chapter 3 chemical formulae
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CHEMICAL FORMULAE AND EQUATIONS
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An atom size is very tiny and descrete
How to determine the mass of atom?
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Relative Atomic Mass,Ar
• = the mass of one atom of the element
1/12 x the mass of carbon-12 atom
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Why pick carbon-12 as standard?
• Hydrogen-1
Exist as gas at room temperature
Hard to handle
• Oxygen-16
Exist in three isotopes O-16, O-17,O-18
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• Carbon-12
Exist as solid at room temperature
Easily to handle
Also found three isotopes:C-12, C-13, C-14 but the C-12 is the most abundant, about 98.89%
Why pick carbon-12 as standard?
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Relative Atomic Mass,Ar
• = the mass of one atom of the element
1/12 x the mass of carbon-12 atom
Example: Ar for Magnesium = 24 .
1/12 x 12
= 24
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Relative Atomic Mass,Ar
= Nucleon number (p+n)
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• Adding up the Ar of all atoms in a molecule
• Example: MgCO3 ;
Ar Mg = 24 , C=12 , O=16
Mr of MgCO3 = (1x24)+(1x12)+(3x16)
=24+12+48
=84
Relative Molecular Mass,Mr
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Example: HPO4: ;
Ar H = 1 , P=31 , O=16
Mr of HPO4 =(1x1)+(1x31)+(4x16)
=1+31+64
=96
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Let’s try!