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    Chapter 2Introduction to Probability

    Experiments and the Sample Space Assigning Probabilities to

    Experimental Outcomes

    Events and Their Probability

    Some Basic Relationshipsof Probability

    Bayes Theorem

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    Probability as a Numerical Measureof the Likelihood of Occurrence

    0 1.5

    Increasing Likelihood of Occurrence

    Probability:

    The event

    is very

    unlikelyto occur.

    The occurrence

    of the event is

    just as likely asit is unlikely.

    The event

    is almost

    certainto occur.

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    Assigning Probabilities

    Classical Method

    Relative Frequency Method

    Subjective Method

    Assigning probabilities based on the assumptionof equally likely outcomes

    Assigning probabilities based on experimentationor historical data

    Assigning probabilities based on judgment

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    Events and Their Probabilities

    An experimentis any process that generateswell-defined outcomes.

    The sample space for an experiment is the set ofall sample points.

    An experimental outcome is also called a sample

    point.

    An event is a collection of particular sample points.

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    Classical Method

    If an experiment has npossible outcomes, this method

    would assign a probability of 1/nto each outcome.

    Experiment: Rolling a dieSample Space: S= {1, 2, 3, 4, 5, 6}

    Probabilities: Each sample point has a

    1/6 chance of occurring

    Example

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    Example: Lucas Tool Rental

    Relative Frequency Method

    Lucas Tool Rental would like to

    assign probabilities to the number of car

    polishers it rents each day. Office records show the

    following frequencies of daily rentals for the last40 days.

    Number ofPolishers Rented

    Numberof Days

    0

    1234

    4

    618102

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    Each probability assignment is given by

    dividing the frequency (number of days) bythe total frequency (total number of days).

    Relative Frequency Method

    4/40

    Probability

    Number of

    Polishers Rented

    Number

    of Days012

    34

    46

    18

    10240

    .10

    .15

    .45

    .25.051.00

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    Subjective Method

    When economic conditions and a companys

    circumstances change rapidly it might beinappropriate to assign probabilities based solely onhistorical data.

    We can use any data available as well as our

    experience and intuition, but ultimately a probabilityvalue should express our degree of belief that theexperimental outcome will occur.

    The best probability estimates often are obtained by

    combining the estimates from the classical or relativefrequency approach with the subjective estimate.

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    Example: Bradley Investments

    Bradley has invested in two stocks, Markley Oil and

    Collins Mining. Bradley has determined that thepossible outcomes of these investments three months

    from now are as follows.

    Investment Gain or Lossin 3 Months (in $000)

    Markley Oil Collins Mining

    10

    50

    -20

    8

    -2

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    Applying the subjective method, an analyst

    made the following probability assignments.

    Exper. Outcome Net Gain orLoss Probability

    (10, 8)

    (10, -2)(5, 8)

    (5, -2)

    (0, 8)

    (0, -2)(-20, 8)

    (-20, -2)

    $18,000 Gain

    $8,000 Gain$13,000 Gain

    $3,000 Gain

    $8,000 Gain

    $2,000 Loss$12,000 Loss

    $22,000 Loss

    .20

    .08

    .16

    .26

    .10

    .12

    .02

    .06

    Example: Bradley Investments

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    Events and Their Probabilities

    EventM= Markley Oil ProfitableM= {(10, 8), (10, -2), (5, 8), (5, -2)}

    P(M) = P(10, 8) + P(10, -2) + P(5, 8) + P(5, -2)

    = .20 + .08 + .16 + .26

    = .70

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    Events and Their Probabilities

    Event C= Collins Mining ProfitableC= {(10, 8), (5, 8), (0, 8), (-20, 8)}

    P(C) = P(10, 8) + P(5, 8) + P(0, 8) + P(-20, 8)

    = .20 + .16 + .10 + .02

    = .48

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    Some Basic Relationships of Probability

    There are some basic probability relationships that

    can be used to compute the probability of an eventwithout knowledge of all the sample point probabilities.

