chapter 18 wave motion. 18-1 mechanical waves in this chapter, we consider only mechanical waves,...
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Chapter 18Wave Motion
18-1 Mechanical wavesIn this chapter, we consider only mechanical waves, such as sound waves, water waves, and the waves transmitting in a guitar’s strings.
• Elastic mediums are needed for the travel of mechanical waves.
• Mechanical waves can appear when an initial disturbance is made to the mediums.
On a microscopic level, the forces between atoms in the mediums are responsible for the propagation of the waves.
•The particles of the medium do not experience any net displacement in the direction of the wave-as the wave passes, the particles simply move back and forth through small distance about their equilibrium position.
What is a wave?It is the process of propagating oscillation in space.
What are transmitted by a wave?Energy, momentum, phase…, but the particles are not.
18-2 Types of waves
Waves can be classified according to their properties as following.
1.According to direction of particle motion(a)“Transverse waves(横波 )”: If the motion of the particle is perpendicular to the direction of propagation of the waves itself.
(b)“Longitudinal wave(纵波 )”: If the motion of the particle is parallel to the direction of propagation of the waves.
See动画库 \波动与光学夹 \2-01 波的产生 2 3
2. According to number of dimensions
1-D Waves moving along the string or spring 2-D Surface waves or ripple on water3-D Waves traveling radially outward from a small source, such as sound waves and light waves.
3 According to periodicity
pulse waves or periodic wave.
The simplest periodic wave is a “simple harmonic wave’’ in which each particle undergoes simple harmonic motion.
y
xo
The simplest periodic wave
Other kinds of periodic waves:
Square waveTriangle wavemodulated waveSawtoothed wave
4. According to shape of wavefronts
(a) The definitions of ‘wave surface’ (波面或同相面 )and ‘wavefront’(波前或波阵面 )?
See动画库 \波动与光学夹 \2-02 波的描述 1
(b) The definition of ‘a ray’(波线 ): A line normal to the wavefronts, indicating the direction of motion of the waves.
Wavefronts are always direction of Ray
Plane wave: The wavefronts are planes, and the
rays are parallel straight lines.
Spherical wave: The wavefronts are spherical,
and the rays are radial lines leaving the point
source in all directions.
★ Two different types of wavefronts: Plane waves Spherical waves
Ray(波线 ) Wave surface(波面 ) Wavefront(波前 )
*
Spherical wave Plane wave
波前
波面
ray
5. Waves in different fields in physics
sound waveswater wavesearthquake waveslight waveselectromagnetic wavesgravitational wavesmatter waveslattice waves
18-3 Traveling waves(行波 )• All the waves would travel or propagate, why here say ‘traveling waves’?
(with respect to ‘standing wave’(驻波 ))
• Definition of traveling waves: The waves formed and traveling in an open medium system.
• Description of traveling waves We use a 1-D simple harmonic, transverse, plane wave as an example
• Mathematics expressions The vibration displacement y as a function of t and x.
The difference between vibration and wave motion: Vibration y(t): displacement as a function of time Wave y(x,t): displacement as a function of both time and distance
)2
sin()0,( xyxy m
Fig 18-6
vt
y
x
t = 0 t = t
υ
What we want to know: ),( txy ))(
2sin( vtxym
1. Equation of a sine wave
If there is initial phase constant in the sinusoidal waves, the general equation of the wave at time t is:
))(2
sin(),(
vtxytxy m (18-16)
Several important concepts about waves:1) The period T of the wave is the time necessary forpoint at any particular x coordinate to undergo one complete cycle of transverse motion. During this time T, the wave travels a distance that must correspond to one wavelength .
vT
2) The wavelength : the length of a complete wave shape.
3) The frequency of the wave : T
f1
4) The wave number:2
k
5) The angular frequency : fT
22
(18-16) )sin(),( tkxytxy m
Note that:
speed of the wave
The equation of a sine wave traveling in direction is
x
)sin(),( tkxytxy m
The equation of a sine wave traveling in the direction is
x
)sin(),( tkxytxy m
(18-11)
(18-12)
kfv
(18-13)
(18-16)
2. Transverse velocity of a particle
vNote that is the speed of wave transmitting.
