chap 010

THE FOLLOWING 3 QUESTIONS HAD ERRORS IN ASBE 4e EXAM QUESTION DATABASE. CORRECTED TEXT IS MARKED BELOW 33. John wants to compare two means. His sample statistics were and . Assuming equal variances, the 95 percent confidence interval for the difference of the population means is approximately: A) [2.445, 6.195]. B) [1.178, 5.083]. C) [–2.386, 6.786]. D) [–0.098, 3.195]. Answer: C Difficulty: 3 Hard Learning Objective: 10-09 Blooms: Apply AACSB: Analytic Topic: Confidence Interval for the Difference of Two Means, μ 1 – μ 2 Feedback: Pool the variances and add the degrees of freedom because equal variances are assumed. 34. John wants to compare two means. His sample statistics were and . Assuming equal variances, the pooled variance is: A) 21.06 B) 24.01 C) 24.75 D) 14.44 Answer: A Difficulty: 2 Medium Learning Objective: 10-02 Blooms: Apply AACSB: Analytic Topic: Comparing Two Means: Independent Samples Feedback: The pooled variance is [(n 1 – 1)s 1 2 + (n 2 – 1)s 2 2 ]/[(n 1 – 1) + (n 2 – 1)] = 21.06. 35. John wants to compare two means. His sample statistics were and . Assuming equal variances, the test statistic is: A) 2.375 B) 1.017 C) 1.960

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THE FOLLOWING 3 QUESTIONS HAD ERRORS IN ASBE 4e EXAM QUESTION DATABASE. CORRECTED TEXT IS MARKED BELOW

33. John wants to compare two means. His sample statistics were and . Assuming equal variances, the 95 percent confidence interval for the difference of the population means is approximately:A) [2.445, 6.195].B) [1.178, 5.083].C) [2.386, 6.786].D) [0.098, 3.195].Answer: CDifficulty: 3 HardLearning Objective: 10-09Blooms: ApplyAACSB: AnalyticTopic: Confidence Interval for the Difference of Two Means, 1 2Feedback: Pool the variances and add the degrees of freedom because equal variances are assumed.

34. John wants to compare two means. His sample statistics were and . Assuming equal variances, the pooled variance is:A) 21.06B) 24.01C) 24.75D) 14.44Answer: ADifficulty: 2 MediumLearning Objective: 10-02Blooms: ApplyAACSB: AnalyticTopic: Comparing Two Means: Independent SamplesFeedback: The pooled variance is [(n1 1)s12 + (n2 1)s22]/[(n1 1) + (n2 1)] = 21.06.

35. John wants to compare two means. His sample statistics were and . Assuming equal variances, the test statistic is:A) 2.375B) 1.017C) 1.960D) Must know to answer.Answer: BDifficulty: 2 MediumLearning Objective: 10-02Blooms: ApplyAACSB: AnalyticTopic: Comparing Two Means: Independent SamplesFeedback: The pooled variance is (n1 1)s12 + (n2 1)s22 = (9 1)(5.4) + (9 1)(3.6) = 21.06.

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