    Complement of an Event

    Intersection of Two Events

    Mutually Exclusive Events

    Union of Two Events

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    The complement ofAis denoted byAc.

    The complement of eventA is defined to be the eventconsisting of all sample points that are not inA.

    Complement of an Event

    EventA AcSampleSpace S

    VennDiagram

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    The union of eventsAand Bis denoted byA B

    The union of eventsAand Bis the event containingall sample points that are inA orB or both.

    Union of Two Events

    SampleSpace SEventA Event B

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    Union of Two Events

    EventM= Markley Oil ProfitableEvent C= Collins Mining Profitable

    M C= Markley Oil Profitable

    or Collins Mining Profitable

    M C= {(10, 8), (10, -2), (5, 8), (5, -2), (0, 8), (-20, 8)}

    P(M C)=P(10, 8) + P(10, -2) + P(5, 8) + P(5, -2)

    + P(0, 8) + P(-20, 8)

    = .20 + .08 + .16 + .26 + .10 + .02= .82

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    The intersection of eventsAand Bis denoted byA

    The intersection of eventsAand Bis the set of allsample points that are in bothA and B.

    SampleSpace SEventA Event B

    Intersection of Two Events

    Intersection ofAand B

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    Intersection of Two Events

    EventM= Markley Oil ProfitableEvent C= Collins Mining Profitable

    M C = Markley Oil Profitable

    and Collins Mining Profitable

    M C= {(10, 8), (5, 8)}

    P(M C)=P(10, 8) + P(5, 8)

    = .20 + .16

    = .36

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    The addition law provides a way to compute theprobability of eventA,or B,or bothAand B occurring.

    Addition Law

    The law is written as:

    P(A B) = P(A) + P(B) -P(AB

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    EventM= Markley Oil ProfitableEvent C= Collins Mining Profitable

    M C= Markley Oil Profitable

    or Collins Mining Profitable

    We know: P(M) = .70, P(C) = .48, P(M C) = .36

    Thus: P(MC) = P(M) + P(C) -P(MC)

    = .70 + .48 -.36

    = .82

    Addition Law

    (This result is the same as that obtained earlier

    using the definition of the probability of an event.)

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    Mutually Exclusive Events

    Two events are said to be mutually exclusive if theevents have no sample points in common.

    Two events are mutually exclusive if, when one eventoccurs, the other cannot occur.

    SampleSpace S

    EventA Event B

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    Mutually Exclusive Events

    If eventsAand Bare mutually exclusive, P(AB= 0.

    The addition law for mutually exclusive events is:

    P(A B) = P(A) + P(B)

    There is no need toinclude -P(AB

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    The probability of an event given that another eventhas occurred is called a conditional probability.

    A conditional probability is computed as follows :

    The conditional probability ofAgiven Bis denoted

    by P(A|B).

    Conditional Probability

    ( )

    ( | ) ( )

    P A BP A B

    P B

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    EventM= Markley Oil ProfitableEvent C= Collins Mining Profitable

    We know: P(M C) = .36, P(M) = .70

    Thus:

    Conditional Probability

    ( ) .36( | ) .5143

    ( ) .70

    P C MP C M

    P M

    = Collins Mining Profitable

    given Markley Oil Profitable

    ( | )P C M

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    Multiplication Law

    The multiplication law provides a way to compute theprobability of the intersection of two events.

    The law is written as:

    P(A B) = P(B)P(A|B)

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    EventM= Markley Oil ProfitableEvent C= Collins Mining Profitable

    We know: P(M) = .70, P(C|M) = .5143

    Multiplication Law

    M C = Markley Oil Profitable

    and Collins Mining Profitable

    Thus: P(MC) = P(M)P(M|C)

    = (.70)(.5143)

    = .36(This result is the same as that obtained earlier

    using the definition of the probability of an event.)

