ch18 z7e nuclear
TRANSCRIPT
1 CHAPTER 18
Nuclear
Chemistry
CHAPTER 18
Nuclear
Chemistry18.I Nuclear 18.I Nuclear Stability & Stability &
Radioactive Decay Radioactive Decay pppp
18.I Nuclear 18.I Nuclear Stability & Stability &
Radioactive Decay Radioactive Decay pppp
I
2
Black dots are stable nuclides.
As A (atomic mass) increases, nº/p+ ratio increases.
3
Subatomic Particles
• Protons - plus charge
In the nucleus• Neutrons - neutral
• Electrons - negative charge
Outside the nucleus
4
Radiation
• Radiation comes from the nucleus of an atom.• Unstable nucleus emits a particle or energy
alpha
beta
gamma
5
He42
Types of RadiationTypes of RadiationTypes of RadiationTypes of Radiation
Alpha particle () helium nucleus paper2+
Beta particle (-) electron
e0-1 1-
leadPositron (+)
positron e01
1+
Gamma () high-energy photon 0
concrete
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Radiation Protection
• Shielding
alpha – paper, clothing
beta – lab coat, gloves
gamma- lead, thick concrete
• Limit time exposed
• Keep distance from source
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Radiation Protection
8 Nuclear DecayNuclear DecayNuclear DecayNuclear Decay
Alpha Emission
He Th U 42
23490
23892
parentnuclide
daughternuclide
alphaparticle
Atomic & Mass Numbers must balance!!
9 Nuclear DecayNuclear DecayNuclear DecayNuclear Decay
Beta Emission
e Xe I 0-1
13154
13153
electronPositron Emission
e Ar K 01
3818
3819
positron
10 Nuclear DecayNuclear DecayNuclear DecayNuclear Decay
Electron Capture (of inner orbital electrons)
Pd e Ag 10646
0-1
10647
electronGamma Emission
Usually follows other types of decay.
Transmutation One element becomes another.
11
12
Gamma radiation
No change in atomic or mass number
11B 11B + 0
5 5 0
boron atom in a
high-energy state
13
14 Table 18.2 Types of Nuclear Processes p. 845 Table 18.2 Types of Nuclear Processes p. 845
15
Learning Check
Write the nuclear equation for the beta emitter Cobalt-60. . .
60Co 60Ni + 0 e 27 28 -1
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Producing Radioactive Isotopes
Bombardment of atoms produces radioisotopes = 60 = 60
59Co + 1n 56Mn + 4H e 27 0 25 2
= 27 = 27
cobalt neutron manganese alpha atom radioisotope particle
17
Learning Check NR2
What radioactive isotope is produced in the following bombardment of boron?
10B + 4He ? + 1n
5 2 0
18
Solution NR2
What radioactive isotope is produced in the following bombardment of boron?
10B + 4He 13N + 1n
5 2 7 0
nitrogen
radioisotope
19Nuclear DecayNuclear Decay ppppNuclear DecayNuclear Decay pppp
Why nuclides decay… need stable ratio of neutrons to protons
He Th U 42
23490
23892
e Xe I 0-1
13154
13153
e Ar K 01
3818
3819
Pd e Ag 10646
0-1
10647
DECAY SERIES TRANSPARENCY
2020
The decay series.The decay series.
2121
18.2 Kinetics of Radioactive Decay18.2 Kinetics of Radioactive Decay
Rate of decay is a 1st order process, which is . . .Rate of decay is a 1st order process, which is . . . ln(N/Nln(N/N00) = -kt) = -kt (memorize -- not on AP sheet) (memorize -- not on AP sheet)
NN00 = original number of nuclides at t = 0 = original number of nuclides at t = 0
N = nuclides N = nuclides remainingremaining at time t at time tHalf-life (tHalf-life (t1/21/2) = time for nuclides to reach half ) = time for nuclides to reach half
their original value.their original value. tt1/21/2 = 0.693/k = 0.693/k
22 Half-lifeHalf-lifeHalf-lifeHalf-life
Half-life (t1/2) Time required for half the atoms of a
radioactive nuclide to decay. Shorter half-life = less stable.
23
24
Examples of Half-Life
Isotope Half lifeC-15 2.4 secRa-224 3.6 daysRa-223 12 daysI-125 60 daysC-14 5700 yearsU-235 710 000 000 years
25
Learning Check NR3
The half life of Iodine-123 is 13 hr. How much of a 64 mg sample of Iodine-123 is left after 26 hours?
26
Solution NR3
t1/2 = 13 hrs
26 hours = 2 x t1/2
Amount initial = 64mg
Amount remaining = 64 mg x 1/2 x 1/2
= 16 mg
27 Half-lifeHalf-lifeHalf-lifeHalf-life
nif mm )( 2
1
mf: final massmi: initial massn: # of half-lives
28Half-lifeHalf-life ppppHalf-lifeHalf-life pppp
Fluorine-21 has a half-life of 5.0 seconds. If you start with 25 g of fluorine-21, how many grams would remain after 60.0 s?
