centrifugal separation (unit operation-2)

23
CENTRIFUGAL SEPARATION (Unit Operation-2) Prof. Saikat Maitra

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Page 1: CENTRIFUGAL SEPARATION (Unit Operation-2)

CENTRIFUGAL SEPARATION

(Unit Operation-2)

Prof. Saikat Maitra

Page 2: CENTRIFUGAL SEPARATION (Unit Operation-2)

Today Topics :

Centrifugal Separation

Introduction

Application

Equipment: Cyclone Separator

Theory

Centrifugal force

Rate of Settling

Critical Diameter

TODAY’S TOPIC

Page 3: CENTRIFUGAL SEPARATION (Unit Operation-2)

Students should be able to

comprehend & discuss concept & theory on

centrifugal separation

determine centrifugal force, critical diameter, rate of

settling

analyze & design an application

LESSON OUTOMES

Page 4: CENTRIFUGAL SEPARATION (Unit Operation-2)

Centrifugal Separation

Page 5: CENTRIFUGAL SEPARATION (Unit Operation-2)

Centrifugal settling or sedimentation

separation of particles from a fluid by centrifugal forces acting

on the particles

used on particles that cannot be settled easily in gravity

settling – smaller particles

does not change relative settling velocities

overcome

disturbing effect of Brownian motion

free convective currents

gives faster results than gravity settling

Introduction

Page 6: CENTRIFUGAL SEPARATION (Unit Operation-2)

Slurry feed Slurry feed

liquid solid heavy

liquid

fraction

light

liquid

fraction

Liquid-liquid feed Slurry feed Slurry feed

liquid solid heavy

liquid

fraction

light

liquid

fraction

Liquid-liquid feed

Slurry feed

Slurry feed

Slurry feed

Slurry Fed Slurry Fed

Liquid Solid

Liquid –Liquid Feed

Heavy Liquid Faction

Light Liquid Fraction

Basic Theory of Centrifugal Separation

Page 7: CENTRIFUGAL SEPARATION (Unit Operation-2)

separation of cream from whole milk

separation of cellular materials

beers

vegetable oil

fish-protein-concentration

fruit juice

drying crystals

separation of emulsion into liquids or solid-liquid

remove dust particles from air

vacuum cleaner

Application

Page 8: CENTRIFUGAL SEPARATION (Unit Operation-2)

Size classification

vertical

conical

Equipment: Cyclone Separators

Page 9: CENTRIFUGAL SEPARATION (Unit Operation-2)

• Centrifugal force

ae= acceleration from a centrifugal force (m/s2)

r = radial distance from centre

= angular velocity (rad/s)

Page 10: CENTRIFUGAL SEPARATION (Unit Operation-2)

• Rotational speed, N rev/min

• Gravitational Force,

• Centrifugal force in terms of gravitational force

Basic theory of centrifugal separation

Page 11: CENTRIFUGAL SEPARATION (Unit Operation-2)

Force in a centrifuge

A centrifuge having a radius of the bowl of 0.1016 m is

rotating at N = 1000 rev/min.

a) Calculate the centrifugal force developed in terms of

gravity forces.

b) Compare this force to that for a bowl with a radius of

0.2032 m rotating at the same rev/min.

Example

Page 12: CENTRIFUGAL SEPARATION (Unit Operation-2)

Force in a centrifuge

A centrifuge having a radius of the bowl of 0.1016 m is

rotating at N = 1000 rev/min.

a) Calculate the centrifugal force developed in terms of

gravity forces.

b) Compare this force to that for a bowl with a radius of

0.2032 m rotating at the same rev/min.

Example

Page 13: CENTRIFUGAL SEPARATION (Unit Operation-2)

Given: (a) r = 0.1016 m (a)

(b) r = 0.2032 m

N = 1000 rev/min

Calculate: centrifugal force

Example : Problem Statement

Page 14: CENTRIFUGAL SEPARATION (Unit Operation-2)

g

rNF

F

g

c

6.113

001118.0 2

g

rNF

F

g

c

2.227

001118.0 2

Example : Solution

Page 15: CENTRIFUGAL SEPARATION (Unit Operation-2)

Rate of settling in centrifuges

Page 16: CENTRIFUGAL SEPARATION (Unit Operation-2)

• Settling in Stoke’s law range,

• Integrating between the limits r = r1 at t = 0 and r = r2 at t = tT

Rate of settling in centrifuges

Page 17: CENTRIFUGAL SEPARATION (Unit Operation-2)

• Critical diameter, Dpc – diameter of particle that reaches half

the distance between r1 and r2.

Rate of settling in centrifuges

Page 18: CENTRIFUGAL SEPARATION (Unit Operation-2)

Settling in a centrifuge

A viscous solution containing particles with a density

1461 kg/m3 is to be clarified by centrifugation. The

solution density is 801 kg/m3 and its viscosity is 100 cp.

The centrifuge has bowl with r2 = 0.02225 m, r1 =

0.00716 m and height b = 0.1970 m. Calculate the

critical particle diameter of the largest particles in the

exit stream if N=23000 rev/min and the flowrate q =

0.002832 m3/h.

Example

Page 19: CENTRIFUGAL SEPARATION (Unit Operation-2)

Given: viscous solution containing particles

rp = 1461 kg/m3

r = 801 kg/m3, m = 100 cp

bowl: r2 = 0.02225 m, r1 = 0.00716 m

N = 23000 rev/min

q = 0.002832 m3/h

Calculate: critical diameter

Page 20: CENTRIFUGAL SEPARATION (Unit Operation-2)

Convert rotation into rad/s

Bowl volume

Convert flow rate

Use Eqn. to find Dpc

Example : Solution

3600

002832.0

)(

60

2

2

1

2

2

cq

rrbV

N

Page 21: CENTRIFUGAL SEPARATION (Unit Operation-2)

comprehend & discuss concept & theory on centrifugal

separation

determine

centrifugal force, FC

critical diameter, DPC

rate of settling, qC

analyze & design an application

RECAP

Page 22: CENTRIFUGAL SEPARATION (Unit Operation-2)

References:

[1] Geankoplis C. J., Transport Processes and Unit Operations,

4th Edition, Prentice Hall, 2003.

[2] Perry, R.H. and Green, D. Perry’s Chemical Engineers’

Handbook, 6th ed. New York, McGraw-Hill Book Company,

1984.

Page 23: CENTRIFUGAL SEPARATION (Unit Operation-2)

Question & Answers

THANK YOU