challenge 5cm 6cm 12 cm 7cm solution: sa = (b x h) + (a x l) + (b x l) + (c x l) sa = (6cm x 5cm) +...

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Challenge 5cm 6cm 6cm 12 cm 7cm Solution: SA = (b x h) + (a x l) + (b x l) + (c x l) SA = (6cm X 5cm) + (7cm X 5cm) + (6cm X 12cm) + (6cm X 12cm)

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Page 1: Challenge 5cm 6cm 12 cm 7cm Solution: SA = (b x h) + (a x l) + (b x l) + (c x l) SA = (6cm X 5cm) + (7cm X 5cm) + (6cm X 12cm) + (6cm X 12cm)

Challenge

5cm6cm

6cm

12 cm

7cm

Solution: SA = (b x h) + (a x l) + (b x l) + (c x l)SA = (6cm X 5cm) + (7cm X 5cm) + (6cm X 12cm) + (6cm X 12cm)

Page 2: Challenge 5cm 6cm 12 cm 7cm Solution: SA = (b x h) + (a x l) + (b x l) + (c x l) SA = (6cm X 5cm) + (7cm X 5cm) + (6cm X 12cm) + (6cm X 12cm)

Your Turn………

8 cm

9 cm7 cm

11 cm

7.5 cm

Given: a = 7cmb = 8cmc = 11cmheight = 7.5cmlength = 9cm

Required: Surface Area of Triangular Prism

Analysis: SA = (b x h) + (a x l) + (b x l) + (c x l)

Solution:SA = (8cm x 7.5cm) + (7cm x 8cm) + (8cm x 9cm) + (11cm x 9cm)=

Paraphrase: Therefore the Surface Area of this Triangular Prism is 277 cm³

Page 3: Challenge 5cm 6cm 12 cm 7cm Solution: SA = (b x h) + (a x l) + (b x l) + (c x l) SA = (6cm X 5cm) + (7cm X 5cm) + (6cm X 12cm) + (6cm X 12cm)

Homework Check

Page 4: Challenge 5cm 6cm 12 cm 7cm Solution: SA = (b x h) + (a x l) + (b x l) + (c x l) SA = (6cm X 5cm) + (7cm X 5cm) + (6cm X 12cm) + (6cm X 12cm)

Lesson 11 – Friday November 18

100mins

Introduction to 3.4: Volume of Triangular

Prism

Page 5: Challenge 5cm 6cm 12 cm 7cm Solution: SA = (b x h) + (a x l) + (b x l) + (c x l) SA = (6cm X 5cm) + (7cm X 5cm) + (6cm X 12cm) + (6cm X 12cm)

Recall Area of a triangle is

1/2 (base X height)Which is one half the area of a rectangle

To calculate Volume of a Rectangular prism Volume = _________

http://www.youtube.com/watch?v=g2UnCcmoabY&feature=fvsr

http://www.mathsnet.net/geometry/solid/houses1.html

Page 6: Challenge 5cm 6cm 12 cm 7cm Solution: SA = (b x h) + (a x l) + (b x l) + (c x l) SA = (6cm X 5cm) + (7cm X 5cm) + (6cm X 12cm) + (6cm X 12cm)

ActivityNumber everyone 1 to 4Give students a net for a triangular prismStudents are to create a rectangular prism

that would fit the triangular prism. Come up with a way to calculate the volume

of the triangular prism based on what you know about the area of a triangle and rectangle and volume of rectangular prism

You are not allowed to use your textbook for aid.

Write down your thoughts of how you came up with the formulas.

Page 7: Challenge 5cm 6cm 12 cm 7cm Solution: SA = (b x h) + (a x l) + (b x l) + (c x l) SA = (6cm X 5cm) + (7cm X 5cm) + (6cm X 12cm) + (6cm X 12cm)

Define Volume: __________________________________________________________________________

Page 8: Challenge 5cm 6cm 12 cm 7cm Solution: SA = (b x h) + (a x l) + (b x l) + (c x l) SA = (6cm X 5cm) + (7cm X 5cm) + (6cm X 12cm) + (6cm X 12cm)

Class Example:

Area of Base = ____m²Volume = ____m³

Page 9: Challenge 5cm 6cm 12 cm 7cm Solution: SA = (b x h) + (a x l) + (b x l) + (c x l) SA = (6cm X 5cm) + (7cm X 5cm) + (6cm X 12cm) + (6cm X 12cm)

Class Example #2:

Page 10: Challenge 5cm 6cm 12 cm 7cm Solution: SA = (b x h) + (a x l) + (b x l) + (c x l) SA = (6cm X 5cm) + (7cm X 5cm) + (6cm X 12cm) + (6cm X 12cm)

Homework:

Page 119 – 120 # 1 - 6

Page 11: Challenge 5cm 6cm 12 cm 7cm Solution: SA = (b x h) + (a x l) + (b x l) + (c x l) SA = (6cm X 5cm) + (7cm X 5cm) + (6cm X 12cm) + (6cm X 12cm)

Reminder:

TEST: Wednesday November 23, 2011