chapter 4 calculating the derivative
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Chapter 4 Calculating the Derivative. JMerrill, 2009. Review. Find the derivative of (3x – 2x 2 )(5 + 4x) -24x 2 + 4x + 15 Find the derivative of. 4.3 The Chain Rule. Composition of Functions. A composition of functions is simply putting 2 functions together—one inside the other. - PowerPoint PPT PresentationTRANSCRIPT
Chapter 4Calculating the
Derivative
JMerrill, 2009
Review
Find the derivative of (3x – 2x2)(5 + 4x)
-24x2 + 4x + 15 Find the derivative of
25x 2x 1
22 2
5x 4x 5(x 1)
4.3The Chain Rule
Composition of Functions
A composition of functions is simply putting 2 functions together—one inside the other.
Example: In order to convert Fahrenheit to Kelvin we have to use a 2-step process by first converting Fahrenheit to Celsius.
89oF = 31.7oC 31.7oC = 304.7K But if we put 1 function inside the other function,
then it is a 1-step process.
5C (F 32) 9K C 273
Composition of Functions
We are used to writing f(x). f(g(x)) simply means that g(x) is our new x in the f equation.
We can also go the other way. means g(f(x)).
The composite of f(x) and g(x) is denoted which means the same as f(g(x)).
f g x
g f x
Given 2( ) 4 2 ( ) 2f x x x g x x
f(g(3)) =
= f(6)
= 4(6)2 – 2(6)
= 144 – 12
= 132
g(3) = 6
Given 1( ) ( ) 1f x g x xx
f g x
( ( ))f g x ( ( ))( 1)f g xf x
( ( ))( 1)1
1
f g xf x
x
g f x
( ( ))1
1 1
g f x
gx
x
g(x) = x+1
Substitute x+1In place of the
x in the f equation
=
The new x in the g equation
The Chain Rule
Chain Rule Example
Use the chain rule to find Dx(x2 + 5x)8
Let u = x2 + 5x Let y = u8
72
7
dy dy dudx du dx 8u 2
8 x 5x
x 5
2x 5
Another way to think of it: The derivative of the outside times the derivative of the inside
Chain Rule – You Try
Use the chain rule to find Dx(3x - 2x2)3
Let u = 3x - 2x2 Let y = u3
22
2
dy dy dudx du dx 3u 3 4x
3x 2x 3 4x3
The derivative of the outside times the derivative of the inside
Chain Rule
Find the derivative of y = 4x(3x + 5)5
This is the Product Rule inside the Chain Rule. Let u = 3x + 5; y = u5
4
4 5
4 5
4 5
5
4x 5u (3) (3x 5) (4)
4x 5(3x 5) (3) 4(3x 5)
4x 15(3x 5) 4(360x(3x 5)
x 5)4(3x 5)
Chain Rule
4
4
4
5
Factor out the common f actor14(3x 5)
60x(3x 5) 4(3x 5)
4(3x 5) (18x 55x (3x 5)
)
Chain Rule
Find the derivative of This is the Quotient Rule in the Chain Rule Let u = 3x + 2; let y = u7
73x 2x 1
6 7
2
6
2
7
2
6 7
(x 1) 7u (3) (3x 2) (1)(x 1)
(x 1) 7(
21 (x 1)(3x 2) (3x 2
3x 2) (3) (3x 2)(x 1)
)(x 1)
Chain Rule
6
6 7
2
6
2
2
2
6
Factor out the common f actor21(x 1) (3x 2)(x
(3x 2)
(
21 (x 1)(3x 2) (3x 2)(x 1)
(3x 2)
3
1
x
8
1)21x 21 3x 2(x 1)
x 2)
2
3
)
(x 1
4.4 Derivatives of Exponential Functions
Derivative of ex
Derivative of ax
xx
x(lD 3 n3)3
Other Derivatives
Examples – Find the Derivative
y = e5x
g(x)
x 5x5e (g'(x)e (5) 5e
Examples – Find the Derivative
y = 32x+1
g(x)
2
2x 1
x 1
lna a g'(x)
ln3 32ln3 3
(2)
Example
Find if Use the product rule
1
21 5x 2 (5)2
52 5x 2
2x 1y e 5x 2 dydx
12 2x 1 x 12x xy e D 5x 2 5x 2 D e
2x 1e (2x)
Example
12 2x 1 x 12x x
2 2x 1 x 1
2x 1 2x 1
y e D 5x 2 5x 2 D e
5e 5x 2 2xe2 5x 25e 5x 2 2xe2 5x 2
Example Continued
2x 1 2x 1
2x 1 2
2 2x 1 x 1
2x 1
5e 2xe 5x 22 5x 2
5e e (4x)(5x 2)2 5x
e 2
2e 5 4x(5x 2)
2 5x
2 5x 2
0x 8x 52 5x
2 5 2
2
x
2
Get a common denominator to add the 2 parts together
4.5Derivatives of Logarithmic Functions
Definition
Bases – a side note Everything we do is in Base 10.
We count up to 9, then start over. We change our numbering every 10 units. 1 11 212 12 223 13 23…4 145 156 167 178 189 1910 20
Ones Place
One group of ten and 1, 2, 3…
ones
Two tens
and …ones
Bases The Yuki of Northern California used Base 8.
They counted up to 7, then started over. The numbering changed every 8 units.
1 13 252 14 263 15 27…4 165 176 207 2110 2211 2312 24
Ones Place
One eight
and 3…ones
Two eights and …ones
So, 17 in Base 8 = 15 in Base 10
258 = 2 eights + 5 ones = 21
Bases
The Mayans used Base 20. The Sumerians and people of Mesopotamia
used Base 60.
Definition
Example
Find f’(x) if f(x) = ln 6x Remember the properties of logs ln 6x = ln 6 + ln x
d d(ln6) (lnx)dx dx10 1
xx
Definitions
Examples – Find the Derivatives
y = ln 5x If g(x) = 5x, then g’(x) = 5
dy g'(x) 5dx g(x) 5
1xx
F’(x)
f(x) = 3x ln x2
Product Rule
2 2
2
2
2
df ' (x) (3x) lnx lnx (3)
6 3lnx
dx2x3x lnx (3)x