chapter 4 general equilibrium
TRANSCRIPT
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8/13/2019 Chapter 4 General Equilibrium
1/21
General
equilibrium
Conditions of equilibrium
( ) ( ) ( )1 M 0 2 X 0 3 Y 0= = =
( )
( )
( )( )
1 Your drawing must be in a large scale
2 If you didn't find the word hori!ontal "osition# then your body is inclined to the hori!ontal
3 $he reaction of any body is always "er"endicular to the "lane%
( )
&
e are dealing with two "lanes (
)mooth "lanes *ough "lanes
+
& * where Coefficient of friction and * the normal reaction
=
Equilibrium rule :
About to move rule :
( )
$his is called a limiting friction
, 2 2F
Resultant reaction R' = F + R
*
* *
&&
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/ntro0uctionIn "reious year# we hae ta-en the equilibrium of a body under the action of three force/
In this cha"ter# we will deal with a body in equilibrium under the action of more than three
forces "laced on smooth or rough "lanes/
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efinition : set of co"lanar forces is said to be in equilibrium if both the ectorsum of
the forces and the ector sum of the moments of the forces about any"oint anish/ lso when a
body is acted on by such a set of co"lanar forces#the body is said to be in equilibrium/
1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111
Some notes %hich %ill ma3e "our %or3 easier
Static - r0secon0ar" 4ha#ter four - General equilibrium1
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C
o30
o,0
2
3
( )4 5se the following methods to sole your "roblem quic-ly
Co%+
o%+
2
C
o%+
o%+
6
6
107am"le
106
2=
C
C
107am"le
Cos
)in
10)in
10Cos
C C
8 7
If 87 .. C
8 7 87
C C= =
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Static - r0secon0ar" 4ha#ter four - General equilibrium2
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8/13/2019 Chapter 4 General Equilibrium
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uniform rod of 90 cm long of weight 3 -g/wt is hinged at to a ertical wall# lam" of
12 -g/wt is hung from a "oint on the rod 10 cm from the end # this end is tied with a light ro"e
with its end C fied on the wall at "oint ertically aboe and far from it ,0 cm so that the rod
is -e"t hori!ontal# find the tension of the string and the reaction of the hinge and its direction/
( )
( )
( )
:otes 1 $he "roblem mentioned that your rod is hori!ontal
2 :osmooth or rough mentioned in the "roblem
3 hen there is a hinge in the "roblem# then its
reaction has no fied direction# so we must
( ) ( )
( ) ( )
y
2 2
ma-e
a resolution in the ; ais * and the y ; ais *
C ,0 90 100 cm
M 0 ( try to anish the most un-nown forces
;3 %0 12 40 $ )in 90 0
,090$ )in
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8/13/2019 Chapter 4 General Equilibrium
4/21
( )
( )
( )
:otes 1 $he "roblem mentioned that your rod is hori!ontal
2 :o smooth or rough mentioned in the "roblem
3 hen there is a hinge in the "roblem# then its
reaction has no fied direction# so we must
( ) ( )
( ) ( )
y
2 2
ma-e
a resolution in the ; ais * and the y ; ais *
C %/+ , 4/+ m
&irst ( we hae to -now that $
M 0 ( try to anish the most un-nown forces
;+ %/+ 3 , $ )in , 0
,$ )i
= + =
=
=
+ =
Q
( )
( ) ( )
Y Y
%/+n %0/+ $ )in ,/4+ $ ,/4+ $ 11/2+ -g/wt
4/+
,X 0( ( * $ Cos 0 * $ Cos * 11/2+ < -g/wt
4/+
Y 0( ( 8on' t ta-e here as we -now that $
* $ )in 9 * 9 ,/4+ 1/2+ -g/wt
$h
= = = = =
= = = = =
= =
+ = = =
Q
( ) ( )2 22 2
y
1321en the reaction of the hinge is( * * * < 1/2+ -g/wt
%= + = + =
%/+ m
+
1/+ m
3
C