What is the velocity of particle oscillating?
---- It is called transverse velocity of a particle for transverse wave
)cos(
)]sin([),(
tkxy
tkxytt
ytxu
m
my
Transverse velocity:
Tansverse acceleration:
ytkxydt
ydtxa my
222
2
)sin(),(
(18-14)
(18-15)
3. Phase and phase constant
)sin(),( tkxytxy m
)( tkx
If the equation of the wave is:
Phase
phase constant
Eq(18-16) can be written in two equivalent forms:
(18-17a)
(18-17b)
])(sin[),( tk
xkytxy m
)](sin[),( tkxytxy m
(18-16)
In y-x, wave A is ahead of wave B by a distance /k
In y-t, wave A is ahead of wave B by a time /ω
(a)
x
k
B A
y
y = ymsin(kx – ωt – )Two waves A and B:
y = ymsin(kx – ωt ) wave A wave B
(b)
t
Fig 18-7
y
A B
])(sin[),( tk
xkytxy m
)](sin[),( tkxytxy m
lead lag
Sample problem 18-1
A transverse sinusoidal wave is generated at one end of a long horizontal string by a bar that movesthe end up and down through a distance of 1.30cm. The motion is repeated regularly 125 times per second(a) If the distance between adjacent wave crests is 15.6 cm, find the amplitude, frequency, speed, and wavelength of the wave .(b) Assuming the wave moves in the +x direction and that at t=0, the element of the string at x=0 is at its equilibrium position y=0 and moving downward, find the equation of the wave.
Solution:
(a) The amplitude
frequency
wavelength
speed
(b) The general expression for a sinusoidal waves
is given by Eq(18-16)
cmcmym 65.02
30.1
Hzf 125
smfv /5.19cm6.15
)sin(),( tkxytxy m
Imposing the given initial condition ( and
for x=0 and t=0 ) yields
and
thus ,
0)sin( my 0cos my
0
])/786()/3.40sin[()65.0(
)sin(),(
tsradxmradcm
tkxytxy m
0y 0
t
y
Sample problem 18-2
In sample problem 18-1.
(a) Find expressions for the velocity and acceleration of a particle P at
(b) Evaluate the y, , of this particle at
Solution:
(a)
(b)
mxP 245.0
ya mst 0.15
ytxa py2),(
cmy 61.0scmu y /173
25 /108.3 scma y
)cos(),( tkxytxu mpy
yu
18-4 Wave velocity (speed)
1) Phase velocity
• Definition: The velocity of the motion of certain phase in a wave (for monochromatic wave(单色波 ,单一频率的波 ))
k
ωv
• Wave speed on a stretched string
Phase velocity vs group velocity
From dimensional analysis:F
v
From mechanical analysis:F
v
: source of the wave: the medium (non-dispersive)
v
oR
l
F
F
R
lFFFF ynet
2sin2,
0, xnetF
R
vl
R
vmma
R
lF y
22
F
v (18-19)
F --- tension force exerted between neighboring elementsμ --- mass density (mass/unit length)
v
v
Wave velocity
• When a wave passes from one medium to another medium, the frequency keeps the same, namely
21 ff may vary. λ and v
2) Group velocity
For a group of waves with different :In non- dispersive medium,
All the waves with different moves with same speed.
time = 0
time = tx
x
υ
Shape keeps
, determined only by the mediumv
time 0
time tx
x
In dispersive medium,
All the waves with different moves with different speeds.
Shape does notkeeps!!!
Group speedGroup speed is needed to describe the waves.
dk
dωv
In this chapter, all the mediums met is assumed to be nondispersive.
A crazy physicist!?
18-5* The wave equation
18-6 Energy in wave motion
1. Energy in wave
motionFig18-11a shows a
wave traveling along the
string at times and
( a time later ). 1t 2t
4
T
A B
y
x
(a)
dx
dydl (b)
yu
1t 2t
yu
time time
Fig 18-11
Wave transmits energy.
What do we want to calculate?
• dK/dt – the rate at which kinetic energy is transportedby wave.
• dU/dt – the rate at which potential energy is transported.
