bollard pull analysis_21!10!15

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PROJECT No. -PTT - MODULE TRANSPORTATIONSHEET 1 of 1 REV ABY AB DATE 01/10/2010CHKD CH DATE 01/10/2010

A. TOW DESCRIPTION

B. DESIGN ASUMPTION

C. VESSEL PARTICULARSLength between perpendiculars = 330 ft. = 100.584 m.Vessel beam = 100 ft. = 30.480 m.Vessel depth = 20 ft. = 6.096 m.Vessel tow draft d = 14.764 ft. = 4.500 m.Cargo height h = 45.932 ft. = 14.000 m. top of module cargo to the deckCargo width w = 88.583 ft. = 27.000 m. approx. width of module cargo

Hull Wind Area, = = 48.6Hull Current Area, = = 137.2Cargo Wind Area, = w x h = 378.0

Wetted Surface Area S = 45697.0 = 4245.4Frontal Area (Total Block Area) A = 4592.4 = 426.6

D. TOW FORCE DUE TO CALM WATER RESISTANCE

I. Estimate Skin FrictionThe Froude formula is used to calculate friction resistance is as follow :

Where :f = High surface roughness factor = 0.01 : 0.010d = Average Barge Draft : 14.76 ft

: 45697V = Tow Speed ( ft / Sec ) : 8.44 ft/s : 2.57 m/s : 5.00 Knotsn = 1.8 : 1.80RF = Friction Resistance ( lb ) : 21243 lb : 9.636 Metric Tons

II. Residuary ResistanceFor proude number up to 0.1, the residuary resistance component is unlikely to exceed 25% of the total resistance.

Where :: 0.30

: 6373 lb : 2.891 Metric Tons

III. Total Skin Friction ResistanceTotal skin friction resistance is sum of friction resistance and residual resistance as follow:

Where :

: 27616 lb : 12.526 Metric Tons

IV. Wind ResistanceWind Resistance is added to above formula to deduce the total calm water towing resistance into a head wind.Wind Resistance is calculated from :

Where :CD = 1.28 : 1.28

: 0.00238: 4592.36

v = Relative wind speed ft/s : 65.62 ft/s : 20.00 m/s : 38.9 Knots (ND Criteria)

PT. INDONESIAN SERVICE BUREAU

1. 5.0 Kts ( Knots ) tow speed at maximum transport sea state criteria with 39 Knots Wind

LoaBmDm

AHW Bm x (Dm-d) m2AHC Bm x d m2ACW m2

Ft2 m2

Ft2 m2

RF = f S V n

S = Wetted Surface Area ( ft2 ) ft2

RR = x RF

= Residuary Resistance FactorRF = Friction ResistanceRR = Residuary Resistance

RT = RF + RR

RF = Friction ResistanceRR = Residuary ResistanceRT = Total Skin Friction Resistance

Rw = CD x 1/2 A v2

= 0.00238 lb sec2 / ft4 sec2/ft4

A = Frontal Area ( Total block Area ), ft2 ft2

MISC. CALCULATION TOWING - PONTOON BARGE

Case : Worst Case

BARGE Tug Boat

CARGOCARGO#1CARGO#2CARGO#3CARGO#4

WAVE & CURRENTVELOCITY

TOW SPEED

WIND

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Case : Worst Case

: 30118 lb : 13.661 Metric TonsRw = Wind Resistance

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Case : Worst Case

V. Total Calm Water ResistanceTotal Calm Water Resistance is sum of total skin friction resistance and total wind resistance ahead the barge.

Where :

R = Total calm Water Resistance : 57734 lb : 26.188 Metric Tons

E. TOW FORCE DUE TO WAVE AND CURRENT LOADTow force due to wave and current load according with DnV Rules for Planning and Execution of Marine Operations - 1996 - Revision Part 2 Chapter 2 - Towing

I. Seastate CriteriaSignificant wave height 16.4 ft = 5.0 m (ND Criteria) Wind speed 38.9 kts = 20.0 m/sCurrent speed 1.0 kts = 0.50 m/s (ND Criteria/DNV rules 1996) Water Density 1025 AssumedAir Density 1.225 (5.1 DnV Classification Notes 30.5, 1991)