%/+ m
$=
*
*
y*
)in
$ )in
$ Cos
is a rod of , m long of weight + -g/wt and its center of graity is at %/+ m from and hinged
at to a fied hori!ontal hinge# the end is tied to a light string "assing oer a smooth "ulley
lies ertically aboe and at %/+ m away from it# the string carries at its other end a body of
weight / If a body of weight 3 -g/wt is hung from so that the rod became hori!ontal# then
find the magnitude of and find the "ressure of the hinge/
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Static - r0secon0ar" 4ha#ter four - General equilibrium4
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uniform rod of 1,0 cm long and weight 300 gm/wt is hung by a fied nail C by the mean
of two strings attached to its end and # a weight of ,00 gm/wt is hung to a "oint : on the rod/
If the rod i
o o
s in equilibrium in a hori!ontal "osition and the two strings C and C are inclined
to the rod at angles ,0 #30 res"ectiely# find the length of : and the magnitude of the tension
in the two strings
( )
( )
( )
o1
:otes 1 $he "roblem mentioned that your rod is hori!ontal
2 :osmooth or rough mentioned in the "roblem
M 0 ( try to anish the most un-nown forces
,00 90 300 90 $ )in,0 1,0 0
%9000 ,00
=
+ =
( )
( )
( ) ( )
( )
1 1
1
o o1 2 1 2 1 2
o o1 2 1 2
2%000 90 3$ 0 90 3$ ,00 4200 %0
2 3 $ 1+ 1900 1
1 3X 0( ( $ Cos,0 $ Cos30 0 $ $ 0 $ 3$ 2
2 2
3 1Y 0( ( $ )in ,0 300 ,00 $ )in30 0 $ $
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8/13/2019 Chapter 4 General Equilibrium
6/21
uniform rod of 1,0 cm long and weight 30 -g/wt # its lower end rests on a ertical
smooth wall 8# and is tied from "oint = by one end of a string whose other end is attached
to "oint 8 so that t
o
he rod reached its equilibrium state in a "osition inclined to the ertical at
an angle ,0 / If the length = ,0 cm# then find the angle 8= and also find the magnitudes
of the tension of the string and
=the reaction of the wall/
=
:ote when a body is "laced on a smooth "lane# then the
reaction is "er"endicular to the "lane
M 0 ( try to anish the most un-nown forces
;3 10 3 * 30 0 30* 30 3 * 3 -g/wt
X 0 ( * $ )in 0 $
= + = = =
= =
( )( )
( ) ( )
( )
o
o
)in * 3 1
Y 0( $ Cos 3 2
3$hen diide 1 by 2 ( $an 30
2
$hen from 1 ( $ )in 30 3 $ 2 3 -g/wt
= =
= =
= =
= =
30 3 cm
*
3
$ Cos
,0 cm
20
90 cm
$ )in
o,0
o30
o30
o30
10
10 3
1+cm
)mooth
8
=
C
uniform ladder of weight %0 -g/wt and 12 m length rests with its end on a smooth
hori!ontal "lane and its end on a smooth ertical wall# the ladder is -e"t in equilibrium by a
string tied to on
o
e of its ends # and its other end is attached to a "oint on the hori!ontal "lane
ertically below # if the ladder is inclined at %+ to the hori!ontal# gien that the string can not
bear a tension of more than +0 -g/wt# "roe that a man of weight the weight of the ladder can
not ascend more than
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8/13/2019 Chapter 4 General Equilibrium
7/21
uniform rod of lenght 9 m and weight 20 -g/wt# its end is attached to a hinge fied to a
ertical wall# and its end being >oined by a light string , m length whose other end is fied to the
wall at C ertically aboe and 10 m away from it# if a weight of 1+ -g/wt is hung from the end /
&ind the tension in the string# and the magnitude and the direction of the reaction of the hinge
( )
( )
:ote 1 hen a body is "laced on a smooth "lane# then the
reaction is "er"endicular to the "lane
2 hen there is a hinge in the "roblem# then its reaction has no fied direction# so we must
( ) ( )
( )
