning.ANS: agility
5. Power output of SSB transmitters is rated by
____________________.ANS: PEP6. Reducing the dynamic range of a modulating
signal is called ____________________.
ANS: compression7. The opposite of compression is called
____________________.ANS: expansion8. ALC is a form of ____________________.
ANS: compression9. High-level modulation allows the RF
amplifiers to operate more____________________.
ANS: efficiently
10. Low-level modulation requires the RFamplifiers to be ____________________.
ANS: linear11. To isolate the oscillator from load changes, a
____________________ stage is used.
ANS: buffer
12. The peak collector voltage in a Class C RF
amplifier is ____________________ than theDC supplyvoltage.
ANS: higher13. Most practical transmitters are designed to
operate into a ____________________-ohmload.ANS: 50
14. Transmitters built with transistor RF
amplifiers often use a ____________________network forimpedance matching.
ANS: T
15. Matching networks also act as filters to help
reduce ____________________ levels.ANS: harmonic
16. Severe impedance ____________________can destroy a transmitter's output stage.
ANS: mismatch
17. Transceivers combine a transmitter and a____________________ into one "box".ANS: receiver
18. To allow a high modulation percentage, it is
common to modulate the____________________ as well as
the power amplifier in transistor modulators.
ANS: driver19. Pulse-width modulation is the same as pulse-
____________________ modulation.
ANS: duration20. Switching amplifiers are sometimes calledClass ____________________ amplifiers.
ANS: D
21. Because the sideband filter in a SSBtransmitter is fixed, ____________________ is
used to operate atmore than one frequency.ANS: mixing
22. To generate a SSB signal, it is common tostart with a ____________________ signal.
ANS: DSBSC23. Indirect FM is derived from
____________________ modulation.
ANS: phase24. Using a varactor to generate FM is an
example of a ____________________modulator.ANS: reactance
25. The modern way to make a stable VFO is to
make it part of a ____________________ loop.
ANS: phase-lockedSHORT ANSWER
1. If a 50-MHz oscillator is accurate to within
0.001%, what is the range of possiblefrequencies?
ANS:
50 MHz s500 hertz
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2. What is the efficiency of a 100-watt mobile
transmitter if it draws 11 amps from a 12-voltcar battery?ANS:
75.8%
3. The power amplifier of an AM transmitter
draws 100 watts from the power supply with nomodulation.
Assuming high-level modulation, how muchpower does the modulation amplifier deliver for
100%
modulation?ANS:50 watts
4. If the final RF amplifier of an AM transmitter
is powered by 100 volts DC, what is themaximum
collector voltage at 100% modulation?
ANS:400 volts
5. Suppose the output of a balanced modulator
has a center frequency of 10 MHz. The audiomodulationfrequency range is 1 kHz to 10 kHz. To pass the
USB, what should be the center frequency of an
idealcrystal filter?
ANS:10.005 MHz6. Suppose you have generated a USB SSB
signal with a nominal carrier frequency of 10MHz. What is the
minimum frequency the SSB signal can bemixed with so that the output signal has a
nominal carrier
frequency of 50 MHz?ANS:
40 MHz7. Suppose you have an FM modulator that putsout 1 MHz carrier with a 100-hertz deviation. If
frequency
multiplication is used to increase the deviation to
400 hertz, what will be the new carrierfrequency?ANS:
4 MHz8. Suppose you had an FM signal with a carrier
of 10 MHz and a deviation of 10 kHz. Explainhow youcould use it to get an FM signal at 100 MHz
with a deviation of 20 kHz.
ANS:
First, put the signal through a frequency doublerto get a 20-MHz carrier with a 20-kHz deviation.Then
mix that signal with an 80-MHz carrier to
generate a 100-MHz carrier with 20-kHz
deviation.
Chapter 6: ReceiversMULTIPLE CHOICE
1. The two basic specifications for a receiverare:a. the sensitivity and the selectivity
b. the number of converters and the number ofIFs
c. the spurious response and the trackingd. the signal and the noise
ANS: A
2. The superheterodyne receiver was inventedby:
a. Foster c. Armstrongb. Seeley d. HertzANS: C
3. Trimmers and padders are:a. two types of adjusting tools c. small
adjustable inductors
b. small adjustable resistors d. small adjustablecapacitorsANS: D
4. "Skin effect" refers to:
a. the way radio signals travel across a flatsurface
b. the tissue-burning effect of a strong RF signal
c. the increase of wire resistance with frequency
d. none of the aboveANS: C
5. The "front end" of a receiver can include:a. the tuner c. the mixer
b. the RF amplifier d. all of the above
ANS: D
6. "IF" stands for:a. intermediate frequency c. indeterminate
frequencyb. intermodulation frequency d. image frequency
ANS: A7. AGC stands for:
a. Audio Gain Control c. Active Gain Controlb. Automatic Gain Control d. Active GainConversion
ANS: B
8. The frequency of the local oscillator:
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a. is above the RF frequency
b. is below the RF frequencyc. can be either above of below the RFfrequency
d. is fixed, typically at 455 kHz.
ANS: C
9. The local oscillator and mixer are combinedin one device because:
a. it gives a greater reduction of spuriousresponses
b. it increases sensitivity
c. it increases selectivityd. it is cheaperANS: D
10. Basically, sensitivity measures:
a. the weakest signal that can be usefullyreceived
b. the highest-frequency signal that can be
usefully receivedc. the dynamic range of the audio amplifier
d. none of the above
ANS: A11. Basically, selectivity measures:a. the range of frequencies that the receiver can
select
b. with two signals close in frequency, theability to receive one and reject the other
c. how well adjacent frequencies are separatedby the demodulatord. how well the adjacent frequencies are
separated in the mixerANS: B
12. When comparing values for shape factor:a. a value of 1.414 dB is ideal c. a value of 1.0 is
ideal
b. a value of 0.707 is ideal d. there is no idealvalue
ANS: C13. When comparing values for shape factor:a. a value of 2 is better than a value of 4 c. both
values are basically equivalent
b. a value of 4 is better than a value of 2 d. none
of the aboveANS: A14. Distortion in a receiver can occur in:
a. the mixer c. the IF amplifiersb. the detector d. all of the above
ANS: D15. Phase distortion is important in:a. voice communications systems c.
