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TRANSCRIPT
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The Practice of Statistics, 4th edition – For AP*
STARNES, YATES, MOORE
Chapter 9: Testing a Claim
Section 9.1
Significance Tests: The Basics
+ Chapter 9
Testing a Claim
9.1 Significance Tests: The Basics
9.2 Tests about a Population Proportion
9.3 Tests about a Population Mean
+ Section 9.1
Significance Tests: The Basics
After this section, you should be able to…
STATE correct hypotheses for a significance test about a population
proportion or mean.
INTERPRET P-values in context.
INTERPRET a Type I error and a Type II error in context, and give
the consequences of each.
DESCRIBE the relationship between the significance level of a test,
P(Type II error), and power.
Learning Objectives
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Introduction
Confidence intervals are one of the two most common types of
statistical inference. Use a confidence interval when your goal is
to estimate a population parameter. The second common type of
inference, called significance tests, has a different goal: to assess
the evidence provided by data about some claim concerning a
population.
A significance test is a formal procedure for comparing observed
data with a claim (also called a hypothesis) whose truth we want
to assess. The claim is a statement about a parameter, like the
population proportion p or the population mean µ. We express the
results of a significance test in terms of a probability that
measures how well the data and the claim agree.
In this chapter, we’ll learn the underlying logic of statistical tests,
how to perform tests about population proportions and population
means, and how tests are connected to confidence intervals.
+ The Reasoning of Significance Tests
Statistical tests deal with claims about a population. Tests ask if sample
data give good evidence against a claim. A test might say, “If we took
many random samples and the claim were true, we would rarely get a
result like this.” To get a numerical measure of how strong the sample evidence is, replace the vague term “rarely” by a probability.
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We can use software to simulate 400 sets of 50 shots
assuming that the player is really an 80% shooter.
The observed statistic is so unlikely if the
actual parameter value is p = 0.80 that it
gives convincing evidence that the player’s
claim is not true.
You can say how strong the evidence
against the player’s claim is by giving the
probability that he would make as few as
32 out of 50 free throws if he really makes
80% in the long run.
Suppose a basketball player claimed to be an 80% free-throw shooter.
To test this claim, we have him attempt 50 free-throws. He makes 32 of
them. His sample proportion of made shots is 32/50 = 0.64.
What can we conclude about the claim based on this sample data?
+ The Reasoning of Significance Tests
Based on the evidence, we might conclude the player’s claim is
incorrect.
In reality, there are two possible explanations for the fact that he made only 64% of his free throws.
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1) The player’s claim is correct (p = 0.8), and by bad luck, a
very unlikely outcome occurred.
2) The population proportion is actually less than 0.8, so the
sample result is not an unlikely outcome.
An outcome that would
rarely happen if a claim
were true is good evidence
that the claim is not true.
Basic Idea
+ Alternate Example – Can you be confident of victory?
Heading into the mayoral election, Jack is feeling fairly confident that he will be
elected by obtaining more than 50% of the vote. Suppose that a random
sample of 100 voters shows that 56 will vote for Jack. Is his confidence
warranted? Maybe. There are actually two possible explanations for why the
majority of voters in the sample seem to favor Jack.
At most 50% of the voters actually support Jack and the favorable sample
proportion was due to sampling variability. If this explanation is plausible, then
Jack should not be confident of victory.
The sample proportion is above 50% because more than 50% of the voters
actually support Jack. Jack should only believe this explanation and be
confident of victory if explanation #1 can safely be ruled out.
We used Fathom software to simulate 400 samples of size 100 from a
population in which exactly 50% of voters support Jack. Each dot represents
the proportion of voters who prefer Jack in the simulated sample.
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SampleProportion
0.30 0.35 0.40 0.45 0.50 0.55 0.60 0.65 0.70
Collection 1 Dot Plot
In 13.75% of the simulated samples (marked in
red), the sample proportion of voters who
supported Jack was at least 0.56. This means
that it is plausible that at most 50% of the
voters prefer Jack and the favorable sample proportion was due to sampling variability. Since it is plausible that the majority of
voters do not favor Jack, he should not be confident of victory.
