chapter 1 the real number system = 9 - (12 - [8]) = 9 - (4 ... · pdf file4 • 9 + 1...
TRANSCRIPT
Chapter 1 The Real Number System
Section 1.1 Introduction to Algebra
Practice 1.1.11. 25 + 4 is a sum whose terms are 25
and 4.
2. 5w is a product whose factors are 5 and w.
3. 6x + 2 is a sum whose terms are 6x and 2. 6x is a product whose factors are 6 and x.
4. 2m + 3n is a sum whose terms are2m and 3n. 2m is a product whose
factors are 2 and m. 3n is a product Whose terms are 3 and n.
5. 5abc is a product whose factors are 5,a,b,and c.
Practice 1.1.21. 8 + 12 ÷ 3 • 4 = 8 + 4 • 4 = 8 + 16 =
24
2. 5 2 − 2 2 = 25 - 4 = 21
3. (5 - 2)2 = (3)2 = 9
4. (4 -1)(12 - 7)= (3)(5) = 15
5. 24 ÷ (4)(16 - 10) = 24 ÷ (4)(6) = 6(6) = 36
6. 8 − 2 + 5•4
15 − 2 • 2 =
8 − 2 + 2015 − 4
= 8 − 2211
=
8 - 2 = 6
Practice 1.1.31. 14 - [(5 - 3)2 + 6] = 14 - [(2)2 + 6]= 14 - [4 + 6] = 14 - [10] = 4
2. 9 - (12 - [22 + 4]) = 9 - (12 - [4 + 4])
= 9 - (12 - [8]) = 9 - (4) = 5
3. 60 - 3(2 + 3[2 + 3]) = 60 - 3(2 + 3[5]) = 60 - 3(2 + 15) = 60 - 3(17) = 60 - 51 = 9
4. 15 - [(2 + 4) • 2 - (12 - 8)] =15 - [6 •2 - 4] = 15 - [12 - 4] = 15 - 8 = 7
Practice 1.1.41. For t = 7
4t + 3 = 4(7) + 3 = 28 + 3 = 312. For r = 3
π r2 = 3.14 • (3)2 = 3.14 •9 = 28.26
3. For x = 95x + 25(x + 30) = 5(9) + 25(9 + 30) = 5(9) + 25(39) = 45 + 975 = 1020
4. For l = 8, w = 2 and h = 3lwh = (8)(2)(3) = 48
5. For a = 9 and b= 4a2 + b2 = (9)2 + (4)2 = 81 + 16 = 97
6. For a = 9 and b= 4(a + b)2 = (9 + 4)2 = (13)2 = 169
Practice 1.1.51. Variable - Def (pg. 103): A
symbol, usually a letter, that is usedto represent
something, usually a quantity or aquantity that can take on manydifferent values. Ex. x, y
2. Simplify - Def (pg. 106): toperform some or all of the allowableoperations in an expression.Ex: The simplified version of 2+3 is 5.
3. Factor - Def (pg. 103): Numbersbeing multiplied.Ex: In 2x, both 2 and x are factors
4. Exponent - Def (pg. 106): In
1CHAPTER 1 THE REAL NUMBER SYSTEM
exponential notation, the number ofbases being multiplied.
Ex: In 32, 2 is the exponent. 32 means 3 • 3
Exercise Set 1.1
1. 35 + 21 is a sum . The terms are 35and 21.
3. (3.5) • 2 is a product . The factorsare 3.5 and 2.
5. 4u is a product. The factors are 4 andu.
7. 5v + 3w is a sum. The terms are vand 3w. 5v is a product
. The factors are 5 andv. 3w is a product. The
factors are 3 and w.
9. 31 - 8 •3 = 31 - 24 = 7
11. 18 - 22/11 •(5) = 18 - 2 •(5) = 18 - 10 = 8
13. (2 •3)2 = (6)2 = 36
15. 23 • 33 = 8 • 27 = 216
17. 2 + 3(2 + 1) = 2 + 3(3) = 2 + 9 = 11
19. 15 - 3- 6 + 4 • 2 = 15 - 3 - 6 + 8 = 12 - 6 + 8 = 6 + 8 = 14
21. [12 - (12 - 6)] + 8 = [12 - 6] + 8 = 6 + 8 = 14
23. [3 + (10-7)2]2 = [3 + (3)2]2 =[3 + 9]2 = 144
25. 12 + 12 − 2 •3
10 − 3 2 =
12 + 12 − 6 10 − 9
=
12 + 6 1
= 12 + 6 = 18
27. 15 - [(8 - 5)2 - 2] = 15 - [(3)2 - 2] = 15 - [9 - 2] = 15 - 7 = 8
29. 5 + 4(5 +4[5 - 2]) =5 + 4(5 + 4[3]) = 5 + 4(5 + 12) = 5 + 4(17) = 5 + 68 =73
31. 23 - [(8 -2) •3 - (9-5)] =23 - [6 •3 - 4] = 23 - [18 - 4] = 23 - 14 = 9
33. For a = 8 and b = 6a2 - b2 = (8)2 - (6)2 = 64 - 16 = 48
35. For a = 3, b= 9 and c = 2b2 - 4ac = (9)2 - 4(3)(2) = 81 - 24 =57
37. For x = 6 and y = 5x2 + 2xy + y2 = (6)2 + 2(6)(5) + (5)2 = 36 + 60 + 25 = 121
39. For x = 150.05(x) + 0.10(30 - x) = 0.05(15) + 0.10(30 - 15) =0.75 + 0.10 (15) = 0.75 + 1.5 = 2.25
2 CHAPTER 1 THE REAL NUMBER SYSTEM
Section 1.2 Fractions
Practice 1.2.11. 18 = 2 • 3 • 3=2•32
1
3 3
3 9
2 18
2. 54 = 2 • 3 • 3 •3 =2•33
3. 385 = 5 • 7 •11
4. 119 = 7 •17
5. 105 = 3 • 5 •7
6. 60 = 2 •2 •3 •5=22•3•5
Practice 1.2.2
1.1820
= 2•3•32•2•5
= 3•3 2•5
= 9 10
2.2464
= 2 •2 •2 •3
2 •2 •2 •2 •2 •2=
3 2 •2 •2
= 3 8
3.7240
= 2 •2 •2 •3 •32 •2 •2 •5
= 3 •35
= 9 5
4.104156
= 2 •2 •2 •132 •2 •3 •13
= 2 3
5.95152
= 5 •19
2 •2 •2 •19=
5 2 •2 •2
= 5 8
6.84120
= 2 •2 •3 •7
2 •2 •2 •3 •5=
7 2 •5
= 7 10
1
5 5
3 15
2 30
2 60
1
7 7
3 21
5 105
1
17 17
7 119
1
11 11
7 77
5 385
1
3 3
3 9
3 27
2 54
Practice 1.2.3
1.1225
• 1027
= 2•2•35•5
• 2•5
3•3•3=
2•25
• 2
3•3=
2•2• 2 5•3•3
= 8 45
2.203
• 1520
= 203
• 3 • 5 20
= 1 1
• 5 1
= 5
3.4 42
• 146
= 2 • 2
2 • 3 • 7 •
2 • 7 2 • 3
=
3CHAPTER 1 THE REAL NUMBER SYSTEM
1 3
• 2 3
= 1 • 2 3 • 3
= 2 9
4.1825
• 3512
= 2•3•35•5
• 5•7
2•2•3=
3 5
• 7 2
= 3•75•2
= 2110
5.9257
• 190115
= 2•2•233•19
• 2•5•195•23
=
2•23
• 2 1
= 2•2•23•1
= 8 3
6.4298
• 175165
= 2•3•72•7•7
• 5•5•73•5•11
=
1 1
• 5 11
= 5 11
Practice 1.2.4
1.3332
2.1 6
3.x 1
, x ≠ 0
4.1 y
, y≠ 0
Practice 1.2.5
1.5 3
= 1 3
• 5
2.x 3
= 1 3
x
3. 1w
4.5 p 4
= 5 4
p
5.3 c 5
= 3 5
c
Practice 1.2.6
1.3 4
÷ 9 16
= 3 4
• 169
= 1 1
• 4 3
= 4 3
2.
5 9 3527
= 5 9
÷ 3527
= 5 9
• 2735
= 1 1
• 3 7
= 3 7
3.108
÷ 5 = 108
• 1 5
= 2 8
• 1 1
= 1 4
4.7 1420
= 7 1
÷ 1420
= 7 1
• 2014
= 202
= 10
5.5176
÷ 10295
= 5176
• 95102
=
512 • 2 • 19
• 5 • 192 • 51
= 5 8
6.4856
÷ 12 = 4856
• 1 12
= 4 56
= 1 14
7.
152114
= 1521
÷ 14 = 1521
• 1 14
=
5 7
• 1 14
= 5 98
8.