monochrome video receivers
b. color video receivers d. all of the above
ANS: B16. The response of a receiver to weak signals isusually limited by:
a. the AGC c. the dynamic range of the receiver
b. noise generated in the receiver d. the type of
detector circuit being usedANS: B
17. Image frequencies occur when two signals:a. are transmitted on the same frequency
b. enter the mixer, with one being a reflected
signal equal to the IF frequencyc. enter the mixer, one below and one above thelocal oscillator by a difference equal to the
IF
d. enter the mixer, and the difference betweenthe two signals is equal to twice the IF
ANS: C
18. An image must be rejected:a. prior to mixing c. prior to detection
b. prior to IF amplification d. images cannot be
rejectedANS: A19. Image frequency problems would be reduced
by:
a. having an IF amplifier with the proper shapefactor
b. having a wideband RF amplifier after themixerc. having a narrowband RF amplifier before the
mixerd. none of the above
ANS: C20. A common AM detector is the:
a. PLL c. ratio detector
b. envelope detector d. all of the aboveANS: B
21. An FM detector is the:a. PLL c. quadrature detector
b. ratio detector d. all of the above
ANS: D
22. Germanium diodes are used in AM detectors
because:a. they are faster than silicon diodes
b. they are cheaper than silicon diodes
c. they minimize distortion from nonlinearityd. all of the above
ANS: C23. A common SSB detector is:a. a PLL c. a BFO
b. a diode d. a product detector
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ANS: D
24. BFO stands for:a. Beat Frequency Oscillator c. BipolarFrequency Oscillator
b. Barrier Frequency Oscillator d. Bistable
Frequency Oscillator
ANS: A25. To demodulate both SSB and DSBSC, you
need to:a. use a Foster-Seeley discriminator
b. reinject the carrier
c. use double conversiond. use one diode for SSB and two diodes forDSBSC
ANS: B
26. Which would be best for DSBSC:a. carrier detection c. envelope detection
b. coherent detection d. ratio detection
ANS: B27. An FM detector that is not sensitive to
amplitude variations is:
a. Foster-Seeley detector c. a PLL detectorb. a quadrature detector d. all of the aboveANS: C
28. The function of a limiter is:
a. to remove amplitude variations c. to limitdynamic range
b. to limit spurious responses d. to limit noiseresponseANS: A
29. Suppressing the audio when no signal ispresent is called:
a. AGC c. AFCb. squelch d. limiting
ANS: B
30. LNA stands for:a. Limited-Noise Amplifier c. Low-Noise Audio
b. Low-Noise Amplifier d. Logarithmic NoiseAmplificationANS: B
31. AFC stands for:
a. Audio Frequency Compensator c. Automatic
Frequency Controlb. Autodyne Frequency Compensation d.Autonomous Frequency Control
ANS: C32. The function of AFC is:
a. maintain a constant IF frequencyb. match the local oscillator to the receivedsignal
c. lock the discriminator to the IF frequency
d. none of the above
ANS: B33. SAW stands for:a. Symmetrical Audio Wave c. Silicon-Activated
Wafer
b. Surface Acoustic Wave d. Software-Activated
WaveANS: B
34. The important property of a SAW is:a. it stabilizes the audio in a receiver c. it is a
stable bandpass filter
b. it allows software radios to be built d. none ofthe aboveANS: C
35. The main function of the AGC is to:
a. keep the gain of the receiver constantb. keep the gain of the IF amplifiers constant
c. keep the input to the detector at a constant
amplituded. all of the above
ANS: C
36. DSP stands for:a. Dynamic Signal Properties c. Distorted SignalPacket
b. Direct Signal Phase d. Digital Signal
ProcessorANS: D
37. SINAD stands for:a. Sinusoidal Amplitude Distortion
b. Signal and Noise Amplitude Distortion
c. Signal-plus-Noise-to-Noise Ratiod. Signal-plus-Noise and Distortion-to-Noise
and Distortion RatioANS: D
38. TRF stands for:
a. Tuned Radio Frequency c. Transmitted RadioFrequency
b. Tracking Radio Frequency d. Tuned ReceiverFunctionANS: ACOMPLETION
1. Almost all modern receivers use the
_________________________ principle.ANS: superheterodyne2. The first radio receiver of any kind was built
in the year ____________________.ANS: 1887
3. When two tuned circuits____________________ each other, it meansthat when the frequency of one is
adjusted, the other changes with it.
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ANS: track
4. The ____________________ effect causesthe resistance of wire to increase with frequency.ANS: skin
5. The superhet was invented in the year
____________________.
ANS: 19186. In a receiver, the ____________________
refers to the input filter and RF stage.ANS: front end
7. In a superhet, the output of the
____________________ goes to the IFamplifiers.ANS: mixer
8. In a superhet, the ____________________
frequency is the difference between the localoscillator
frequency and the received signal frequency.
ANS:intermediate
IF
9. The ____________________ circuit adjuststhe gain of the IF amplifiers in response to signalstrength.
ANS: AGC
10. An ____________________ converter usesthe same transistor for both the local oscillator
and the mixer.ANS: autodyne11. In low-side injection, the local oscillator is
____________________ than the receivedsignal frequency.
ANS: lower12. ____________________ is the ability of a
receiver to separate two signals that are close to
each other infrequency.
ANS: Selectivity13. ____________________ is the ability of areceiver to receive and successfully demodulate
a very weak
signal.
ANS: Sensitivity14. A receiver with two different IF frequenciesis called a double-____________________
receiver.ANS: conversion
15. A multiple-conversion receiver will havebetter rejection of ____________________frequencies.
ANS: image
16. A demodulator is also called a
____________________.ANS: detector17. An ____________________ detector uses a
diode to half-wave rectify an AM signal.
ANS: envelope
18. A ____________________ detector is usedfor SSB signals.
ANS: product19. A BFO produces a locally generated
____________________.
ANS: carrier20. A DSBSC signal requires a
____________________ detection circuit.
ANS: coherent
21. FM detectors have a characteristic ____________________-shaped curve.
ANS: S
22. While still commonly found, the Foster-Seeley and ratio detectors are
____________________.
ANS: obsolescent23. Unlike the PLL detector, the quadraturedetector is sensitive to changes in
____________________ of the
input signal.ANS: amplitude
24. A dual-____________________ MOSFETis useful for AGC.ANS: gate
25. Diode mixers are too____________________ to be practical in most
applications.ANS: noisy
26. The IF amplifiers in an AM receiver must be
Class ____________________.ANS: A
27. A double-tuned IF transformer is usually____________________ coupled for theresponse to have a flat
top and steep sides.
