chapter 8 – pipe flow - university of notre...

22
Chapter 8 – Pipe Flow CE30460 - Fluid Mechanics Diogo Bolster

Upload: lamhanh

Post on 30-Apr-2018

222 views

Category:

Documents


6 download

TRANSCRIPT

Chapter 8 – Pipe Flow CE30460 - Fluid Mechanics Diogo Bolster

Laminar or Turbulent Flow

Turbulent Flow http://www.youtube.com/watch?v=NplrDarMDF8

Laminar Flow http://www.youtube.com/watch?v=KqqtOb30jWs&NR=1

Re<1000

Re>4000

Re=UDρ/µ

Fully Developed Flow

Entrance length:

Fully Developed Laminar Flow

!   We’ve done this one already in chapter 6

What about Turbulent Flow

Typically: n is between 6 and 10

Dimensional Analysis

!   Pressure Drop depends on !   Mean velocity V

!   Diameter D

!   Pipe length l

!   Wall Roughness ε

!   Viscosity µ

!   Density ρ

!   By dimensional Analysis

!   Pressure drop must increase linearly with length of tube

!   Recall from chapter 5

!   Therefore we can say that (part of) the loss in a pipe is

!

"p12 #V

2=lDf Re, $

D%

& '

(

) *

Friction factor – look up in table

!

hL ,major =lDV 2

2gf Re, "

D#

$ %

&

' (

Moody Diagram (Friction Factor) The image cannot be displayed. Your computer may not have enough memory to open the image, or the image may have been corrupted. Restart your computer, and then open the file again. If the red x still appears, you may have to delete the image and then insert it again.

For non-laminar flow approximately true that

!

1f

= "1.8log#D3.7

$

%

& &

'

(

) )

1.11

+6.9Re

*

+

, ,

-

.

/ /

For laminar

!

f =64Re

Roughness (Typical) The image cannot be displayed. Your computer may not have enough memory to open the image, or the image may have been corrupted. Restart your computer, and then open the file again. If the red x still appears, you may have to delete the image and then insert it again.

Minor Losses

!

hL ,min = KLV 2

2g

KL depends on the flow (expansion, contraction, bend, etc)

Minor Losses

Minor Losses

Sample Problem

Sample Problem

Sample Problem

Pipe Flow Measurement

!

Q = CQideal = CA02 p1 " p2( )# 1" $4( ) C is a constant that depends on geometry

Sample Problem

!  More Problems

Single Pipe – Determine Pressure Drop

Single Pipe – Determine Flowrate

Single Pipe – Determine Diameter

Multiple Pipe Systems