chapter 15 i trigonometry ii student
TRANSCRIPT
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Trigonometry II 1
CHAPTER 15: TRIGONOMETRY
Important Concepts: Trigonometrical Ratios
Exercise 3 :
In Diagram below,ABCandBDEare two right-angled triangles.
Solution :
IfAB = 9 cm,BD= 8 cm,DE= 10 cm, andBE= CE,
calculate the value of sinx.
Example 4
In the diagram above, QRS is a straight line . Given
Adjacent side
Hypotenuse
B
A
C
Sin =eHypothenus
sideOpposite =AC
AB
Cos =eHypothenus
sideAdjacent=
AC
BC
Tan =sideAdjacent
sideOpposite=
BC
AB
Opposite
side
9 cm 8 cmA B D
C
10 cm
E
x
Q
S
P
TR
5 cm
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Trigonometry II 2
cos13
5QPS and tan4
3RTS , find
the length ofRT in
Solution
Exercise4
Based on the figure above, calculate the length of FL , in cm .
Example 5
In the diagram aboveFGH is a straight line . Given that tan 1HEF , thus tan HGE
Solution
5 cm
H
F
G
E7 cm
H F
L
48o
10 cm
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Trigonometry II 3
Exercise 5
In the diagram above, BCD is a straight line and AB is perpendicular to line BCD .Find BAC .
Example 6
In the diagram above , QRS is a straight line .
Given that sin xo =13
12, find the value of
cos yo.
Exercise 6
In the diagram above ,FGH is a straight line . find the value of cosxo.
RS
o
xo
P
14 cm
8 cm
A
B C D
30o
E
FG
G
xo
5 cm4 cm
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Trigonometry II 4
Exercise :
1 Diagram 1 shows a rectanglePQRS,where diagonal SQ= 17 cm andPQ= 15 cm.
Calculate the value of cosx.
2 Diagram 2 shows a triangleKLM.
Diagram 2
Calculate the length, in cm, ofKLifML= 60 cm and cosx=3
1 .
3 In Diagram 3,Mis the midpoint ofBCin a right-angled triangleABC.
DIAGRAM 13
Diagram 3
Given that cosx=25
7 andAB= 50 cm, calculate the length, in cm, ofMC.
x
M
K L
60 cm
B
M
CA
x
17cm
15cmP Q
RS
x
Diagram 1
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Trigonometry II 5
4 In Diagram 4,MNLPis a trapezium.
Diagram 4
IfNL = 2MN, sinx=17
15 ,NL= 8 cm and OP= 15 cm, find the perimeter, in cm, of
the trapezium.
5 In Diagram 5,BCDE is a rectangle andABMis a triangle.
Diagram 5
AMDandABCare straight lines andAB= 6 cm, andED= 20 cm. Given that cosx=3
1 ,
find the length, in cm, ofAD.
P
OM
LN
15 cm
x
8 cm
DE
CB
A
M
x
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Trigonometry II 6
6 In Diagram 6,ABCD is a rectangle.
Diagram 6
IfAB= 9 cm andBX=
3
2AB. IfBC= 16 cm, and BY =
2
1BC, find siny.
7 In Diagram 7 cosx=13
5 .
B
x y
A C D
Diagram 7
IfACD is a straight line andAC= 5 cm, find the length ofBD when siny= .2
1
8 In Diagram 8ABCis an equilateral triangle.
C
X
yA B
Diagram 8
IfAXYis a right-angled triangle, find the value of siny.
BAX
CD
Y
y
Y
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Trigonometry II 7
9 In Diagram 9,ABCDis a trapezium.
15 cm
D C
24 cm
y
A B22 cm
Diagram 9
IfAD= 24 cm,DC = 15 cm andAB= 22 cm, find the value of cosy.
10 In Diagram 10, the area of squareABCDis 49 cm and the area of triangle CDEis 84
cm.
A D
x
B C E
Diagram 10
Given that BCE is a straight line, find the value of cos x.