ANS: over
28. Multiple IF stages can be____________________-tuned to increase thebandwidth.
ANS: stagger29. Compared to tuned circuits, ceramic and
crystal IF filters do not require____________________.ANS: adjustment
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30. Up-conversion is when the output of the
mixer is a ____________________ frequencythan the incomingsignal.
ANS: higher
31. In a block converter, the frequency of the
first local oscillator is ____________________.ANS:
fixedconstant
32. Typically, AGC reduces the gain of the
____________________ amplifiers.ANS: IF33. An ____________________-meter is
designed to indicate signal strength in many
communicationsreceivers.
ANS: S
34. The effectiveness of FM____________________ is measured by a
receivers quieting sensitivity.
ANS: limiting35. A ____________________ refers to anykind of FM or PM detector.
ANS: discriminatorSHORT ANSWER
1. Suppose the bandwidth of a tuned circuit is 10
kHz at 1 MHz. Approximately what bandwidthwould youexpect it to have at 4 MHz?
ANS:20 kHz
2. Using high-side injection for a 1-MHz IF,what is the frequency of the local oscillator
when the receiver
is tuned to 5 MHz?ANS:
6 MHz3. An IF filter has a60 dB bandwidth of 25kHz and a 6 dB bandwidth of 20 kHz. What is
the shape
factor value?
ANS:1.254. Suppose a receiver uses a 5-MHz IF
frequency. Assuming high-side injection, whatwould be the image
frequency if the receiver was tuned to 50 MHz?ANS:60 MHz
5. Suppose a SSB receiver requires an injected
frequency of 1.5 MHz. What would be theacceptablefrequency range of the BFO if the maximum
acceptable baseband shift is 100 hertz?
ANS:
1.5 MHz s100 hertz6. The transformer of a double-tuned IF
amplifier has a Qof 25 for both primary andsecondary. What valueofkc do you need to achieve optimal coupling?
ANS:
0.067. What value of transformer coupling would adouble-tuned 10-MHz IF amplifier with optimal
coupling
need to get a bandwidth of 100 kHz?ANS:
0.01
Chapter 7: Digital CommunicationsMULTIPLE CHOICE
1. The first digital code was the:a. ASCII code c. Morse code
b. Baudot code d. none of the above
ANS: C2. In digital transmission, signal degradation can
be removed using:a. an amplifier c. a regenerative repeater
b. a filter d. all of the above
ANS: C3. TDM stands for:
a. Time-Division Multiplexing c. Ten-DigitalManchester
b. Time-Domain Multiplexing d. Ten Dual-
ManchesterANS: A
4. Hartley's Law is:a. I= ktB c. C=B log2(1 + S/N)
b. C= 2B log2Md. SR = 2fmax
ANS: A
5. The Shannon-Hartley theorem is:
a. I= ktB c. C=B log2(1 + S/N)b. C= 2B log2Md. SR = 2fmax
ANS: B
6. The Shannon Limit is given by:a. I= ktB c. C=B log2(1 + S/N)
b. C= 2B log2Md. SR = 2fmaxANS: C
7. The Nyquist Rate can be expressed as:
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a. I= ktB c. C=B log2(1 + S/N)
b. C= 2B log2Md. SR = 2fmaxANS: D8. Natural Sampling does not use:
a. a sample-and-hold circuit c. a fixed sample
rate
b. true binary numbers d. an analog-to-digitalconverter
ANS: A9. Which is true about aliasing and foldover
distortion?
a. They are two types of sampling error.b. You can have one or the other, but not both.c. Aliasing is a technique to prevent foldover
distortion.
d. They are the same thing.ANS: D
10. Foldover distortion is caused by:
a. noise c. too few samples per secondb. too many samples per second d. all of the
above
ANS: C11. The immediate result of sampling is:a. a sample alias c. PCM
b. PAM d. PDM
ANS: B12. Which of these is not a pulse-modulation
technique:a. PDM c. PPM
b. PWM d. PPS
ANS: D13. Quantizing noise (quantization noise):
a. decreases as the sample rate increasesb. decreases as the sample rate decreases
c. decreases as the bits per sample increases
d. decreases as the bits per sample decreasesANS: C
14. The dynamic range of a system is the ratioof:a. the strongest transmittable signal to the
weakest discernible signal
b. the maximum rate of conversion to the
minimum rate of conversionc. the maximum bits per sample to the minimum
bits per sample
d. none of the aboveANS: A
15. Companding is used to:a. compress the range of base-band frequencies
b. reduce dynamic range at higher bit-rates
c. preserve dynamic range while keeping bit-rate
lowd. maximize the useable bandwidth in digitaltransmission
ANS: C
16. In North America, companding uses:
a. the Logarithmic Law c. the ELaw (alpha law)b. the A Law d. the QLaw (mu law)
ANS: D17. In Europe, companding uses:
a. the Logarithmic Law c. the ELaw (alpha law)
b. the A Law d. the QLaw (mu law)ANS: B
18. Codec stands for:
a. Coder-Decoder c. Code-Compressionb. Coded-Carrier d. none of the above
ANS: A19. A typical codec in a telephone system sends
and receives:a. 4-bit numbers c. 12-bit numbers
b. 8-bit numbers d. 16-bit numbersANS: B20. Compared to PCM, delta modulation:
a. transmits fewer bits per sample c. can suffer
slope overloadb. requires a much higher sampling rate d. all of
the aboveANS: D21. In delta modulation, "granular noise" is
produced when:
a. the signal changes too rapidly c. the bit rate istoo high
b. the signal does not change d. the sample is toolarge
ANS: B22. Compared to PCM, adaptive delta
modulation can transmit voice:a. with a lower bit rate but reduced quality c.
only over shorter distancesb. with a lower bit rate but the same quality d.
