chapter 3: advanced integration (part 2)

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  • 7/29/2019 CHAPTER 3: ADVANCED INTEGRATION (PART 2)

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    NTEGRATION BY PARTS

    1) Solve the integral using integration by partsmethod

    Solution:

    Step 1: Determine u and dv , their derivative and

    integration.

    u =x2 = sinx dxdu = 2xdx v = - cosx

    Step 2: Arrange the equation into correct order as below

    =

    Step 3: If still in form of two functions, repeat theStep 1 again.

    =

    u1= 2x = cosx dxdu1 = 2 dx v1 = sinx

    Step 4: Arrange the equation properly and solve the

    integration part.

    = = [ ]=

    2) Solve the integral using integration by partsmethod

    Step 1:

    u = lnx =x2 dxdu = dx v =

    Step 2: =

    =

    =

    =

    *

    9 +

    3) Solve the integral using integration by parts method

    Step 1:

    u = ex = sinx dxdu = exdx v = - cosx

    Step 2: = - - = -

    Step 3: -

    u1= = cosx dxdu1 = dx v1 = sinx

    Step 4: = =

    2I ; :

    EXERCISE

    Solve the following integrals using integration by parts:

    a)

    b) 3 5c) 4

    u = ? = ?du = ? v = ?

  • 7/29/2019 CHAPTER 3: ADVANCED INTEGRATION (PART 2)

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    NTEGRATION USING PARTIAL FRACTION

    There are 4 types of partial fraction:o Linear functiono Repeated factor functiono Quadratic term functiono Improper fraction

    1) Integrate :;: using partial fraction

    Solution:

    Step 1: Separate into partial fraction

    3

    3

    Step 2: Multiply the equation

    3 3

    3 3 Step 3: Solve for the unknowns

    x = 0 x = 1 x = -3

    When x = 0,

    0 + 1 =A (0 + 03) + 0 + 0

    A = When x = 1,

    (

    3) 3 3

    B = When x = -3,

    3 ( 3) 6 3 () 3

    C= 6

    Step 4: Complete the partial fraction & integrate one by one.

    :;:

    ;

    :

    = 3

    2) Integrate ;;:: using partial fraction

    Solution:

    Step 1:;;

    ::

    :

    :

    :

    Step 2:

    5

    5 4 4 3

    Step 3: When x = 1,

    (-1)2 + 25 =A(1) +B(0) + C(0)

    A = -2

    Compare power of x,

    x2 1 =A +B

    1 = (-2) +B

    B = 3

    x -2 = 4A + 3B + C

    -2 = 4(-2) + 3(3) + C

    C= -3

    Step 4: ;;::

    :

    :

    : 3 3

    3) Integrate ;: using partial fraction

    Step 1:

    ;:

    ; :

    :

    Step 2: x2 =A(x2 + 1) + (Bx+ C) (x2)

    x2 =A(x2 + 1) +B(x22x) + C(x2)

    Step 3: When x = 2,

    4 =A(5) +B(0) + C(0)

    A =

    Compare power of x,

    x2 1 = A +B

    1 = +B

    B =

    x 0 = -2B + C

    = 5 C=

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    Step 4: ; :

    :

    45

    5

    :

    :

    ;

    4) Integrate ;:;8; using partial fraction

    Step 1:

    3 5 6

    5 6 3 3

    3

    3

    Step 2: 18 =A(x2-3x) +B(x-3) + C(x2)

    Step 3: When x = 0, When x = 3,

    B = -6 C= 2

    Compare power of x,

    x2 0 =A + C

    A = -2

    Step 4: *

    ;+

    6 3

    x - 2

    x43x3 ddd

    -2x + 6x -2x3 + 6x2 i

    -18

    EXERCISE

    Solve the following integrals using partial fraction:

    a) ;7;;

    b) ;;;

    c) :;;:

    d) ;::