chapter 20 oxidation-reduction reactions_2
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Oxidation and Reduction (Redox)Oxidation and Reduction (Redox)
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2
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22
p ClNaClNa
Each sodium atom loses one electron:
Each chlorine atom gains one electron:
p eNaNa
10
10
p CleCl
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LEO says GER :LEO says GER :
p eNaNa
10
Lose Electrons = Oxidation
Sodium is oxidized
Gain Electrons = Reduction
10
CleCl Chlorine is reduced
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LEO says GER :LEO says GER :
- Losing electrons is oxidation, and thesubstance that loses the electrons is
called the reducing agent.
- Gaining electrons is reduction, and
the substance that gains the electrons is
called the oxidizing agent.
Mg(s) + S(s) MgS(s)
Mg is oxidized: loses e-, becomes a Mg2+ ion
S is reduced: gains e- = S2- ion
Mg is thereducing
agent
S is the oxidizing agent
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Rules for Assigning Oxidation NumbersRules for Assigning Oxidation Numbers
1)The oxidation number of any
uncombined element is zero.
2)The oxidation number of a
monatomic ion equals its charge.
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p ClNaClNa
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Rules for Assigning Oxidation NumbersRules for Assigning Oxidation Numbers
3)The oxidation number ofoxygen incompounds is -2, except in
peroxides, such as H2O2 where it is -1.
4)The oxidation number ofhydrogen in
compounds is +1, except in metal
hydrides, like NaH, where it is -1.
2
2
1
OH
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Rules for Assigning Oxidation NumbersRules for Assigning Oxidation Numbers
5) The sum of the oxidation numbers of theatoms in the compound must equal 0.
2
2
1
OH2(+1) + (-2) = 0
H O
2
122
)(
HOCa(+2) + 2(-2) + 2(+1) = 0Ca O H
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Rules for Assigning Oxidation NumbersRules for Assigning Oxidation Numbers
6) The sum of the oxidation numbers in
the formula of a polyatomic ion is equal
to its ionic charge.
3
2?
ON
X + 3(-2) = -1N O
2
4
2?
OS
thus X= +5
thus X = +6
X + 4(-2) = -2S O
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Reducing Agents and Oxidizing AgentsReducing Agents and Oxidizing Agents
An increase in oxidation number = oxidation
A decrease in oxidation number = reduction
p eaa
10
10
p CleCl
Sodium is oxidized it is the reducing agent
Chlorine is reduced it is the oxidizing agent
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Trends in Oxidation and ReductionTrends in Oxidation and Reduction
Active metals:
Lose electrons easily
Are easily oxidized
Are strong reducing agents
Active nonmetals:
Gain electrons easily
Are easily reduced
Are strong oxidizing agents
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BalancingBalancing RedoxRedox EquationsEquations
OBJECTIVES
Describe how oxidation
numbers are used to identify
redox reactions.
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BalancingBalancing RedoxRedox EquationsEquations
OBJECTIVES
Balance a redox equation
using the oxidation-number-
change method.
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BalancingBalancing RedoxRedox EquationsEquations
OBJECTIVES
Balance a redox equation
by breaking the equation into
oxidation and reduction half-
reactions, and then using thehalf-reaction method.
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Identifying Redox EquationsIdentifying Redox Equations
In general, all chemical reactions can
be assigned to one of two classes:
1)oxidation-reduction, in which
electrons are transferred:
Single-replacement, combination,
decomposition, and combustion
2) this second class has no electrontransfer, and includes all others:
Double-replacement and acid-
base reactions
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Identifying Redox EquationsIdentifying Redox EquationsIn an electrical storm, nitrogen and
oxygen react to form nitrogen monoxide:
N2(g) + O2(g) 2NO(g)
Is this a redox reaction?If the oxidation number of an element
in a reacting species changes, then
that element has undergone eitheroxidation or reduction; therefore, the
reaction as a whole must be a redox.
Conceptual Problem 20.4, page 647
YES!
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Balancing Redox EquationsBalancing Redox EquationsIt is essential to write a correctly
balanced equation that represents
what happens in a chemical reaction
Fortunately, two systematic methodsare available, and are based on the
fact that the total electrons gained in
reduction equals the total lost in
oxidation. The two methods:
1)Use oxidation-number changes
2)Use half-reactions
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Using OxidationUsing Oxidation--Number ChangesNumber ChangesSort of like chemical bookkeeping, you
compare the increases and decreases inoxidation numbers.
start with the skeleton equation
Step 1: assign oxidation numbers to all
atoms; write above their symbols
Step 2: identify which are oxidized/reduced
Step 3: use bracket lines to connect them
Step 4: use coefficients to equalize
Step 5: make sure they are balanced for
both atoms and charge Problem 20.5, 649
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Using halfUsing half--reactionsreactions
A half-reaction is an equation showing
just the oxidation or just the reduction thattakes place
they are then balanced separately, and
finally combinedStep 1: write unbalanced equation in ionic
form
Step 2: write separate half-reactionequations for oxidation and reduction
Step 3: balance the atoms in the half-
reactions (More steps on the next screen.)
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ChoosingChoosing a Balancing Methoda Balancing Method
1) The oxidation number changemethod works well if the oxidized
and reduced species appearonly
once on each side ofthe equation,andthere are no acids orbases.
2) The half-reaction method worksbest for reactions takingplace in
acidicor alkaline solution.