+ Stating Hypotheses
A significance test starts with a careful statement of the claims we want to
compare. The first claim is called the null hypothesis. Usually, the null
hypothesis is a statement of “no difference.” The claim we hope or
suspect to be true instead of the null hypothesis is called the alternative
hypothesis.
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Definition:
The claim tested by a statistical test is called the null hypothesis (H0).
The test is designed to assess the strength of the evidence against the
null hypothesis. Often the null hypothesis is a statement of “no
difference.”
The claim about the population that we are trying to find evidence for is the alternative hypothesis (Ha).
In the free-throw shooter example, our hypotheses are
H0 : p = 0.80
Ha : p < 0.80
where p is the long-run proportion of made free throws.
+ Stating Hypotheses
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Definition:
The alternative hypothesis is one-sided if it states that a parameter is
larger than the null hypothesis value or if it states that the parameter is
smaller than the null value.
It is two-sided if it states that the parameter is different from the null hypothesis value (it could be either larger or smaller).
Hypotheses always refer to a population, not to a sample. Be sure
to state H0 and Ha in terms of population parameters.
It is never correct to write a hypothesis about a sample statistic,
such as
ˆ p 0.64 or x 85.
In any significance test, the null hypothesis has the form
H0 : parameter = value
The alternative hypothesis has one of the forms
Ha : parameter < value
Ha : parameter > value
Ha : parameter ≠ value
To determine the correct form of Ha, read the problem carefully.
+ Example: Studying Job Satisfaction
Does the job satisfaction of assembly-line workers differ when their work is machine-
paced rather than self-paced? One study chose 18 subjects at random from a
company with over 200 workers who assembled electronic devices. Half of the
workers were assigned at random to each of two groups. Both groups did similar
assembly work, but one group was allowed to pace themselves while the other
group used an assembly line that moved at a fixed pace. After two weeks, all the
workers took a test of job satisfaction. Then they switched work setups and took
the test again after two more weeks. The response variable is the difference in
satisfaction scores, self-paced minus machine-paced.
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a) Describe the parameter of interest in this setting.
b) State appropriate hypotheses for performing a significance test.
The parameter of interest is the mean µ of the differences (self-paced
minus machine-paced) in job satisfaction scores in the population of all
assembly-line workers at this company.
Because the initial question asked whether job satisfaction differs, the
alternative hypothesis is two-sided; that is, either µ < 0 or µ > 0. For
simplicity, we write this as µ ≠ 0. That is,
H0: µ = 0
Ha: µ ≠ 0
+ Alternate Example – A better golf club?
Mike is an avid golfer who would like to improve his play. A friend suggests
getting new clubs and lets Mike try out his 7-iron. Based on years of
experience, Mike has established that the mean distance that balls travel when
hit with his old 7-iron is = 175 yards with a standard deviation of = 15 yards.
He is hoping that this new club will make his shots with a 7-iron more
consistent (less variable), so he goes to the driving range and hits 50 shots
with the new 7-iron.
Problem:
(a) Describe the parameter of interest in this setting.
Mike is interested in being more consistent, the parameter of interest is the
standard deviation of the distance he hits the ball when using the new 7-iron.
(b) State appropriate hypotheses for performing a significance test.
Because Mike wants to be more consistent, he wants the standard deviation of
the distance he hits the ball to be smaller than 15 yards.
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15:
15:0
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+ Interpreting P-Values
The null hypothesis H0 states the claim that we are seeking evidence
against. The probability that measures the strength of the evidence
against a null hypothesis is called a P-value.
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Definition:
The probability, computed assuming H0 is true, that the statistic would
take a value as extreme as or more extreme than the one actually
observed is called the P-value of the test. The smaller the P-value, the stronger the evidence against H0 provided by the data.
Small P-values are evidence against H0 because they say that the
observed result is unlikely to occur when H0 is true.
Large P-values fail to give convincing evidence against H0 because
they say that the observed result is likely to occur by chance when H0
is true.
