chapter 5 problems - home : homepageprofkatz.com/.../2014/10/ch1710-chapter-5-problems.pdfthe...
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![Page 1: Chapter 5 Problems - Home : HomePageprofkatz.com/.../2014/10/CH1710-Chapter-5-Problems.pdfThe temperature inside a balloon is raised from 25.0 C ! to 250.0 C. If the volume of cold](https://reader030.vdocument.in/reader030/viewer/2022013121/5ca190c788c993f7068c5d75/html5/thumbnails/1.jpg)
Chapter 5 Lecture Problems
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A cylinder with a movable piston has a volume of 7.25 L at 4.52 atm. What is the volume at 1.21 atm?
V1 =7.25 L, P1 = 4.52 atm, P2 = 1.21 atm, V2= ?P1 · V1 = P2 · V2
V1, P1, P2 V2
V2 = =(P1)(V1)!(P2)
(4.52 atm)(7.25 L)!(1.21 atm)
= 27.1 L
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V2 =2780 mL, P1 = 762 torr, P2 = 0.500 atm V1 = ?
V2, P1, P2 V1
P1 · V1 = P2 · V2 , 1 atm = 760 torr (exactly) !
A balloon is put in a bell jar and the pressure is reduced from !782 torr to 0.500 atm. If the volume of the balloon is now !
2.78 x 103 mL, what was it originally?
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D = m/V
A balloon is put in a bell jar and the pressure is reduced from !782 torr to 0.500 atm. If the volume of the balloon is now !
2.78 x 103 mL, what was it originally?
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A gas has a volume of 2.57 L at 0.00 °C. What was the temperature when the volume was 2.80 L?
V2 =2.57 L, T2 = 0.00 °C, V1 = 2.80 L T1 = ?
V1, V2, T2 T1
(2.80 L)(2.57 L)
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The temperature inside a balloon is raised from 25.0 °C !to 250.0 °C. If the volume of cold air was 10.0 L, what is the
volume of hot air?
V1 =10.0 L, t1 = 25.0 °C L, t2 = 250.0 °C V2 = ?
V1, T1, T2 V2
V2 = =(T2)(V1)!(T1)
= 17.5 L(523.2 K)(10.0 L)!(298.2 K)
V1!T1
V2!T2
=T(K) = t(ºC) + 273.15
T1 = 25.0 + 273.15 = 298.2 KT2 = 250.0 + 273.15 = 523.2 K
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If 1.00 mole of a gas occupies 22.4 L and the temperature and pressure are not changed, what volume would !
0.750 moles occupy?
V1 =22.4 L, n1 = 1.00 mol, n2 = 0.750 mol V2 = ?
V1, n1, n2 V2
V1!n1
V2!n2
=
(V1)(n2)!(n1)
V2 = = 16.8 L(22.4 L)(0.750 mol)!(1.00 mol)=
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A gas occupies 10.0 L at 44.1 psi and 27 °C. What volume will it occupy at standard conditions?
V1 = 10.0L, P1 = 44.1 psi, t1 = 27 °C, P2 = 1.00 atm, t2 = 0 °C, V2 = ?
P1, V1, T1, R n
n = PV!RT V = nRT!
P
P2, n, T2, R V2
1.00 atm!14.7 psi
44.1 psi x = 3.00 atm
T1(K) = 27ºC + 273.15 = 300. K
n = PV!RT
= 1.218 mol
atm L!mol K
(3.00 atm)(10.0 L)!(0.0821 )(300. K)=
= 1.22 mol
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A gas occupies 10.0 L at 44.1 psi and 27 °C. What volume will it occupy at standard conditions?
n =1.218 mol
P1, V1, T1, R n
n = PV!RT V = nRT!
P
P2, n, T2, R V2
V = (1.22 mol)(.0821 )(273 K)!1.00 atm
atm L!mol K
= 27.3 L
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Calculate the volume occupied by 637 g of SO2 (MM 64.07) at 6.08 x 104 mmHg and –23 °C.
mSO2 = 637 g, P = 6.08 x 104 mmHg, t = −23 °C, V = ?
g n P, n, T, R V
K = 273+ºC=273+(-23)=250
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How many liters of O2 @ STP can be made from the decomposition of 100.0 g of PbO2?
2 PbO2 → 2 PbO + O2
100.0 g PbO2, PbO2: 239.2 g/mol, O2: 32.00 g/mol, L O2 = ?
g PbO2 mol O2mol PbO2 L O2
g
mol
mol
mol
mol
L
100.0 g PbO2 x x x 1.0 mol PbO2!239.2 g PbO2
1.0 mol O2!2.0 mol PbO2
22.4 L O2!1.0 mol O2
= 4.68 L O2
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Calculate the density of N2(g) at STP.
molar!mass density g!
L
d = = = 1.25 molar mass g/mol!molar volume L/mol
28.02 g/mol!22.4 L/mol
g!L
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Calculate the density of N2 at 125°C and 755 mmHg .
P = 755 mmHg, t = 125 °C, dN2 = ?