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    Independent Events

    If the probability of eventAis not changed by theexistence of event B, we would say that eventsAand Bare independent.

    Two eventsAand Bare independent if:

    P(A|B) = P(A) P(B|A) = P(B)or

    l l

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    The multiplication law also can be used as a test to seeif two events are independent.

    The law is written as:

    P(A B) = P(A)P(B)

    Multiplication Lawfor Independent Events

    M l i li i L

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    Multiplication Lawfor Independent Events

    EventM= Markley Oil ProfitableEvent C= Collins Mining Profitable

    We know: P(MC) = .36, P(M) = .70, P(C) = .48

    But: P(M)P(C) = (.70)(.48) = .34, not .36

    Are eventsMand Cindependent?

    DoesP(MC) = P(M)P(C) ?

    Hence: Mand Care not independent.

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    Bayes Theorem

    NewInformation

    Applicationof BayesTheorem

    PosteriorProbabilities

    PriorProbabilities

    Often we begin probability analysis with initial or

    prior probabilities.

    Then, from a sample, special report, or a producttest we obtain some additional information.

    Given this information, we calculate revised orposterior probabilities.

    Bayes theoremprovides the means for revising theprior probabilities.

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    A proposed shopping center

    will provide strong competitionfor downtown businesses like

    L. S. Clothiers. If the shopping

    center is built, the owner of

    L. S. Clothiers feels it would be bestto relocate to the center.

    The shopping center cannot be built unless a

    zoning change is approved by the town council. The

    planning board must first make a recommendation, foror against the zoning change, to the council.

    Example: L. S. Clothiers

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    Prior ProbabilitiesLet:

    Bayes Theorem

    A1= town council approves the zoning change

    A2= town council disapproves the change

    P(A1) = .7, P(A2) = .3

    Using subjective judgment:

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    New Information

    The planning board has recommended against thezoning change. Let Bdenote the event of a negativerecommendation by the planning board.

    Given that Bhas occurred, should L. S. Clothiers

    revise the probabilities that the town council willapprove or disapprove the zoning change?

    Bayes Theorem

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    Conditional Probabilities

    Past history with the planning board and thetown council indicates the following:

    Bayes Theorem

    P(B|A1) = .2 P(B|A2) = .9

    P(BC|A1) = .8 P(BC|A2) = .1Hence:

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    P(Bc|A1) = .8P(A1) = .7

    P(A2) = .3

    P(B|A2) = .9

    P(Bc|A2) = .1

    P(B|A1) = .2 P(A1B) = .14

    P(A2B) = .27

    P(A2Bc) = .03

    P(A1Bc) = .56

    Bayes Theorem

    Tree Diagram

    Town Council Planning Board ExperimentalOutcomes

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    Bayes Theorem

    1 1 2 2

    ( ) ( | )( | )

    ( ) ( | ) ( ) ( | ) ... ( ) ( | )

    i i

    i

    n n

    P A P B AP A B

    P A P B A P A P B A P A P B A

    To find the posterior probability that eventAiwill

    occur given that eventB has occurred, we applyBayes theorem.

    Bayes theorem is applicable when the events forwhich we want to compute posterior probabilitiesare mutually exclusive and their union is the entiresample space.

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    Posterior Probabilities

    Given the planning boards recommendation notto approve the zoning change, we revise the priorprobabilities as follows:

    1 11

    1 1 2 2( ) ( | )( | ) ( ) ( | ) ( ) ( | )

    P A P B AP A B

    P A P B A P A P B A

    (. )(. )

    (. )(. ) (. )(. )

    7 2

    7 2 3 9

    Bayes Theorem

    = .34

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    Conclusion

    The planning boards recommendation is goodnews for L. S. Clothiers. The posterior probability ofthe town council approving the zoning change is .34compared to a prior probability of .70.

    Bayes Theorem

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    Tabular Approach

    Step 1

    Prepare the following three columns:

    Column 1 - The mutually exclusive events for whichposterior probabilities are desired.