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Trigonometry II 8
TRIGONOMETRY II
1. The unit circleis the circle with radius 1 unit and its centre at origin.
2.
a)Quadrant Angle
I 0 < < 90II 90 < < 180III 180 < < 270IV 270 < < 360
b) sin = y = y1
cos = x = x1
tan = yx
1
1
-1
(x, y)
y
y
x
x
All +sin +
cos +tan +
3. 0 90 180 270 360
sin 0 1 0 -1 0cos 1 0 -1 0 1tan 0 Undefined 0 Undefined 0
30 45 60sin 1 / 2 1/ 2 3 / 2cos 3 / 2 1/ 2 1 / 2tan 1 / 3 1 3
4.
Quadrant II
1800-Quadrant I
Quadrant III - 1800
Quadrant IV
3600 -
900
1800
2700
0, 360
y
x3600
y
x3600
y
x3600180
0 270
090
0
27001800900900 1800 2700
y = sin x y = cos x y = tan x
1
-1
1 1
-1-1
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Trigonometry II 9
15.1 Identifying the Quadrants and the Angles in A Unit Circle.
1. The x-axis and the y-axis divides the unit circle with centre origin into 4 quadrants as shown in
the diagram below
y1 90
180 -1 II I 1 0 O 360 X
III IV
-1 270
Examples and exercises :
State the quadrant for the following angles in the table below.
Angle Quadrant Angle Quadrant
42 I 19
70 265
100 II 289
136 126
197 303
205 80
275 150
354 212
REMEMBER
QUADRANT I 0 < < 90QUADRANT II 90 < < 180
QUADRANT III 180 < < 270QUADRANT IV 270 < < 360
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Trigonometry II 10
15.1 a) Determine whether the values of
a) sin b) cos c) tan are positive or negative if
oooooo and 360270,270180,18090
y1 90
180 -1 Sin + ALL 1 0O 360 X
Tan + Cos +
-1 270
Examples :
i) Sin 142 ii) cos 232 iii) tan 299
142 is in quadrant II cos 232 is in quadrant III tan 299 is in quadrant IVSin is positive in Quadrant II Cos is negative in quadrant III tan is negative in quadrant IV
Exercises :
Angle Quadrant Value (Positive/ Negative)
Sin Cos Tan
75 I + + +
120 II + - -
160 200
257
280
345
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Trigonometry II 11
15.1 b)Find the values of the angles in quadrant I which correspond to the following values of
angles in other quadrants.
The relationship between the values of sine, cosine and tangent of angles in Quadrant II, III and
IV with their respective values of the corresponding angle in Quadrant I is shown in the diagrambelow :
QUADRANT II QUADRANT III QUADRANT IV
( 90 180 ) ( 180 270) (270 360)Sin = sin ( 180 - )Cos = cos ( 180 - )Tan = tan ( 180 - )
Sin = - sin ( - 180 )Cos = -cos ( - 180 )Tan = tan ( - 180 )
Sin = - sin ( 360 - )Cos = cos ( 360 - )Tan = - tan ( 360 - )
Example :
120
Sin 120 = sin 60Cos 120 = - cos 60Tan 120 = - tan 60
EXERCISES :
Find the values of the angles in quadrant I which correspond to the following values of angles inother quadrants.
ANGLE CORRESPONDING ANGLE IN
QUADRANT I
Sin 125 Sin = sin ( 180 - 125)= sin 55
Cos 143
Tan 98
Sin 200 Sin = - sin ( 200 - )= - sin 20
Cos 245
Tan 190
Sin 285 Sin = - sin ( 360 - )= -sin 55
Cos 300
Tan 315
230 340
Sin 230 = - sin 50Cos 230 = - cos 50
Tan 230 = tan 50
Sin 340 = - sin 20Cos 340 = cos 20Tan 340 = - tan 20
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Trigonometry II 12
15.1 c)Find the value of Sine, Cosine and Tangent of the angle between 90 and 360
TIPS :If a calculator is used, press either , or
Followed by the value of the angle and then
Example :
a) sin 145 b) cos 220 = c) tan 92.5
Exercises :
Angle Value
Sin 46
Cos 57
Tan 79
Sin 139
Cos 154
Tan 122
Sin 200
Cos 187
Tan 256
Sin 342
Cos 278Tan 305
=
Press display
Sin Sin1 sin 1
4 sin 145 sin 145
= 0.573 576
Press display
cos cos2 cos 2
2 cos 220 cos 220
= - 0.951 056
Press display
tan tan9 tan 9
2 tan 92. tan 92.
