caie biology a-level
TRANSCRIPT
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CAIE Biology A-levelTopic 6: Nucleic Acids and Protein
SynthesisFlashcards
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This work by PMT Education is licensed under CC BY-NC-ND 4.0
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Draw the structure of a nucleotide.
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Draw the structure of a nucleotide.
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Name the pentose sugars in DNA and RNA.
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Name the pentose sugars in DNA and RNA.
● Deoxyribose in DNA● Ribose in RNA
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Describe the structure of DNA.
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Describe the structure of DNA.
● Double-stranded polymer of nucleotides twisted to form a double helix
● Nucleotides joined by phosphodiester bonds
● Hydrogen bonds form between complementary base pairs, A and T, C and G
● Antiparallel strands
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Name the purine bases and describe their structure.
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Name the purine bases and describe their structure.
Adenine C5H5N5 Guanine C5H5N5O
two-ring molecules
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Name the pyrimidine bases and describe their structure.
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Name the pyrimidine bases and describe their structure.
Thymine C5H6N2O2 Cytosine C4H5N3O Uracil C4H4N2O2
one-ring molecules
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What is complementary base pairing?
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What is complementary base pairing?
● Describes how hydrogen bonds form between complementary purine and pyrimidine bases
● Two bonds form between A and T (or U)
● Three bonds form between G and C
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Why is DNA replication described as semiconservative?
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Why is DNA replication described as semiconservative?
● Strands from original DNA molecule act as templates
● New DNA molecule contains 1 old strand and 1 new strand (specific base pairing enables genetic material to be conserved accurately)
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How is a new strand formed during semiconservative replication?
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How is a new strand formed during semiconservative replication?1. Free nucleotides from nuclear sap attach to exposed bases via
complementary base pairing
2. DNA polymerase joins adjacent nucleotides on new strand in a 5’ → 3’ direction via condensation reactions to form phosphodiester bonds
3. Hydrogen bonds form between complementary base pairs
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Outline the role of DNA ligase in DNA replication.
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Outline the role of DNA ligase in DNA replication.
As DNA replicates in an antiparallel fashion, the leading strand (5’ 3’) is replicated continuously whereas the lagging end (3’ 5’) is replicated discontinuously.
Short nucleotide sequences (Okazaki fragments) are formed. DNA ligase catalyses the formation of phosphodiester bonds between Okazaki fragments.
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Describe the structure of RNA.
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Describe the structure of RNA.
● Single-stranded polymer of nucleotides
● Nucleotides joined by phosphodiester bonds
● Hydrogen bonds form between complementary base pairs, A and U, C and G
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What is the function of mRNA?
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What is the function of mRNA?
Carries genetic information from the nucleus to the ribosomes for protein synthesis.
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How do genes determine the structure of proteins?
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How do genes determine the structure of proteins?
● DNA base triplets code for amino acids
● Triplet sequence determines amino acid sequence
● Sequence of amino acids determines protein’s primary structure
● Protein primary structure determines where bonds form when folding into tertiary structure, e.g. determines shape of enzyme active site
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What is a mutation?
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What is a mutation?
A random alteration to the DNA base sequence, altering the order of coded amino acids. This may result in a change in protein structure. Mutations often arise spontaneously during DNA replication.
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State the three types of gene mutation.
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State the three types of gene mutation.
● Substitution● Insertion● Deletion
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What are the consequences of substitution mutations?
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What are the consequences of substitution mutations?
● Silent mutation (no consequence) as DNA is degenerate
● Mutation may alter the amino acid coded for. This can alter the structure of the polypeptide causing it to no longer function - missense mutation
● Mutation may lead to the production of a stop codon. The length of the polypeptide chain is shorter - nonsense mutation
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What are the consequences of insertion/ deletion mutations?
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What are the consequences of insertion/ deletion mutations?
Produce a frameshift, altering each subsequent codon and rendering the protein non-functional.
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Describe the structure of tRNA.
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Describe the structure of tRNA.
● Single strand of 80 nucleotides
● Folded into clover shape (some paired bases)
● Anticodon on one end, amino acid binding site on the other
○ Anticodon binds to complementary mRNA codon
○ Amino acid corresponds to anticodon
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What do transcription and translation produce and where do they occur?
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What do transcription and translation produce and where do they occur?
Transcription produces mRNA, occurs in nucleus.
Translation produces proteins, occurs in the cytoplasm in ribosomes (made of protein and rRNA).
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Outline the process of transcription.
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Outline the process of transcription.
1. DNA helicase unwinds section of DNA, breaking hydrogen bonds between the DNA strands. Antisense strand acts as a template.
2. RNA polymerase binds to promoter region on a gene
3. Free RNA nucleotides align next to their complementary bases
4. RNA polymerase joins adjacent RNA nucleotides, forming phosphodiester bonds
5. RNA polymerase reaches stop codon and detaches. mRNA complete.
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Define the term exon.
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Define the term exon.
Regions of DNA or RNA that code for amino acid sequences.
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Define the term intron.
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Define the term intron.
Non-coding sequences of DNA found between exons.
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What happens after a strand of mRNA is transcribed?
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What happens after a strand of mRNA is transcribed?
● RNA polymerase detaches at terminator region
● Hydrogen bonds reform and DNA rewinds
● Splicing removes introns from pre-mRNA (primary transcript) in eukaryotic cells, leaving only exons
● mRNA moves out of nucleus via nuclear pore and attaches to ribosome
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Outline the process of translation.
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Outline the process of translation.
1. mRNA attaches to groove between subunits of ribosome
2. Ribosome moves along mRNA until ‘start’ codon reached
3. Amino acid-tRNA complex anticodon attaches to complementary mRNA codon via hydrogen bonding. Another complex binds
4. Peptide bond forms between adjacent amino acids in the complexes
5. Ribosome moves along one codon and release empty tRNA. Process continues to form polypeptide chain until ‘stop’ codon is reached.
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