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CHAPTER 13 Geometry and Algebra

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CHAPTER 13. Geometry and Algebra. SECTION 13-1. The Distance Formula. Theorem 13-1 The distance between two points (x 1 , y 1 ) and (x 2 , y 2 ) is given by: D = [(x 2 – x 1 ) 2 + (y 2 -y 1 ) 2 ] ½. Example. Find the distance between points A(4, -2) and B(7, 2) d = 5. 13-2 Theorem - PowerPoint PPT Presentation

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Page 1: CHAPTER 13

CHAPTER 13

Geometry and Algebra

Page 2: CHAPTER 13

SECTION 13-1

The Distance Formula

Page 3: CHAPTER 13

Theorem 13-1

The distance between two points (x1, y1) and (x2, y2)

is given by:D = [(x2 – x1)2 + (y2-y1)2]½

Page 4: CHAPTER 13

ExampleFind the distance

between points A(4, -2) and B(7, 2)

d = 5

Page 5: CHAPTER 13

13-2 TheoremAn equation of the circle

with center (a,b) and radius r is

r2 = (x – a)2 + (y-b)2

Page 6: CHAPTER 13

ExampleFind an equation of the circle with center (-2,5) and radius 3.

(x + 2)2 + (y – 5)2 = 9

Page 7: CHAPTER 13

ExampleFind the center and the radius of the circle with equation (x-1)2 + (y+2)2 = 9.

(1, -2), r = 3

Page 8: CHAPTER 13

SECTION 13-2

Slope of a Line

Page 9: CHAPTER 13

SLOPE

is the ratio of vertical change to the horizontal

change. The variable m is used to represent slope.

Page 10: CHAPTER 13

m = change in y-coordinate change in x-coordinate

Or m = rise

run

FORMULA FOR SLOPE

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SLOPE OF A LINEm = y2 – y1

x2 – x1

Page 12: CHAPTER 13

HORIZONTAL LINE

a horizontal line containing the point

(a, b) is described by the equation y = b and has slope

of 0

Page 13: CHAPTER 13

VERTICAL LINE

a vertical line containing the point (c, d) is described by

the equation x = c and has no slope

Page 14: CHAPTER 13

Lines with positive slope rise to the right.

Lines with negative slope fall to the right.

The greater the absolute value of a line’s slope, the steeper the line

Slopes

Page 15: CHAPTER 13

SECTION 13-3

Parallel and Perpendicular Lines

Page 16: CHAPTER 13

Theorem 13-3

Two nonvertical lines are parallel if and only if their slopes are equal

Page 17: CHAPTER 13

Theorem 13-4

Two nonvertical lines are perpendicular if and only if the product of their slopes is - 1

Page 18: CHAPTER 13

Find the slope of a line parallel to the line containing points

M and N.

M(-2, 5) and N(0, -1)

Page 19: CHAPTER 13

Find the slope of a line perpendicular to the line containing points M and

N.

M(4, -1) and N(-5, -2)

Page 20: CHAPTER 13

Determine whether each pair of lines is parallel, perpendicular,

or neither

7x + 2y = 147y = 2x - 5

Page 21: CHAPTER 13

Determine whether each pair of lines is parallel,

perpendicular, or neither

-5x + 3y = 23x – 5y = 15

Page 22: CHAPTER 13

Determine whether each pair of lines is parallel,

perpendicular, or neither

2x – 3y = 68x – 4y = 4

Page 23: CHAPTER 13

SECTION 13-4

Vectors

Page 24: CHAPTER 13

Vector– any quantity such as force, velocity, or acceleration, that has both size (magnitude) and direction

DEFINITIONS

Page 25: CHAPTER 13

Vector AB is equal to the ordered pair (change in x, change in y)

Vector

Page 26: CHAPTER 13

Magnitude of a vector- is the length of the arrow from point A to point B and is denoted by the symbol AB

DEFINITIONS

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Use the Pythagorean Theorem or the Distance Formula to find the magnitude of a vector.

Page 28: CHAPTER 13

Given: Points P(-5,4) and Q(1,2)

Find PQFind PQ

EXAMPLE

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In general, if the vector PQ = (a,b) then

kPQ = (ka, kb)

Scalar Multiple

Page 30: CHAPTER 13

Vectors having the same magnitude and the same

direction.

Equivalent Vectors

Page 31: CHAPTER 13

Two vectors are perpendicular if the

arrows representing them have perpendicular

directions.

Perpendicular Vectors

Page 32: CHAPTER 13

Two vectors are parallel if the arrows representing

them have the same direction or opposite

directions.

Parallel Vectors

Page 33: CHAPTER 13

Determine whether (6,-3) and (-4,2) are parallel or perpendicular.

EXAMPLE

Page 34: CHAPTER 13

Determine whether (6,-3) and (2,4) are parallel or perpendicular.

EXAMPLE

Page 35: CHAPTER 13

(a,b) + (c,d) = (a+c, b+d)Adding Vectors

Page 36: CHAPTER 13

Find the Sum

Vector PQ = (4, 1) and Vector QR = (2, 3). Find the resulting Vector PR.

Page 37: CHAPTER 13

SECTION 13-5

The Midpoint Formula

Page 38: CHAPTER 13

Midpoint Formula

M( x1 + x2, y1 + y2) 2 2

Page 39: CHAPTER 13

ExampleFind the midpoint of

the segment joining the points (4, -6) and (-3, 2)

M(1/2, -2)

Page 40: CHAPTER 13

SECTION 13-6

Graphing Linear Equations

Page 41: CHAPTER 13

LINEAR EQUATIONis an equation whose

graph is a straight line.

Page 42: CHAPTER 13

The graph of any equation that can be written in the form

Ax + By = CWhere A and B are not both zero, is a line

13-6 Standard Form

Page 43: CHAPTER 13

ExampleGraph the line 2x – 3y = 12Find the x-intercept and

the y-intercept and connect to form a line

Page 44: CHAPTER 13

The slope of the line Ax + By = C (B ≠ 0) is

- A/BY-intercept = C/B

THEOREM

Page 45: CHAPTER 13

Theorem 13-7 Slope-Intercept form

y = mx + bwhere m is the slope and b is

the y -intercept

Page 46: CHAPTER 13

Write an equation of a line with the given y-intercept and slope

m=3 b = 6

Page 47: CHAPTER 13

SECTION 13-7

Writing Linear Equations

Page 48: CHAPTER 13

An equation of the line that passes through the point (x1, y1) and has slope m is

y – y1 = m (x – x1)

Theorem 13-8 Point-Slope Form

Page 49: CHAPTER 13

Write an equation of a line with the given slope and through a given point

m=-2P(-1, 3)

Page 50: CHAPTER 13

Write an equation of a line with the through the given points

(2, 5) (-1, 2)

Page 51: CHAPTER 13

Write an equation of a line through (6, 4) and parallel to the line y = -2x +4

Page 52: CHAPTER 13

END