chapter 13
DESCRIPTION
CHAPTER 13. Geometry and Algebra. SECTION 13-1. The Distance Formula. Theorem 13-1 The distance between two points (x 1 , y 1 ) and (x 2 , y 2 ) is given by: D = [(x 2 – x 1 ) 2 + (y 2 -y 1 ) 2 ] ½. Example. Find the distance between points A(4, -2) and B(7, 2) d = 5. 13-2 Theorem - PowerPoint PPT PresentationTRANSCRIPT
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CHAPTER 13
Geometry and Algebra
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SECTION 13-1
The Distance Formula
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Theorem 13-1
The distance between two points (x1, y1) and (x2, y2)
is given by:D = [(x2 – x1)2 + (y2-y1)2]½
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ExampleFind the distance
between points A(4, -2) and B(7, 2)
d = 5
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13-2 TheoremAn equation of the circle
with center (a,b) and radius r is
r2 = (x – a)2 + (y-b)2
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ExampleFind an equation of the circle with center (-2,5) and radius 3.
(x + 2)2 + (y – 5)2 = 9
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ExampleFind the center and the radius of the circle with equation (x-1)2 + (y+2)2 = 9.
(1, -2), r = 3
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SECTION 13-2
Slope of a Line
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SLOPE
is the ratio of vertical change to the horizontal
change. The variable m is used to represent slope.
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m = change in y-coordinate change in x-coordinate
Or m = rise
run
FORMULA FOR SLOPE
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SLOPE OF A LINEm = y2 – y1
x2 – x1
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HORIZONTAL LINE
a horizontal line containing the point
(a, b) is described by the equation y = b and has slope
of 0
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VERTICAL LINE
a vertical line containing the point (c, d) is described by
the equation x = c and has no slope
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Lines with positive slope rise to the right.
Lines with negative slope fall to the right.
The greater the absolute value of a line’s slope, the steeper the line
Slopes
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SECTION 13-3
Parallel and Perpendicular Lines
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Theorem 13-3
Two nonvertical lines are parallel if and only if their slopes are equal
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Theorem 13-4
Two nonvertical lines are perpendicular if and only if the product of their slopes is - 1
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Find the slope of a line parallel to the line containing points
M and N.
M(-2, 5) and N(0, -1)
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Find the slope of a line perpendicular to the line containing points M and
N.
M(4, -1) and N(-5, -2)
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Determine whether each pair of lines is parallel, perpendicular,
or neither
7x + 2y = 147y = 2x - 5
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Determine whether each pair of lines is parallel,
perpendicular, or neither
-5x + 3y = 23x – 5y = 15
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Determine whether each pair of lines is parallel,
perpendicular, or neither
2x – 3y = 68x – 4y = 4
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SECTION 13-4
Vectors
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Vector– any quantity such as force, velocity, or acceleration, that has both size (magnitude) and direction
DEFINITIONS
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Vector AB is equal to the ordered pair (change in x, change in y)
Vector
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Magnitude of a vector- is the length of the arrow from point A to point B and is denoted by the symbol AB
DEFINITIONS
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Use the Pythagorean Theorem or the Distance Formula to find the magnitude of a vector.
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Given: Points P(-5,4) and Q(1,2)
Find PQFind PQ
EXAMPLE
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In general, if the vector PQ = (a,b) then
kPQ = (ka, kb)
Scalar Multiple
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Vectors having the same magnitude and the same
direction.
Equivalent Vectors
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Two vectors are perpendicular if the
arrows representing them have perpendicular
directions.
Perpendicular Vectors
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Two vectors are parallel if the arrows representing
them have the same direction or opposite
directions.
Parallel Vectors
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Determine whether (6,-3) and (-4,2) are parallel or perpendicular.
EXAMPLE
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Determine whether (6,-3) and (2,4) are parallel or perpendicular.
EXAMPLE
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(a,b) + (c,d) = (a+c, b+d)Adding Vectors
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Find the Sum
Vector PQ = (4, 1) and Vector QR = (2, 3). Find the resulting Vector PR.
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SECTION 13-5
The Midpoint Formula
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Midpoint Formula
M( x1 + x2, y1 + y2) 2 2
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ExampleFind the midpoint of
the segment joining the points (4, -6) and (-3, 2)
M(1/2, -2)
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SECTION 13-6
Graphing Linear Equations
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LINEAR EQUATIONis an equation whose
graph is a straight line.
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The graph of any equation that can be written in the form
Ax + By = CWhere A and B are not both zero, is a line
13-6 Standard Form
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ExampleGraph the line 2x – 3y = 12Find the x-intercept and
the y-intercept and connect to form a line
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The slope of the line Ax + By = C (B ≠ 0) is
- A/BY-intercept = C/B
THEOREM
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Theorem 13-7 Slope-Intercept form
y = mx + bwhere m is the slope and b is
the y -intercept
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Write an equation of a line with the given y-intercept and slope
m=3 b = 6
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SECTION 13-7
Writing Linear Equations
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An equation of the line that passes through the point (x1, y1) and has slope m is
y – y1 = m (x – x1)
Theorem 13-8 Point-Slope Form
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Write an equation of a line with the given slope and through a given point
m=-2P(-1, 3)
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Write an equation of a line with the through the given points
(2, 5) (-1, 2)
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Write an equation of a line through (6, 4) and parallel to the line y = -2x +4
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