only if the voice is band-limited
ANS: B
23. Which coding scheme requires DCcontinuity:
a. AMI c. unipolar NRZb. Manchester d. bipolar RZ
ANS: C24. Manchester coding:
a. is a biphase code
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b. has a level transition in the middle of every bit
periodc. provides strong timing informationd. all of the above
ANS: D
25. The number of framing bits in DS-1 is:
a. 1 c. 4b. 2 d. 8
ANS: A26. Framing bits in DS-1 are used to:
a. detect errors c. synchronize the transmitter
and receiverb. carry signaling d. all of the aboveANS: C
27. So-called "stolen" bits in DS-1 are used to:
a. detect errors c. synchronize the transmitterand receiver
b. carry signaling d. all of the above
ANS: B28. The number of bits per sample in DS-1 is:
a. 1 c. 4
b. 2 d. 8ANS: D29. The number of samples per second in DS-1
is:
a. 8 k c. 64 k
b. 56 k d. 1.544 v106ANS: A
30. The bit rate for each channel in DS-1 is:a. 1.544 Mb/s c. 56 kb/s
b. 64 kb/s d. 8 kb/sANS: B
31. In DS-1, bits are transmitted over a T-1 cable
at:a. 1.544 MB/s c. 56 kb/s
b. 64 kb/s d. 8 kb/s
ANS: A32. A T-1 cable uses:
a. Manchester coding c. NRZ codingb. bipolar RZ AMI coding d. pulse-width coding
ANS: B33. The number of frames in a superframe is:
a. 6 c. 24b. 12 d. 48ANS: B34. A typical T-1 line uses:
a. twisted-pair wire c. fiber-optic cable
b. coaxial cable d. microwaveANS: A
35. "Signaling" is used to indicate:a. on-hook/off-hook condition c. ringing
b. busy signal d. all of the above
ANS: D36. A vocoder implements compression by:a. constructing a model of the transmission
medium
b. constructing a model of the human vocal
systemc. finding redundancies in the digitized data
d. using lossless techniquesANS: B
37. Compared to standard PCM systems, the
quality of the output of a vocoder is:a. much better c. about the same
b. somewhat better d. not as good
ANS: DCOMPLETION
1. Digitizing a signal often results in
____________________ transmission quality.
ANS:improved
better
2. To send it over an analog channel, a digitalsignal must be ____________________ onto acarrier.
ANS: modulated
3. To send it over a digital channel, an analogsignal must first be ____________________.
ANS: digitized4. In analog channels, the signal-to-noise ratio ofan analog signal gradually
____________________ as thelength of the channel increases.
ANS:decreases
gets worse
5. The ____________________ value of a pulseis the only information it carries on a digital
channel.ANS: binary6. A ____________________ repeater is used to
restore the shape of pulses on a digital cable.
ANS: regenerative
7. There are techniques to detect and____________________ some errors in digitaltransmission.
ANS: correct8. Converting an analog signal to digital form is
another source of ____________________ indigitaltransmission systems.
ANS:
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error
noise9. ____________________-divisionmultiplexing is easily done in digital
transmission.
ANS: Time
10. All practical communications channels areband-____________________.
ANS: limited11. ____________________ Law gives the
relationship between time, information capacity,
and bandwidth.ANS: Hartley's12. Ignoring noise, the
_________________________ theorem gives
the maximum rate of data transmissionfor a given bandwidth.
ANS: Shannon-Hartley
13. The ____________________ limit gives themaximum rate of data transmission for a given
bandwidth
and a given signal-to-noise ratio.ANS: Shannon14. ____________________ sampling is done
without a sample-and-hold circuit.
ANS: Natural15. The ____________________ Rate is the
minimum sampling rate for converting analogsignals to digitalformat.
ANS: Nyquist16. ____________________ distortion occurs
when an analog signal is sampled at too slow arate.
ANS: Foldover
17. ____________________ means that higherfrequency baseband signals from the transmitter
"assume theidentity" of low-frequency baseband signals atthe receiver when sent digitally.
ANS: Aliasing
18. The output of a sample-and-hold circuit is a
pulse-____________________ modulatedsignal.ANS: amplitude
19. ____________________ modulation is themost commonly used digital modulation
scheme.ANS: Pulse-code
20. ____________________ noise results from
the process of converting an analog signal intodigital format.ANS: Quantizing
21. ____________________ is used to preserve
dynamic range using a reasonable bandwidth.
ANS: Companding22. In North America, compression is done
using the ____________________-law equation.ANS:
Q
mu
23. In Europe, compression is done using the ____________________-law equation.ANS: A
24. A ____________________ is an IC that
converts a voice signal to PCM and vice versa.ANS: codec
25. In a PCM system, the samples of the analogsignal are first converted to
____________________ bitsbefore being compressed to 8 bits.
ANS: 1226. The number of bits per sample transmitted indelta modulation is ____________________.
ANS:
1one
27. Delta modulation requires a____________________ sampling rate than
PCM for the same quality ofreproduction.
ANS: higher
28. ____________________ noise is producedby a delta modulator if the analog signal doesn'tchange.
ANS: Granular29. In delta modulation,
____________________ overload can occur ifthe analog signal changes too fast.
ANS: slope30. The ____________________ size varies in
adaptive delta modulation.ANS: step31. Adaptive delta modulation can transmitPCM-quality voice at about
____________________ the bit rate
of PCM.ANS: half
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32. Unipolar NRZ is not practical because most
channels do not have ____________________continuity.ANS: DC
33. In AMI, binary ones are represented by a
voltage that alternates in
____________________.ANS: polarity
34. Long strings of ____________________should be avoided in AMI.
ANS: zeros
35. Manchester code has a level____________________ in the center of eachbit period.
ANS: transition
36. Manchester coding provides____________________ information regardless
of the pattern of ones and
zeros.ANS: timing
37. There are ____________________ channels
in a DS-1 frame.ANS: 2438. DS-1 uses a ____________________ bit to
synchronize the transmitter and receiver.
ANS: framing39. In DS-1, each channel is sampled
____________________ times per second.ANS: 800040. Data is carried over a T-1 line at a rate of
____________________ bits per second.ANS: 1.544 v10641. A group of 12 DS-1 frames is called a
____________________.ANS: superframe42. From a group of twelve frames, signaling
bits are "stolen" from every ____________________ frame.
ANS: sixth43. ____________________ compression
transmits all the data in the original signal butuses fewer bits to do
it.ANS: LosslessSHORT ANSWER
1. Use Hartley's Law to find how much time it
would take to send 100,000 bits over a channel
with abandwidth of 2,000 hertz and a channel constant
ofk= 10.ANS:
5 seconds
2. Use the Shannon-Hartley theorem to find thebandwidth required to send 12,000 bits persecond if the
number of levels transmitted is 8.