GIVEN:
T1/2 = 5.0 s
mi = 25 g
mf = ?
total time = 60.0 s
n = 60.0s ÷ 5.0s =12
WORK:
mf = mi (1/2)n
mf = (25 g)(0.5)12
mf = 0.0061 g
29 Kinetics of Nuclear Decay Problems ppKinetics of Nuclear Decay Problems pp
The rate constant for 9943Tc = 1.16 x 10-1/h
What is its half life? . . . t1/2 = 0.693/k = 0.693/(1.16 x 10-1/h) = 5.98 h
It will take 5.98 hours for a given sample of technetium-99 to decrease to half the original number of nuclides.
30 Kinetics of Nuclear Decay Problems ppKinetics of Nuclear Decay Problems pp
How long for 87.5% of a sample of cobalt-60 How long for 87.5% of a sample of cobalt-60 to decay if tto decay if t1/21/2 = 5.26 years? Steps. . . = 5.26 years? Steps. . .
What % is left? . . .What % is left? . . . 12.5%12.5% How many half-lives to get to this percent?How many half-lives to get to this percent? 3. So, your answer to the problem is . . .3. So, your answer to the problem is . . . 3 x 5.26 = 15.8 years.3 x 5.26 = 15.8 years.
31 Actual AP question: 1989 MC #68 ppActual AP question: 1989 MC #68 pp
If k = 0.023 min-1 how much of X was originally present if have 40. g after 60 min.?
Your answer is . . .160. g. Solution . . . t1/2 = 0.693/k = 0.693/0.023 min-1 = 30 min.
60 minutes is 2 half-lives so going backwards 40. g to 80. g to 160. g.
32 18.3 Nuclear Transformations18.3 Nuclear Transformations
Transmutation - change of one element into another.
Particle and linear accelerators are used to synthesize new elements (currently up to element number 119).
Difficult to characterize the chemical properties because with some only a few atoms are formed with very short half-lives.
3333
A representation of a Geiger-Müller counter.A representation of a Geiger-Müller counter.
34 18.4 Detection & Uses of Radioactivity18.4 Detection & Uses of Radioactivity
Half-life measurements of radioactive elements are used to determine the age of an object
Decay rate indicates amount of radioactive material
EX: 14C - up to 40,000 years238U and 40K - over 300,000 years
35 Synthetic ElementsSynthetic ElementsSynthetic ElementsSynthetic Elements Transuranium Elements
elements with atomic #s above 92 synthetically produced in nuclear reactors and accelerators most decay very rapidly
Pu He U 24294
42
23892
36 Carbon-14 Dating Carbon-14 Dating You will have a test question like this!You will have a test question like this! pppp
Carbon-14 Dating Carbon-14 Dating You will have a test question like this!You will have a test question like this! pppp
An ancient fire in an African cave has a An ancient fire in an African cave has a 1414C decay rate of 3.1 cpm (cts per minute). C decay rate of 3.1 cpm (cts per minute). If fresh wood has 13.6 cpm how old is the If fresh wood has 13.6 cpm how old is the campfire if tcampfire if t1/21/2 = 5730 years? Steps . . . = 5730 years? Steps . . .
Decay rates are directly proportional to Decay rates are directly proportional to nuclides so their ratio = nuclides so their ratio = N/NN/N00 What is the What is the
numerical ratio? Your answer . . .numerical ratio? Your answer . . . 3.1 cpm/13.6 cpm = 3.1 cpm/13.6 cpm = 0.230.23 Use the two previous equations to solve Use the two previous equations to solve
(next slide).(next slide).
37 Carbon-14 Dating You will have a test question like this! pp
Carbon-14 Dating You will have a test question like this! pp
Ancient fire 14C decay rate 3.1 cpm, fresh wood 13.6 cpm how old if t1/2 = 5730 yrs?
3.1 cpm/13.6 cpm = 0.23 = N/N0
ln(N/N0) = -kt and t1/2 = 0.693/k
You want to solve for t (vs. t1/2) so use t1/2 to get k then plug into the 1st equation and solve for t. Your answer is . . .
The campfire is 12 000 years old. ln(N/N0) = ln(0.23) = -(0.693/5730)t
Se Ex 18.4A & 18.4B in Study Guide
38 Carbon-14 Dating You will have another test question like this! pp
Carbon-14 Dating You will have another test question like this! pp
A rock has ratio of Pb-206 to U-238 of 0.115. How old is it if t1/2 of U-238 = 4.5 x 109 yrs?
Strategy: figure out N/N0 of U-238, then use the 2 previous equations to get . . .
7.1 x 108 years. Calculations . . .Pb/U = 115/1000 so N0 U238 = 1115, N = 1000
ln(1000/1115) = -(0.693/4.5 x 109)t
39 Nuclear MedicineNuclear MedicineNuclear MedicineNuclear Medicine
Radioisotope Tracers absorbed by specific organs and used
to diagnose diseasesRadiation Treatment
larger doses are used to kill cancerous cells in targeted organs
internal or external radiation source
Radiation treatment using-rays from cobalt-60.