+
Alternate Example – Can you be confident of
victory
In the alternate example on page 530, when we
assumed that exactly 50% of voters supported Jack,
13.75% of the 400 simulated samples gave values of at
least as high as the observed value of = 0.56. In
other words, the P-value is P( ≥ 0.56 | p = 0.5) ≈
0.1375. So, if exactly 50% of the voters in the
population support Jack, there is about a 14% chance
that in a sample of 100 voters, 56% or more would
support Jack. This is not a small probability, so this
does not provide convincing evidence to support the
alternative hypothesis that p > 0.5.
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p̂p̂
+ Example: Studying Job Satisfaction
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a) Explain what it means for the null hypothesis to be true in this setting.
b) Interpret the P-value in context.
In this setting, H0: µ = 0 says that the mean difference in satisfaction
scores (self-paced - machine-paced) for the entire population of
assembly-line workers at the company is 0. If H0 is true, then the workers
don’t favor one work environment over the other, on average.
For the job satisfaction study, the hypotheses are
H0: µ = 0
Ha: µ ≠ 0
Data from the 18 workers gave x 17 and sx 60. That is, these workers rated the
self -paced environment, on average, 17 points higher. Researchers performed a
significance test using the sample data and found a P - value of 0.2302.
The P-value is the probability of observing a sample result as extreme or more
extreme in the direction specified by Ha just by chance when H0 is actually true.
Because the alternative hypothesis is two- sided, the P - value is the probability of
getting a value of x as far from 0 in either direction as the observed x 17 when
H0 is true. That is, an average difference of 17 or more points between the two
work environments would happen 23% of the time just by chance in random
samples of 18 assembly- line workers when the true population mean is = 0.
An outcome that would occur so often just by chance
(almost 1 in every 4 random samples of 18 workers) when
H0 is true is not convincing evidence against H0.
We fail to reject H0: µ = 0.
+ Alternate Example: A better golf club?
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When Mike was testing a new 7-iron, the hypotheses were:
Where σ = the true standard deviation of the distances Mike hits golf balls using the
new 7-iron. Based on 50 shots with the new 7-iron, the standard deviation was
SX = 10.9 yards.
Problem: A significance test using the sample data produced a P-value of 0.002.
(a) Interpret the P-value in this context.
If the true standard deviation is 15 yards, then there is an approximate
probability of 0.002 that the sample standard deviation would be 10.9 yards or
lower because of random chance alone.
(b) Do the data provide convincing evidence against the null hypothesis?
Explain.
Yes. Since the P-value is very small, random chance is not a plausible
explanation for why the sample standard deviation was lower than 15 yards.
Thus, there is convincing evidence that the true standard deviation with the new
7-iron is smaller.
15:
15:0
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+ Statistical Significance
The final step in performing a significance test is to draw a conclusion
about the competing claims you were testing. We will make one of two
decisions based on the strength of the evidence against the null
hypothesis (and in favor of the alternative hypothesis) -- reject H0 or fail
to reject H0.
If our sample result is too unlikely to have happened by chance
assuming H0 is true, then we’ll reject H0.
Otherwise, we will fail to reject H0.
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Note: A fail-to-reject H0 decision in a significance test doesn’t mean
that H0 is true. For that reason, you should never “accept H0” or use
language implying that you believe H0 is true.
In a nutshell, our conclusion in a significance test comes down to
P-value small → reject H0 → conclude Ha (in context)
P-value large → fail to reject H0 → cannot conclude Ha (in context)
+
Alternate Example – Elections and golf clubs
In the mayoral election example, the estimated P-value
was 0.1375. Since the P-value is large, we fail to reject
H0 : p = 0.5 and cannot conclude that more than 50% of
all voters favor Jack.
In the 7-iron example, the estimated P-value was 0.002.
Since the P-value is small, we reject H0 : = 15 and
conclude that Mike is more consistent when using the
new 7-iron (i.e. the true standard deviation of distances
when using the new 7-iron is less than 15 yards).