703
17515
= 703
÷ 17515
= 703
• 15175
=
703
• 3 35
= 2
Practice 1.2.7
1.5 8
+ 7 8
= 128
= 3 2
4 CHAPTER 1 THE REAL NUMBER SYSTEM
2.1 12
+ 5 12
= 6 12
= 1 2
3.4 15
+ 1 15
− 2 15
= 3 15
= 1 5
4.7 20
− 3 20
+ 1 20
= 5 20
= 1 4
Practice 1.2.81. 9 = 32
12 = 22•3LCD = 22•32 = 36
2. 18 = 2•32
24 = 23•3LCD = 23•32 = 72
3. 8 = 23
9 = 32
10 = 2•5LCD = 23•32•5=360
4. 34 = 2•1751 = 3•1785 = 5•17LCD = 2•3•5•17 = 510
Practice 1.2.9
1.4 5
= 4 • 8 5 • 8
= 3240
2.5 16
= 5 • 3 16• 3
= 1548
3. 4 = 4 • 181 • 18
= 7218
4. 3 = 3 • 541 • 54
= 16254
Practice 1.2.101. 12 = 22•3 18 = 2•32
LCD = 22•32 = 365
12 +
5 18
=
5 • 3 12• 3
+ 5 • 2 18• 2
= 1536
+ 1036
= 2536
2. 8 = 22 24 = 22•3 LCD = 22•3=247 8
− 1724
= 7 • 3 8 • 3
− 1724
=
2124
− 1724
= 4 24
= 1 6
3. 10 = 2•5 9 = 32 15 = 3•5LCD = 2•32•5 = 909 10
− 1 9
+ 1415
=
9 • 9 10• 9
− 1 • 109 • 10
+ 14• 6 15• 6
=
8190
− 1090
+ 8490
= 15590
= 5 • 315 • 18
= 3118
4. 9 =32 14 = 2•7 7 = 1•7LCD = 2•32•7 = 1264 9
+ 4 7
− 1 14
=
4 • 149 • 14
+ 4 • 187 • 18
− 1 • 9 14• 9
=
56126
+ 72126
− 9
126=
119126
=
7 • 177 • 18
= 1718
5. 15 =3•5 12 = 22•3 10=2•5LCD = 22•3•5=607 15
+ 5 12
+ 7 10
=
7 • 4 15• 4
+ 5 • 5 12• 5
+ 7 • 6 10• 6
=
2860
+ 2560
+ 4260
= 9560
= 5 • 195 • 12
= 1912
6. 4 = 22 9 =32 36=22•32
LCD = 22•32=363 4
+ 1 9
− 1336
= 3 • 9 4 • 9
+ 1 • 4 9 • 4
− 1336
=
273 6
+ 4 36
− 1336
= 1836
= 1 2
5CHAPTER 1 THE REAL NUMBER SYSTEM
Practice 1.2.11
1. 10 − 4 ( 3 ) 2 + 4
=
10 − 126
= 10 − 2 = 8
2. 5 − 2 • 6 4
= 5 − 124
= 5 − 3 = 2
3.1 2
+ 1 3
( 5 4
− 1 6
) =
1 2
+ 1 3
( 1512
− 2 12
) = 1 2
+ 1 3
( 1312
)
1 2
+ 1336
= 1836
+ 1336
= 3136
4.2 3
+ 2 7
( 1 4
+ 1 3
) = 2 3
+ 2 7
( 3 12
+ 4 12
)
2 3
+ 2 7
( 7 12
) = 2 3
+ 1 6
= 4 6
+ 1 6
= 5 6
5. ( 4 5
+ 2 10
) 2 − 3 4
+ 1 4
=
( 8 10
+ 2 10
) 2 − 3 4
+ 1 4
=
( 1010
) 2 − 3 4
+ 1 4
= ( 1 ) 2 − 3 4
+ 1 4
=
1 − 3 4
+ 1 4
= 4 4
− 3 4
+ 1 4
= 2 4
= 1 2
6.5 + 2 3
6 − 2 ÷
24 + 2
3 2 + 5 =
5 + 8 4
÷ 26
9 + 5 =
134
÷ 2614
= 134
• 1426
= 1 2
• 7 2
= 7 4
Exercise Set 1.2
1. 96 =25•3
3. 378 = 2•33•7
5. 825=3•52•11
7. 484 = 22•112
9.6 20
= 3 • 2
2 • 2 • 5 =
3 10
11.3690
= 2 • 2 • 3 • 3 2 • 3 • 3 • 5
= 2 5
13.135126
= 3 • 3 • 3 • 5 2 • 3 • 3 • 7
= 3 • 5 2 • 7
= 1514
15.8 15
• 2012
= 2 • 4 3 • 5
• 4 • 5 3 • 4
= 2 3
• 4 3
= 8 9
17.3042
• 8 60
= 1 • 302 • 21
• 2 • 4 2 • 30
= 1 21
• 4 2
=
1 21
• 2 = 2 21
19.11030
• 2133
= 10• 113 • 10
• 3 • 7 3 • 11
=
1 1
• 7 3
= 7 3
21.9850
• 60315
= 2 • 7 • 7 2 • 5 • 5
• 2 • 5 • 2 • 3 3 • 3 • 5 • 7
=
7 5
• 2 • 2 3 • 5
= 2875
23.1 8
25.6 5
27.a 7
, a≠0
29.1 t
, t≠0
31.1 15
• 13
33.1 2
x
35.3 8
•t
6 CHAPTER 1 THE REAL NUMBER SYSTEM
37.4 9
÷ 1227
= 4 9
• 2712
= 1 1
• 3 3
= 1
39.9 185
= 9 ÷ 185
= 9 • 5 18
= 1 • 5 2
= 5 2
41.135210
÷ 18 = 135210
• 1 18
=
5 • 3 • 3 • 3 2 • 3 • 5 • 7
• 1
2 • 3 • 3 =
1 2 • 7
• 1 2
= 1 28
43.1415
÷ 6090
= 1415
• 9060
=
2 • 7 3 • 5
• 2 • 3 • 3 • 5 2 • 2 • 3 • 5
= 7 1
• 1 5
= 7 5
45.
3 4 1 8
÷ 6 = 3 4
÷ 1 8
÷ 6 =
3 4
• 8 1
• 1 6
= 2424
= 1
47.1 15
+ 1115
= 1215
= 4 5
49.139
− 2 9
+ 109
= 219
= 7 3
51.1954
− 5 54
− 5 54
= 9 54
= 1 6
53. 8 = 23 14 = 2•7LCD = 23•7=56
55. 9 = 32 15 = 3•5 35 = 5•7LCD = 32•5•7= 315
57. 27 = 33 36 = 22•32 48 = 24•3
LCD = 24•33=432
59.1 6
= 1 • 3 6 • 3
= 3 18
61.1 36
= 1 • 5 36• 5
= 5
180
63. 3 = 3 1
= 3 • 911 • 91
= 27391
65. 9 = 32 24 = 23•3 LCD = 23•32 = 72
2 9
+ 5 24
= 2 • 8 9 • 8
+ 5 • 3 24• 3
=
1672
+ 1572
= 3172
67. 8 = 23 20 = 22•5 LCD = 23•5=40
6 8
− 3 20
= 6 • 5 8 • 5
− 3 • 2 20• 2
=
3040
− 6 40
= 2440
= 3 5
69. 6 = 2•3 2 = 2•1 3 = 3•1 LCD = 6
5 6
+ 1 2
+ 8 3
= 5 6
+ 1 • 3 2 • 3
+ 8 • 2 3 • 2
=
5 6
+ 3 6
+ 166
= 246
= 4
71. 28 = 22•7 21 = 3•7 9 = 32
LCD = 22•32•7 =252
9 28
+ 1021
− 7 9
=
9 • 9 28• 9
+ 10• 1221• 12
− 7 • 289 • 28
=
81252
+ 120252
− 196252
= 5
252
73. ( 2 3
) 2 + ( 1 4
) 2 = 4 9
+ 1 16
7CHAPTER 1 THE REAL NUMBER SYSTEM
9 = 32 16 =24 LCD = 24•32 = 144
4 9
+ 1 16
= 4 • 169 • 16
+ 1 • 9 16• 9
=
64144
+ 9
144=
73144
75. 10 = 2•5 6 = 2•3 LCD=2•3•5=30
( 3 7
) ( 1 10
+ 5 6
) =
( 3 7
) ( 1 • 3 10• 3
+ 5 • 5 6 • 5
) =
( 3 7
) ( 3 30
+ 2530
) = ( 3 7
) ( 2830
) = 4 10
=
2 5
77. 2 + 3 + 5 3 ( 2 )
= 2 + 8 6
= 2 + 4 3
=
2 • 3 1 • 3
+ 4 3
= 6 3
+ 4 3
= 103
79. ( 4 15
+ 1 5
) ( 7 6
+ 4 3
) =
15 = 3•5 LCD=15 6=2•3 LCD = 6
( 4 15
+ 1 • 3 5 • 3
) ( 7 6
+ 4 • 2 3 • 2
) =
( 4 15
+ 3 15
) ( 7 6
+ 8 6
) = ( 7 15
) ( 156
) =
7 6
81.3 8
÷ 9 4
+ 1 9
÷ 1 3
= 3 8
• 4 9
+ 1 9
• 3 1
=
1 6
+ 1 3
= 1 6
+ 2 6
= 3 6
= 1 2
83.1 3
+ 2 3
( 1 2
+ 1 7
) =
1 3
+ 2 3
( 7 14
+ 2 14
) = 1 3
+ 2 3
( 9 14
)
1 3
+ 3 7
= 7 21
+ 9 21
= 1621
85. Sum is -2r + 5s with the terms being -2r and 5s. The products are-2r and 5s. The factors of -2r are -2 and r and the factors of 5s are 5and s.