( ) ( ) ( ) ( )
( ) ( ) ( ) ( )
( ) ( ) ( )
y
2 2
2 2 2 2
2 2 2 o
y
y
ma-e
a resolution in the ; ais * and the y ; ais *
In C( C 10 100
nd C , 9 100
C C m
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8/13/2019 Chapter 4 General Equilibrium
8/21
uniform rod of weight 1+0 -g/wt and +% cm rests with its lower end on a ertical smooth
wall# and it is fied at "oint = on a hori!ontal smooth su""ort "arallel to the wall# if the length
= equals 12 cm and the rod is in equilibrium when it is "er"endicular to the wall# "roe that
2the sin angle of the inclination between the rod and the wall is # then calculate the magnitude
3
of the reaction of the su""ort and that of the wall/
( ) ( )
( )
o= 1
1
1
:ote when a body is "laced on a smooth "lane# then the
reaction is "er"endicular to the "lane
M 0 ( * 12 )in
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8/13/2019 Chapter 4 General Equilibrium
9/21
uniform ladder of length + m and weight 20 -g/wt rests with one end on a smooth ertical wall
and the other end on a smooth hori!ontal floor# if the lower end of the ladder is 3m away from
the wall# the ladder is -e"t from sli""ing by a string attached to a "oint on it and the other end
of the string is fied to a "oint on the line of intersection of the floor and the wall# -nowing that
the direction of the string is "er"endicular to that of the ladder# find the tension of the string and
the reaction of each of the wall and the floor/
( )
( ) ( )2 2
:ote 1 hen a body is "laced on a smooth "lane# then the reaction is "er"endicular to the "lane
7 + 3 % m
18& 7 1/+ m and 7 7
2
nd 7C # then by using 7ucl
= =
= =
Q Q
( )
( )
( ) ( )
( ) ( )
2
y
y y
y
id's theorem
1, 7 C 1, +C C m
+1, 1,
M 0 ( ;20 1/+ $ Cos Cos $ )in )in * 3 0+ +
% 1, % 3 1, 3 1, ;30 $ $ 3* 0 3* $ 30 1
+ + + + + + +
%X 0( ( * $ Cos $ 2
+
3
Y 0( ( * 20 $ )in 20 $ 3+
)ubstit
= = == + =
+ = =
= = =
= = + = +
Q
( ) ( )
( )
( )
y
3 1, < 1, 1+0ute 3 in 1 ( 3 20 $ $ 30 ,0 $ $ 30 $ -g/wt
+ + + + 4
% 1+0 120&rom 2 ( * -g/wt
+ 4 4
3 1+0 230&rom 3 ( * 20 -g/wt
+ 4 4
+ = + = =
= =
= + =
20
C
&
*
y*
$ )in
2/+
$
)mooth
)mooth
1/+
?
8
7
1,)in
+
3 m
2/+$ Cos
1,Cos
+
% m
1,C m
+=
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8/13/2019 Chapter 4 General Equilibrium
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uniform ladder rests with its end on a smooth ertical wall and the its other end on a
smooth hori!ontal "lane# the ladder is -e"t from sli""ing by a string whose one of its ends fied
to a "oint
( )
at the bottom of the wall ertically below and the other end is fied to one stair at a
1distance from equals of the ladder length# if the "ressure of the ladder on the wall is @
%
and on the floor ( )is A / If # are at distance ,0 cm# 90 cm res"ectiely from the bottom of the
@ %wall# then "roe that(A +
=
( )
( ) ( )2 2
:ote 1 hen a body is "laced on a smooth "lane# then the
reaction is "er"endicular to the "lane
7 + 3 % m
18& 7 %0 cm & 30 cm
2In &8# =C ( &8 .. =C
& =
= =
= = =
=
Q
Q
( ) ( )
( )
( ) ( ) ( ) ( )
2 2
8
8 &8 30 +0 %0
C =C = 4+ =C
= %+ cm &= 1+ cm =C ,0 cm
In C7=( 7C 1+ ,0 1+ 14 cm
e don't need # so we will ta-e M 0 (
; @ 30 $ )in 20 $ Cos 1+ A %0 0
1+ ,0 2 ;30@ $ 20 $ 1+ %0A 0 %0A 30@
1+ 14 1+ 14
= = =
= = =
= + =
=
+ =
+ =
Q
( )
( ) ( )
( ) ( )
0 ,0$ $ 0
14 14
90 %0A 30@ $ 0 1
14
,0 14 X 0( ( @ $ Cos $ $ 2
141+ 14
90 14 )ubstitute 2 in 1 ( %0A 30@ @ 0
%14
@ % %0A 30@ 20@ 0 %0A +0@
A +
=
=
= = = =
=
= = =
C
&
@
A
$ )in
+0
%0 cm
=
8
7
,0 cm
20
2+
$ Cos
30
1+2+
1+ 1+ 14
20%0
$