5 tan 92.5= 0.573 576
SIN COS TAN
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Trigonometry II 13
15.1 d ) Find the angle between 0 and 360 when the values of sine, cosine and tangent are
Given
TIPS :
If a calculator is used, press either SIN 1 , COS 1 or TAN 1
Followed by the value of the angle and then
Examples :
a) Sin1 0. 94 b) Cos
1 -0.64 c) Tan
10.625
Press display Press Display Press Display
Shift Sin Sin 1 Shift Cos Cos
1 Shift Tan Tan
1
0 Sin 1 0 (-) - 0 Tan
10
. Sin 1 0. 0 Cos
1-0 . Tan
10.
9 Sin 1 0.9 . Cos
1-0. 625 Tan
10.625
4 Sin 1 0.94 64 Cos
1-0.64 = 32.00
= 70.05 15 = 129.79
Sin1 0. 94 = 70.05 Cos
1-0.64 = 129.79 Tan
1 0.625 = 32.00
Exercises :
VALUE ANGLE
Sin1 0.7654
Sin1 -0.932
Sin10.1256
Cos10.4356
Cos1-0.6521
Cos1-0.7642
Tan1-1.354
Tan 1
0.7421
Tan 1
1.4502
=
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Trigonometry II 14
15.1 e) Determine The Value Of Sin , Cos And Tan For Special Angles
A A
45
3030
2 2 1 23
4560 60
B D C B 1 C
1 1
Using The Right-Angled Triangle Bad, Using Isosceles Triangle
Sin 30 =2
1 Sin 45 =
Cos 30 =2
3 Cos 45 =
Tan 30 =3
1 tan 45=
sin 60 =2
3
cos 60 =
tan 60 =
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Trigonometry II 15
15.2 Graphs Of Sine, Cosine And Tangent15.2.a) For each of the following equations, complete the given table and draw its graph based on
the data in the table.
i) y = sin x
X 0 45 90 135 180 225 270 315 360
Y
ii) y = cos x
X 0 45 90 135 180 225 270 315 360
Y
iii) y = tan x
X 0 45 90 135 180 225 270 315 360
Y
Examples :
The diagram shows graphs y = sin x for 0 360 . Find the value of y when yis a) 90
b) 270
c) 360
SOLUTION : a) y = 1
b) y = -1
c) y = 0
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Trigonometry II 16
15.3 Questions Based on the Examination Format.
1. Which of the following is equal to cos 35 ?
A. cos 145 C. cos 235 B. cos 215 D. cos325
2. Find the value of sin 150 + 2 cos 240 - 3 tan 225
A. -3.5 B. -1.5 C. 1.5 D. 2.5
3. Sin 30 + cos 60 =
A.4
1 B.
2
1 C. 1 D. 0
4. Given that sin 45 = cos 45 = 0.7. Find the value of 3 sin 315 - 2 cos 135
A. -3.5 B. -1.5 C. 1.5 D. 2.5
5. Given that cos = 0.9511 and 0 360, find the value of
A. 18 B. 162 C. 218 D. 300
6. Given that tan = 05774 and 0 360, find the value of
A. 30 , 210 B. 152 , 210 C.30 , 330 D. 30 , 150
7. Given that sin = -0.7071 and 90 270, find the value of
A. 135 B. 225 C. 45 D. 315
8. Given that Sin x = 0.848 and 90 x 180 , find the value of x
A. 108 B. 122 C. 132 D. 158
9. Given that tan y = -2.246 and 0 360 , find the value of y
A. 66 , 246 B. 114 ,246 C. 114 , 294 D.246 , 294
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10.
y(0,1)
( -1,0) (1,0)
O X
(0.87,-0.50)
( -1,0)
The diagram shows the unit circle. The value of tan is
A. -1.74 B. -0.57 C. -0.50 D. 0.87
11.
y1
-1 1O X
P
-1
The diagram shows the unit circle. If P is (-0.7, -0.6), find the value of Sin
A. -6
7 B. -
7
6 C. -0.6 D. 0.6
12
y1
-1 1O X
R (0.8, -0.4)
-1
The diagrams shows a unit circle and R (0.8, -0.4). find the value of cos
A. 0.8 B. 0.4 C. 1 D.8.0
4.0
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13. In the diagram, ABC is a straight line. The value of sin x is
BA C
x
15 8
D
A.15
8 B.
17
8 C.
17
15 D.
15
17
14.