86. 18/3•2+32= 18/3•2+9=6•2+912 + 9=21
87. 3•22-32= 3•4 - 9 = 12 - 9= 3
88. 8+24÷2•3=8 +12•3=8+36=44
89. 5 + 8 − 2 • 2 2
4 + 3 2 = 5 +
8 − 2 • 4 4 + 9
=
5 + 8 − 8 13
= 5 + 0 13
= 5 + 0 = 5
90. (32-2•4)(20-12/2•3)=(9 - 2•4)(20-12/2•3) = (9 - 8)(20-
6•3)(1)(20-18) = 1(2) = 2
91. 4+2(109-5(2 + 62÷2)) = 4+2(109-5(2+36÷2))=4+2(109-5(2+18)=4+2(109-5(20))=4+2(109-100)=4+2(9)=4+18=22
92. 18-3(8-3(22-3)) = 18-3(8-3(4 -3))=18-3(8-3(1))= 18-3(8-3)=18-3(5)=18-15 = 3
93. 6÷2• 9 = 6÷2•3=3•3=9
94. For c = 38c - c2 = 8(3) - 32=8(3) -9=24-9=15
95. For a = 62a(a2÷2•3-50) = 2(6)((6)2÷2•3-50)=
8 CHAPTER 1 THE REAL NUMBER SYSTEM
12(36÷2•3-50)= 12(18•3-50)=12(54 - 50)= 12(4) = 48
Section 1.3 Real Numbers
Practice 1.3.11.<--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|-->
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9
2.<--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|-->
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9
Practice 1.3.21. {-9.9,-4.7,-0.6, 3.1, 5.8,10}
2. {-7.4, -4, -2.1,0.5,3,5.7}
Practice 1.3.31.<--|-----|-----|-----|-----|-----|-----|-----|-----|----->
-300 -250 -200 -150 -100- -50 0 50 100
2.<--|-----|-----|-----|-----|-----|-----|-----|-----|----|->
-200 -100 0 100 200- 300 400 500 600 700
3.<--|-----|-----|-----|-----|-----|-----|---->
20 30 40 50 60 70 80
4.<--|-----|-----|-----|-----|-----|-----|-----|-----|----->
5 10 15 20 25 30 35 40 45
5.<--|---|---|---|---|---|--|--|---|---|---|--|---|---|--|--|---|--|->
-0.5 -0.4 -0.3 -0.2 -0.1 0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 1.2
6. <--|-----|-----|-----|-----|-----|-----|---->
-2.5 -2.0 -1.5 -1.0 -0.5 0 0.5
Practice 1.3.41. 7 is to the left of 12 on the number
line so 7<12.
2.1 2
is to the left of 3 4
on the number
line so 1 2
< 3 4
.
3. -12 is to the right of -22 on thenumber line so -12>-22.
4. 5 is to the right of -12 on thenumber line so 5> -12.
Practice 1.3.51. -36
2. 45 or +453. 2w
4. -7t
5. -(-(-2)) = -2
9CHAPTER 1 THE REAL NUMBER SYSTEM
Practice 1.3.61. 12 = 12 since the distance from 12
to 0 on the numberline is 12.
2. − 57 = 57 since the distance from-57 to 0 on the number line is 57.
3. − 4445
= 4445
since the distance from
− 4445
to 0 is 4445
4. − 179 = -179 since this is theopposite of 179 . The absolutevalue of 179 is 179 and
the opposite of 179 is -179 so − 179 = − 179
5. − − 59 = − 59 since this is theopposite of the absolute value of
-59. The absolute value of -59 is 59and the opposite of 59 is -59.
Practice 1.3.71. 15 + − 12 = 15 + 12 = 27
2. 25 − 7 = 25 − 7 = 18
3. − 17 + 2 • 21 = 17 + 2 • 21 = 17+42 =59
4. 5 + − 45 ÷ 5 + − 7 = 5 + 45÷ 5 + 7 =5+9+7=21
5. 22 − − 10 − 3 = 22 − 10 − 3 = 9
6. − 32 + − 15 • 3 = 32 + 15• 3 = 32+45=77
Exercise Set 1.31.<--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|-->
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9
3. {-8,-4.5,-1,3,6,9.9}
5.<--|-------|-------|-------|------•-------|-------|->
1940 1950 `960 1970 1980 1990 2000
7.<--|------|------|------|------|------|----•-|------|------|-->
0 5 10 15 20 25 30 3540
9.<--|--•--|-----|-----|-----|-----|-----|-----|-----|----->
-2 -1.5 -1.0 -0.5 0 0.5 1.0 1.5 2.0
11. -3>-4 since -3 is to the right of -4 onthe number line.
13. − 1 2
< − 1 3
since − 1 2
is to the left of
− 1 3
on the number line.
15. 5>-12 since 5 is to the right of -12 onthe number line.
17. 0 >− 7 9
since 0 is to the right of− 7 9
on the number line.
19.5 12
> − 6 7
since 5 12
is to the right of
− 6 7
on the number line.
21. -12
23. 5x
25. -(-(-7))=-(7) = -7
27. − 577 = 577 since the distance onthe number line from -
577 to 0 is 577.
29. − − 7 . 5 = − 7 . 5 since the absolutevalue of -7.5 is 7.5 and the oppositeof 7.5 is -7.5.
31. 8 − − 5 = 8 − 5 = 3
33. 15 − 3 ÷ 5 − 3 = 12 ÷ 2 = 12÷ 2 = 6
35. − ( 8 + − 6 ) = − ( 8 + 6 ) = − 14
37. 8 − 2 ÷ ( 6 − 6 ) = 6 ÷ ( 6 − 6 ) 6 ÷ 0 is not possible since we cannotdivide by zero.
10 CHAPTER 1 THE REAL NUMBER SYSTEM
39. The sum is 8 + 2 and the terms are8 and 2.
40.9 8 343
= 2 • 7 • 7 7 • 7 • 7
= 2 7
41.2 x
, x≠0
42.1 3
• 7
43. 16/2•(13-2(5-1)-2)=16/2•(13-2(4)-2)=16/2•(13-8-2)=16/2•(3)=8•3=24
44. 8 + 5•2 = 8+10=18
45. 8 − 1
2 • 14
1
3 + 2
= 8 − 7 1
3 + 6
3
=
8 − 7 7
3
= 8 − 7 ÷ 7 3
=
8 − 7 • 3 7
= 8 - 3 = 5
46.32
25
24
35
= 3225
÷ 2435
= 3225
• 3524
=2815
47.84
15
4
25
= 8415
÷ 4
25= 84
15•
254
=
3 • 4 • 7 3 • 5
• 5 • 5 4
= 7 • 5 = 35
48.4
15+ 7
25= 4 • 5
15• 5 + 7 • 3
25• 3 =
2075
+ 2175
= 4175
49.3 4
+ 7 10
+ 1 5
= 3 • 5 4 • 5
+ 7 • 2 10• 2
+ 1 • 4 5 • 4
=
1520
+ 1420
+ 4 20
= 3320
50.6 2 − 2 • 3 15 − 5 • 2
= 36 − 6 15 − 10
= 305
= 6
51.9 24
• 6072
= 9
2 • 12•
5 • 128 • 9
= 5 16
Section 1.4 Multiplying and Dividing Real Numbers
Practice 1.4.11. 6(-5) = -30
2. (-6)(-9) = 54
3. (-12)(5) = -60
4. ( 8 ) ( − 3 4
) = 2 ( − 3 ) = − 6
5. ( − 12) ( − 2 3
) = 8
6. (-2)(5)(4) = -40
7. (-2)(-7)(-4) = -56
Practice 1.4.21. For m = -5
-7m = -7(-5)=35
2. For m = -55m = 5(-5) = -25
3. For m = -5 and n = -4n2m = (-4)2(-5) = 16(-5) = -80
4. For m = -5 and n = -4m3n = (-5)3(-4) = (-125)(-4) = 500
5. For n = -4
− 3 16
n = − 3 16
( − 4 ) = 3 4
6. For m = -5 and n = -4(mn)3 = ((-5)(-4))3= (20)3 = 8000
Practice 1.4.31. For m= -8
-m = -(-8) = 8
11CHAPTER 1 THE REAL NUMBER SYSTEM
2. For n = 3-n2 = -(3)2= -9
3. For n= 3(-n)2 = (-3)2 = 9
4. For m = -8 and n = 3-(-m)(-n) = -(-(-8)(-3)) = -(-24) =
24
Practice 1.4.41. The cube of -2 = (-2)3 = -82. The product of 5 and -1 =
(5)(-1) = -5
3. Twice -10 = 2(-10) = -20
4. Two thirds of nine = 2 3
• 9 = 6
5. Five percent of 8 = 0.05(8) = 0.4
6. 15 fifteen multiplied by -4 = -60
Practice 1.4.51. Product of -2 and 4, or -2 multiplied
by 4 or -2 times 4.
2. Product of 7 and 8, or 7 multiplied by8 or 7 times 8.
3. Product of 1/2 and 5, or 1/2multiplied by 5 or 1/2 of 5.
4. Six cubed or 6 to the third power
Practice 1.4.61. -20/4 = -5
2.49− 7
= − 7
3. -54÷0 is undefined. We can’t divideby zero.
4. 0/-9 = 0
5. (-1.5)/(-0.3) = 5
Practice 1.4.7
1.
