chapter 5 design & analysis of experiments 1 8e 2012
TRANSCRIPT
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Chapter 5 Design & Analysis of Experiments
8E 2012 Montgomery
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Design of Engineering Experiments
– Introduction to Factorials
• Text reference, Chapter 5
• General principles of factorial experiments
• The two-factor factorial with fixed effects
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• The two-factor factorial with fixed effects
• The ANOVA for factorials
• Extensions to more than two factors
• Quantitative and qualitative factors –response curves and surfaces
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Some Basic Definitions
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Factor effect: The change in the mean response when the
factor is changed from low to high
40 52 20 3021
2 2
30 52 20 4011
2 2
52 20 30 401
2 2
A A
B B
A y y
B y y
AB
+ −
+ −
+ += − = − =
+ += − = − =
+ += − = −
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The Case of Interaction:
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50 12 20 401
2 2
40 12 20 509
2 2
12 20 40 5029
2 2
A A
B B
A y y
B y y
AB
+ −
+ −
+ += − = − =
+ += − = − = −
+ += − = −
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Regression Model & The Associated Response Surface
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0 1 1 2 2 12 1 2
1 2 1 2 1 2
The least squares fit is
ˆ 35.5 10.5 5.5 0.5 35.5 10.5 5.5
y x x x x
y x x x x x x
β β β β ε= + + + +
= + + + ≅ + +
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The Effect of Interaction on the Response Surface
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Suppose that we add an interaction term to the model:
1 2 1 2ˆ 35.5 10.5 5.5 8y x x x x= + + +
Interaction is actually a form of curvature
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Example 5.1 The Battery Life Experiment
Text reference pg. 187
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A = Material type; B = Temperature (A quantitative variable)
1. What effects do material type & temperature have on life?
2. Is there a choice of material that would give long life regardless of
temperature (a robust product)?
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The General Two-Factor
Factorial Experiment
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a levels of factor A; b levels of factor B; n replicates
This is a completely randomized design
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Statistical (effects) model:
1, 2,...,
( ) 1, 2,...,
1, 2,...,
ijk i j ij ijk
i a
y j b
k n
µ τ β τβ ε
=
= + + + + = =
Other models (means model, regression models) can be useful
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Extension of the ANOVA to Factorials
(Fixed Effects Case) – pg. 189
2 2 2
... .. ... . . ...
1 1 1 1 1
2 2
. .. . . ... .
( ) ( ) ( )
( ) ( )
a b n a b
ijk i j
i j k i j
a b a b n
ij i j ijk ij
y y bn y y an y y
n y y y y y y
= = = = =
− = − + −
+ − − + + −
∑∑∑ ∑ ∑
∑∑ ∑∑∑
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. .. . . ... .
1 1 1 1 1
( ) ( )ij i j ijk ij
i j i j k
n y y y y y y= = = = =
+ − − + + −∑∑ ∑∑∑
breakdown:
1 1 1 ( 1)( 1) ( 1)
T A B AB ESS SS SS SS SS
df
abn a b a b ab n
= + + +
− = − + − + − − + −
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ANOVA Table – Fixed Effects Case
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JMP and Design-Expert will perform the computations
Text gives details of manual computing (ugh!) – see pp.
192
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Design-Expert Output – Example 5.1
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Residual Analysis – Example 5.1
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Residual Analysis – Example 5.1
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Interaction Plot DESIGN-EXPERT P lot
L i fe
X = B: T em perature
Y = A: M ateria l
A1 A1
A2 A2
A3 A3
A: Materia l
Interaction Graph
Lif
e
104
146
188
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B: Tem perature
15 70 125
20
62
2
2
22
2
2
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Quantitative and Qualitative Factors
• The basic ANOVA procedure treats every factor as if it
were qualitative
• Sometimes an experiment will involve both quantitative
and qualitative factors, such as in Example 5.1
• This can be accounted for in the analysis to produce
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• This can be accounted for in the analysis to produce
regression models for the quantitative factors at each level
(or combination of levels) of the qualitative factors
• These response curves and/or response surfaces are often
a considerable aid in practical interpretation of the results
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Quantitative and Qualitative Factors
Candidate model
terms from Design-
Expert:
Intercept
A
A = Material type
B = Linear effect of Temperature
B2 = Quadratic effect of
Temperature
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A
B
B2
AB
B3
AB2
Temperature
AB = Material type – TempLinear
AB2 = Material type - TempQuad
B3 = Cubic effect of
Temperature (Aliased)
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Quantitative and Qualitative Factors
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Regression Model Summary of Results
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Regression Model Summary of Results
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Factorials with More Than
Two Factors
• Basic procedure is similar to the two-factor case; all
abc…kn treatment combinations are run in random
order
• ANOVA identity is also similar:
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• ANOVA identity is also similar:
• Complete three-factor example in text, Example 5.3
T A B AB AC
ABC AB K E
SS SS SS SS SS
SS SS SS
= + + + + +
+ + + +L
L L
L
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Homework
• Solve
– Problem 5.3
– Problem 5.18– Problem 5.18
• both manually and using DesignExpert
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