ANS:
2000 hertz3. What is the Shannon Limit of a channel that
has a bandwidth of 4000 hertz and a signal-to-noise ratio of
15?
ANS:16 kbps4. What is the minimum required number of
samples per second to digitize an analog signal
with frequencycomponents ranging from 300 hertz to 3300
hertz?
ANS:6600 samples/second
5. What is the approximate dynamic range, in
dB, of a linear PCM system that uses 12 bits persample?ANS:
74 dB
6. What is the approximate data rate for a systemusing 8 bits per sample and running at 8000
samples persecond?ANS:
64 kbps7. If bits were "stolen" from every DS-1 frame,
what would the useable data-rate be for eachchannel in the
frame?
ANS:56 kbps
8. Assuming maximum input and outputvoltages of 1 volt, what is the output voltage of a
Q-law compressor
if the input voltage is 0.388 volt?ANS:
0.833 volt
Chapter 8: The Telephone SystemMULTIPLE CHOICE
1. DTMF stands for:
a. Digital Telephony Multiple Frequency c.Dual-Tone Multifrequency
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b. Dial Tone Master Frequency d. Digital Trunk
Master FrequencyANS: C2. PSTN stands for:
a. Public Switched Telephone Network c.
Primary Service Telephone Network
b. Private Switched Telephone Network d.Primary Service Telephone Numbers
ANS: A3. POTS stands for:
a. Private Office Telephone System c. Primary
Operational Test Systemb. Primary Office Telephone Service d. PlainOld Telephone Service
ANS: D
4. LATA stands for:a. Local Access and Transport Area c. Local
Area Telephone Access
b. Local Access Telephone Area d. Local AreaTransport Access
ANS: A
5. A LATA is a:a. a local calling area c. a way of accessing atandem office
b. a type of digital local network d. a way of
accessing a central officeANS: A
6. Central offices are connected by:a. local loops c. both a and b
b. trunk lines d. none of the above
ANS: B7. Local loops terminate at:
a. a tandem office c. a central officeb. a toll station d. an interexchange office
ANS: C
8. Call blocking:a. cannot occur in the public telephone network
b. occurs on the local loop when there is anelectrical power failurec. occurs only on long-distance cables
d. occurs when the central office capacity is
exceeded
ANS: D9. In telephony, POP stands for:a. Post Office Protocol c. Power-On Protocol
b. Point Of Presence d. none of the aboveANS: B
10. The cable used for local loops is mainly:a. twisted-pair copper wire c. coaxial cable
b. shielded twisted-pair copper wire d. fiber-
optic
ANS: A
11. FITL stands for:a. Framing Information for Toll Loops c.Framing In The Loop
b. Fiber In the Toll Loop d. Fiber-In-The-Loop
ANS: D
12. Loading coils were used to:a. increase the speed of the local loop for digital
datab. reduce the attenuation of voice signals
c. reduce crosstalk
d. provide C-type conditioning to a local loopANS: B13. DC current flows through a telephone:
a. when it is on hook c. as long as it is attached
to a local loopb. when it is off hook d. only when it is ringing
ANS: B
14. The range of DC current that flows through atelephone is:
a. 20 QA to 80 QA c. 2 mA to 8 mA
b. 200 QA to 800 QA d. 20 mA to 80 mAANS: D
15. The separation of control functions from
signal switching is known as:a. step-by-step switching control c. common
control
b. crossbar control d. ESS
ANS: C16. The typical voltage across a telephone when
on-hook is:a. 48 volts DC c. 90 volts DC
b. 48 volts, 20 hertz AC d. 90 volts, 20 hertz AC
ANS: A
17. The typical voltage needed to "ring" atelephone is:a. 48 volts DC c. 90 volts DC
b. 48 volts, 20 hertz AC d. 90 volts, 20 hertz AC
ANS: D18. The bandwidth of voice-grade signals on atelephone system is restricted in order to:
a. allow lines to be "conditioned" c. allow
signals to be multiplexedb. prevent "singing" d. all of the above
ANS: C19. VNL stands for:a. voltage net loss c. via net loss
b. volume net loss d. voice noise level
ANS: C20. Signal loss is designed into a telephone
system to:
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a. eliminate reflections c. improve signal-to-
noise ratiob. prevent oscillation d. reduce powerconsumption
ANS: B
21. The reference noise level for telephony is:
a. 1 mW c. 1 pWb. 0 dBm d. 0 dBr
ANS: C22. The number of voice channels in a basic
FDM group is:
a. 6 c. 24b. 12 d. 60ANS: B
23. Basic FDM groups can be combined into:
a. supergroups c. jumbogroupsb. mastergroups d. all of the above
ANS: D
24. In telephone system FDM, voice is put on acarrier using:
a. SSB c. PDM
b. DSBSC d. PCMANS: A25. PABX stands for:
a. Power Amplification Before Transmission
b. Private Automatic Branch Exchangec. Public Automated Branch Exchange
d. Public Access Branch ExchangeANS: B26. SLIC stands for:
a. Single-Line Interface Circuit c. SubscriberLine Interface Card
b. Standard Line Interface Card d. StandardLocal Interface Circuit
ANS: C
27. In DS-1, bits are "robbed" in order to:a. provide synchronization c. cancel echoes
b. carry signaling d. check for errorsANS: B28. "Bit-stuffing" is more formally called:
a. compensation c. justification
b. rectification d. frame alignment
ANS: C29. ISDN stands for:a. Integrated Services Digital Network c.
Integrated Services Data Networkb. Information Services Digital Network d.
Information Systems Digital NetworkANS: A30. Basic ISDN has not been widely adopted
because:
a. it took to long to develop
b. it is too slowc. it has been surpassed by newer technologiesd. all of the above
ANS: D
31. ADSL stands for:
a. All-Digital Subscriber Line c. AllocatedDigital Service Line
b. Asymmetrical Digital Subscriber Line d.Access to Data Services Line
ANS: B
32. Compared to ISDN, internet access usingADSL is typically:a. much faster c. much more expensive
b. about the same speed d. none of the above
ANS: ACOMPLETION
1. A ____________________ is a local calling
area.ANS: LATA
2. Central offices are connected together by
____________________ lines.ANS: trunk3. One central office can be connected to another
through a ____________________ office.