5 6
− 109
= 5 6
÷ − 10
9
5 6
• 9
− 10=
3 2 • ( − 2 )
=
3 − 4
= − 3 4
2. ( 24) ÷ ( 1
− 3 ) = 24• (
− 3 1
) = − 72
3.−
4 5
− 6 = −
4 5
÷ − 6 = − 4 5
• 1
− 6 =
− 2 5
• 1
− 3 =
− 2 − 15
= 2 15
Practice 1.4.81. For x = -5 and y = -3
y x
= − 3 − 5
= 3 5
2. For y = -3 and z = 1/4
z y
=
1 4
− 3 =
1 4
÷ − 3 =
1 4
• 1
− 3 =
1 − 12
= − 1 12
3. For x = -5 , y = -3 and z = 1/4
− xy2
z =
− ( − 5 ) ( − 3 ) 2
1 4
= 5 ( 9 )
1 4
=
45÷ 1 4
= 45• 4 = 180
4. For x = -5 and y = -3
12 CHAPTER 1 THE REAL NUMBER SYSTEM
x 2
y
y 2
x
= x 2
y ÷
y 2
x =
( − 5 ) 2
− 3 ÷
( − 3 ) 2
− 5 =
25− 3
÷ 9
− 5 =
25− 3
• − 5 9
=
− 125− 27
= 12527
Practice 1.4.91. The quotient of -8 and 4 = -8/4 = -2
2. The quotient of -24 and 4 3
=
− 24÷ 4 3
= − 24• 3 4
= − 18
3.8 9
divided by -3 = 8 9
÷ − 3
8 9
• 1
− 3 =
8 − 27
= − 8 27
4. -36 divided by -4 = -36/-4 = 9
5. The reciprocal of 2 is 1/2
6. The reciprocal of 4 less than six is1
6 − 4 =
1 2
Practice 1.4.101. 18 divided by 4 or the quotient of 18
and 4.
2. 39 divided by -5 or the quotient of 39and -5.
3. The reciprocal of three more than 5.
4. The reciprocal of twice -4.
Exercise Set 1.41. (-15)(-5) = 75
3. (-2)(-5)(-3) = -30
5. ( − 6 5
) ( − 5 ) = ( − 6 ) ( − 1 ) = 6
7. ( 1518
) ( − 6 5
) = ( 5 6
) ( − 6 5
) = − 1
9. For x = -22x = 2(-2) = -4
11. For y = -3-6y = -6(-3) = 18
13. For x = -2 and y = -3-xy = -(-2)(-3) = -6
15. For x = -2-x2 = -(-2)2= -4
17. For y = -3 and z = 4(yz)2 = ((-3)(4))2 = (-12)2 = 144
19. For x = -2 and y = -3xy2 = (-2)(-3)2 = (-2)(9) = -18
21. For x = -2
− 5 4
x 2 = − 5 4
( − 2 ) 2 = − 5 4
( 4 ) = − 5
23. The square of -5 = (-5)2 = 25
25. Double -8 = 2(-8) = -16
27. Six-sevenths of -14 =6 7
• ( − 141
) =
6 • ( − 2 ) = − 12
29. 12% of 80 = 0.12(80) = 9.6
31. Product of 6 and 3 or 6 multiplied by3 or 6 times 3.
33. Product of 3/4 and 12 or 3/4multiplied by 12 or 3/4 of 12.
35. -45/9 = -5
37.− 27− 3
= 9
39. 54÷(-9) = -6
13CHAPTER 1 THE REAL NUMBER SYSTEM
41.15− 3 4
= 15÷ − 3 4
= 15• 4
− 3 =
− 5 • 4 = − 20
43.− 5 8
÷ ( − 1516
) = − 5 8
• ( 16
− 15) =
2 3
45.2 3
÷ ( − 6 ) = 2 3
• ( 1
− 6 ) =
1 − 9
= − 1 9
47.18
− 258
− 15
= 18
− 25÷
8 − 15
=
18− 25
• − 15
8 =
− 27− 20
= 2720
49.
24− 5 − 8
= 24− 5
÷ ( − 8 ) =
24− 5
• 1
− 8 =
3 5
51.− 2 − 3 − 4
= − 2 ÷ − 3 − 4
= − 2 • − 4 − 3
=
8 − 3
= − 8 3
53. For p = -4 and r = -1/3p r
= − 4
− 1 3
= − 4 ÷ ( − 1 3
) =
− 4 • ( − 3 ) = 12
55. For p = -4 and q = -2
q p•q
= − 2
− 4 • ( − 2 ) =
1 − 4
= − 1 4
57. For p = -4 and q = -2
( q
p 2 ) 2 = (
− 2
( − 4 ) 2 ) 2 =
( − 2 16
) 2 = ( − 1 8
) 2 = 1 64
59. For p = -4, q = -2 and r = -1/3
r(p÷q) = (− 1 3
) ( − 4 ÷ ( − 2 ) ) =
( − 1 3
) ( 2 ) = − 2 3
61. 50÷(-150) = 1/(-3) = -1/3
63.1
12 − 5 =
1 7
65.4 5
÷ ( − 2 ) = 4 5
• 1
− 2 = − 2
5
67.6 15
÷ − 2 5
= 6 15
• 5
− 2 =
− 3 3
= − 1
69. The quotient of 64 and -8 or 64divided by -8
71. The quotient of 2 and 1/3 or 2divided by 1/3.
73. The quotient of 1/3 and 2/9 or 1/3divided by 2/9.
75. 12 + 5 is a sum whose terms are
76. 300=22•3•52
1
5 5
5 25
3 75
2 150
2 300
14 CHAPTER 1 THE REAL NUMBER SYSTEM
77.8 3
78.1 9
x
79.1620
= 4 • 4 4 • 5
= 4 5
80. -8
81. <--|---|---|---|---|---|---|---|---|---|---|---|•--|---|-->
-10 -5 0 5 10 15 20 25 30 35 40 45 50 55
82. 6•2+3 = 12+3 = 15
83. 8 - [(2+3)2 - 18] =8 -[(5)2 - 18] =8 - [25-18]= 8 -7=1
84.1224
• 6 30
= 1 2
• 1 5
= 1 10
85.1812
÷ 6 15
= 1812
• 156
=
3 • 5 4
= 154
86.1 2
+ 5 6
= 1 • 3 2 • 3
+ 5 6
= 3 6
+ 5 6
=
8 6
= 4 3
87.24 − 2 • 3 2
3 • 2 2 − 5 • 2 =
24 − 2 • 9 3 • 4 − 5 • 2
=
24 − 1812 − 10
= 6 2
= 3
88. − 2 + 5 = 2 + 5 = 7
89. − 3 • 18÷ ( − 9 • 2 ) = 3 • 18÷ ( − 18) = 54÷ ( − 18) = − 3
Section 1.5 Adding and SubtractingReal Numbers
Practice 1.5.11. (-8) +(-10)
Add absolute values |-8| +|-10| = 18Attach the common sign -18
2. (-25)+(-16) Add absolute values |-25| +|-16| = 41Attach the common sign -41
3. 9 + (-36) Subtract absolute values |-36| -|9| =27Attach sign of larger absolute value
-27
4. (-15) + 18Subtract absolute values |18| -|15| =
15CHAPTER 1 THE REAL NUMBER SYSTEM
3Attach sign of larger absolute value +3 or 3
5. (-25) +(-10) + 14 = (-35) + 14 = -21
6. 8 + (-31) + 34 = -23 + 34 = 11
7. 21 + (-27) + (-14) = -6 + (-14) = -20
8. (-12) + (-26) + (-13) = -38 + (-13) = -51
9. ( − 1 2
) + ( − 3 4
) =
( − 2 4
) + ( − 3 4
) = − 5 4
= -1 1 4
10. ( − 5 6
) + ( 3 4
) =
( − 1012
) + ( 9 12
) = − 1 12
11. − 3 8
+ ( − 3 1 2
) =
− 3 8
+ ( − 3 4 8
) = − 3 7 8
12. − 2 1 4
+ 3 2
= − 9 4
+ 3 2
=
− 9 4
+ 6 4
= − 3 4
Practice 1.5.21. The box is -11 since 11 + (-11) =02. The box is 22 since 22 + (-22) = 0
3. The box is 5 6
5 6
+ ( − 5 6
) = 0
4. The box is -0.002 since -0.002+0.002 = 0
Practice 1.5.31. -18 increased by 10
‘Increased by’ tells us to add-18 + 10 <---- Translated-8
2. -8.6 increased by 15‘Increased by’ tells us to add-8.6 + 15 <---- Translated6.4 <----Simplified
3.3 7
more than − 5 7
‘More than’ tells us to add3 7
+ − 5 7
<---- Translated
− 2 7
<----Simplified
4. 1 more than − 7 8
‘More than’ tells us to add
1 + − 7 8
<---- Translated
8 8
+ − 7 8
= 1 8
<----Simplified
5. -10 added to -16‘Added to’ tells us to add-10 + -16 <----Translated-26 <---- Simplified
6. The sum of 25 and -36‘The sum of’ tells us to add25 + -36 <---Translated-11 <----Simplified
Practice 1.5.41. The sum of -12 and 7.
-12 increased by 77 more than -127 added to -12
2. The sum of 15.9 and 25.15.9 increased by 2525 more than 15.925 added to 15.9
Practice 1.5.51. The current temperature is -40
degrees and it warms up 3 degrees.What is the new temperature?-40 + 3 <----Translated-37 degrees or 37 degrees below 0
2. You begin on a hill 650 feet abovesea level and descend
16 CHAPTER 1 THE REAL NUMBER SYSTEM
780 feet from the top of the hill.What is your new elevation?
650 feet above sea level is +650Descending 780 feet would berepresented by -780.650 + -780 <-----Translated-130 <---- Simplified-130 feet or 130 feet below sea level
3. Checking account overdrawn by $36is represented by -
$36. When $15 is depositedthen you are adding $15 to the -$36.