40 Other UsesOther UsesOther UsesOther Uses
Food Irradiation radiation is used to kill bacteria
Radioactive Tracers explore chemical pathways trace water flow study plant growth, photosynthesis
Consumer Products ionizing smoke detectors - 241Am
41 Radioisotopes Used As TracersRadioisotopes Used As Tracers
4218.5 Thermodynamic Stability of the Nucleus18.5 Thermodynamic Stability of the Nucleus
Mass Defect - difference from mass of an Mass Defect - difference from mass of an atomatom & the mass of its individual particles. & the mass of its individual particles.
4.00260 amu 4.03298 amu
43 Nuclear Binding Nuclear Binding EnergyEnergy
Nuclear Binding Nuclear Binding EnergyEnergy
Energy released when a nucleus is formed from nucleons.
High binding energy = stable nucleus.
E = mc2E: energy (J)m: mass defect (kg)c: speed of light
(3.00 x 108 m/s)
44 Nuclear Binding EnergyNuclear Binding EnergyNuclear Binding EnergyNuclear Binding Energy
Unstable nuclides - radioactive & undergo radioactive decay.Elements with intermediate atomic masses (e.g., Fe) have greatest binding energy, so are the most stable.
45 18.6 Nuclear Fission and Nuclear Fusion 18.6 Nuclear Fission and Nuclear Fusion
Fission - splitting
Fusion - Combining
Both produce more stable nuclides so they are exothermic processes
46 A. Nuclear FissionA. Nuclear FissionA. Nuclear FissionA. Nuclear Fission
Splitting a nucleus into two or more smaller nuclei
1 g of 235U = 3 tons of coal
U23592
47
Nuclear Fission
Fission
large nuclei break up
235U + 1n 139Ba + 94Kr + 3 1n +
92 0 56 36 0
Energy
48 Nuclear PowerNuclear PowerNuclear PowerNuclear Power
Fission Reactors Cooling Tower
4949
Schematic of the reactor core.Schematic of the reactor core.
50 Nuclear PowerNuclear PowerNuclear PowerNuclear Power
Fission Reactors
51 FissionFissionFissionFission chain reaction - self-propagating reaction critical mass -
mass required to sustain a chain reaction
52
53 Nuclear FusionNuclear FusionNuclear FusionNuclear Fusion combining of two nuclei to form one nucleus of larger mass thermonuclear reaction – requires temp of 40,000,000 K to sustain 1 g of fusion fuel =
20 tons of coal (vs. 3 in fission) occurs naturally in
stars
HH 31
21
54
Nuclear Fusion
Fusion
small nuclei combine
2H + 3H 4He + 1n +
1 1 2 0
Occurs in the sun and other stars
Energy
55 Nuclear PowerNuclear PowerNuclear PowerNuclear Power
Fusion Reactors (not yet sustainable)
56 Nuclear PowerNuclear PowerNuclear PowerNuclear Power
Fusion Reactors (not yet sustainable)
Tokomak Fusion Test Reactor
Princeton University
National Spherical Torus Experiment
57 Fission vs. FusionFission vs. Fusion ppFission vs. FusionFission vs. Fusion pp
235U is limited danger of meltdown toxic waste thermal pollution
fuel is abundant no danger of meltdown no toxic waste not yet sustainable
FISSION
FUSION
58
Learning Check NR4
Indicate if each of the following are(1) Fission (2) fusion
A. Nucleus splits B. Large amounts of energy releasedC. Small nuclei form larger nucleiD. Hydrogen nuclei react
Energy
59
Solution NR4
Indicate if each of the following are(1) Fission (2) fusion
A. 1 Nucleus splits B. 1 + 2 Large amounts of energy releasedC. 2 Small nuclei form larger nucleiD. 2 Hydrogen nuclei react
60 E. Nuclear WeaponsE. Nuclear WeaponsE. Nuclear WeaponsE. Nuclear Weapons
Atomic Bomb chemical explosion is used to form a
critical mass of 235U or 239Pu fission develops into an uncontrolled
chain reaction
Hydrogen Bomb chemical explosion fission fusion fusion increases the fission rate more powerful than the atomic bomb
61 18.7 Effects of Radiation pp18.7 Effects of Radiation pp
Somatic - damage to the organism causing sickness or death.
Genetic - damage to the genetic machinery causing birth defects.
62 Factors for Biological Effects of Radiation ppFactors for Biological Effects of Radiation pp
Energy - higher energy content (rads) causes more damage.
Penetrating Ability - > - > Ionizing Ability - > - > (eating an -particle
producer like Pu is very deadly) Chemical Properties
• Kr-85 is chemically inert, passes through quickly
• Sr-90 collects in bone and stays a long time in the body.
63
64
Radioactive Radioactive particles and particles and
rays vary rays vary greatly in greatly in penetrating penetrating
power.power.
Radioactive Radioactive particles and particles and
rays vary rays vary greatly in greatly in penetrating penetrating
power.power.
65
6666
Diagram for Diagram for the tentative the tentative plan for deep plan for deep underground underground isolation of isolation of
nuclear wastenuclear waste..