ANS: tandem4. With 7-digit phone numbers,
____________________ thousand telephonescan connect to a centraloffice.
ANS: ten5. Call ____________________ is when it
becomes impossible for a subscriber to place acall due to an
overload of lines being used.
ANS: blocking6. New ____________________ switching
equipment uses TDM to combine signals.ANS: digital7. Most local loops still use
____________________ copper wire.
ANS: twisted-pair
8. As compared to a hierarchical network, a____________________ network never needsmore than one
intermediate switch.ANS: flat
9. ____________________ coils were used toreduce the attenuation of voice frequencies.ANS: Loading
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10. In a twisted-pair telephone cable, the red
wire is called ____________________.ANS: ring11. In a twisted-pair telephone cable, the green
wire is called ____________________.
ANS: tip
12. Of the red and green 'phone wires, the____________________ wire is positive with
respect to the other.ANS: green
13. A telephone is said to have
____________________ the line when thecentral office sends it dial tone.ANS: seized
14. The ____________________ functions are
provided by a SLIC.ANS: BORSCHT
15. A ____________________ coil prevents
loss of signal energy within a telephone whileallowing fullduplex
operation over a single pair of wires.
ANS: hybrid16. In a crosspoint switch, not all
____________________ can be in use at the
same time.
ANS: lines17. The old carbon transmitters generated a
relatively ____________________ signalvoltage.ANS: large
18. The generic term for Touch-Tone signalingis ____________________.
ANS: DTMF19. A ____________________ line provides
more bandwidth than a standard line.
ANS: conditioned20. In the telephone system, amplifiers are called
____________________.ANS: repeaters21. An echo ____________________ converts a
long-distance line from full-duplex to half-
duplex operation.
ANS: suppressor22. ____________________ weighting is anattempt to adjust the noise or signal level to the
response of atypical telephone receiver.
ANS: C-message23. In FDM telephony, the modulation is usually
____________________.
ANS:
SSB
SSBSC24. In FDM telephony, ____________________
bands separate the channels in a group.
ANS: guard
25. Because of "bit robbing", a channel in a DS-
1 frame allows only ____________________kbps when
used to send digital data.ANS: 56
26. A ____________________ is a group of 12
DS-1 frames with signaling information in thesixth andtwelfth frames.
ANS: superframe
27. In DS-1C, ____________________ bits areused to compensate for differences between
clock rates.
ANS: stuff28. Busy and dial tone are referred to as
____________________ signals because they
use the same pair ofwires as the voice signal.ANS: in-channel
29. SS7 is the current version of
_________________________ signaling.ANS: common-channel
30. SS7 is a ____________________-switcheddata network.ANS: packet
31. In ISDN, the ____________________channel is used for common-channel signaling.
ANS: D32. In ISDN, the ____________________
channels are used for voice or data.
ANS: B33. Terminal equipment especially designed for
ISDN is designated ____________________equipment.ANS: TE1
34. The A in ADSL stands for
____________________.
ANS: asymmetrical35. In ADSL, the speed from the network to thesubscriber is ____________________ than the
speed in theopposite direction.
ANS:greaterfaster
SHORT ANSWER
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1. For a certain telephone, the DC loop voltage
is 48 V on hook and 8 V off hook. If the loopcurrent is 40mA, what is the DC resistance of the local loop?
ANS:
1000 ohms
2. For a certain telephone, the DC loop voltageis 48 V on hook and 8 V off hook. If the loop
current is 40mA, what is the DC resistance of the telephone?
ANS:
200 ohms3. Which two DTMF tones correspond to thedigit "1"? (Use the table in the text.)
ANS:
697 Hz and 1209 Hz4. Calculate the dB of VNL required for a
channel with a 3 ms delay.
ANS:1 dB
5. If a telephone voice signal has a level of 0
dBm, what is its level in dBrn?ANS:90 dBrn
6. A telephone test-tone has a level of 80 dBrn at
a point where the level is +5dB TLP. If C-weighting
produces a 10-dB loss, what would the signallevel be in dBrnc0?ANS:
65 dBrnc TLP
Chapter 9: Data TransmissionMULTIPLE CHOICE
1. In practical terms, parallel data transmission is
sent:a. over short distances only c. over any distance
b. usually over long distances d. usually over a
coaxial cable
ANS: A2. The five-level teletype code was invented by:
a. the Morkum Company c. Western Unionb. the Teletype Company d. Emile Baudot
ANS: D3. Data codes are also called:
a. character codes c. they do not have any othername
b. character sets d. both a and b
ANS: C
4. Digital data that is not being used to carry
characters is called:a. FIGS data c. numerical data
b. binary data d. all of the above
ANS: B
5. Character codes include:
a. alphanumeric characters c. graphic controlcharacters
b. data link control characters d. all of the aboveANS: D
6. ASCII stands for:
a. American Standard Character-set 2b. American Standard Code for InformationInterchange
c. American Standard Code 2
d. Alphanumeric Standard Code for InformationInterchange
ANS: B
7. BS, FF, and CR are examples of:a. nonstandard character codes c. control
characters
b. escape characters d. none of the aboveANS: C8. LF stands for:
a. Line Feed c. Line Forward
b. Link Feed d. Link ForwardANS: A
9. UART stands for:a. Universal Asynchronous Receiver-Transmitter
b. Unidirectional Asynchronous Receiver-Transmitter
c. Unaltered Received Textd. Universal Automatic Receiver for Text
ANS: A
10. In asynchronous transmission, thetransmitter and receiver are:
a. frame-by-frame synchronized using the databitsb. frame-by-frame synchronized using a
common clock
c. frame-by-frame synchronized using the start
and stop bitsd. not synchronized at all, hence the name"asynchronous"
ANS: C11. In asynchronous transmission, the time
between consecutive frames is:a. equal to zero c. equal to the start and stop bit-times
b. equal to one bit-time d. not a set length
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ANS: D
12. In synchronous transmission, the frames are:a. about the same length as ten asynchronousframes
b. much longer than asynchronous frames
c. 128 bytes long
d. 1024 bytes longANS: B
13. Synchronous transmission is used because:a. no start and stop bits means higher efficiency
b. it is cheaper than asynchronous since no
UARTS are requiredc. it is easier to implement than asynchronousd. all of the above
ANS: A
14. In synchronous transmission, the receiver"syncs-up" with the transmitter by using:
a. the clock bits c. the CRC bits
b. the data bits d. a separate clock lineANS: B
15. To maintain synchronization in synchronous
transmission:a. long strings of 1s and 0s must not be allowed
b. transmission must stop periodically for
resynchronization
c. the clock circuits must be precisely adjustedd. the channel must be noise-free
ANS: A16. BISYNC:a. is an IBM product c. requires the use of DLE
b. is a character-oriented protocol d. all of theabove
ANS: D17. HDLC:
a. is an IBM product c. is identical to SDLC
b. is a bit-oriented protocol d. all of the aboveANS: B
18. The use of flags in SDLC requires:a. "bit-stuffing" c. FEC
b. different flags at either end of a frame d. ARQ
ANS: A
19. The initials ARQ are used to designate:
a. automatic request for resynchronization c.automatic receiver queue
b. automatic request for retransmission d.