22 )]cos()[(2
1
2
1tkxydxudmdK my
For : dK/dt
)(cos2
1 222 tkxdt
dxy
dt
dKm
v)(cos
2
1 222 tkxvydt
dKm (18 - 26)
)(cos2
1 222 tkxdxym
For :dU/dt )( dxdlFdU
]1)(1[])()([ 222 dx
dyFdxdxdydxFdu
22 )()( dydxdl
The quantity is the slope of the string, and if the amplitude of the wave is not too large this slope will be small.
dx
dy
z2
11z)(1 using 1/2
22 )(2
1]1)(
2
11[
x
yFdx
x
yFdxdu
;)/( 22 kvF
)cos( tkxkyx
ym
vdt
dx
dt
dKtkxvy
dt
dUm )(cos
2
1 222 (18-29)
Note that:
(a) dK and dU are both zero when the element has its maximum displacement ( the element at relaxed length ).
(b) The mechanical energy is not constant, because the mass element is not an isolated
system—neighboring mass elements are doing work on it to change its energy.
dKdUdE
)(cos2
1 222 tkxdxydUdK m
2. Power (功率 ) and intensity(能流密度)
• Power: the rate at which mechanical energy is transmitted.
dt
dEP
dKdKdUdE 2
)(cos222 tkxvym (18-30)
Average power :avP
T
av dtdt
dE
TP
0
1vym
22
2
1 (18-32)
• Intensity I:A
PI av (18-33)
For spherical wave: ;1
4 22 rr
PI av
rym
1
18-7 The principle of superposition The principle of superposition:
Two or more waves travel simultaneously through the same region of space, the superposition principle holds.
...),(),(),( 21 txytxytxy (18-34)
See动画库 \波动与光学夹 \2-03 波的叠加原理
18-8 Interference(干涉 ) of waves
When two or more waves combine at a particular point, they are said to “interfere”, and the phenomenon is called “interference.”
We consider a general case, the equation of the two waves are
Using the principle of superposition,
)sin(),( 11 tkxytxy m
)sin(),( 22 tkxytxy m
)sin()]2/cos(2[
)]sin()[sin(
),(),(),(
'
21
21
tkxy
tkxtkxy
txytxytxy
m
m
(18-36)
(18-37)
where ,
This resultant wave corresponds to a new wave having the same frequency but with an amplitude
1. If (in phase(同相 )) , the resultant amplitude
is , this case is known as constructive Interference (相长干涉 ).
2. If (out of phase (反相 ) ), the resultant amplitude is nearly zero, this is destructive interference (相消干涉 ).
12 2
12'
.)2/cos(2 my
0
my2
180
The resultant amplitude is shown in Fig18-16.
x x
21 yy 1y
2y
21 yy 1y
2y
0 180
Fig 18-16
波源发出的波,到达两个狭缝时,成为两列频率相同、振动频率相同、振动方向平行、相位方向平行、相位相同或相位差恒相同或相位差恒定定的波,在狭缝后面的屏幕上产生 波 的 干 涉 现象。呈现明暗相间的条纹。
Interference of Waves
Young’s double slit light-interference experimentRanked as 5 in top 10 beautiful experiments in Physics
See动画库 \波动与光学夹 \2-04 波的干涉
One paradox (佯谬 ) about energy of wave interference:
两个沿相同方向传播的一维简谐波,它们的频率和振幅 A均相同。如果位相相反,那末叠加后振幅为零,波的能量哪里去了?
如果位相相同,叠加后振幅为 2A,在其它参数相同的情况下,波的能量正比于振幅的平方,两个波在叠加前能量为 A2 + A2,叠加后变为 (2A)2,能量怎么会多出来了?
vym22
2
1 avP
18-9 Standing waves
In previous section, we consider the effect of superposing two component waves of equal amplitude and frequency moving in the same direction on a string. What is the effect if the waves are moving along the string in opposite direction?
1. We represent the two waves by
)sin(1 tkxyy m
)sin(2 tkxyy m
Hence the resultant wave is:
(a) Eq(18-42) is the equation of a standing wave.
It is not a traveling wave, because x and t do not appear in the combination or , required for a traveling wave.