II. Current Force

Current Drag Coefficients:1. Hull: Ref: DnV Classification Notes 30.5, 1991; Table 5.5

L/B = 3.30 > 3d/B = 0.15 < 1 =>

1.0 as a conservative estimate

Total Current Force: = 17.6 kN = 1.76 MT (6.1.8 DnV Classification Notes 30.5 1991)

III. Wave Force

L / B = 3.3 >3.0, OK (3.3.2.5 DnV 1996 Part 2 Chapter 2, Ref 3)B / d = 6.8 >6.0, OK (3.3.2.5 DnV 1996 Part 2 Chapter 2, Ref 3)

= 298 kN = 30.35 MT (3.3.2.5 DnV 1996 Part 2 Chapter 2)

IV. Total Wave and Current ForceThe environmental force is sum of total current force and total wave drift force

Where :

F = Total environmental force : 32.11 Metric Tons

F. BOLLARD PULL REQUIREMENTThe required bollard pull are sum of total calm water resistance and total wave and current force

Where :

: 0.750 (3.3.2.6 DnV 1996 Part 2 Chapter 2)

R = Total Calm Water Resistance

F = Total Current and Wave Force

T = Bollard Pull Required : 77.73 Metric Tons

The required bollard pull of the tug tow to withstand wave drift force, current & wind force and tow speed is 77.73 Metric Tons

Tugboat Required is from 6218 BHP up to 6996 BHP

R = RT + Rw

RT = Total Skin Friction ResistanceRw = Wind Resistance

HsVwVcrw kg/m3rA kg/m3

CWH = 0.7 for an ideal block shapeUse CWH =

FC = 0.5 CD rW B d Vc2 x 10-3

Total Drift Force, Fdrift = Hs2 B [0.52 L - 13] / L

F = Fc + Fdrift

Fc = Total Current Force

Fdrift = Total Drift Force

T = x (R + F)

= Tug Efficiency

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Case : Worst Case

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A. TOW DESCRIPTION

B. DESIGN ASUMPTION









Where :: 0.30



Where :

: 27616 lb : 12.526 Metric Tons


Where :CD = 1.28 : 1.28

: 0.00238: 4592.36

v = Relative wind speed ft/s : 49.21 ft/s : 15.00 m/s : 29.2 Knots (ND Criteria)


1. 5.0 Kts ( Knots ) tow speed at maximum transport sea state criteria with 29.1 Knots Wind

LoaBmDm


Ft2 m2

Ft2 m2

RF = f S V n


RR = x RF


RT = RF + RR


Rw = CD x 1/2 A v2

= 0.00238 lb sec2 / ft4 sec2/ft4



Case : Benign Case

BARGE Tug Boat



TOW SPEED

WIND

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Case : Benign Case


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Case : Benign Case


Where :



I. Seastate CriteriaSignificant wave height 6.6 ft = 2 m (ND Criteria) Wind speed 29.2 kts = 15.0 m/sCurrent speed 1.0 kts = 0.50 m/s (ND Criteria/DNV rules 1996) Water Density 1025 AssumedAir Density 1.225 (5.1 DnV Classification Notes 30.5, 1991)

II. Current Force


L/B = 3.30 > 3d/B = 0.15 < 1 =>



III. Wave Force




Where :



Where :

: 0.750 (3.3.2.6 DnV 1996 Part 2 Chapter 2)






R = RT + Rw




FC = 0.5 CD rW B d Vc2 x 10-3


F = Fc + Fdrift



T = x (R + F)

= Tug Efficiency

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Case : Benign Case

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A. TOW DESCRIPTION

B. DESIGN ASUMPTION









Where :: 0.30



Where :

: 27616 lb : 12.526 Metric Tons


Where :CD = 1.28 : 1.28

: 0.00238: 4592.36

v = Relative wind speed ft/s : 63.63 ft/s : 19.39 m/s : 37.7 Knots (Basis of Design - Environmental Data)



LoaBmDm


Ft2 m2

Ft2 m2

RF = f S V n


RR = x RF


RT = RF + RR


Rw = CD x 1/2 A v2

= 0.00238 lb sec2 / ft4 sec2/ft4



Case : 10 Year Rt Period Case

BARGE Tug Boat



TOW SPEED

WIND

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Where :