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+ Statistical Significance
There is no rule for how small a P-value we should require in order to reject
H0 — it’s a matter of judgment and depends on the specific
circumstances. But we can compare the P-value with a fixed value that we regard as decisive, called the significance level. We write it as α,
the Greek letter alpha. When our P-value is less than the chosen α, we
say that the result is statistically significant.
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Definition:
If the P-value is smaller than alpha, we say that the data are statistically significant at level α. In that case, we reject the null
hypothesis H0 and conclude that there is convincing evidence in favor of the alternative hypothesis Ha.
When we use a fixed level of significance to draw a conclusion in a
significance test,
P-value < α → reject H0 → conclude Ha (in context)
P-value ≥ α → fail to reject H0 → cannot conclude Ha (in context)
+ Example: Better Batteries
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a) What conclusion can you make for the significance level α = 0.05?
b) What conclusion can you make for the significance level α = 0.01?
Since the P-value, 0.0276, is less than α = 0.05, the sample result is
statistically significant at the 5% level. We have sufficient evidence to
reject H0 and conclude that the company’s deluxe AAA batteries last
longer than 30 hours, on average.
A company has developed a new deluxe AAA battery that is supposed to last longer
than its regular AAA battery. However, these new batteries are more expensive to
produce, so the company would like to be convinced that they really do last longer.
Based on years of experience, the company knows that its regular AAA batteries last
for 30 hours of continuous use, on average. The company selects an SRS of 15 new
batteries and uses them continuously until they are completely drained. A significance
test is performed using the hypotheses
H0 : µ = 30 hours
Ha : µ > 30 hours
where µ is the true mean lifetime of the new deluxe AAA batteries. The resulting P-
value is 0.0276.
Since the P-value, 0.0276, is greater than α = 0.01, the sample result is
not statistically significant at the 1% level. We do not have enough
evidence to reject H0 in this case. therefore, we cannot conclude that the
deluxe AAA batteries last longer than 30 hours, on average.
+ Alternate Example: Tasty chips
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a) What conclusion would you make for the significance level α = 0.01?
b) What conclusion can you make for the significance level α = 0.001?
Since the P-value is less than σ (0.0055 < 0.01), we reject H0 and
conclude that students at Zenon’s school prefer name-brand chips.
For his second semester project in AP Statistics, Zenon decided to
investigate if students at his school prefer name-brand potato chips to
generic potato chips. He randomly selected 50 students and had each
student try both types of chips, in random order. Overall, 34 of the 50
students preferred the name-brand chips. Zenon performed a significance
test using the hypotheses:
H0 : p = 0.5
Ha : p > 0.5
Where p is the true proportion of students at his school that prefer name-
brand chips. The resulting P-value was 0.0055.
Since the P-value is greater than σ (0.0055 > 0.001), we fail to reject H0
and cannot conclude that students at Zenon’s school prefer name-brand
chips.
+ Type I and Type II Errors
When we draw a conclusion from a significance test, we hope our
conclusion will be correct. But sometimes it will be wrong. There are two
types of mistakes we can make. We can reject the null hypothesis when
it’s actually true, known as a Type I error, or we can fail to reject a false
null hypothesis, which is a Type II error.
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Definition:
If we reject H0 when H0 is true, we have committed a Type I error.
If we fail to reject H0 when H0 is false, we have committed a Type II error.
Truth about the population
H0 true H0 false
(Ha true)
Conclusion
based on
sample
Reject H0 Type I error Correct
conclusion
Fail to reject
H0
Correct
conclusion Type II error
+ Example: Perfect Potatoes
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Describe a Type I and a Type II error in this setting, and explain the
consequences of each.
• A Type I error would occur if the producer concludes that the proportion of
potatoes with blemishes is greater than 0.08 when the actual proportion is
0.08 (or less). Consequence: The potato-chip producer sends the truckload
of acceptable potatoes away, which may result in lost revenue for the
supplier.
• A Type II error would occur if the producer does not send the truck away
when more than 8% of the potatoes in the shipment have blemishes.
Consequence: The producer uses the truckload of potatoes to make potato
chips. More chips will be made with blemished potatoes, which may upset
consumers.
