chapter 24-capacitance
TRANSCRIPT
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Chapter 24 Capacitors and Dielectrics
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What is Capacitance?• Capacitance (C) is equal to the Charge (Q ) between two charges or
charged “regions” divided by the Voltage (V) in those regions.
• Here we assume equal and opposite charges (Q)
• Thus C = Q/V or Q = CV or V=Q/C
• The units of Capacitance are “Farads” after Faraday denoted F or f
• One Farad is one Volt per Coulomb
• One Farad is a large capacitance in the world of electronics
• “Capacitors” are electronic elements capable of storing charge
• Capacitors are very common in electronic devices
• All cell phones, PDA’s, computers, radio, TV’s … have them
• More common units for practical capacitors are micro-farad (10-6 f = μf), nano-farad (10-9 f = nf) and pico-farads (10-12 f = pf)
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A classic parallel plate capacitor
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General Surfaces as CapacitorsThe Surfaces do not have to be the same
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Cylindrical – “Coaxial” Capacitor
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Spherical Shell Capacitor
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How most practical cylindrical capacitors are constructd
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Dielectrics – Insulators – Induced and Aligned Dipole Moments
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Aligning Random Dipole Moments
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Creating Dipole Moments – Induced Dipoles
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Adding Dielectric to a Capacitor INCREASES its Capacitance since it DECREASES the Voltage for a GIVEN Charge
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Induced Dipole Moments in a Normally Unpolarized Dielectric
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Electrostatic Attraction – “Cling”Forced on Induced Dipole Moments
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Energy Stored in a Capacitor• Capacitors store energy in their electric fields
• The force on a charge in E field E is F=qE
• The work done moving a charge q across a potential V is qV
• Lets treat a capacitor as a storage device we are charging
• We start from the initial state with no charge and start adding charge until we reach the final state with charge Q
and Voltage V.
• Total work done W = ∫ V(q) dq (we charge from zero to Q)
• BUT V = q/C
• We assume here the Capacitance in NOT a function of Q and V BUT only of Geometry
• Thus the energy stored is W = 1/C ∫q dq = ½ Q2/C = ½ CV2
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Calculating Parallel Capacitor Capacitance• Assume two metal plates, area A each, distance d apart,
Voltage V between them, Charge +-Q on Plates
• σ = Q/A V = ∫Edx = Ed E = σ/є0 (from Gauss)
• Therefore C = Q/V = σA/ (Ed) = є0 A/d
• Note – As d decreases C increases
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Force on a Dielectric inserted into a Capacitor
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Force on Capacitor PlatesF=QE V=Ed (d separation distance)
F=QV/dQ=CV -> F =CV2/d
Recall W (Stored Energy) = ½ CV2
Hence F = 2W/d or W = ½ Fd
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Capacitors in Series
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Capacitors in Parallel
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Series and Parallel Capacitors
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Dielectric Constants of Some Common Materials
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Two Dielectric Constants – As if capacitors in Series
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Two Dielectric Constants – As if two capacitors in Parallel
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Dielectric Plus Vacuum (Air)Treat is if three capacitors in Series
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Capacitance of simple systems
Type Capacitance Comment
Parallel-plate capacitorA: Aread: Distance
Coaxial cablea1: Inner radiusa2: Outer radiusl: Length
Pair of parallel wires[17]
a: Wire radiusd: Distance, d > 2al: Length of pair
Wire parallel to wall[17]
a: Wire radiusd: Distance, d > al: Wire length
Concentric spheresa1: Inner radiusa2: Outer radius
Two spheres,equal radius[18][19]
a: Radiusd: Distance, d > 2aD = d/2aγ: Euler's constant
Sphere in front of wall[18]
a: Radiusd: Distance, d > aD = d/a
Sphere a: Radius
Circular disc a: Radius
Thin straight wire,finite length[20][21][22]
a: Wire radiusl: LengthΛ: ln(l/a)