    Column 2-

    The prior probabilities for the events.Column 3 - The conditional probabilities of the newinformationgiveneach event.

    b l h

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    Tabular Approach

    (1) (2) (3) (4) (5)

    Events

    Ai

    Prior

    Probabilities

    P(Ai)

    Conditional

    Probabilities

    P(B|Ai)

    A1

    A2

    .7

    .3

    1.0

    .2

    .9

    b l A h

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    Tabular Approach

    Step 2

    Column 4

    Compute the joint probabilities for each event andthe new information Bby using the multiplicationlaw.

    Multiply the prior probabilities in column 2 by thecorresponding conditional probabilities in column 3.That is, P(AiIB) = P(Ai) P(B|Ai).

    T b l A h

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    Tabular Approach

    (1) (2) (3) (4) (5)

    Events

    Ai

    Prior

    Probabilities

    P(Ai)

    Conditional

    Probabilities

    P(B|Ai)

    A1

    A2

    .7

    .3

    1.0

    .2

    .9

    .14

    .27

    Joint

    Probabilities

    P(AiIB)

    .7 x .2

    T b l A h

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    Tabular Approach

    Step 2 (continued)

    We see that there is a .14 probability of the towncouncil approving the zoning change and a negativerecommendation by the planning board.

    There is a .27 probability of the town council

    disapproving the zoning change and a negativerecommendation by the planning board.

    T b l A h

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    Tabular Approach

    Step 3

    Column 4Sum the joint probabilities. The sum is the

    probability of the new information, P(B). The sum

    .14 + .27 shows an overall probability of .41 of a

    negative recommendation by the planning board.

    T b l A h

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    Tabular Approach

    (1) (2) (3) (4) (5)

    Events

    Ai

    Prior

    Probabilities

    P(Ai)

    Conditional

    Probabilities

    P(B|Ai)

    A1

    A2

    .7

    .3

    1.0

    .2

    .9

    .14

    .27

    Joint

    Probabilities

    P(Ai

    IB)

    P(B) = .41

    T b l A h

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    Step 4

    Column 5Compute the posterior probabilities using the basic

    relationship of conditional probability.

    The joint probabilities P(AiIB) are in column 4 and

    the probability P(B) is the sum of column 4.

    Tabular Approach

    )()()|(

    BP

    BAPBAP i

    i

    T b l A h

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    (1) (2) (3) (4) (5)

    Events

    Ai

    Prior

    Probabilities

    P(Ai)

    Conditional

    Probabilities

    P(B|Ai)

    A1

    A2

    .7

    .3

    1.0

    .2

    .9

    .14

    .27

    Joint

    Probabilities

    P(Ai

    IB)

    P(B) = .41

    Tabular Approach

    .14/.41

    Posterior

    Probabilities

    P(Ai|B)

    .3415

    .6585

    1.0000

    Using Excel to Compute

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    Formula Worksheet

    A B C D E

    2 A1 0.7 0.2 =B2*C2 =D2/$D$4

    3 A2 0.3 0.9 =B3*C3 =D3/$D$4

    4 =SUM(B2:B3) =SUM(D2:D3) =SUM(E2:E3)

    5

    Posterior

    Probabilities1 Events

    Prior

    Probabilities

    Conditional

    Probabilities

    Joint

    Probabilities

    Using Excel to ComputePosterior Probabilities

    Using Excel to Compute

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    Value Worksheet

    A B C D E

    2 A1 0.7 0.2 0.14 0.3415

    3 A2 0.3 0.9 0.27 0.6585

    4 1.0 0.41 1.0000

    5

    Posterior

    Probabilities1 Events

    Prior

    Probabilities

    Conditional

    Probabilities

    Joint

    Probabilities

    Using Excel to ComputePosterior Probabilities

    E d f Ch t 2

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    End of Chapter 2