A potato chip producer and its main supplier agree that each shipment of potatoes
must meet certain quality standards. If the producer determines that more than 8% of
the potatoes in the shipment have “blemishes,” the truck will be sent away to get
another load of potatoes from the supplier. Otherwise, the entire truckload will be
used to make potato chips. To make the decision, a supervisor will inspect a random
sample of potatoes from the shipment. The producer will then perform a significance
test using the hypotheses
H0 : p = 0.08
Ha : p > 0.08
where p is the actual proportion of potatoes with blemishes in a given truckload.
+
Alternate Example: Faster fast food? S
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Describe a Type I and a Type II error in this setting, and explain the
consequences of each.
• A Type I error would occur if the manager decides that the true proportion of
drive-through customers that have to wait at least 2 minutes has been
reduced, when it really hasn’t been reduced. A consequence is that the
manager will have to pay unnecessarily for an additional employee.
• A Type II error would occur if the manager didn’t decide that the true
proportion of customers that had to wait at least 2 minutes had been reduced,
when it really had been reduced. A consequence is that the restaurant would
not have an additional employee helping with the drive-through, so they aren’t
providing faster service when they could.
The manager of a fast-food restaurant want to reduce the proportion of drive-through
customers who have to wait more than 2 minutes to receive their food once their
order is placed. Based on store records, the proportion of customers who had to wait
at least 2 minutes was p = 0.63. To reduce this proportion, the manager assigns an
additional employee to assist with drive-through orders. During the next month the
manager will collect a random sample of drive-through times and test the following
hypotheses:
H0 : p = 0.63
Ha : p < 0.63
where p is the true proportion of drive-through customers who have to wait more than
2 minutes after their order is placed to receive their food.
+ Error Probabilities
We can assess the performance of a significance test by looking at the
probabilities of the two types of error. That’s because statistical inference
is based on asking, “What would happen if I did this many times?”
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For the truckload of potatoes in the previous example, we were testing
H0 : p = 0.08
Ha : p > 0.08
where p is the actual proportion of potatoes with blemishes. Suppose that the
potato-chip producer decides to carry out this test based on a random sample of
500 potatoes using a 5% significance level (α = 0.05).
Assuming H0 : p 0.08 is true, the sampling distribution of ̂ p will have :
Shape : Approximately Normal because 500(0.08)= 40 and
500(0.92)= 460 are both at least 10.
Center : ̂p p 0.08
Spread: ̂p p(1 p)
n0.08(0.92)
500 0.0121
The shaded area in the right tail is 5%.
Sample proportion values to the right of
the green line at 0.0999 will cause us to
reject H0 even though H0 is true. This will
happen in 5% of all possible samples.
That is, P(making a Type I error) = 0.05.
+ Alternate Example – Faster fast food?
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For the fast food alternate example, we were testing the following hypotheses:
H0 : p = 0..63
Ha : p < 0.63
where p = the true proportion of drive-through customers who have to wait
more than 2 minutes after their order is placed to receive their food. Suppose
that the manager decided to carry out this test using a random sample of 250
orders and a significance level of σ = 0.10. What is the probability of a
making a Type I error?
p
P(Type I error) =α = 0.10
0.63
Values of
Reject Ho Fail to Reject H0
To make a Type I error means
that we reject H0 when H0 is
actually true. In this case, a Type
I error occurs when the true
proportion of customers that
have to wait at least 2 minutes
remains p = 0.63, but we get a
value of small enough that the
P-value is less than 0.10. When
H0 is true, this will happen 10%
of the time. In other words,
P(Type I error) = σ. p
+ Error Probabilities
The probability of a Type I error is the probability of rejecting H0 when it is
really true. As we can see from the previous example, this is exactly the
significance level of the test.
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The significance level α of any fixed level test is the probability of a Type I
error. That is, α is the probability that the test will reject the null
hypothesis H0 when H0 is in fact true. Consider the consequences of a
Type I error before choosing a significance level.
