chapter 3 lesson 7 using formulas pgs. 131-136 what you will learn: solve problems by using formulas...
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![Page 1: Chapter 3 Lesson 7 Using Formulas pgs. 131-136 What you will learn: Solve problems by using formulas Solve problems involving the perimeters & areas of](https://reader036.vdocument.in/reader036/viewer/2022082711/56649edb5503460f94beab3a/html5/thumbnails/1.jpg)
Chapter 3 Lesson 7Using Formulaspgs. 131-136
Chapter 3 Lesson 7Using Formulaspgs. 131-136
What you will learn:
Solve problems by using formulas
Solve problems involving the perimeters & areas of rectangles
What you will learn:
Solve problems by using formulas
Solve problems involving the perimeters & areas of rectangles
![Page 2: Chapter 3 Lesson 7 Using Formulas pgs. 131-136 What you will learn: Solve problems by using formulas Solve problems involving the perimeters & areas of](https://reader036.vdocument.in/reader036/viewer/2022082711/56649edb5503460f94beab3a/html5/thumbnails/2.jpg)
Vocabulary:Vocabulary:
Formula (131): an equation that shows a Relationship among certain quantities. A formula
Usually contains two or more variables.
• Perimeter (132): the distance around a geometric figure
• Area (132): the space inside a geometric figure
expressed as square units
Formula (131): an equation that shows a Relationship among certain quantities. A formula
Usually contains two or more variables.
• Perimeter (132): the distance around a geometric figure
• Area (132): the space inside a geometric figure
expressed as square units
![Page 3: Chapter 3 Lesson 7 Using Formulas pgs. 131-136 What you will learn: Solve problems by using formulas Solve problems involving the perimeters & areas of](https://reader036.vdocument.in/reader036/viewer/2022082711/56649edb5503460f94beab3a/html5/thumbnails/3.jpg)
Key Concept (131)Distance Formula
Key Concept (131)Distance Formula
Words: Distance equals the rate multiplied by the time
Variables: Let d= distance, r = rate, & t = timeEquation: d = rt
Words: Distance equals the rate multiplied by the time
Variables: Let d= distance, r = rate, & t = timeEquation: d = rt
What is the rate in miles per hour of a dolphin that travels120 miles in 4 hours?
d = rt120 = r4 Make it look pretty! 4r = 120
4r = 1204 4 r = 30
The dolphin travels at a rate of 30 mph
![Page 4: Chapter 3 Lesson 7 Using Formulas pgs. 131-136 What you will learn: Solve problems by using formulas Solve problems involving the perimeters & areas of](https://reader036.vdocument.in/reader036/viewer/2022082711/56649edb5503460f94beab3a/html5/thumbnails/4.jpg)
Key Concept (132):Key Concept (132):
Perimeter of a Rectangle
Words: The perimeter of a rectangle is twice the sum of the length and width
Symbols: P = l + l + w + w Use the way
you or P = 2l + 2w prefer!
or P = 2 (l + w) l
Model: w
Perimeter of a Rectangle
Words: The perimeter of a rectangle is twice the sum of the length and width
Symbols: P = l + l + w + w Use the way
you or P = 2l + 2w prefer!
or P = 2 (l + w) l
Model: w
![Page 5: Chapter 3 Lesson 7 Using Formulas pgs. 131-136 What you will learn: Solve problems by using formulas Solve problems involving the perimeters & areas of](https://reader036.vdocument.in/reader036/viewer/2022082711/56649edb5503460f94beab3a/html5/thumbnails/5.jpg)
Key Concept (132):Key Concept (132):
Area of a Rectangle
Words: The area of a rectangle is the product of
the length and width
Symbols: A = lwl Remember area is
Model: w expressed in square units
Area of a Rectangle
Words: The area of a rectangle is the product of
the length and width
Symbols: A = lwl Remember area is
Model: w expressed in square units
![Page 6: Chapter 3 Lesson 7 Using Formulas pgs. 131-136 What you will learn: Solve problems by using formulas Solve problems involving the perimeters & areas of](https://reader036.vdocument.in/reader036/viewer/2022082711/56649edb5503460f94beab3a/html5/thumbnails/6.jpg)
Apply what you know! Find the perimeter of arectangle.
8 ft.
4 ft
The perimeter of this rectangle is 28 meters. Its width is 8 meters. Find the length.
P = 2(l + w)P = 2(8+4)P = 2(12)P = 24 ft.
P = 2(l+w)28 = 2(l+8)
28 = 2l + 16
28 - 16 = 2l +16 - 16
12 = 2l 2 2 6 = l
8m
Check:24 = 2(8+4)24 = 2(12)24 = 24
28 = 2(6+8)28 = 2(14)28 = 28
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Apply more of what you know!
Find the area of the rectangle:
12 in.
10 in.
A = lwA = 12(10)A = 120 in2
The area of a rectangle is 323 square yards. Its length is 17 yards. Find the width.
A = lw323 = 17w323 = 17w w = 19 yds 17 17
Check:
A = lw323 = 17(19)323 = 323
Check:120= 12(10)120 = 120
![Page 8: Chapter 3 Lesson 7 Using Formulas pgs. 131-136 What you will learn: Solve problems by using formulas Solve problems involving the perimeters & areas of](https://reader036.vdocument.in/reader036/viewer/2022082711/56649edb5503460f94beab3a/html5/thumbnails/8.jpg)
Find the perimeter and area of each rectangle:
6 mi
4 mi
18 in.
50 in.
A= lwA = 6(4)A = 24 mi2
P = 2(l+w)P = 2(6 + 4)P = 2(10)P = 20 mi
Check:20= 2(6+4)20= 2(10)20 = 20
P = 2(l+w)P = 2(18 + 50)P = 2(68)P = 136 in.
Check:136 = 2(18+50)136 = 2(68)136 = 136
A= lwA = 18(50)A = 900 in2
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Find the missing dimension:
7m
w
P = 24m
A = 176 yd2
w
16yd
P = 2(l+w)24 = 2(7+w)
24 = 14 + 2w24-14 = 14-14+2w10 = 2w 2 2 w= 5m
Check:24=2(7+5)24=2(12)24=24
A = lw176 = 16w176 = 16w 16 16 w = 11yd
Check:176=16(11)176=176
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Homework
Quiz Monday!!Test Wednesday!!
Practice Page is by the door!