)sin()sin(21
tkxytkxy
yyy
mm
tkxyy m cos]sin2[
vtx vtx
(18-41)
(18-42) or
(b) Nodes (波节 ) and antinodes(波腹 ) of standing waves
In a standing wave, the amplitude is not the same for different particles. The behavior is different from that of a traveling wave.
Antinodes(波腹 )
The positions where the amplitude has a maximum value.
,2sin2 mm ykxy ,)2
1( nkxif n=0,1,2,…….
2)
2
1(
nxor (18-43)
...4
9,
4
7,
4
5,
4
3,
4
x
Nodes(波节 )The positions where the amplitude has a minimum value of zero.
,0sin2 kxym ,nkx if
or2
nx ,...2,
2
3,,
2,0
x
n=0,1,2,…,
See动画库 \波动与光学夹 \2-14驻波演示
To form a standing wave
n n n
aa
—— Forward wave
—— Backward wave—— Resultant wave
(c) Energy of standing waves
For standing waves, the energy can not be transported along it, because the energy cannot flow past the nodes, which are permanently at rest.
U k
Fig 18-18
U k U k U k
2. Reflection at a boundary
Let us discuss the case when a transverse pulse wave travels along a string and reaches an end (boundary).
What will happen when it is reflected at the boundary?
(a) If the reflection end is a fixed on, the reflected pulse is inverted (changes a phase of 180o), loses half wave at the boundary.
(b) If the reflection end is a free one, the reflected pulse is unchanged, no half wave loss at the boundary.
Suppose a pulse travels along a string and reaches an end
(a) (b)
(a) Reflection from a fixed end, a transverse wave undergoes a phase change of 180o
(b) At a free end, a transverse wave is reflected without change of phase.
See动画库 \波动与光学夹 \2-05半波损失
Fig 18-19
18-10 Standing waves and Resonance
L22
L
L
24
λL
2
3L
(a)
(b)
(c)
(d)
n=1
n=2
n=3
n=4Fig 18-20
...3,2,1,2
nnL
1) Standing waves in a string fixed at both ends
Thus the condition for a standing wave to be set up in a string of length L fixed at both ends is (18-45)
(18-46)
is the nth wavelength in this infinite series.
n is the number of half-wavelengths in the patterns.
is the frequency of the allowed standing waves,
(natural frequencies).
n
Ln
2
nL
vn
vf
nn 2
nf
2) Resonance in the stretched string
(a) In Fig18-20, a student begins to shake the string. If the frequency of the driving force matches one of the natural frequencies, we get a resonance in the string.
(b) If the student shakes the string at a frequency
that differs from one of the natural frequencies, the
reflected wave returns to the student’s hand out of
phase with the motion of the hand. No fixed standing
wave pattern is produced.
Sample problem 18-4
In Fig18-23, a motor sets the
string into motion at a
f=120Hz. The string has a
length of L=1.2m, and its
linear mass density .
Find the tension F, at which
we obtain the pattern of
motion having four loops?
mg /6.1 m
motor
Fig 18-23
Solution:
Substituting Eq(18-19) into Eq(18-46), we obtain
NmkgHzm
n
fLvF n
3.84
)/0016.0()120()2.1(4
4
2
22
2
222
L
vn
vf
nn 2
Sample problem 18-5
A violin string tuned to concert A (440Hz) has a
length L=0.34m. (a)What are the three longest
wavelengths of the resonances of the string? (b)
What are the corresponding wavelengths that reach
the ear of listener?
Solution:
(a)
(b)
,68.012 mLλ1 ,34.02
22 mL mL 23.03
23
n
Ln
2
string1n
stringn nf2L
vn
λ
vf ,, stringn,airairn, /fvλ
m/svair 343
Cover page of our text book
A Circular Quantum Corral constructed by 48 Fe atoms on Cu(111) at 4K in 1993.
Average diameter of ring = 14.26 nm.
Standing wave formed by electron wave interference inside a Quantum Corral (量子围栏 )
Double-walled ring of Fe atoms on Cu(111)
Quantum stadium
Schematic illustration of the process for sliding an atom across a surface.
Nature 344, 524 (1990)
Atomic-scale IBM logo produced by 35 Xe atoms on Ni(110) using scanning tunneling microscope (STM) at 4K in 1990.
Each letter is 5 nm from top to bottom.