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Chapter 12 Static Equilibrium; El ti it dF t Elasticity and Fracture Copyright © 2009 Pearson Education, Inc.

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Page 1: Chapter 12 Static Equilibrium; El ti it d F tElasticity ...zuhairusnizam.uitm.edu.my/lecture notes/PSE4_Lecture_Ch12 week 10... · serves as a seesaw for two children. Child A has

Chapter 12Static Equilibrium;

El ti it d F tElasticity and Fracture

Copyright © 2009 Pearson Education, Inc.

Page 2: Chapter 12 Static Equilibrium; El ti it d F tElasticity ...zuhairusnizam.uitm.edu.my/lecture notes/PSE4_Lecture_Ch12 week 10... · serves as a seesaw for two children. Child A has

Units of Chapter 12• The Conditions for Equilibrium

• Solving Statics Problemsg

• Stability and Balance

• Elasticity; Stress and Strain

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12-1 The Conditions for Equilibrium

An object with forces acting on it, but with zero net force, is said to be in equilibrium.

The first condition for equilibrium:The first condition for equilibrium:

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Copyright © 2009 Pearson Education, Inc.

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12-1 The Conditions for Equilibrium

Example 12-1: Ch d li d t iChandelier cord tension.

Calculate the tensions AFr

and B in the two cords that are connected to the vertical cord supporting

Fr

vertical cord supporting the 200-kg chandelier shown Ignore the massshown. Ignore the mass of the cords.

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12-1 The Conditions for EquilibriumThe second condition of equilibrium is that there be no torque around any axis; the choice

f i i bitof axis is arbitrary.

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12-2 Solving Statics ProblemsExample 12-3: Balancing a seesaw.

A b d f 2 0 kA board of mass M = 2.0 kg serves as a seesaw for two children. Child A has a mass of 30 kg and sits 2.5 m from the pivot point, P (his center of gravity is 2 5(his center of gravity is 2.5 m from the pivot). At what distance x from the pivot

t hild B f 25must child B, of mass 25 kg, place herself to balance the seesaw? Assume the

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board is uniform and centered over the pivot.

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12-2 Solving Statics Problems

If a force in your solution comes out negative (asA will here), it just means that it’s in the oppositeFr

direction from the one you chose. This is trivial to fix, so don’t worry about getting all the signs of the forces right before you start solvingof the forces right before you start solving.

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12-2 Solving Statics ProblemsExample 12-4: Force exerted by biceps muscle.

How much force must the biceps muscle exert when a 5.0-kg ball is held in the hand (a) with theis held in the hand (a) with the arm horizontal, and (b) when the arm is at a 45° angle? The biceps m scle is connected to themuscle is connected to the forearm by a tendon attached 5.0 cm from the elbow joint. Assume that the mass of forearm and hand together is 2.0 kg and their CG is as shown.

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CG is as shown.

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12-2 Solving Statics ProblemsExample 12 5: Hinged beamExample 12-5: Hinged beam and cable.

A uniform beam 2 20 m longA uniform beam, 2.20 m long with mass m = 25.0 kg, is mounted by a small hinge on

ll Th b i h ld ia wall. The beam is held in a horizontal position by a cable that makes an angle θ = 30.0°.The beam supports a sign of mass M = 28.0 kg suspended from its end Determine thefrom its end. Determine the components of the force Hthat the (smooth) hinge exerts

th b d th t i

Fr

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on the beam, and the tension FT in the supporting cable.

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12-2 Solving Statics Problems

Example 12-6: Ladder.

A 5.0-m-long ladder leans against a smooth wall at a point 4 0 m above a cementpoint 4.0 m above a cement floor. The ladder is uniform and has mass m = 12.0 kg.and has mass m 12.0 kg. Assuming the wall is frictionless (but the floor is not), determine the forces exerted on the ladder by the fl d b th ll

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floor and by the wall.

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If the forces on an object are such that they12-3 Stability and Balance

If the forces on an object are such that they tend to return it to its equilibrium position, it is said to be in stable equilibrium.q

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If h h f d i f

12-3 Stability and BalanceIf, however, the forces tend to move it away from its equilibrium point, it is said to be in unstableequilibriumequilibrium.

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A bj i bl ilib i b

12-3 Stability and BalanceAn object in stable equilibrium may become unstable if it is tipped so that its center of gravity is outside the pivot point Of course itgravity is outside the pivot point. Of course, it will be stable again once it lands!

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People carrying heavy loads automatically12-3 Stability and Balance

People carrying heavy loads automatically adjust their posture so their center of mass is over their feet. This can lead to injury if theover their feet. This can lead to injury if the contortion is too great.

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12-4 Elasticity; Stress and Strain

Hooke’s law: the change inHooke s law: the change in length is proportional to the applied force.pp

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12-4 Elasticity; Stress and StrainThis proportionality holds until the force reaches the proportional limit. Beyond that, the

bj t ill till t t it i i l h tobject will still return to its original shape up to the elastic limit. Beyond the elastic limit, the material is permanently deformed and it breaksmaterial is permanently deformed, and it breaks at the breaking point.

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The change in length of a stretched object12-4 Elasticity; Stress and Strain

The change in length of a stretched object depends not only on the applied force, but also on its length, cross-sectional area and the g ,material from which it is made.

The material factor E is called the elasticThe material factor, E, is called the elastic modulus or Young’s modulus, and it has been measured for many materials.y

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12-4 Elasticity; Stress and Strain

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12-4 Elasticity; Stress and Strain

E ample 12 7 Tension in piano ireExample 12-7: Tension in piano wire.

A 1.60-m-long steel piano wire has a diameter of 0.20 cm. How great is the tension in the wire if it stretches 0.25 cm when tightened?when tightened?

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12-4 Elasticity; Stress and Strain

Stress is defined as the force per unit areaarea.

Strain is defined as the ratio of the h i l th t th i i l l thchange in length to the original length.

Therefore, the elastic modulus is equal to the stress divided by the strain:

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12-4 Elasticity; Stress and Strain

In tensile stress, forces tend to stretch the objectobject.

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12-4 Elasticity; Stress and StrainCompressional stress is exactly the opposite of tensional stress. These columns are under

icompression.

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12-4 Elasticity; Stress and StrainThe three types of stress for rigid objects:

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12-4 Elasticity; Stress and Strain

The shear strain, where Gis the shear modulus:is the shear modulus:

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12-4 Elasticity; Stress and Strain

If an object is subjected to inward forces on ll id it l h d diall sides, its volume changes depending on

its bulk modulus. This is the only deformation that applies to fluidsdeformation that applies to fluids.

or

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