automatic request for queueANS: B
20. ARQ is used to:a. correct bit errors c. put data into a temporary
buffer
b. correct synchronization problems d. none of
the aboveANS: A21. FEC stands for:
a. Fixed Error Control c. Forward Error
Correction
b. Forward Error Control d. False ErrorCondition
ANS: C22. VRC is another name for:
a. FEC c. LRC
b. ARQ d. parityANS: D23. CRC stands for:
a. Control Receiver Code c. Cyclic Redundancy
Checkb. Correct Received Character d. Cycle Repeat
Character
ANS: C24. Huffman codes:
a. allow errors to be detected but not corrected
b. allow errors to be detected and correctedc. allow alphanumeric data to be correctedd. allow alphanumeric data to be compressed
ANS: D
25. Run-length encoding is used to:a. encrypt data c. correct data
b. compress data d. none of the aboveANS: B26. Public-key encryption:
a. allows the use of digital signatures c. avoidsthe "password problem"
b. is used to convey symmetric keys d. all of theabove
ANS: D
27. SDLC stands for:a. Synchronous Data Link Control c.
Synchronous Data Link Characterb. Synchronous Data Line Control d.Synchronous Data Line Character
ANS: A
28. HDLC is:
a. a bit-oriented protocol c. an ISO standardb. based on SDLC d. all of the aboveANS: DCOMPLETION
1. Parallel transmission can be used only for
____________________ distances.ANS: short2. The term "baud" was named after Emil
____________________.
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ANS: Baudot
3. Data codes are also called ____________________ codes.ANS: character
4. The ____________________ code is a 7-bit
code commonly used in communication between
personalcomputers.
ANS: ASCII5. The two letters ____________________
designate the code character used to advance a
printer to the nextpage.ANS: FF
6. An asynchronous frame begins with the
____________________ bit.ANS: start
7. An asynchronous frame ends with the
____________________ bit.ANS: stop
8. At the end of an asynchronous frame, the line
will be at the ____________________ level.ANS:mark
binary 1
9. An integrated circuit called a____________________ is used in an
asynchronous communication systemto convert between parallel and serial data.ANS: UART
10. When receiving digital data,____________________ are used to hold data
until they can be read.ANS: buffers
11. Synchronous communication is more
____________________ than asynchronoussince there are fewer
"overhead" bits.ANS: efficient12. There must be sufficient 1-to-0
____________________ to maintain
synchronization in synchronous
transmission.ANS: transitions13. Clock sync is derived from the stream of
____________________ bits in synchronoustransmission.
ANS: data14. In the ____________________ protocol,each frame begins with at least two SYN
characters.
ANS: BISYNC
15. In HDLC, each frame starts with an 8-bit____________________.ANS: flag
16. The first eight bits of an SDLC frame are
____________________.
ANS: 0111111017. BCC stands for ____________________
check character.ANS: block
18. DLE stands for data link
____________________.ANS: escape19. HDLC uses bit-____________________ to
prevent accidental flags.
ANS: stuffing20. ____________________ errors cause many
consecutive bits to be bad.
ANS: Burst21. FEC stands for ____________________
error correction.
ANS: forward22. An ____________________ scheme correctserrors by requiring the retransmission of bad
blocks.
ANS: ARQ23. Parity fails when an
____________________ number of bits are inerror.ANS: even
24. CRC codes are particularly good at detecting____________________ errors.
ANS: burst25. Huffman coding and run-length encoding are
examples of data ____________________.
ANS: compression26. A ____________________ is an encoding
scheme that is not public in order to protect data.ANS: cipher27. A ____________________ is often used to
generate an encryption key because it is easier to
remember.
ANS: password28. If the key is ____________________enough, private-key encryption can be quite
secure.ANS: long
29. Messages cannot be____________________ using a public key.ANS: decrypted
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30. Because it is ____________________-
intensive, public-key encryption can be slow.ANS: computationSHORT ANSWER
1. How many different characters could be
encoded using a six-bit code?
ANS:64
2. What is the numerical difference betweenASCII 'a' and ASCII 'A' if you treat them as
hexadecimal (hex)
numbers?ANS:20 hex (32 decimal)
3. The ASCII codes for the characters '0' through
'9' are what hex numbers?ANS:
30H to 39H
4. If an asynchronous frame is used to sendASCII characters in the form of bytes (8 bits),
what is the
shortest time it could take to send 1000characters if each bit in a frame is 1 msec long?ANS:
10 seconds
5. Suppose an asynchronous frame holds 8 bitsof data, a parity bit, and two stop bits (it could
happen).Calculate the efficiency of the communicationsystem.
ANS:66.7%
6. Suppose a synchronous frame has 16 bits ofnon-data in the front and a 16-bit BCC at the
end. The frame
carries 1024 bytes of actual data. Calculate theefficiency of the communication system.