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o
is a uniform rod of mass 20 -g rests with its u""er end on a smooth inclined "lane that's
to the hori!ontal at an angle of measure ,0 # and it is resting with its lower end on a smooth
hori!ontal "lane# it is -e"t from sli""ing by a string C which is attached with one end to and
with the other end to C# so that the "lane C is "er"endicular to the line of intersection of the
two "lanes/ &
o
ind the magnitude of the reaction of each of the "lane on the rod# and find the
tension on the string when the angle of inclination of the rod to the hori!ontal is 30
( ) ( )
o
:ote when a body is "laced on a smooth "lane# then the
reaction is "er"endicular to the "lane
1M 0 ( ;* 3 20 3 $ 0
2
8iide by ; 3* 10 3 $ 0 1
3X 0 ( $ * Cos30 0 $ *
2
= + + =
+ + = = = =
( )
( )
( ) ( ) ( )
( ) ( )
( )
o
2 * $ 2
3
Y 0( * * )in30 20 3
1 2 3)ubstitute 2 in 3 ( * $ 20 * 20 $ %2 33
3)ubstitute % in 1 ( ; 3 20 $ 10 3 $ 0 ;20 3 $ 10 3 $ 0
3
2$ 10 3 $ + 3 -g/wt # then from 2 ( *
=
= + =
+ = =
+ + = + + + =
= =
( )
2+ 3 10 -g/wt
3
3
then from % ( * 20 + 3 1+ -g/wt 3
= =
= =
20
*
$
o30
1
2
o
* Cos30
o,0
13
2
o* )in30
o30
o30
o,0
3
120
o30
o30
1
2
*
C
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1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111
Static - r0secon0ar" 4ha#ter four - General equilibrium11
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8/13/2019 Chapter 4 General Equilibrium
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uniform rod BM of length 1+0 cm and weight + -g/wt tied by its two ends B#M by means of two
strings B: and M= whose lenghts are 1+0# 300 cm res"ectiely# and the two free ends of the two
strings are f
( ) ( )
ied at "oints :# = on a hori!ontal straight line# := 300 cm# then a hori!ontal
force & acted on the rod and its end B so the rod became in equilibrium "osition as the
string B: is ertical and the whol
=
( )
e system of forces lie in the same ertical "lane# determine
& and find the magnitude of the tension in each string/
=
1$
:
& 2$
2$ )in
2
B
?
M2$ Cos
4+
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8/13/2019 Chapter 4 General Equilibrium
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5roblems of equilibrium on rou!h #lanes
o
uniform ladder of weight 30 -g/wt rests with one of its ends on a smooth ertical wall and with
its other end on a rough hori!ontal floor# so that it is inclined at angle %+ to the hori!ontal# if a
man whose weight is ,0 -g/wt is ascending the ladder slowly# and the ladder was about to sli"
3when the man ascended of the length of the ladder# find the coefficient of friction between
%
the the floor and the ladder# and if the man wanted to continue to ascend the to" of the ladder#
then find the least hori!ontal force which acts at the lower end at this case/( )
( )
:ote 1 when a body is "laced on a "lane# then the
reaction is "er"endicular to the "lane
2 when a body is "laced on a "lane# then the
reaction is "er"endicular to the "l
smooth
rou!h
( )
&
st
1
1 1
1
ane and & a""ears
let the length of the ladder be %
31 case when the man ascended the length of the ladder(
%
% 3 2 2M 0 ( ;* ,0 30 0
2 2 2
%* 2%0 * ,0 -g/wt
X 0( ( *
= + + =
= == =
( )
( )
&
2
&&
nd
1
1 1
& ,0 -g/wt
Y 0( ( * ,0 30
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8/13/2019 Chapter 4 General Equilibrium
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%
2
( )
uniform ladder of length % m rests on a hori!ontal rough floor and a smooth ertical wall/ If
