chapter 20 oxidation-reduction reactions_2

Upload: kunasahu1

Post on 09-Apr-2018

219 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    1/19

    Oxidation and Reduction (Redox)Oxidation and Reduction (Redox)

    11

    2

    00

    22

    p ClNaClNa

    Each sodium atom loses one electron:

    Each chlorine atom gains one electron:

    p eNaNa

    10

    10

    p CleCl

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    2/19

    LEO says GER :LEO says GER :

    p eNaNa

    10

    Lose Electrons = Oxidation

    Sodium is oxidized

    Gain Electrons = Reduction

    10

    CleCl Chlorine is reduced

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    3/19

    LEO says GER :LEO says GER :

    - Losing electrons is oxidation, and thesubstance that loses the electrons is

    called the reducing agent.

    - Gaining electrons is reduction, and

    the substance that gains the electrons is

    called the oxidizing agent.

    Mg(s) + S(s) MgS(s)

    Mg is oxidized: loses e-, becomes a Mg2+ ion

    S is reduced: gains e- = S2- ion

    Mg is thereducing

    agent

    S is the oxidizing agent

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    4/19

    Rules for Assigning Oxidation NumbersRules for Assigning Oxidation Numbers

    1)The oxidation number of any

    uncombined element is zero.

    2)The oxidation number of a

    monatomic ion equals its charge.

    11

    2

    00

    22

    p ClNaClNa

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    5/19

    Rules for Assigning Oxidation NumbersRules for Assigning Oxidation Numbers

    3)The oxidation number ofoxygen incompounds is -2, except in

    peroxides, such as H2O2 where it is -1.

    4)The oxidation number ofhydrogen in

    compounds is +1, except in metal

    hydrides, like NaH, where it is -1.

    2

    2

    1

    OH

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    6/19

    Rules for Assigning Oxidation NumbersRules for Assigning Oxidation Numbers

    5) The sum of the oxidation numbers of theatoms in the compound must equal 0.

    2

    2

    1

    OH2(+1) + (-2) = 0

    H O

    2

    122

    )(

    HOCa(+2) + 2(-2) + 2(+1) = 0Ca O H

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    7/19

    Rules for Assigning Oxidation NumbersRules for Assigning Oxidation Numbers

    6) The sum of the oxidation numbers in

    the formula of a polyatomic ion is equal

    to its ionic charge.

    3

    2?

    ON

    X + 3(-2) = -1N O

    2

    4

    2?

    OS

    thus X= +5

    thus X = +6

    X + 4(-2) = -2S O

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    8/19

    Reducing Agents and Oxidizing AgentsReducing Agents and Oxidizing Agents

    An increase in oxidation number = oxidation

    A decrease in oxidation number = reduction

    p eaa

    10

    10

    p CleCl

    Sodium is oxidized it is the reducing agent

    Chlorine is reduced it is the oxidizing agent

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    9/19

    Trends in Oxidation and ReductionTrends in Oxidation and Reduction

    Active metals:

    Lose electrons easily

    Are easily oxidized

    Are strong reducing agents

    Active nonmetals:

    Gain electrons easily

    Are easily reduced

    Are strong oxidizing agents

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    10/19

    BalancingBalancing RedoxRedox EquationsEquations

    OBJECTIVES

    Describe how oxidation

    numbers are used to identify

    redox reactions.

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    11/19

    BalancingBalancing RedoxRedox EquationsEquations

    OBJECTIVES

    Balance a redox equation

    using the oxidation-number-

    change method.

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    12/19

    BalancingBalancing RedoxRedox EquationsEquations

    OBJECTIVES

    Balance a redox equation

    by breaking the equation into

    oxidation and reduction half-

    reactions, and then using thehalf-reaction method.

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    13/19

    Identifying Redox EquationsIdentifying Redox Equations

    In general, all chemical reactions can

    be assigned to one of two classes:

    1)oxidation-reduction, in which

    electrons are transferred:

    Single-replacement, combination,

    decomposition, and combustion

    2) this second class has no electrontransfer, and includes all others:

    Double-replacement and acid-

    base reactions

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    14/19

    Identifying Redox EquationsIdentifying Redox EquationsIn an electrical storm, nitrogen and

    oxygen react to form nitrogen monoxide:

    N2(g) + O2(g) 2NO(g)

    Is this a redox reaction?If the oxidation number of an element

    in a reacting species changes, then

    that element has undergone eitheroxidation or reduction; therefore, the

    reaction as a whole must be a redox.

    Conceptual Problem 20.4, page 647

    YES!

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    15/19

    Balancing Redox EquationsBalancing Redox EquationsIt is essential to write a correctly

    balanced equation that represents

    what happens in a chemical reaction

    Fortunately, two systematic methodsare available, and are based on the

    fact that the total electrons gained in

    reduction equals the total lost in

    oxidation. The two methods:

    1)Use oxidation-number changes

    2)Use half-reactions

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    16/19

    Using OxidationUsing Oxidation--Number ChangesNumber ChangesSort of like chemical bookkeeping, you

    compare the increases and decreases inoxidation numbers.

    start with the skeleton equation

    Step 1: assign oxidation numbers to all

    atoms; write above their symbols

    Step 2: identify which are oxidized/reduced

    Step 3: use bracket lines to connect them

    Step 4: use coefficients to equalize

    Step 5: make sure they are balanced for

    both atoms and charge Problem 20.5, 649

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    17/19

    Using halfUsing half--reactionsreactions

    A half-reaction is an equation showing

    just the oxidation or just the reduction thattakes place

    they are then balanced separately, and

    finally combinedStep 1: write unbalanced equation in ionic

    form

    Step 2: write separate half-reactionequations for oxidation and reduction

    Step 3: balance the atoms in the half-

    reactions (More steps on the next screen.)

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    18/19

  • 8/8/2019 Chapter 20 Oxidation-Reduction Reactions_2

    19/19

    ChoosingChoosing a Balancing Methoda Balancing Method

    1) The oxidation number changemethod works well if the oxidized

    and reduced species appearonly

    once on each side ofthe equation,andthere are no acids orbases.

    2) The half-reaction method worksbest for reactions takingplace in

    acidicor alkaline solution.