calculation of wind pressure
TRANSCRIPT
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8/22/2019 calculation of wind pressure
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Part 1 (iii)
Frontal Length = 50 m = Pad foundationBuilding depth = 25 m
Therefore, use grid spacing of 5 m
= Typical pad foundColumn spacing = 5 m
Beam Span = 5 m = Area of influence p
Floor loading = 3 kN/m2
Area of influence = 6.25 m2 (2.5m x 2.5m)
Load of column / floor = 18.75 kN
No. of floors = 4
Load on foundation = 75 kN
* Note that I am only taking into consideration a basic floor load of 3kN/m2 here, whereas in reality other loads such as slab weight and s
25 m
Part 2 (i) (this is a brief overview of the load path - you should perhaps include a visual sketch of this load path and a short descriptio
Wind
Roof cladding
Purlins / Rafters
Roof truss structure
Columns / Beams of ste
Bracing / Gable posts
Wind Cladding / Brickwork
(walls)
Part 2(ii)
Calculation of Basic wind pressure
kb = 1
Eaves Height = 12
Roof Height = 4.55 m
Total height = 16.5 m
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Cr = 0.02
vb = 23.8 m/s
Sa = 1 (assumed topography is not significant)
Sd = 1 (orientation unkown)
Ss = 1
Sp = 1
vs = 23.8 m/s
Hr = 16.5 m (max. height as a conservative value)
Sb = 1.82
Ve = 43.3 m/s
DYNAMIC PRESSURE, qs = 1150 Pa
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tion loading
er floor on pad foundation
ad weight of steel alongside live loads would come into play
50 m
n - I just dont have the time lad)
el frame
Foundation