cepi math porject

7/28/2019 Cepi Math Porject

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Title: is there a relation between doing a specific diet and gender?

Statement of the task:

I will investigate if doing a specific diet is related to gender

I will collect primary data by doing an oral survey and then annotating results, thissurvey is going to be asked personally to each individual so results are not inaccurate.

I will investigate this relation between diet and gender since in our country body care

and good looking is a very important matter during adolescence and doing the survey i

want to validate my hypothesis which is: Argentina is a country where physical aspect

is of huge importance during adolescence.

I will collect data from 100 people, 50 males and 50 females ate year 12 of St Andrews

Scot school, Buenos Aires, Argentina.

This survey will only be done to year since year 12 since 100 people are more than 50%of the people in this year and results will be more accurate instead of asking people in

different year which will give a broader but less accurate percentage result. The survey

will only present two answers doing diet or not doing diet. Then this data will be

displayed in a pie chart and also in tables. The pie chart will give a percentage whilst

the table the number of people. Both will be divided into four groups males doing diet,

females doing diet, male not doing diet and females not doing diet. Then I will do a chi

square test involving the following steps:

1) Set a hypothesis2) Calculate the expected frequency and set them in a table3) Calculate the chi square value4) Calculate the degree of freedom5) Calculate value for the given degree of freedom and level of significance6) State a conclusion proving my hypothesis between a relation in gender and

doing a diet


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Data collection:

This is the data collected after doing the survey. This data is not processed; it is defined

as raw data. Raw data is the initial step to obtain the results, obtaining this data

collected after doing the survey to the St Andrews Scot School in Argentina I will

develop my chi square analysis and prove my hypothesis.

Gender: Doing a diet Not doing a diet

Female 40 10

Male 23 27

Data Table:

After doing the survey and adding up the results, the data was annotated in this table,

here we can observe the final results of the survey asked to St Andrews scot school, this

raw data will be processed to obtain pie chart and calculate the chi square value.

General Pie chart: in this pie chart we can observe a general view of all the results so I

will do 2 more pie chart so we can observe the deference within each survey to obtain a

different observation. In the general pie chart we can observe there is a relation betweendiet and gender since a high percentage of females are under a diet process whilst in

males the percentage of men doing diet is low, this shows that women care more about

their figure whilst men do not.

40

23

10

27

Survey on diet and gender

Female doing diet

Male doing diet

Female not doing diet

Male not doing diet


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Specific pie charts: this pie charts are divided by gender to show a more precise

proportion of results within each gender. Here we will observe more clear results within

a relation between the specific gender.

23

27

Male and diet survey

Male doing diet

Male not doing diet

40

10

Female and diet Survey

Female doing diet

Female not doing diet


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Calculating a relation:


Female 40 10

Male 23 27

Contingency table:


Female: 40 10 50

Male: 23 27 50

63 37 100

P(M/D.D)= (23/100)/(50/100)= 0,46 = 0,46 x 100 = 46%

P(M/N.D)= (27/100)/(50/100)=0,54 = 0,54x 100 = 54%

P(F/D.D)= (40/100)/(50/100)= 0,80= 0,80x 100 = 80%

P(F/N.D)= (10/100)/(50/100)=0,20 = 0,20 x 100 = 20%


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Calculating the Chi-square

H0: Doing a diet and gender are independent

H1: Doing a diet and gender are not independent

Calculating theExpected Frequency:


Female: 40 10 50

Male: 23 27 50

63 37 100

Expected frequency table:


Female: 31,5 18,5

Male: 31,5 18,5

Fe: (total row x total column) / general total

FDD: (50x63)/100= 31, 5

MDD:(50x63)/100=31,5

FND:(50x37)/100=18,5

MND:(50x37)/100=18,5


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Fo Fe Fo-Fe (Fo-Fe)2 (Fo-Fe)2/ Fe

40 31,5 8,5 72,25 2,301587302

10 18,5 -8,5 72,5 3.918918919

23 31,5 -8,5 72,5 2.301587302

27 18,5 8,5 72,25 3.918918919

12,44101244

Calculating the degree of freedom:

V= (number of rows-n)x(number of columns-n)

V= (2-1)x(2-1)

V= 1

(X)2 Test

(X) 2= 12,44101244

P= 4.2976(E-04)

DF= 1

X calc Critical value= 3.841

I reject the null hypothesis H0 as the x2 calc value 12,44101244 as it is greater than the

critical value 3.841

Statement:

Doing a diet and gender are not independent

Using

matrixs


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After doing the chi square test, the value obtained was (x2= 12.4).

This value was higher than the critical value (x2 critic Val=

3.841). So the null hypothesis had to be discarded. This means

that the results show that the gender is related to doing a specificdiet. The level of confidence used in these project obtained from

our maths Sl data booklet is a 95% and this states that gender and

doing a specific diet are not independent in st andrews scot school

year 12 students.

to acomplish my maths Project, the data was collected from surveys done bymysleft to st andrews scot school students in buenos aires argentina in year 12.This was done only for one year group to obtain a higher

, data was collected from surveys done by students and teachers from St.Andrews Scots School in Buenos Aires, Argentina and business people from aProcter & Gambles office in the same province. This is relevant due to the factthat if this survey would have been done in another location, or with different

groups of people, the results would have varied and might have been different.Regarding the mathematical processes used and their validity, the x2 valuefound in this project (10.7) was compared to the value obtained by the use ofthe same chi-squared process in a GDC (Graphic Display Calculator), whichgave 10.3 as a result rounded to 3 significant figures. This similarity in figuresindicates the projects results were reliable; therefore meaning the nullhypothesis was rejected.

cepi math porject

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