I. Seastate CriteriaSignificant wave height 11.5 ft = 3.505 m (Basis of Design - Environmental Data) Wind speed 37.7 kts = 19.4 m/sCurrent speed 0.6 kts = 0.31 m/s (Basis of Design - Environmental Data) Water Density 1025 AssumedAir Density 1.225 (5.1 DnV Classification Notes 30.5, 1991)

II. Current Force


L/B = 3.30 > 3d/B = 0.15 < 1 =>



III. Wave Force




Where :



Where :

: 0.750 (3.3.2.6 DnV 1996 Part 2 Chapter 2)






R = RT + Rw




FC = 0.5 CD rW B d Vc2 x 10-3


F = Fc + Fdrift



T = x (R + F)

= Tug Efficiency

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A. TOW DESCRIPTION

B. DESIGN ASUMPTION









Where :: 0.30



Where :

: 27616 lb : 12.526 Metric Tons


Where :CD = 1.28 : 1.28

: 0.00238: 4592.36

v = Relative wind speed ft/s : 61.44 ft/s : 18.73 m/s : 36.4 Knots (Basis of Design - Environmental Data)



LoaBmDm


Ft2 m2

Ft2 m2

RF = f S V n


RR = x RF


RT = RF + RR


Rw = CD x 1/2 A v2

= 0.00238 lb sec2 / ft4 sec2/ft4




BARGE Tug Boat



TOW SPEED

WIND

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Where :



I. Seastate CriteriaSignificant wave height 10.8 ft = 3.2918 m (Basis of Design - Environmental Data) Wind speed 36.4 kts = 18.7 m/sCurrent speed 0.6 kts = 0.31 m/s (Basis of Design - Environmental Data) Water Density 1025 AssumedAir Density 1.225 (5.1 DnV Classification Notes 30.5, 1991)

II. Current Force


L/B = 3.30 > 3d/B = 0.15 < 1 =>



III. Wave Force




Where :



Where :

: 0.750 (3.3.2.6 DnV 1996 Part 2 Chapter 2)






R = RT + Rw




FC = 0.5 CD rW B d Vc2 x 10-3


F = Fc + Fdrift



T = x (R + F)

= Tug Efficiency

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PROJECT No. -PTT - MODULE TRANSPORTATIONSHEET 1 of 1BY AB DATECHKDCH DATE

A. TOW DESCRIPTION

B. DESIGN ASUMPTION

1. Significant Wave Height 16.4 ft2. Wind Speed : 39.0 knots3. Current Speed : 1.0 knots

C. VESSEL PARTICULARSLength between perpendicular = 180.446 ft. = 55.000 m.Vessel beam = 52.49344 ft. = 16.000 m.Vessel depth = 11.483 ft. = 3.500 m.Vessel tow draft d = 3.608924 ft. = 1.100 m.Deck House height = 16.404 ft. = 5.000 m.Deck House width = 45.932 ft. = 14.000 m.Raised Quarter height = 1.640 ft. = 0.500 m.Raised Quarter width = 52.493 ft. = 16.000 m.Spud Height = 0.000 ft. = 0.000 m.Spud Width = 0.000 ft. = 0.000 m.Hull Wind Area, = = 38.4Hull Current Area, = = 17.6Deck house Area, = = 70.0Raised Quarter Area = = 8.0Spud Area = = 0.0

Wetted Surface Area S = 11153.6 = 1036.2Frontal Area (Total Block Area)A = 1252.9 = 116.4



Where :

f = High surface roughness factor = 0.01 : 0.010d = Average Barge Draft : 3.61 ft


II. Residuary ResistanceFor Froude number up to 0.1, the residuary resistance component is unlikely to exceed 25% of the total resistance.

Where :: 0.40


Transportation sea state criteria based on Environmental Criteria given by client.