Significance and Type I Error
What about Type II errors? A significance test makes a Type II error when it
fails to reject a null hypothesis that really is false. There are many values of
the parameter that satisfy the alternative hypothesis, so we concentrate on
one value. We can calculate the probability that a test does reject H0 when
an alternative is true. This probability is called the power of the test against
that specific alternative.
Definition:
The power of a test against a specific alternative is the probability that
the test will reject H0 at a chosen significance level α when the specified alternative value of the parameter is true.
+ Error Probabilities
The potato-chip producer wonders whether the significance test of H0 : p = 0.08
versus Ha : p > 0.08 based on a random sample of 500 potatoes has enough
power to detect a shipment with, say, 11% blemished potatoes. In this case, a
particular Type II error is to fail to reject H0 : p = 0.08 when p = 0.11.
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Earlier, we decided to reject
H0 at α = 0.05 if our sample
yielded a sample proportion
to the right of the green line.
What if p = 0.11?
Since we reject H0 at α= 0.05
if our sample yields a
proportion > 0.0999, we’d
correctly reject the shipment
about 75% of the time.
The power of a test against any alternative is
1 minus the probability of a Type II error
for that alternative; that is, power = 1 - β.
Power and Type II Error
( ˆ p 0.0999)
+ Planning Studies: The Power of a Statistical Test
How large a sample should we take when we plan to carry out a
significance test? The answer depends on what alternative values of the
parameter are important to detect.
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Here are the questions we must answer to decide how many
observations we need:
1.Significance level. How much protection do we want against a
Type I error — getting a significant result from our sample when
H0 is actually true?
2.Practical importance. How large a difference between the
hypothesized parameter value and the actual parameter value
is important in practice?
3.Power. How confident do we want to be that our study will
detect a difference of the size we think is important?
Summary of influences on the question “How many
observations do I need?”
•If you insist on a smaller significance level (such as 1% rather
than 5%), you have to take a larger sample. A smaller
significance level requires stronger evidence to reject the null
hypothesis.
• If you insist on higher power (such as 99% rather than 90%),
you will need a larger sample. Higher power gives a better
chance of detecting a difference when it is really there.
• At any significance level and desired power, detecting a small
difference requires a larger sample than detecting a large
difference.
+ Section 9.1
Significance Tests: The Basics
In this section, we learned that…
A significance test assesses the evidence provided by data against a null hypothesis H0 in favor of an alternative hypothesis Ha.
The hypotheses are stated in terms of population parameters. Often, H0 is a statement of no change or no difference. Ha says that a parameter differs from its null hypothesis value in a specific direction (one-sided alternative) or in either direction (two-sided alternative).
The reasoning of a significance test is as follows. Suppose that the null hypothesis is true. If we repeated our data production many times, would we often get data as inconsistent with H0 as the data we actually have? If the data are unlikely when H0 is true, they provide evidence against H0 .
The P-value of a test is the probability, computed supposing H0 to be true, that the statistic will take a value at least as extreme as that actually observed in the direction specified by Ha .
Summary
+ Section 9.1
Significance Tests: The Basics
Small P-values indicate strong evidence against H0 . To calculate a P-value,
we must know the sampling distribution of the test statistic when H0 is true.
There is no universal rule for how small a P-value in a significance test
provides convincing evidence against the null hypothesis.
If the P-value is smaller than a specified value α (called the significance
level), the data are statistically significant at level α. In that case, we can
reject H0 . If the P-value is greater than or equal to α, we fail to reject H0 .
A Type I error occurs if we reject H0 when it is in fact true. A Type II error
occurs if we fail to reject H0 when it is actually false. In a fixed level α
significance test, the probability of a Type I error is the significance level α.
The power of a significance test against a specific alternative is the
probability that the test will reject H0 when the alternative is true. Power
measures the ability of the test to detect an alternative value of the
parameter. For a specific alternative, P(Type II error) = 1 - power.
Summary
+ Looking Ahead…
We’ll learn how to test a claim about a population proportion.
We’ll learn about
Carrying out a significance test
The one-sample z test for a proportion
Two-sided tests
Why confidence intervals give more information
than significance tests
In the next Section…