T13 cm
5 cm
Q S
R
X 7 cm
U
In the diagram, PQRS is a straight line and R is the mid-point of QS. The value of cos x is
A.13
12 B.
25
12 C.
25
13 D.
25
24
15. P
15 cm T 6 cm SQ
R
In the diagram, PQR and QTS are straight lines. Given that sin TRS =5
3, then
sin PQT =
A.15
8 B.
17
8 C.
15
8 D.
17
8
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16.
Given that PQR is a straight line and tan x = -1, find the length of PR in cm.
A. 6 B. 8 C. 10 D. 12
17.
In the diagram above, PQR is a straight line. Given that cos5
3SQP , find tan x.
A.21 B.
85 C.
43 D.
54
18.
In the diagram above, EFGH is a straight line. If sin5
3JGH , the value of tan x =
A.5
4 B.
2
1 C.
3
1 D.
5
3
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Trigonometry II 20
19. Diagram below shows a graph of trigonometric function.
The equation of the trigonometric function is
A. y = sin x B. y = -sin x C. y = cos x D. y = -cos x
20.
The value of cos is
A.3
4 B.
5
3 C.
5
3 D.
5
4
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15.4 PAST YEAR SPM QUESTIONS
Nov 2003, Q11
1. In Diagram 5, GHEK is a straight line. GH = HE.
7 cm 25 cm
Diagram 5
Find the value of tan x
A. 12
5 C.
12
13
B. 13
12 D.
5
12
Nov 2003, Q12
2. Which of the following graphs represents y = sin x ?
F
G
EK
H
J
13
x
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Nov 2004, Q 11
3. In Diagram 5, PRS is a straight line
x
Find the value of cox x =
A.24
7 C.
24
7
B.25
24 D.
25
24
Nov 2004, Q 12
4. Diagram 6 shows the graph of y = sin x.
The value of p is
A. 90 C. 270
B. 180 D. 360
Q
P
7 cm
24 cm
R
S
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Nov 2004, Q13
5. In diagram 7, JKL is a straight line.
Diagram 7
It is given that cos x =13
5 and tan y = 2. Calculate the length, in cm, of JKL
A. 22 C. 44
B. 29 D. 58
Nov 2005, Q11
6. It is given that cos = 0.7721 and 180 360. Find the value of
A. 219 27 C. 309 27B. 230 33 D. 320 33
Nov 2005, Q12
7. In Diagram 6, QRS is a straight line.
4 cm
Q P
3 cm
R
Diagram 6
S
What is the value of cos ?
A.5
4 C.
5
3
B.5
3 D.
5
4
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16 cm
12 cm
x
13 cm
H
E
G
F
JUNE 2004, Q13
Diagram 6
8. Diagram 6 shows a quadrilateral EFGH. Find the value of x.
A. 33 01 C. 49 28B. 40 33 D. 50 54
JUNE 2004, Q14
9. In Diagram 7, O is the origin of a Cartesian plane.
Diagram 7
The value of sin r is
A. 5
3 C. 5
3
B.5
4 D.
4
3
P(-3, 4)
r
y
x0
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y
NM
P
Q
x 0
0
-1
1
090 18 0
00
y
x
D
JUNE 2005, Q12
10. Which of the f ollowing graphs represents y = sin 2x for 0 x 180,?
JUNE 2005, Q13
11. In Diagram 5, MPQ is a straight line.
Diagram 5
Given cos x=25
24, find the value of tan y.