LoaBmDm

h1w1h2w2h3w3

AHW Bm x (Dm-d) m2AHC Bm x d m2ACW w1 x h1 m2ARQ w2 x h2 m2

As w3 x h3 m2

Ft2 m2

Ft2 m2

RF = f S V n


RR = x RF

= Residuary Resistance FactorRF = Friction Resistance

MISC. CALCULATION TOWING - CARGO BARGE

Case : 1 Year Return Period Case

BARGE



TOW SPEED

WIND

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Where :



Where :CD = 1.28 : 1.28

: 0.00238: 1252.92

v = Relative wind speed ft/s : 65.82 ft/s: 20.06 m/s : 39.0 Knots : 8269 lb : 3.751 Metric Tons


Where :


E. TOW FORCE DUE TO WAVE AND CURRENT LOAD

I. Seastate CriteriaSignificant wave height 16.4 ft = 5.000 mWind speed 39.0 kts = 20.1 m/sCurrent speed 1.0 kts = 0.50 m/sWater Density 1025Air Density 1.225 (5.1 DnV Classification Notes 30.5, 1991)

II. Current Force


L/B = 3.44 > 3d/B = 0.07 < 1 =>

1.0 as a conservative estimateFrom Ref:6.1.8 DnV Classification Notes 30.5 1991)Total Current Force = 2.3 kN = 0.23 MT

III. Wave Force



RR = Residuary Resistance

RT = RF + RR


Rw = CD x 1/2 A v2

= 0.00238 lb sec2 / ft4 sec2/ft4A = Frontal Area ( Total block Area ), ft2 ft2

Rw = Wind Resistance

R = RT + Rw


Tow force due to wave and current load according with DnV Rules for Planning and Execution of Marine Operations - 1996 - Revision Part 2 Chapter 2 - Towing



FC = 0.5 CWH rW B d Vc2 x 10-3


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Where :



TPR = (R + F)

Where :: 0.21

R = Total Calm Water ResistanceF = Total Current and Wave ForceTPR = Tow Line Pull Required : 17.75 Metric TonsBP = Static Bollard Pull : 85.29 Metric Tons

The required bollard pull (BP) to withstand wave drift force, current & wind force and tow speed is 85.29 Metric Tons

F = Fc + Fdrift

Fc = Total Current ForceFdrift = Total Drift Force

TPR = x BP

= Tug Efficiency (Table12-3 , Guidelines for Marine transportations,Bollard pull requirements, by GL Noble Denton

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PTT - MODULE TRANSPORTATIONREV B

DATE April 29, 2011DATE April 29, 2011

Tug Boat

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(3.3.2.5 DnV 1996 Part 2 Chapter 2)

Tow force due to wave and current load according with DnV Rules for Planning and Execution of Marine Operations - 1996 - Revision

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Metric Tons

(Table12-3 , Guidelines for Marine transportations,Bollard pull requirements, by GL Noble Denton

PROJECT No.PTT - MODULE TRANSPORTATIONSHEETBYCHKD

A. TOW DESCRIPTION

B. DESIGN ASUMPTION

1. Significant Wave Height 16.4 ft2. Wind Speed : 39.0 knots3. Current Speed : 1.9 knots

C. VESSEL PARTICULARSLength between perpendicular = 180.446 ft. = 55.000 m.Vessel beam = 52.49344 ft. = 16.000 m.Vessel depth = 11.483 ft. = 3.500 m.Vessel tow draft d = 3.608924 ft. = 1.100 m.Deck House height = 16.404 ft. = 5.000 m.Deck House width = 45.932 ft. = 14.000 m.Raised Quarter height = 1.640 ft. = 0.500 m.Raised Quarter width = 52.493 ft. = 16.000 m.Hull Wind Area, = = 38.4Hull Current Area, = = 17.6Deck house Area, = = 70.0Raised Quarter Area = = 8.0

Wetted Surface Area S = 11153.6 = 1036.2Frontal Area (Total Block Area A = 1252.9 = 116.4


I. Estimate Skin Friction

The Froude formula is used to calculate friction resistance is as follow :

Where :

f = High surface roughness factor = 0.01 : 0.010d = Average Barge Draft : 3.61 ft

: 11154


Transportation sea state criteria based on Environmental Criteria given by client.

LoaBmDm

h1w1h2w2

AHW Bm x (Dm-d) m2AHC Bm x d m2ACW w1 x h1 m2ARQ w2 x h2 m2

Ft2 m2

Ft2 m2

RF = f S V n




BARGE



TOW SPEED

WIND

V = Tow Speed ( ft / Sec ) : 6.75 ft/s : 2.06 m/s : 4.00n = 1.8 : 1.80RF = Friction Resistance ( lb ) : 3470 lb : 1.574 Metric Tons

II. Residuary ResistanceFor Froude number up to 0.1, the residuary resistance component is unlikely to exceed 25% of the total resistance.