-36 + 15 <---- Translated-21 <--- Simplified-$21 is the balance. The account isstill overdrawn by $21.
4. A balance of $45 would berepresented by +45. A $60 checkwould be represented by -60.45 + (-60) <---- Translated-15 <---- Simplified-$15 is the balance. The account isstill overdrawn by $15.
5. The new share price is represented
by the sum 136 + ( − 2 1 2
) <--
Translated
136 + ( − 2 1 2
) = 136 + ( − 5 2
) =
1361
• 2 2
+ ( − 5 2
) =
2722
+ ( − 5 2
) = 2672
= 1331 2
The new price is 133 1/2 or $133.50.
6. The new share price is represented
by 255 + ( − 3 1 4
) <----
Translated
255 + ( − 3 1 4
) = 255 + ( − 134
) =
2551
• 4 4
+ ( − 134
) =
10204
+ ( − 134
) = 1007
4 =
2513 4
The new price is 2513 4
or $251.75.
Practice 1.5.61. -8 -10 = -8 + (-10) = -18
2. -9 -12 = -9 + (-12)= -21
3. 42 - (-27)= 42 + (+27) = 69
4. 4 - (-36) = 4 + (+36) = 40
5. -10 - (-4) = -10 + (4) = -6
6. -7 - (-3) = -7 + (+3) = -4
7. 18 - 27 = 18 + (-27) = -9
8. 11 - 32 = 11 + (-32) =-21
9. -25 - (-10) -14 = -25+(+10)+ (-14)=-15 + (-14) = -29
10. -8 -(-31) - 34= -8 + (+31) +(-34)=23 + (-34) = -11
11. ( − 1 2
) − ( 3 4
) =
( − 2 4
) + ( − 3 4
) = − 5 4
= -1 1 4
12. ( − 3 8
) − ( 3 5
) =
( − 1540
) + ( − 2440
) = − 3940
Practice 1.5.71. 7 - (6-9) = 7 - (6 + (-9))=
7 - (-3) = 7 +(+3)= 10
2. -7 -(4+2) = -7 -(6) = -7 + (-6) = -13
3. 25 - (-10 + 13) = 25 - (3) = 22
4. 19 - (25 - 36) = 19 - (25 + (-36)) = 19 - (-11) = 19 + (+11) = 30
17CHAPTER 1 THE REAL NUMBER SYSTEM
5. 25 - (-10 -13) = 25 - (-10 + (-13)) = 25 - (-23) = 25 + (+23) = 48
6. (19 - 25) - 36 = (19 + (-25)) - 36 = -6 - 36 = -6 + (-36) = -42
7. (-8 -2) - (-5 + 4) = (-8 + (-2)) - (-1)=(-10) - (-1) = (-10) + (+1) = -9
8. (-5 -1) - (-3 + 8) = (-5 + (-1)) - (5) = (-6) - (5) = -6 + (- 5) = -11
Practice 1.5.81. For x = -8 and y = 7
x - y = (-8) - 7 = (-8) + (-7) = -15
2. For p = 10 and q = -4-3p - q = -3(10) - (-4) = -30 - (-4) =-30 + (+4) = -26
3. For w = -32 and v = -25w - (v - w) = -32 -(-25 -(-32)) = -32 - (-25 + (+32)) = -32 - 7 = -32 + (-7) = -39
4. For p=-5 and q = 3p-2(q - 3p) = -5 -2(3 - 3(-5)) = -5 - 2(3 - (-15)) = -5 -2(3 + (+15)) = -5 -2(18) - -5 -36 = -5 + (-36) = -41
Practice 1.5.91. -18 decreased by 10
‘Decreased by’ tells us to subtract-18 -10 <----Translated-18 + (-10) = -28 <--- Simplified
2. 15 decreased by 9‘Decreased by’ tells us to subtract15 -9 <----Translated6 <----Simplified
3. 1 less than − 7 8
− 7 8
− 1 <---Translated with
rearranged order tomatch Englishmeaning
− 7 8
− 1 = − 1 7 8
4. -10 subtracted from -16
-16 - (-10) <---Translated with rearranged order tomatch Englishmeaning
-16 + (+ 10) = -6
5. -13 subtracted from 2828 - (-13) <---Translated with
rearranged order tomatch Englishmeaning
28 + (+13) = 41
6. The difference of 5 and − 3 4
5 − ( − 3 4
) = 5 + ( + 3 4
) = 5 3 4
Practice 1.5.101. The difference of -12 and 7
-12 decreased by 77 less than -12 7 subtracted from -12
2. The difference of -1 and -3-1 decreased by -3-3 less than -1-3 subtracted from -1
Exercise Set 1.51. -5 + (-9) = -14
3. 24 + (-26) = -2
5. -39 + 54 + (-7) = 15 + (-7) = 8
7. 36 + (-45) + (-22) + 73 =-9 + (-22) + 73 = -31 + 73 = 42
9. − 5 12
+ 3 4
= − 5 12
+ 9 12
= 4 12
= 1 3
11. − 1 + 1 8
+ ( − 5 6
) =
− 2124
+ ( − 2024
) = − 4124
= − 1 1724
13. The box is -29 since 29 + (-29) = 0
15. The box is 1315
18 CHAPTER 1 THE REAL NUMBER SYSTEM
since 1315
+ ( − 1315
) = 0
17. The box is 24.9 since -24.9+24.9 =0
19. -32 increased by 24‘Increased by’ tells us to add-32 + 24 <----Translated-8 <----Simplified
21. -22 added to 13‘Added to’ tells us to add-22 + 13 <-----Translated-9 <---- Simplified
23. The sum of 5 8
and − 1 6
‘The sum of’ tells is to add5 8
+ − 1 6
<---- Translated
5 8
+ − 1 6
= 1524
+ − 4 24
= 1124
25. 5 more than − 2 3
‘More than‘tells us to add
5 + − 2 3
<---Translated
5 + − 2 3
= 153
+ − 2 3
=
133
= 4 1 3
<----Simplified
27. The sum of -36 and 1111 more than -36-36 increased by 1111 added to -36
29. The sum of -5 and (-2)(-2) added to -5
31. Checking account is overdrawn by$25 and $40 is
deposited. What is thenew balance?Overdrawn is represented by -25
and the deposit is representedby 40.
-25 + 40 <---Translated15 <-----Simplified$15 is in the account
33. Price was $25 and the value changed
by - 3 4
. What is the current value?
25 + ( − 3 4
) <----Translated
25 + ( − 3 4
) = 251
• 4 4
+ ( − 3 4
) =
1004
+ ( − 3 4
) =
974
= 241 4
<--Simplified
Current price is $241 4
or $24.25
35. -5 -9 = -5 + (-9) = -14
37. -24 - (-26) = -24 + (+26) = 2
39. -36 - (-22) - 18 = -36 + (+22) -18=-14 -18 = -14 + (-18) = -32
41. 11 - 18 - (-30) = 11 + (-18) -(-30) = -7 -(-30) = -7 +(+30) = 23
43. 36 - (-45) - (-22) - 73= 36 + (+45) + (+22) + (-73)=81 + 22 + (-73) = 103 + (-73) = 30
45.− 3 14
− 6 7
= − 3 14
− 1214
=
− 3 14
+ ( − 1214
) = − 1514
= − 1 1 14
47. 12 - (4 - 8)= 12 - (4 + (-8)) = 12 - (-4) = 12 + (+4) = 16
49. (12 - 4) - 8 = 8 - 8 = 0
51. (-10 - 7) - 2 = (-10 + (-7)) - 2=-17 - 2 = -17 + (-2) = -19
53. (36 - 45) - (6 -8) = (36 + (-45)) - (6 + (-8)) = -9 - (-2) = -9 + (+2) = -7
55. For x = -28 and y = 15x - y = -28 - 15 = -28 + (-15) =-43
57. For m= -2 and n= -5
19CHAPTER 1 THE REAL NUMBER SYSTEM
m - (m -n) = -2 - (-2 - (-5)) = -2 -(-2 +(+5)) = -2 -3 = -2 +(-3) =-5
59. For x = 4 and y = 93x - 5y = 3(4) - 5(9) = 12 - 45= 12 + (-45) = -33
61. -32 decreased by 24-32 - 24 <-----Translated-32 + (-24) = -56 <----Simplified
63. -22 subtracted from 1313 - (-22) <---Translated withrearranged order to match Englishmeaning13 -(-22) = 13 + (+22) = 35
65. the difference of -1 3
and 3
− 1 3
− 3 <---Translated
− 1 3
− 3 = − 1 3
− 3 1
• 3 3
=
− 1 3
− 9 3
= − 1 3
+ − 9 3
= − 10
3 =
− 3 1 3
<-----Simplified
67. 5 less than -24-24 - 5 <---Translated withrearranged order to match Englishmeaning-24 - 5 = -24 + (-5) = -29
69. The difference of -36 and 11-36 decreased by 1111 less than -3611 subtracted from -36
71. The difference of 4/9 and 44/9 decreased by 44 less than 4/94 subtracted from 4/9
73. 150 = 2•3•5•5 = 2•3•52
74.1 x
, x≠0
75. 4•2 is a product whose factors are 4and 2.