A.24
7 B.
7
24 C.
24
7 D.
7
24
-1
1
090 180
00
y
x
B1
0
-1
90 18000
y
x
A
2
1
090 180
00
y
x
C
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JUNE 2005, Q11
12. Given cos x= - 0.8910 and 0 x 360, find the values of x.
A 117 and 243 C. 153 and 207
B 117 and 297 D 153 and 333
NOV 2005, Q11
13. It is given that cos = -0.721 and00 360180 . Find the value of .
A. 19o27
B. 230o33
C. 309o27
D. 320o33
NOV 2005, Q12
14. In Diagram 6, QRS is a straight line
Diagram 6
What is the value of cos0
A.
5
4
B.5
3
C.5
3
D.5
4
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JUNE 2006, Q11
15. Diagram 5 shows a rhombus PQRS
Diagram 5
It is given that QST is a straight line and QS = 10cm.
Find the value of tan xo.
A.13
5 C.
12
5
B.12
13 D.
5
12
JUNE 2006, Q12
16. Which of the following represents part of the graph of y = tan x?
A. C.
B. D.
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JUNE 2006, Q13
17. In Diagram 6, PQR and TSQ are straight lines.
Find the length of ST , in cm.
A. 2.09 C. 3.56
B. 3.44 D. 4.91
NOV 2006, Q11
18. In Diagram 5, S is the midpoint of straight line QST.
The value of cos xois
A.3
4 C.
4
3
B.5
4 D.
5
3
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NOV 2006, Q12
19. In Diagram 6, MPQ is a right angled triangle.
It is given that QN = 13cm, MP = 24cm and N is the midpoint of MNP.
Find the value of tan y0.
A.135
C.1312
B.12
5 D.
12
13
NOV 2006, Q13
20. Which of the following represents the graph of y = cos x for00 1800 x ?
A.
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B.
C.
D.
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JUNE 2007, Q13
21. In Diagram 7, SPQ and PRU are right angle triangles. STQ and PTU are straight lines.
It is given that cos yo
= 13
12
and PQ = QR . Calculate the length incm, of PTU
A. 25.54
B. 27.67
C 65.94
D. 70.17
JUNE 2007,Q14
22. In Diagram 8. PRS is a straight line,
S
R
U
P Q
T
20O y
o
Diagram 7
P 12 cm Q
xo
R
S
Diagram 8
h cm
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If tan xo=4
3 , then the value of h is
A. 5
B. 15
C. 16
D. 20
JUNE 2007 , Q15
23, Which of the following represents the graph of y = sin x for 0o x 369o
A.
B.
C.
0.5
060 180
y
x360O
0.5
045 180
y
x360O
0.5
090 180
0
y
x360O
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D.
NOV 2007, Q11
In diagram 6, USR and VQTS are straight lines,
It is given that TS = 29 cm, PQ = 13 cm, QR = 16 cm and sin xo=
17
8 ,
Find the value of tan yo
A.5
12
B.125
C.12
5
D.5
12
1
0
y
x360O
-1
180o
V Digram 6
U
S
R
xo
T
P
Qy
o
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NOV 2007, Q12
24.
In Diagram 7, O is the origin and JOK is a straight line on a Cartesian plane.
The value of cos is
A. -5
4
B. -5
3 .
C.5
3
D.5
4
NOV 2007, Q13
25. Which of the following graphs represents y = Sin x for 00 1800 x ?A.
B.
K(3,4)
J
0x
y
1
090 180
y
x
-1
1
090 180
y
x
-1
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C.
JUNE 2008,Q 12
27. In Diagram 7, RTU is a right angled triangle RST and TUV are straight lines
It is given that RS = 28 cm, TU = 15 cm and tan RUV = -5
12
Find the length, in cm, of SU.
A. 23
B. 22.63
T U V
R
S
Digram 7
1
0 90 180
y
x
-1
1
090
O
180
y
x
-1
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C. 17
D 15.73
JUNE 2008,Q13
28. Given that sin x = -2
1, 270900 x find the value of 3 cos x.
A. -2
3
B.2
3
C 23
D. 23
JUNE 2008,Q14
28. Which graph represents y = cos x for00 3600 x ?
A.