ANS:97.0%
Chapter 10: Local Area NetworksMULTIPLE CHOICE
1. CSMA stands for:a. Client-Server Multi-Access c. Carrier Server
Master Applicationb. Carrier Sense Multiple Access d. none of the
aboveANS: B2. The CD in CSMA/CD stands for:
a. Carrier Detection c. Collision Detection
b. Carrier Delay d. Collision Delay
ANS: C
3. The Internet is:a. a network of networks c. a very largeCSMA/CD network
b. a very large client-server network d. not really
a network at all
ANS: A4. Most LANs:
a. are based on Ethernet c. use UTP cableb. use CSMA/CD d. all of the above
ANS: D
5. Dumb terminals are still used:a. in token-passing networks
b. in networks requiring central monitoring
c. in networks that cannot provide central
monitoringd. none of the above
ANS: B
6. In a circuit-switched network:a. communication is half-duplex only
b. each channel carries only one data stream
c. connection is usually done using a bustopologyd. all of the above
ANS: B
7. Each computer on a network is called a:a. hub c. node
b. token d. circuitANS: C8. Compared to CSMA/CD systems, token-
passing rings are:a. slower c. not as widely used
b. more expensive d. all of the aboveANS: D
9. The key feature of a star network is that
individual workstations are connected to:a. a central ring c. a node
b. a central bus d. none of the aboveANS: D10. On networks, long messages are divided into
"chunks" called:
a. packets c. carriers
b. nodes d. tokensANS: A11. When two or more PCs try to access a
baseband network cable at the same time, it iscalled:
a. a collision c. excess trafficb. contention d. multiple accessANS: B
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12. When two PCs send data over a baseband
network cable at the same time, it is called:a. a collision c. excess traffic
b. contention d. multiple access
ANS: A
13. One type of network that never has a
collision is:a. CSMA c. token-passing
b. Ethernet d. all networks have collisionsANS: C
14. In an Ethernet-based network, a switch can
be used to reduce the number of:a. nodes c. packets
b. users d. collisions
ANS: D
15. The effect of too many collisions is:a. the network goes down c. the cable overheats
b. the network slows down d. data is lost
ANS: B16. MAU stands for:
a. Multistation Access Unit c. Multiple
Auxiliary Unitsb. Multiple Access Unit d. none of the aboveANS: A
17. The standard that describes Ethernet-type
networks is:a. EIA 232 c. IEEE 802.3
b. IEEE 488.1 d. CCITT ITU-EANS: C18. Ethernet was invented by:
a. IBM c. Xeroxb. INTEL d. Digital Equipment Corporation
ANS: C19. An Ethernet running at 10 Mbits / second
uses:
a. Manchester encoding c. NRZ encodingb. Three-Level encoding d. AMI encoding
ANS: A20. A 100BaseT cable uses:a. fiber-optic cable c. RG-58U coaxial cable
b. twisted-pair copper wires d. 50-ohm coaxial
cable
ANS: B21. The word "Base" in 10BaseT means:a. the cable carries baseband signals
b. the cable has a base speed of 10 Mbpsc. it can be used as the base for a backbone cable
systemd. none of the aboveANS: A
22. The reason a CSMA/CD network has a
minimum length for packets is:a. to increase the data rate
b. to prevent packets from reaching all other
nodes during transmission
c. to make sure all other nodes hear a collision in
progressd. all of the above
ANS: C23. The reason a CSMA/CD network has a
maximum length for cables is:
a. to increase the data rateb. to prevent packets from reaching all othernodes during transmission
c. to make sure all other nodes hear a collision in
progressd. all of the above
ANS: C
24. NIC stands for:a. Network Interface Card c. Network Interface
Code
b. Network Interface Cable d. Network InternalCodeANS: A
25. 10BaseT cable typically uses:
a. a BNC connector c. an RJ45 connectorb. a T connector d. an RS11 connector
ANS: C26. UTP stands for:a. Untwisted-Pair copper wire c. Uninterruptible
Terminal Packetb. Unshielded Twisted-Pair copper wire d.
Unicode Text PacketANS: B
27. Compared to twisted-pair telephone cables,
CAT-5 cables:a. are cheaper c. allow faster bit rates
b. are easier to crimp connectors onto d. all ofthe aboveANS: C
28. A hub:
a. sends incoming packets out to all other
terminals connected to itb. sends incoming packets out to specific portsc. cannot be used in an Ethernet-type network
d. are more common in token-passing networksANS: A
29. A switch:a. sends incoming packets out to all otherterminals connected to it
b. sends incoming packets out to specific ports
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c. cannot be used in an Ethernet-type network
d. are more common in token-passing networksANS: B30. An advantage of using a switch instead of a
hub is:
a. it is cheaper when used in large networks
b. it is faster when used in large networksc. it reduces the number of collisions in large
networksd. all of the above
ANS: C
31. Broadband LANs:a. modulate the data onto a carrier
b. use coaxial cables
c. are provided by cable TV companies for
Internet accessd. all of the above
ANS: D
32. Using one node in the network to hold all theapplication software is done in:
a. peer-to-peer networks c. both a and b
b. client-server networks d. none of the aboveANS: B33. Record locking is used to:
a. store records securely on a server
b. prevent multiple users from looking at adocument simultaneously
c. prevent one user from reading a record thatanother user is writing tod. none of the above
ANS: C34. The software that runs a client-server
network must be:a. UNIX-based c. multitasking
b. WINDOWS-based d. Novell certified
ANS: C35. A "thin" client is:
a. basically, a PC with no disk drives c. same asa "dumb" terminal
b. a node that rarely sends data d. all of the
above
ANS: A
COMPLETION1. A LAN is a ____________________ Area
Network.
ANS: Local2. The Internet is a network of
____________________.ANS: networks3. In a ____________________ network, all
nodes are connected to a central computer.
ANS: star
4. In a ____________________-switchednetwork, users have a dedicated channel for theduration of
communications.
ANS: circuit
5. The ____________________ of a networkdescribes how it is physically connected
together.ANS: topology
6. Ring networks often use
____________________-passing.ANS: token7. A ____________________ is a short section
of a message in digital form.
ANS: packet8. ____________________ is when two nodes
try to seize the same cable at the same time.
ANS: Contention9. A ____________________ occurs when two
nodes transmit simultaneously on the same
baseband cable.ANS: collision10. In CSMA/CD networks, all collisions must
be ____________________.
ANS: detected11. Carrier-Sense means that a node "listens" for
the cable to be ____________________ beforeusing it.ANS:
quietfree
unusedavailable
12. A "____________________" cable links
clusters of computers together.ANS: backbone
13. 100BaseT cables can reliably carry up to____________________ bits per second.ANS: 100 mega
14. In CSMA/CD, packets must hav