76.2 t 3
= 2 3
t
77. -0.23
78.2436
= 2 • 123 • 12
= 2 3
79. 8 + 2 • 3 + 6 12 − 2 • 3
= 8 + 6 + 6 12 − 6
=
8 + 126
= 8 + 2 = 10
80.1835
• 2124
= 3 • 6 5 • 7
• 3 • 7 4 • 6
=
3 5
• 3 4
= 9 20
81.5 8
+ 2 3
= 1524
+ 1624
= 3124
= 1 7 24
82.2 4 − 5 • 2
5 2 − 2 • 3 2 − 1 =
16 − 1025 − 2 • 9 − 1
=
6 25 − 18 − 1
= 6 6
= 1
83. 8 - 2(8 + 2(8 - 2) -19) =8 - 2(8 + 2(6) - 19) =8 - 2(8 + 12 - 19) = 8 - 2(1) = 8 - 2= 6
84. 2 • |-3| -4 = 2 • 3 - 4 = 6 - 4 = 2
85. 6 • 6 • ( − 1 2
) = 6 1
• ( − 1 2
) = − 3
86. -0.5 •2 ÷ (-0.4) =-1.0 ÷(-0.4) = 2.5
87. -5 •12
88. x is the number
x÷7 or x 7
20 CHAPTER 1 THE REAL NUMBER SYSTEM
Section 1.6 Properties of Real Numbers
Practice 1.6.11. The box is 0 since 0 + -36 = -36
2. The box is 1 since -12 • 1 = -12
3. The box is 7 since 7 + -7 + 2z = 0 + 2z = 2z
4. The box is -33 since -33 + 33 + 8n = 0 + 8n = 8n
5. The box is 3 2
since ( 3 2
) ( 2 3
) ( 9 ) = 1 ( 9 ) = 9
6. The box is 1 23
since ( 1 23
) ( 23) ( 11) = 1 ( 11) = 11
Practice 1.6.21. 22 +5
2. 8 - 23 = 8 + (-23) = -23 + 8
3. 5y2 +3y+2
4. 5w3 -2w2 + w
5. -8x -12
6. p - 5 - p2 = p -5 + (-p2)= -p2 + p - 5
7. a2 - 2a - 3
Practice 1.6.31. 5•4
2. 5w
3. 12(y - 8)
4. (d - 3)8
5. (x +2 )(x - 12)
6. a2 bc since this is alphabetical order
Practice 1.6.4
1. ( 5 6
+ 1 6
) + 9
2. − 10 + ( 1 3
+ 2 3
)
3. 6 + (7x + 3x)
4. (3x + 4x) + 12
Practice 1.6.51. 7 • (3 • 5)
2. -4 • (2 • (-8))
3. (4 • 5) • 3
4. ( 2 3
• 3 ) x
5. ( 12• 1 12
) y
6. ( 8 • 1 8
) z
Practice 1.6.61. 2(y + 7) = 2•y + 2•7=2y +14
21CHAPTER 1 THE REAL NUMBER SYSTEM
2. -4(x + 2) = -4•x + (-4)•2 = -4x - 8
3. 6(r + 3s + 2) = 6•r + 6•3s + 6•2 = 6r + 18s + 12
4. -2(5x + y + 4) =-2•5x + (-2)•y + (-2)•4= -10x -2y -8
5. -7(y - 4) = -7•y - (-7)•4 = -7y -(-28)=-7y + 28
6. -4(-2x - 3)= -4(-2x) -(-4)•3 = 8x - (-12) = 8x + 12
Practice 1.6.71. 2y + 12y = y(2 +12)
2. 5y + 8y + 11y = y(5 + 8 + 11)
3. 3x - 5x = x(3 - 5)
4. xy + wy = y(x + w)
5. nm + mp = m(n + p)Practice 1.6.81. 63
• base is 6• exponent is 3• 63 = 6•6•6 = 216
2. 45
• base is 4• exponent is 5• 45 =4•4•4•4•4 =1024
3. 5•42 • base is 5• exponent is 1• base is 4• exponent is 2• 42 =4•4=165•42 =80
4. (3•2)3
• base is (3•2)• exponent is 3• (3•2)3 =(3•2)•(3•2)•(3•2)(3•2)3=63=6•6•6 = 216
5. (-7)2
• base is -7• exponent is 2• (-7)2 =-7•-7=49
6. -(8)2
• base is 8• exponent is 2• -(8)2 =-8•8=-64
7. -72
• base is 7• exponent is 2• -72 =-7•7= -49
8. -(-8)2
• base is -8• exponent is 2• -(-8)2 =-(-8)•(-8)= - 64
Practice 1.6.91. y 7
•y is the base and its exponent is 7•the expanded form is y•y•y•y•y•y•y
2. 8z5
•8 is a base and its exponent is 1•z is a base and its exponent is 5•the expanded form is 8•z•z•z•z•z
3. (4y)3
•4y is the base and its exponent is 3•the expanded form is 4y•4y•4y
4. 53 b4
•5 is the base of the first factor andits exponent is3
•b is the base of the second factorand its exponentis 4
•the expanded form is 5•5•5•b•b•b•b
Practice 1.6.101. 3•3•3•3
• the base is 3• there are 4 factors so the exponent should be 4• written in exponential notation we have 34
2. xxyyyyy• one base is x, the other base is y• there are 2 factors of x so its exponent should be 2• there are 5 factors of y so its exponent should be 5
22 CHAPTER 1 THE REAL NUMBER SYSTEM
• written in exponential notation we have x2y5
3. 8•8•8•x•x•x•x• one base is 8, the other base is x• there are 3 factors of 8 so its exponent should be 3• there are 4 factors of x so its exponent should be 4• written in exponential notation we have 83x4
4. 2•2•2•2•2•2•y• one base is 2, the other base is y• there are 6 factors of 2 so its exponent should be 6• there is 1 factor of y so its exponent should be 1• written in exponential notation we have 26y
5. (-3)(-3)(-3)(-3)mmmmmnnn• one base is (-3), another is m and the other base is n• there are 4 factors of (-3) so its exponent should be 4• there are 5 factors of m so its exponent should be 5• there are 3 factors of n so its exponent should be 3• written in exponential notation we have(-3)4m5n3
Exercise Set 1.61. The box is 0 since 0 + -18 = -18
3. The box is 1 since 8•1 = 8
5. The box is 7.7 since 7.7 + (-7.7) + 6z = 0 + 6z=6z
7. The box is − 4 5
since − 4 5
+ 4 5
+ 12n =
0 + 12n = 12n
9. The box is 6 5
since
6 5
• ( 5 6
) • ( 33) = 1 • ( 33) = 33
11. 7 - 13 = 7 + (-13) = -13 + 7
13. 3x - 2x2 + 5 = 3x + (-2x2) + 5=-2x2 + 3x + 5
15. 12•26 = 26•12
17. r3 = 3r
19. (x - 5)9 = 9(x - 5)
21. (2x + 3)(x + 9) = (x + 9)(2x + 3)
23.1 16
+ ( 1516
+ 10) = ( 1 16
+ 1516
) + 10
25. (-2 + 6y) + 8y = -2 + (6y + 8y)
27. (6•2)•3 = 6•(2•3)
29.7 9
( 9 y ) = ( 7 9
• 9 ) y
31. 12(y + 3) = 12•y + 12•3 = 12y + 36
33. 8(x - 2) = 8•x - 8•2 = 8x - 16
35. -3(y - 5x) = -3•y - (-3)(5x) = -3y - (-15x) = -3y + 15x
37. -2(x + y - 6) = -2•x + -2•y -(-2)(6)=-2x -2y -(-12)= -2x - 2y +12
39. 3(y - 2x + 6) = 3•y -3•2x + 3•6 = 3y - 6x + 18
41. 3h + 6h = h(3 + 6)
43. 8x - 2x = x(8-2)
45. 2y - 3y + 5y = y(2 -3 +5)
47. rs - rt = r(s - t)
49. 73
• 7 is the base• 3 is the exponent• 73=7•7•7 = 343
51. 2 •43
• 2 is a base whose exponent is 1•4 is a base whose exponent is 3• 2 •43 =2•4•4•4 = 128
23CHAPTER 1 THE REAL NUMBER SYSTEM
53. (2•4)3
• 2•4 is the base whose exponent is3
• (2 •4)3 =(2 •4)(2 •4)(2 •4) = • 83=512
55. -62
• 6 is the base whose exponent is 2• -62 =-6•6 = -36
57. 9p4
• 9 is a base whose exponent is 1•p is a base whose exponent is 4• The expanded form is 9•p•p•p•p
59. (-8r)3
• -8 is a base whose exponent is 3• The expanded form is (-8r)(-8r)(-8r)
61. 42q4
• 4 is a base whose exponent is 2•q is a base whose exponent is 4• The expanded form is 4•4•q•q•q•q
63. -r3
• r is a base whose exponent is 3• The expanded form is -r•r•r
65. -(-t)4
• -t is a base whose exponent is 4• The expanded form is -(-t)(-t)(-t)(-
t)
67. 11•11•11• 11 is the base with three factors so the
exponent should be 3• exponential notation is 113
69. pppppprrr• p is a base with six factors so the exponent should be 6• r is a base with three factors so the exponent should be 3• exponential notation is p6r3
71. (zzz)(zzzz)• In the first parenthesis z is the
base with 3 factors so the exponent should be 3.