B
1
0180
o
y
x360O
-1
1
0180o
y
x360O
-1
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C
D
NOV 2008,Q11
30. Digram 6 shows a right angled triangle PQR.
Given sin xo=
2
1, find the value of h.
A.o
k
30tan
B. k tan 30O
C.o
k
60cos
D. k cos 60o
1
0180o
y
x360O
-1
1
0180o
y
x
360
O
-1
P k Q
xo
R
h
Diagram 6
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NOV 2008, Q13
31. Which of the following represents the graph of y = tan x for 00 3600 x ?
A.
B.
C
D.
1
0
y
x360O
-1
180o
1
0
y
x360O
-1
180o
1
0
y
x360O
-1
180o
1
0
y
x360O
-1
180o
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ANSWERS
Chapter 15 Trigonometry
Exercise 1:
Sin x =13
12, Cos x =
13
5, Tan x =
5
12
Exercise 2: CD = 17 Exercise 3: Sin x =9
12=
3
4 Exercise 4 : FL = 9cm
Exercise 5 : BAC = 28.96
Exercise 6 :5
3
Exercise:
1. Cos x =
17
8
2. KL = 20 cm 3. MC = 12.5 cm4. Perimeter = 48 5. AD = 18 + 60 = 78
6. Sin y =10
8or
5
4
7. BD = 24 8. Sin y = Sin 30
Sin 30
= 0.59. Cos y =
96.22
7
10. Cos x =25
24
15.1a)
Angle Quadrant Angle Quadrant42 I 19 I
70 I 265 III
100 II 289 IV
136 II 126 II
197 III 303 IV
205 III 80 I
275 IV 150 II
354 IV 212 III
15.1 b.
Angle Quadrant Value (Positive/ Negative)
Sin Cos Tan75 I + + +
120 II + - -
160 II
200 III
257 III 280 IV
345 IV
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Trigonometry II 40
15.1 c
ANGLE CORRESPONDING ANGLE IN
QUADRANT I
Cos 143 Cos 37
Tan 98 Tan 82
Cos 245 Cos 65
Tan 190 Tan 10
Cos 300 Cos 60
Tan 315 Tan 45
15.1 d
Angle Value
Sin 46 0.7193398
Cos 57 0.5446390
Tan 79 5.1445
Sin 139 0.6560
Cos 154 -0.8987
Tan 122 -1.6003
Sin 200 -0.3420
Cos 187 -0.9925
Tan 256 4.01078
Sin 342 -0.30901
Cos 278 0.13917
Tan 305 -1.42814
15.1 e
VALUE ANGLE
Sin1 0.7654 49..94
Sin1 -0.932 68.74
Sin10.1256 7.215
Cos10.4356 64.17
Cos1-0.6521 49.29
Cos1-0.7642 40.16
Tan1-1.354 53.55
Tan 1
0.7421 36.57
Tan 1
1.4502 55.411
15.3: EXAMINATION FORMAT QUESTIONS
No Answer No Answer
1 D 11 C
2 A 12 B
3 C 13 C
4 B 14 D
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5 A 15 B
6 A 16 D
7 A 17 A
8 B 18 C
9 C 19 B
10 B 20 D
15.4
Questions Answers Questions Answers
NOV 2003, Q11 A
NOV 2003, Q12 D
JUN 2004, Q13 C NOV 2004, Q11 D
JUN 2004, Q14 B NOV 2004, Q12 A
NOV 2004, Q13 B
JUN 2005, Q12 C NOV 2005, Q11 A
JUN 2005, Q13 B NOV 2005, Q12 DJUN 2005, Q11 C
JUN 2006, Q15 D NOV 2006, Q11 B
JUN 2006, Q16 A NOV 2006, Q12 C
JUN 2006, Q17 C NOV 2006, Q13 B
JUN 2007, Q13 A NOV 2007, Q11 D
JUN 2007, Q14 D NOV 2007, Q12 B
JUN 2007, Q15 D NOV 2007, Q13 C
JUN 2008, Q12 C NOV 2008, Q11 B
JUN 2008, Q13 A NOV 2008, Q12 A
JUN 2008, Q14 C NOV 2008, Q13 D