the ladder is about to slide under the action of a weight when it is inclined to the hori!ontal
at an an
o
3gle of tangent # find the coefficient of friction# and if the ladder was inclined to the
%hori!ontal at an angle %+ # find the farthest distance on the ladder a man whose weight is % times
the ladder's weight can ascend before the ladder is about to slide/
( )
( )
:ote 1 when a body is "laced on a "lane# then the reaction is "er"endicular to the "lane
2 when a body is "laced on a "lane# then the
reaction is "er"endicular to the "l
smooth
rou!h
( )
( )
&
st
1
1 1
ane and & a""ears
C 3 C 12)in C m
% + % +
8 % 8 9nd Cos 8 m
2 + 2 +1 case If the ladder is about to slide under weight (
12 9 +M 0 ( ;* 0
+ + %
2 3* 2 * 1
3
X 0(
= = =
= = =
= + =
= =
=
Q
Q
( )
( )
( )
( ) ( )
( ) ( )
1 &
2
& 2
nd o
1
1 1
1 & 2
&
2( * &
3
Y 0( ( *
2 2nd & *
3 3
2 case when %+ (
% 2M 0 ( ;* % 0 2
2 2 2
1 %* % 2 % * 12
1X 0( ( * & nd Y 0( ( * +
2
and & *
= =
= =
= = =
= = + + =
= + = +
= = = + = =
= +
Q
Q ( )1 2 1 10 14
+ m2 3 2 3 ,
= + = =
2
9
+
C
12
+
1*
2*
&&
2
*ough
)mooth
2
2
C
%
2
1*o
%+
2*
&&
,0 %
2
2
2
7
2
&
%
2
8
%
+3
%
o%+
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uniform ladder of length + m and weight 20 -g/wt rests with its end on a smooth ertical
wall and with its other end on a rough hori!ontal floor# the coefficient of friction between the
ground a1
nd the ladder is / If the "oint is 3 m away from the wall# "roe that the ladder can%
not be in equilibrium in this case# and then find the magnitude of the least weight could be "laced
at to "ree1
nt sliding# gien that the coeficient of friction between this weight and the ground is /+
( )
( )
:ote 1 when a body is "laced on a "lane# then the
reaction is "er"endicular to the "lane
2 when a body is "laced on a "lane# then the
reaction is "er"endicular to the "l
smooth
rou!h
( ) ( )
( )
( )1
1
1
&
st 2
2 2
2 &
1
& 1
& 1
ane and & a""ears
let the length of the ladder be %
1 case M 0 ( 20 1/+ * % 0
%* 30 * 4/+ -g/wt
X 0( ( * & 4/+ -g/wt
Y 0( ( * 20 -g/wt
1)o & 4/+ and * 20 + -g/wt
%$hen & * $
= =
= =
= = =
= =
= = =
>
Q
1
1
nd
& 1
& 1
hen the ladder is not in equilibrium
2 case to get the least weight to "reent the ladder from
sliding & must be equal to *
& * + -g/wt
nd the wei
= =
Q
( ) ( )( )
( )
2
1 2 2 2
&
3 3 3
3 & & & &
2 2 2 2
1 2
ght has another friction &
M 0 ( ;* % 20 1/+ 0 %* 30 * 4/+ -g/wt
X 0( ( * & & 0 4/+ + & & 2/+ -g/wt
1 * 2/+ * 2/+ * 12/+ -g/wt
+
Y 0( ( * * 20 20 12/+ 20 12/+ -g/wt
= + = = == = =
= = =
= + = + + = + =
20
C
%
2*
1*
1&&
2/+
2/+
*ough
)mooth
3m
3 m
20
C
%
3*
2*
2&&
2/+
2/+
1&&
1*
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uniform inclined ladder rests with the end on a rough hori!ontal floor# and the other end
1on a rough ertical wall# if the coefficient of the friction between the ladder and the floor is # a
2nd
1
that between the ladder and the wall is # and the ladder was about to slide# find the tangent of the%
angle of the inclination of the ladder to the hori!ontal/
( ) ( ) ( )
( )
=
+ = + =
2
2
&
st
& 2
& 2
2 2
:ote when a body is "laced on a "lane# then the
reaction is "er"endicular to the "lane and & a""ears
1 case M 0 (
;& 2Cos * 2 )in Cos 0 ;2& Cos 2* )in Cos 0
;2 * Cos
rou!h
( )
( )
( ) ( )
( ) ( )
( ) ( )
( ) ( )
+ =
+ =
+ =
= = = =
= + = + = + =
=
+
1
2
2
2 2
2 2
2 & 1 1 1
& 1 2 2 1 2 1
1 2
2 2
2* )in Cos 0
1;2 * Cos 2* )in Cos 0 Cos
%
1 * 2* $an 1
2
1X 0( ( * & * * 22
1Y 0( ( & * * * * * 3
%
&rom 2 ( * 2* %
1$hen substitute % in 3 ( * 2*
%
( )
( ) ( ) ( )
= = =
+ = + =
= = =
2 2
< % * * +
%