• In the second parenthesis z is the base with 4 factors so the exponent should be 4.• exponential notation is (z3)(z4)
73. -5•5•5•5• 5 is a base with 4 factors so the exponent should be 4• exponential form -54
75. (-3)•(-3)•(-3)•(-3)• (-3) is a base with 4 factors so the exponent should be
4• exponential form (-3)4
77. − 5 4
78.5 x 2
= 5 2
x
79. 12x
80. Let x = the number
x÷6 or x 6
81. Let x = the number x - 4
82. 2( 8 9
)
83. 4[12 - (6 -4)2] = 4[12 - (2)2] = 4[12 - 4] = 4(8) = 32
84.6480
• 3015
= 4 • 165 • 16
• 2 • 151 • 15
=
4 5
• 2 1
= 8 5
= 1 3 5
85.
15214549
= 1521
÷ 4549
= 1521
• 4945
=
153 • 7
• 7 • 7 3 • 15
= 1 3
• 7 3
= 7 9
24 CHAPTER 1 THE REAL NUMBER SYSTEM
86.5 6
+ 7 8
= 2024
+ 2124
= 4124
= 1 1724
87. 12 - |-5| + 2 = 12 - 5 + 2 = 7 + 2 = 9
88. For x = -2 and y = -312 - y - xy = 12 - (-3) - (-2)(-3) = 12 + 3 - 6 = 9
89.4812
= 4 • 1212
= 4
90. <--|----|-----|----|-----|----|----|----•----|-----|-----|->
-0.5 -0.4 -0.3 -0.2 -0.1 0 0.1 0.2 0.3 0.4 0.5
Section 1.7 Simplifying Algebraic Expressions
Practice 1.7.11. 2x2, 3x2 are like terms
2. 5y, 3 2
y are like terms
3. 2x2y4,x 2 y 4
π , 7x2y4 are like terms
0.07y3x2, -x2y3 are like terms
-2x3y2 is not like any other terms
4. 5x5y2, 1.25y2x5 are like terms-9x2y5, 1.1x2y5 are like terms10x3y2 is not like any other term
5. None of these are like any otherterm.
6. 7r2s, 8sr2 are like terms-4rs2, 15r2s 2, 6r2, 2s2 are not likeany other terms
Practice 1.7.21. 6m + 3m = 9m
2. -6r + 8r = 2r
3. 7w - 15w = 7w + (-15w) = -8w
4. 4s - s = 4s - 1s = 3s
5. -8x3 + 5x3 - 12x3 = -3x3 + (-12x3) = -15x3
6. -15a + 7a - 14a = -8a + (-14a) = -22a
7. 8x - 2y + 3y - x = 8x - 1x - 2y + 3y =7x + y
8. 9xy2 + 3x2y - 7xy2 + 2x2y = 2xy2 + 5x2y
Practice 1.7.31. 4x + (2x - 12x) = 4x + (-10x) =-6x
2. -8y + (3y - 6y) = -8y + (-3y) = -11y
3. 5w - (4w - 6w) = 5w - (-2w) =5w + 2w = 7w
4. -7m - (4m - 3m) = -7m - 1m = -8m
25CHAPTER 1 THE REAL NUMBER SYSTEM
5. (6x + 4x) - (3x + 7x) = 10x - 10x = 0
6. (5m + 7m) - (m - 8m) = 12m - (-7m) =12m + 7m = 19m
7. (5r - r) - (9r - 6r) = 4r - 3r = r
8. (5n + 2n) - (6n - 15n) = 7n - (-9n) =7n + 9n = 16n
Practice 1.7.41. 5x + 3(x + 3) = 5x + 3x + 9 = 8x + 9
2. 3m + 6(m+6) = 3m + 6m + 36 = 9m + 36
3. 4y + 3(2y - 7) = 4y + 3(2y) - 3(7) = 4y + 6y - 21 = 10y - 21
4. 2(3x) = 6x
5. -12(3x + 8) = -12(3x) + (-12)(8) = -36x - 96
6. -5(4x + 4) = -5(4x) + (-5)(4) = -20x -20
7. -3(2x - 5) = -3(2x) -(-3)(5) = -6x - (-15) = -6x + 15
8. 6x - 3(5x) = 6x - 15x = -9x
9. 1.5(6x + 10) = 1.5(6x) + 1.5(10) = 9x + 15
10.1 3
( 6 x − 9 ) = 1 3
( 6 x ) − 1 3
( 9 ) =
2x - 3
Practice 1.7.51. -(-4x) = 4x
2. -(6m3 + 3m2 - 4m) = -6m3 - 3m2 + 4m
3. -(-3n2 - 2n + 5) = 3n2+ 2n - 5
4. -(-2x2 - 3x - 5) = 2x2 + 3x + 5
Practice 1.7.6
1. 5x - 6(3x + 7) = 5x - 18x - 42 = -13x - 42
2. 2n - 7(4n + 8) = 2n - 28n - 56 = -26n - 56
3. 3r - 12(5 - 2r) = 3r - 60 + 24r = 27r - 60
4. 5t - 3(7 - 4t) = 5t - 21 + 12t = 17t - 21
5. 4x -(2x2 + 3x - 6) = 4x - 2x2 - 3x + 6= -2x2 + x + 6
6. 4n -(-3n2 - 2n + 5) = 4n + 3n2 + 2n - 5 = 3n2 + 6n - 5
7. -(4x + 5) - (3x - 3) =-4x - 5- 3x + 3= -7x - 2
8. -(2y + 9) - (4y - 2) = -2y - 9 - 4y + 2-6y - 7
Practice 1.7.71. x - 6[3x + (7x - 1) + 2] =
x - 6[3x + 7x - 1 + 2] =x - 6[10x + 1]=x - 60x - 6 = -59x - 6
2. 5x - 3[2 + 2(x + 1) + 4x] = 5x - 3[2 + 2x + 2 + 4x] = 5x - 3[6x + 4] = 5x - 18x -12 = -13x - 12
3. 2x - [2x - (2x + 3) - 4] = 2x - [2x - 2x - 3 - 4] = 2x - [-7]=2x + 7
4. 5x - [5x + 2(x + 3) + 3]=5x - [5x + 2x + 6 + 3] = 5x - [7x + 9] = 5x - 7x - 9 = -2x -9
5. 5x + [3x - (2x + 4x)] = 5x + [3x - 6x] = 5x + [-3x] = 2x
6. 8w + [4w - (5w - 7w)] = 8w + [4w-(-2w)]=8w + [4w + 2w] = 8w + 6w = 14w
7. -3[2x + 4(x - 1)] = -3[2x + 4x - 4]=-3[6x - 4] = -18x + 12
8. -2[5x + 3(x - 4)] = -2[5x + 3x - 12]=
26 CHAPTER 1 THE REAL NUMBER SYSTEM
-2[8x - 12] = -16x + 24
9. 5[3x - 4(2x + 1)] = 5[3x - 8x - 4]=5[-5x - 4] = -25x - 20
10. 2[5x - 3(3x + 1)] = 2[5x - 9x - 3] = 2[-4x - 3] = -8x - 6
Exercise Set 1.7
1. -4m + 7m = 3m
3. -5mn + 2mn - 13mn = -3mn - 13mn=- 3mn +(-13mn ) = -16mn
5. 1.2xy + 2.4xy - 5.7xy = 3.6xy + (-5.7xy) = -2.1xy
7. x − 1 2
x + 3 4
x =
4 4
x − 2 4
x + 3 4
x = 5 4
x = 1 1 4
x
9. 8x + (5x - 11x) = 8x +(5x + (-11x))=8x + (-6x ) = 2x
11. -2w+(4w - 5w)=-2w+ (4w +(-5w))= -2w + (-1w) = -3w
13. (-5x + 3x) - (8x + 12x) =- 2x- 20x = -2x + (-20x) = -22x
15. 5x+[3x-(2x +4x)]= 5x+[3x-6x]=5x +[3x + (-6x)] = 5x + (-3x) = 2x
17. -12m +7(2m - 6) = -12m + 14m -42=2m - 42
19. -8(2y -5) = -8•2y - (-8)(5)=-16y - (-40) = -16y + 40
21. 2.5(4x + 6) = 2.5(4x) +2.5(6) = 10x + 15
23. − 1 2
( 6 x − 2 ) =
− 1 2
( 6 x ) − ( − 1 2
) ( 2 ) =
− 3 x − ( − 1 ) = − 3 x + 1
25. -(-12y) = 12y
27. -(x2 - 3x + 5) = -x2 + 3x - 5 29. 2w -3(2w + 2) = 2w - 6w - 6 =
-4w - 6
31. 3r -(2r2 + 5r - 3)=3r -2r2 - 5r + 3=-2r2 - 2r + 3
33. (2x + 5) -3(x - 7) = 2x + 5-3x +21=-x + 26
35. (4t2 + 3t - 8)-2(3t2 + 5t -5)= 4t2 + 3t - 8 - 6t2 - 10t + 10 = -2t2 -7t+ 2
37. x + 4(2x + 6(x + 1) - 8)=x + 4(2x + 6x + 6 - 8) =x + 4(8x - 2) = x + 32x - 8 = 33x - 8
39. x -2(5x + 3(x - 8) + 7) = x - 2(5x + 3x - 24 + 7) = x - 2(8x - 17) = x - 16x + 34=-15x + 34
41. 3x - 2(4x - 3(x - 5) + 6) =3x - 2(4x - 3x + 15 + 6) = 3x - 2(x + 21) = 3x - 2x - 42= x - 42
43. -2[-4x -(1-4x)] = -2[-4x - 1 +4x]=-2[-1] = 2
45. − 1 6
46.1 6
w
47. 0 has no opposite
48. 7x + 2x = x(7 + 2)
49. 23 • 8÷4 = 8 • 8÷4 = 64 ÷4 = 16
50. 39 - 2[3 + 22(5 - 1)]=39 - 2[3 + 22(4)]= 39 - 2[3 + 4(4)]=39 - 2[3 + 16] = 39 - 2[19] = 39 - 38 = 1
27CHAPTER 1 THE REAL NUMBER SYSTEM
51.4228
• 6 24
= 2 • 3 • 7 2 • 2 • 7
• 6
4 • 6 =
3 2
• 1 4
= 3 8
52. 8 - |-6|÷2 + 3 •4 = 8 - 6÷2 + 3•4 = 8 - 3 + 12 = 5 + 12 = 17
53. Three percent of 9 = 0.03(9)
54. Let n = the number
n÷3 or n 3
55. Let n= the numbern - 5
56. For x = -2 and y = -33x - y = 3(-2) - (-3) = -6 + 3= -3
57. The commutative property ofaddition
58. 3w5
• One base is 3 and its exponent is 1• The other base is w and its exponent is 5
Chapter 1 Review Exercises
1. -8rs is a product whose factors are--8,r and s
2. 3w + 5p is a sum whose terms are3w and 5p. 3w is a
product whose factors are 3and w. 5p is a product
whose factors are 5 and p.
