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Copyright © 2010 Pearson Education, Inc. Chapter 10 Rotational Kinematics and Energy

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Copyright © 2010 Pearson Education, Inc.

Chapter 10

Rotational Kinematics and Energy

Copyright © 2010 Pearson Education, Inc.

Units of Chapter 10• Angular Position, Velocity, and Acceleration

• Rotational Kinematics

• Connections Between Linear and Rotational Quantities

•Rolling Motion

• Rotational Kinetic Energy and the Moment of Inertia

• Conservation of Energy

Copyright © 2010 Pearson Education, Inc.

10-1 Angular Position, Velocity, and Acceleration

1 rev = 2π rad

2π rad = 360o

1 rad = 360o/ 2π = 57.3o

Copyright © 2010 Pearson Education, Inc.

10-1 Angular Position, Velocity, and Acceleration

Degrees and revolutions:

= 2π rad

Q: Sign of θ here?

Copyright © 2010 Pearson Education, Inc.

10-1 Angular Position, Velocity, and Acceleration

Arc length s, measured in radians:

Q: Why do we define 1 rev = 2π rad?A: The circumference of a circleC = 2π r

the angle for 1rev is C/r = 2π rad

s = r θ

Copyright © 2010 Pearson Education, Inc.

10-1 Angular Position, Velocity, and Acceleration

Copyright © 2010 Pearson Education, Inc.

10-1 Angular Position, Velocity, and Acceleration

Note: the sign of ω

Question 10.1aQuestion 10.1a Bonnie and Bonnie and KlydeKlyde II

ω

BonnieBonnieKlydeKlyde

Bonnie sits on the outer rim of a merry-go-round, and Klyde sits midway between the center and the rim. The merry-go-round makes one complete revolution every2 seconds.Klyde’s angular velocity is:

a) same as Bonnie’sb) twice Bonnie’sc) half of Bonnie’sd) one-quarter of Bonnie’se) four times Bonnie’s

The angular velocityangular velocity ωω of any point on a solid object rotating about a fixed axis is the sameis the same. Both Bonnie and Klyde go around one revolution (2π radians) every 2 seconds.

Question 10.1aQuestion 10.1a Bonnie and Bonnie and KlydeKlyde II

ω

BonnieBonnieKlydeKlyde

Bonnie sits on the outer rim of a merry-go-round, and Klyde sits midway between the center and the rim. The merry-go-round makes one complete revolution every2 seconds.Klyde’s angular velocity is:

a) same as Bonnie’sb) twice Bonnie’sc) half of Bonnie’sd) one-quarter of Bonnie’se) four times Bonnie’s

Hint: angular velocity has a sign, negative or positive?

Copyright © 2010 Pearson Education, Inc.

10-1 Angular Position, Velocity, and Acceleration

Ask: why?

Copyright © 2010 Pearson Education, Inc.

Copyright © 2010 Pearson Education, Inc.

Copyright © 2010 Pearson Education, Inc.

10-1 Angular Position, Velocity, and Acceleration

Copyright © 2010 Pearson Education, Inc.

10-1 Angular Position, Velocity, and Acceleration

Copyright © 2010 Pearson Education, Inc.

10-2 Rotational Kinematics

If the angular acceleration is constant:

Copyright © 2010 Pearson Education, Inc.

10-2 Rotational Kinematics

Analogies between linear and rotational kinematics:

Copyright © 2010 Pearson Education, Inc.

below

Copyright © 2010 Pearson Education, Inc.

below

An object at rest begins to rotate with a constant angular acceleration. If this object rotates through an angle θin the time t, through what angle did it rotate in the time t?

a) θb) θc) θd) 2 θe) 4 θ

Question 10.3aQuestion 10.3a Angular Displacement IAngular Displacement I

½

¼

¾

½

An object at rest begins to rotate with a constant angular acceleration. If this object rotates through an angle θin the time t, through what angle did it rotate in the time t?

a) θb) θc) θd) 2 θe) 4 θ

The angular displacement is θ = αt 2 (starting from rest), and there is a quadratic dependence on time. Therefore, in half the half the timetime, the object has rotated through oneone--quarter the anglequarter the angle.

Question 10.3aQuestion 10.3a Angular Displacement IAngular Displacement I

12

½

¼

¾

½

An object at rest begins to rotate with a constant angular acceleration. If this object has angular velocity ωat time t, what was its angular velocity at the time t?

a) ½ ω

b) ¼ ω

c) ¾ ω

d) 2 ωe) 4 ω

Question 10.3bQuestion 10.3b Angular Displacement IIAngular Displacement II

½

An object at rest begins to rotate with a constant angular acceleration. If this object has angular velocity ωat time t, what was its angular velocity at the time t?

The angular velocity is ω = αt (starting from rest), and there is a linear dependence on time. Therefore, in half the timehalf the time, the object has accelerated up to only half the speedhalf the speed.

Question 10.3bQuestion 10.3b Angular Displacement IIAngular Displacement II

a) ½ ω

b) ¼ ω

c) ¾ ω

d) 2 ωe) 4 ω

½

Copyright © 2010 Pearson Education, Inc.

10-3 Connections Between Linear and Rotational Quantities

Q: derive this?

Copyright © 2010 Pearson Education, Inc.

10-3 Connections Between Linear and Rotational Quantities

Question 10.1bQuestion 10.1b Bonnie and Bonnie and KlydeKlyde IIII

ω

BonnieBonnieKlydeKlyde

a) Klydeb) Bonniec) both the samed) linear velocity is zero

for both of them

Bonnie sits on the outer rim of amerry-go-round, and Klyde sits midway between the center and the rim. The merry-go-round makes one revolution every 2 seconds. Who has the larger linear (tangential) velocity?

Their linear speeds linear speeds vv will be

different because v = r v = r ωω and

Bonnie is located farther outBonnie is located farther out(larger radius r) than Klyde.

ω

BonnieBonnie

KlydeKlyde

BonnieKlyde V21V =

Question 10.1bQuestion 10.1b Bonnie and Bonnie and KlydeKlyde IIII

FollowFollow--upup:: Who has the larger centripetal acceleration?Who has the larger centripetal acceleration?

a) Klydeb) Bonniec) both the samed) linear velocity is zero

for both of them

Bonnie sits on the outer rim of a merry-go-round, and Klyde sits midway between the center and the rim. The merry-go-round makes one revolution every 2 seconds. Who has the larger linear (tangential) velocity?

Copyright © 2010 Pearson Education, Inc.

Copyright © 2010 Pearson Education, Inc.

Copyright © 2010 Pearson Education, Inc.

10-3 Connections Between Linear and Rotational Quantities

Copyright © 2010 Pearson Education, Inc.

10-3 Connections Between Linear and Rotational Quantities

This merry-go-round has both tangential and centripetal acceleration.

Copyright © 2010 Pearson Education, Inc.

Copyright © 2010 Pearson Education, Inc.

(a)

(b)

Two methods

Copyright © 2010 Pearson Education, Inc.

below

Copyright © 2010 Pearson Education, Inc.

below

Copyright © 2010 Pearson Education, Inc.

Summary of Chapter 10• Describing rotational motion requires analogs to position, velocity, and acceleration

• Average and instantaneous angular velocity:

• Average and instantaneous angular acceleration:

Copyright © 2010 Pearson Education, Inc.

Summary of Chapter 10

• Period:

• Counterclockwise rotations are positive, clockwise negative

• Linear and angular quantities:

Copyright © 2010 Pearson Education, Inc.

Summary of Chapter 10

• Linear and angular equations of motion:

Tangential speed:

Centripetal acceleration:

Tangential acceleration: