bzmw1e_ppt_3_1
TRANSCRIPT
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CHAPTER 3
Number Theory and theReal Number System
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3.1
Number Theory: Prime & Composite
Numbers
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Objectives
1. Determine divisibility.2. Write the prime factorization of a composite
number.
3. Find the greatest common divisor of twonumbers.
4. Solve problems using the greatest common
divisor.
5. Find the least common multiple of two numbers.
6. Solve problems using the least common
multiple.
3
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Number Theory and Divisibility
Number theory is primarily concerned with theproperties of numbers used for counting, namely 1, 2,
3, 4, 5, and so on.
The set of natural numbers is given by
Natural numbers that are multiplied together are
called thefactors of the resulting product.
,11,...6,7,8,9,101,2,3,4,5,N
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Divisibility
Ifa and b are natural numbers, a isdivisible by b if the
operation of dividing a by b leaves a remainder of 0.
This is the same as saying that b is adivisor ofa, or b
divides a.
This is symbolized by writing b|a.Example: We write 12|24 because 12 divides 24 or 24
divided by 12 leaves a remainder of 0. Thus, 24 is
divisible by 12.
Example: If we write 13|24, this means 13 divides 24 or
24 divided by 13 leaves a remainder of 0. But this is
not true, thus, 13|24.
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Aprime number is a natural number greater than 1
that has only itself and 1 as factors.
Acomposite number is a natural number greater than
1 that is divisible by a number other than itself and 1.
The Fundamental Theorem of ArithmeticEvery composite number can be expressed as a
product of prime numbers in one and only one
way.
One method used to find the prime factorization of a
composite number is called afactor tree.
Prime Factorization
E l 2 P i F i i i
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Example: Find the prime factorization of 700.Solution: Start with any two numbers whose product is
700, such as 7 and 100.
Example 2: Prime Factorization using aFactor Tree
Continue factoring the
composite number, branching
until the end of each branch
contains a prime number.
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Thus, the prime factorization of 700 is
700 = 7 2 2 5 5
= 7
2
2
5
2
Notice, we rewrite the prime factorization using a dot to
indicate multiplication, and arranging the factors from
least to greatest.
Example 2 (continued)
752 22
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Greatest Common Divisor
To find the greatest common divisor of two or more
numbers,
1. Write the prime factorization of each number.
2. Select each prime factor with the smallest exponentthat is common to each of the prime factorizations.
3. Form the product of the numbers from step 2. Thegreatest common divisor is the product of thesefactors.
Pairs of numbers that have 1 as their greatestcommon divisor are calledrelatively prime.
For example, the greatest common divisor of 5 and26 is 1. Thus, 5 and 26 are relatively prime.
E l 3 Fi di th G t t
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Example: Find the greatest common divisor of 216 and
234.
Solution:Step 1. Write the prime factorization of each
number.
Example 3: Finding the GreatestCommon Divisor
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216 = 23 33 234 = 2 32 13Step 2. Select each prime factor with the smallest
exponent that is common to each of the prime
factorizations.
Which exponent is appropriate for 2 and 3? We choose
the smallest exponent; for 2 we take 21, for 3 we take
32.
Example 3: (continued)
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Step 3. Form the product of the numbers from step 2.
The greatest common divisor is the product of thesefactors. Greatest common divisor = 2 32 = 2 9 =
18. Thus, the greatest common factor for 216 and 234
is 18.
Example 3: (continued)
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Least Common Multiple
The least common multiple of two or more natural
numbers is the smallest natural number that is divisibleby all of the numbers.
To find the least common multiple using prime
factorization of two or more numbers:1. Write the prime factorization of each number.
2. Select every prime factor that occurs, raised to the
greatest power to which it occurs, in these
factorizations.
3. Form the product of the numbers from step 2. The least
common multiple is the product of these factors.
E l 5 Fi di th L t C
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Example: Find the least common multiple of 144 and300.
Solution:Step 1. Write the prime factorization of each
number.
144 = 24 32
300 = 22 3 52
Step 2. Select every prime factor that occurs, raised to
the greatest power to which it occurs, in thesefactorizations. 144 = 24 32
300 = 22 3 52
Example 5: Finding the Least CommonMultiple
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Step 3. Form the product of the numbers from step 2.The least common multiple is the product of these
factors.
LCM = 24 3252 = 16 9 25 = 3600
Hence, the LCM of 144 and 300 is 3600. Thus, the
smallest natural number divisible by 144 and 300 is
3600.
Example 5: continued
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Example 6: Solving a Problem Using the LeastCommon Multiple
A movie theater runs its films continuously. One
movie runs for 80 minutes and a second runs for 120
minutes. Both movies begin at 4:00 P.M. When will
the movies begin again at the same time?
Solution:We are asked to find when the movies will
begin again at the same time. Therefore, we are
looking for the LCM of 80 and 120. Find the LCM
and then add this number of minutes to 4:00 P.M.
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Begin with the prime factorization of 80 and 120:80 = 24 5
120 = 23 3 5
Now select each prime factor, with the greatestexponent from each factorization.
LCM = 24 3 5 = 16 3 5 = 240
Therefore, it will take 240 minutes, or 4 hours, for the
movies to begin again at the same time. By adding 4
hours to 4:00 P.M., they will start together again at 8:00
P.M.
Example 6: (continued)