3. 392 = 2•2•2•7•7 = 23•72
4. 572 = 2•2•11•13 = 22•11•13
5.128312
= 8 • 168 • 39
= 1639
6.11848
= 2 • 592 • 24
= 5924
7.7 5
8. − 1 2
9.5
3 m
10.5 9
b
11. (18 - 5•2)2 = (18 - 10)2 = 82 = 64
28 CHAPTER 1 THE REAL NUMBER SYSTEM
12. 72/32 •5 = 72/9 •5 = 8•5 = 40
13. 10 - [(8 - 5)2 - 12/(3•4)]10 - [(3)2 - 12/12]= 10 - [9 - 1]=10 - 8 = 2
14. 8 + 2[35 - 2(24/6)2 - 3] = 8 + 2[35 - 2(4)2 - 3]=8 + 2[35 - 2(16) - 3]=8 + 2[35 - 32 - 3] = 8 + 2[0] = 8 + 0 = 8
15.4062
• 2430
= 2 • 2 • 102 • 31
• 3 • 8 3 • 10
=
2 31
• 8 1
= 1631
16.1870
• 6030
= 2 • 9 2 • 35
• 2 • 3030
=
9 35
• 2 1
= 1835
17.9012
÷ 1015
= 9012
• 1510
=
3 • 3 • 103 • 4
• 3 • 5 10
= 3 4
• 3 • 5 1
=
454
= 111 4
18.4556
÷ 2735
= 4556
• 3527
=
5 • 9 7 • 8
• 5 • 7 3 • 9
= 5 8
• 5 3
= 2524
= 1 1 24
19.9 16
+ 5 12
= 9 • 3 16• 3
+ 5 • 4 12• 4
=
2748
+ 2048
= 4748
20.6 25
+ 7 30
+ 8 75
=
6 • 6 25• 6
+ 7 • 5 30• 5
+ 8 • 2 75• 2
=
36150
+ 35150
+ 16150
= 87150
= 2950
21.4 • 3 2 − 2 3
2 • 6 − 5 =
4 • 9 − 8 12 − 5
=
36 − 8 7
= 287
= 4
22. 12 − 30 −
1 3
• 12
3 − 2 5
=
12 − 30 − 4 155
− 2 5
= 12 − 26135
=
12 − 26÷ 135
= 12 − 261
• 5 13
=
12 - 2•5 = 12- 10 = 2
23.3 2
+ 185
( 5 6
) 2 =
3 2
+ 185
( 5 6
) ( 5 6
) =
3 2
+ 3 • 6 5
( 5
2 • 3 ) (
5 6
) =
3 2
+ 1 1
( 1 2
) ( 5 1
) = 3 2
+ 5 2
=
8 2
= 4
24.30 + 5 2 • 2 3 • 7 − 5
= 30 + 25• 2
21 − 5 =
30 + 5016
= 8016
= 5
25. 12 - |-8| ÷4 + 2 •5 = 12 - 8÷4 + 10=12 - 2+ 10 = 10 + 10 = 20
29CHAPTER 1 THE REAL NUMBER SYSTEM
26. |2 - 11| • 2 - |12| ÷3= |-9| • 2 -12÷3=9 • 2- 4 = 18 - 4 = 14
27. -34 = - 3•3•3•3 = -81
28. -(x - 5x) + 3x = -(-4x) + 3x = 4x + 3x = 7x
29. 8x - 12x2 - 13x + 19x2 = 7x2 - 5x
30. -(7x - x) + 3x = -(6x) + 3x = -6x + 3x = -3x
31. 4x - (3x + 2) = 4x - 3x - 2= x - 2
32. -(3x - 2) - (5 - x) = -3x + 2 -5 + x=-2x - 3
33. z + 3[4z - 3(2z + 1)] = z+3[4z - 6z -3] = z + 3[-2z - 3]=z + (-6z) - 9= -5z -9
34. m + 4[5m -2(5m + 1)]=m + 4[5m - 10m -2] = m +4[-5m -2]= m + (-20m) - 8 = -19m - 8
35. <--|--|--|--|--•--|--|--|•-|--|--|•|--|--|--|•-|--|--|--|--|->
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8
9
36. 12.6
37. − 5 8
38. -3.5, -2, 0.5, 6
39.<--|---|---|---|--•|---|---|---|---|---|---|---|---|---|---|---|---|>
-800 -700 -600 -500 -400 -300 -300 -100 0 100 200 300 400 500 600 700 800
40. <--|----|----|----|----|----|----|----|----|---•---|-->
-1 -0.8 -0.6 -0.4 -0.2 0 0.2 0.4 0.6 0.8 1.0
41. 0.08 •12 = 0.96
42. Let x = the number 2x
43. Let x= the number
x÷(-8) or x
− 8
44. Let x = the number
2x÷3 or 2 x 3
45. Let x = the numberx + 5
46. For x = -2 and y = -38 - (x - y) = 8 - (-2 -(-3)) = 8 - (-2 + 3) = 8 - 1 = 7
47. For x = -2 and y = -3y - xy2 - 3x = -3 -(-2)(-3)2 - 3(-2)=-3 - (-2)(9) -(-6) = -3 - (-18) + 6=-3 + 18 + 6 = 15 + 6 = 21
48. Let x = the numberx - (-2) = x + 2
49. Let x = the numberx - 4
50. Let x = the number1 2
x + 3
51. The Commutative Property ofAddition5 - x = 5 + (-x) = -x + 5
52. Multiplication Property of one
53. 2x + 7x = x(2 + 7)
54. 3a - a = a(3 - 1)
30 CHAPTER 1 THE REAL NUMBER SYSTEM
Chapter 1 Test
1. 8 + x is a sum whose terms are 8and x
2. <--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|--|-->
-10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2 3 4 5 6 7 8 9
3. -5.5, -2, 0, 3.5
4. <--|-----|-----|----•-----|-----|-----|-----|-----|-->
-100 -25 50 125 200 275 350 425 500
5. - 1 3
31CHAPTER 1 THE REAL NUMBER SYSTEM
6. − 3 2
7.1 2
w
8. 5b + b = b(5 + 1)
9. 459 = 3•3•3•17 = 33 •17
10. Let x = the number1 3
x + 2
11.56112
= 56
2 • 56 =
1 2
12. For x = -2 and y = -32x3 - xy2 = 2(-2)3 - (-2)(-3)2 = 2(-8) - (-2)(9) = -16 - (-18) = -16 + 18 = 2
13. The Commutative Property ofAddition
14. Associative Property of Addition
15. 36/22 • (5 - 2) = 36/4 • 3 = 9 •3 = 27
16.2039
• 5125
= 4 • 5 3 • 13
• 3 • 175 • 5
=
4 13
• 175
= 6865
= 1 3 65
17.2130
÷ 4220
= 2130
• 2042
=
213 • 10
• 2 • 102 • 21
= 1 3
• 1 1
= 1 3
18. -26 = -2•2•2•2•2•2= -64
19.8 15
+ 3 40
= 8 • 8 15• 8
+ 3 • 3 40• 3
=
64120
+ 9
120=
73120
20. 20 −
7 5
• 20
2 − 1 4
=
20 − 7 • 4
8 4
− 1 4
= 20 − 287 4
=
20 − 28÷ 7 4
= 20 − 28• 4 7
=
20 − 4 • 4 = 20 − 16 = 4
21. 9 − − 16 ÷ 8 + 12 / 3 = 9 -16÷8 + 4=9 - 2 + 4 = 7 + 4 = 11
22. 12x3 - 3x2 + 5x3 - 4x2 = 17x3 - 7x2
23. 6x - (3x - 8x) + 2x = 6x - 3x + 8x + 2x = 13x
24. 9x - 3(3x - 2) = 9x - 9x + 6 = 6
25. 6r -2[r +4(r - 3) + 1] = 6r - 2[r + 4r - 12 +1] = 6r -2[5r - 11]=6r - 10r + 22 = -4r + 22
26. 26 - 3(12 - (5 - 2)2 + 36/12) = 26 - 3(12 - (3)2 + 3)= 26 - 3(12 - 9 + 3) = 26 - 3(6) = 26 - 18 = 8
32 CHAPTER 1 THE REAL NUMBER SYSTEM