Where :: 0.35



Where :



Where :CD = 1.28 : 1.28

: 0.00238: 1252.92

v = Relative wind speed ft/s : 65.82 ft/s: 20.06 m/s : 39.0 Knots: 8269 lb : 3.751 Metric Tons


Where :


E. TOW FORCE DUE TO WAVE AND CURRENT LOAD

I. Seastate CriteriaSignificant wave height 16.4 ft = 5.000 mWind speed 39.0 kts = 20.1 m/sCurrent speed 1.9 kts = 1.00 m/sWater Density 1025

RR = x RF


RT = RF + RR


Rw = CD x 1/2 A v2

= 0.00238 lb sec2 / ft4 sec2/ft4A = Frontal Area ( Total block Area ), ft2 ft2

Rw = Wind Resistance

R = RT + Rw


Tow force due to wave and current load according with DnV Rules for Planning and Execution of Marine Operations - 1996 - Revision Part 2 Chapter 2 - Towing

HsVwVcrw kg/m3

Air Density 1.225 (5.1 DnV Classification Notes 30.5, 1991)

II. Current Force


L/B = 3.44 > 3d/B = 0.07 < 1 =>

1.0 as a conservative estimateFrom Ref:6.1.8 DnV Classification Notes 30.5 1991)Total Current Force = 9.0 kN = 0.92 MT

III. Wave Force




Where :



TPR = (R + F)

Where :: 0.69 (Table1 , Tug Efficiency; By Towing Recommendations - DNV)

R = Total Calm Water ResistanceF = Total Current and Wave ForceTPR = Tow Line Pull Required : 18.36 Metric TonsBP = Static Bollard Pull : 26.61 Metric Tons

The required bollard pull (BP) to withstand wave drift force, current & wind force and tow speed is 26.61

39.922

Tugboat Required is 0 BHP up to 0 BHP###

rA kg/m3


FC = 0.5 CWH rW B d Vc2 x 10-3


F = Fc + Fdrift

Fc = Total Current ForceFdrift = Total Drift Force

TPR = x BP

= Tug Efficiency

PROJECT No. -PTT - MODULE TRANSPORTATIONSHEET 1 of 1 REV B

AB DATE April 29, 2011CH DATE April 29, 2011

3.608924

0.31

Tug Boat

Knots

For Froude number up to 0.1, the residuary resistance component is unlikely to exceed 25% of the total resistance.

Wind Resistance is added to above formula to deduce the total calm water towing resistance into a head wind.

Total Calm Water Resistance is sum of total skin friction resistance and total wind resistance ahead the barge.

Tow force due to wave and current load according with DnV Rules for Planning and Execution of Marine Operations - 1996 - Revision

(5.1 DnV Classification Notes 30.5, 1991)

as a conservative estimate

(3.3.2.5 DnV 1996 Part 2 Chapter 2, Ref 3)(3.3.2.5 DnV 1996 Part 2 Chapter 2, Ref 3)

(3.3.2.5 DnV 1996 Part 2 Chapter 2)

0 80.00 62.752 62.75

1.7 65.3375

(Table1 , Tug Efficiency; By Towing Recommendations - DNV) For Hs : 5mBP 62.8012 0

3429 London Offshore Consultants LOCG-GEN-Guideline-002 Rev.1 0.29241 29.2414653938

For Hs : 2m26.61 Metric Tons 0.8 80

Delta 50.7585346062Delta 1 3Delta 2 0.804% 26.8Reduction (%) 13.6032872745

66.3967127255Interpolation

47.9 21.27299

21.27299

London Offshore Consultants LOCG-GEN-Guideline-002 Rev.1

44.73461

KG 0.817 59.53666d 0.444 0.222 3.226 0.595v 7.716 0.119lwl 5.8 33.1147mr 3.940649 3.940649

3.940649

1.221528

BOLLARD PULL WORST CASEBOLLARD PULL BENIGN CASEBOLLARD PULL 10 YR MTC CASEBOLLARD PULL5 YR MTC CASEBOLLARD PULL 1 YR MTC CASESheet1Sheet2

bollard pull analysis_21!10!15

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