chapter 19
DESCRIPTION
Chapter 19. Gas Stoichiometry. If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many cm 3 of bromine gas can be produced at STP?. 2KBr + Cl 2 → Br 2 + 2KCl. 1 mol Br 2. 20.0g KBr. mol KBr. 22.4 dm 3. 1000 cm 3. = 1880 cm 3. 119g KBr. - PowerPoint PPT PresentationTRANSCRIPT
Chapter 19
Gas Stoichiometry
If an excess of chlorine gas reacts with a solution containing 20.0g of potassium bromide how many
cm3 of bromine gas can be produced at STP?
2KBr + Cl2 → Br2 + 2KCl
20.0g KBr
119g KBr
mol KBr
2 mol KBr
1 mol Br2
1 mol Br2
22.4 dm3
1 dm3
1000 cm3
= 1880 cm3
In the reaction between aluminum and oxygen, how many grams of aluminum are needed to react with
5.00 dm3 of oxygen at STP?
4Al + 3O2 → 2Al2O3
5.00 dm3 O2
22.4 dm3
mol O2
3 mol O2
4 mol Al
mol Al
27.0 g= 8.04 g
How many cm3 of chlorine gas are required to react with hydrogen gas to produce 50.0 cm3 of hydrogen chloride gas at STP?
H2 + Cl2 → 2HCl
• This is a volume – volume calculation.• We can use a shortcut for these type of calculations.
50.0cm3 HCl
2 cm3 HCl
1 cm3 Cl2
= 25.0 cm3
Homework
• Worksheet: Gas Stoichiometry
• Lab Summary: “Molecular Mass of a Gas”