P, MM, T, R d
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Calculate the density of a gas at 775 torr and 27 °C if 0.250 moles weighs 9.988 g.
m = 9.988 g, n = 0.250 mol, P = 775 torr, T = 27ºC, density = ?
K = 273+ºC=273+(27)=300
P, n, T, R V V, m d
V = (n)(R)(T)!P
d = m!V
(0.250 mol)(0.0821 )(300 K)!(1.02 atm)
atm L!mol K
775 torr x = 1.0197 atm 1 atm!760 torr
V = = !! ! ! ! ! = 6.037 L
(n)(R)(T)!P
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Calculate the density of a gas at 775 torr and 27 °C if 0.250 moles weighs 9.988 g.
m = 9.988g, n = 0.250 mol, P = 775 torr, T = 27ºC, density = ?
V, m d P, n, T, R V
V = (n)(R)(T)!P
V = 6.037 L
V = (n)(R)(T)!P
d = 9.988 g!6.037 L
= 1.65 g/L
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Calculate the molar mass of a gas with mass 0.311 g that has a volume of 0.225 L at 55°C and 886 mmHg.
m=0.311g, V=0.225 L, P=886 mmHg, T = 55 ºC, molar mass(MM) = ?
P, V, T, R n
n = (P)(V)!(R)(T)
K = 273+ºC=273+(55)=328
n, m MM
MM = m!n
886 mmHg x = 1.1658 atm 1 atm!760 mmHg
n = = (P)(V)!(R)(T)
(1.17 atm)(0.225 L)!(0.0821 )(328 K)atm L!
mol K
= 9.7754 x10-3 mol
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Calculate the molar mass of a gas with mass 0.311 g that has a volume of 0.225 L at 55°C and 886 mmHg.
m=0.311g, V=0.225 L, P=886 mmHg, T = 55 ºC, molar mass = ?
n = 9.7754 x10-3 mol
n = (P)(V)!(R)(T)
P, V, T, R n
n = (P)(V)!(R)(T)
MM = 0.311 g!9.78 x 10-3 mol
n, m MM
MM = m!nMM = m!n
MM = 31.8 g/mol
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What is the molar mass of a gas if 12.0 g occupies 197 L at 3.80 x 102 torr and 127 °C?
m=12.0 g, V= 197 L, P=380 torr, t=127°C, molar mass = ?
P, V, T, R n n, m MM
K = 273+ºC=273+(127)=400
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Find the partial pressure of neon in a mixture of neon and xenon with total pressure 3.9 atm, volume 8.7 L,
temperature 598 K, and 0.17 moles Xe.
Ptot = 3.9 atm, V = 8.7 L, T = 598 K, Xe = 0.17 mol , PNe = ?
nXe, V, T, R PXe Ptot, PXe PNe
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Find the mole fractions and partial pressures in a 12.5 L tank with 24.2 g He and 4.32 g O2 at 298 K.
mHe = 24.2 g, mO2 = 4.32 g, V = 12.5 L, T = 298 K!!χHe, χO2, PHe, PO2, Ptotal = ?????
mgas ngas χgas
χgas, Ptotal Pgas
ntot, V, T, R Ptot
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1.02 L of O2 collected over water at 293 K with a total pressure of 755.2 mmHg. Find the mass of O2.
V=1.02 L, P=755.2 mmHg, T=293 K, mass O2 = ?
Ptot, PH2O PO2 PO2,V,T nO2 gO2
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0.12 moles of H2 is collected over water in a 10.0 L container at 323 K. Find the total pressure in torr.
V=10.0 L, nH2 = 0.12 mol, T = 323 K, Ptotal = ?
nH2,V,T PH2 PH2, PH2O Ptotal
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What volume of H2 is needed to make 37.5 g of CH3OH at 738 mmHg and 355 K?
CO(g) + 2 H2(g) → CH3OH(g)
mCH3OH = 37.5g, P=738 mmHg, T=355 K , VH2 = ?
g CH3OH mol CH3OH mol H2 P, n, T, R V
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How many grams of H2O form when 1.24 L H2 reacts completely with O2 at STP?O2(g) + 2 H2(g) → 2 H2O(g)
VH2 = 1.24 L, P = 1.00 atm, T = 273 K massH2O = ?
g H2O L H2 mol H2 mol H2O
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What volume of O2 at 0.750 atm and 313 K is generated by the thermolysis of 10.0 g of HgO?2 HgO(s) → 2 Hg(l) + O2(g)
(MMHgO = 216.59 g/mol)
mHgO = 10.0g, P=0.750 atm, T=313 K VO2 = ?
g HgO mol HgO mol O2 P, n, T, R V
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Calculate the rms velocity of O2 at 25 °C
MM, T urms
√3RT MMurms=
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Calculate the ratio of rate of effusion for oxygen to hydrogen.
O2, 32.00 g/mol; H2 2.016 g/mol = ?
This means that, on average, the O2 molecules are traveling at ¼ the speed of H2 molecules.
0.251
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Calculate the molar mass of a gas that effuses at a rate 0.462 times N2.
MMgas A = ?
rateA/rateB, MMN2 MMunknown
MMN2 = 28.02 g/mol