chapter_5 heat exchanger
DESCRIPTION
Heat TransferTRANSCRIPT
BKF2422 HEAT TRANSFERBKF2422 HEAT TRANSFERCHAPTER 5CHAPTER 5
HEAT EXCHANGERHEAT EXCHANGER
Shell and tube exchangerShell inlet
Shell outlet
Tube inlet
Tube outlet
Shell inlet
Tube inlet
Tube outlet
Shell outlet
Cross-flow heat exchanger
2
1
21
lnT
T
TTTlm
flow, (parallel)cocurrent in or
flowrent countercur in true areexchanger heat ain fluids cold andhot When the
wcounterfloor parallelin pass tube1 and pass
shell 1with exchanger 1-1 andexchanger heat pipe-double afor holds This lmT
cihi
cico
TT
TTY
cico
hohi
TT
TTZ
:follows as used are ratios essdimensionl Two
drop. raturemean tempe true
thecalculate toused factor correction theexchanger,heat pass-multipleFor TF
Tlmm FTT
ciho
cohi
cihocohilm
TT
TT
TTTTT
ln
EXAMPLE 4.9-1 Temperature Correction Factor for a Heat Exchanger
A 1-2 heat exchanger containing one shell pass and two tubes passes heats 5.52 kg/s of water from 21.1 to 54.4oC by using hot water under pressure entering at 115.6 and leaving at 48.9oC. The outside surface area of the tubes in the exchanger is Ao = 9.30 m2
a) Calculate the mean temperature difference ΔTm in the exchanger and the overall heat-transfer coefficient Uo
b) For the same temperature but using 1 2-4 exchanger, what would be the ΔTm
1T
2T
hiTC 15.61 o
C 9.48 ohoT
C 1.21 ociT
coTC 4.54 o
hot water
kJ/kg.K 187.4waterpc
ExchangerHeat 21(a)
352.01.216.115
1.214.54
cihi
cico
TT
TTY
00.21.214.54
9.486.115
cico
hohi
TT
TTZ
K 3.42
1.219.484.546.115
ln
1.219.484.546.115
ln2
1
21
TT
TTTlm
K 31.3C 31.3
)74.0(3.42 o
Tlmm FTT
0.74 4a,-4.9 Fig theFrom TF
(b) ExchangerHeat 42
W348200
)1.214.54)(4187(52.2
cicopm TTcmq
.K W/m1196)3.31(30.9
348200 2
mo
o TA
qU
94.0 4b,-4.9 Fig theFrom TF
K 39.8C 39.8
)94.0(3.42 o
Tlmm FTT
max
fluid min
maxferheat trans possiblemax
ferheat trans actual
T
T
q
qactual
maxminminminmax TCTTCTTcmq ichiichip
ichipactual TTcmq min
minmin where pcmC
,
min
having fluid = fluidmin pcm
EXAMPLE 4.9-2 Effectiveness of Heat Exchanger
Water flowing at rate of 0.667 kg/s enters a countercurrent heat exchanger at 308 K and is heated by an oil stream entering at 383 k at a rate of 2.85 kg/s (cp = 1.89 kJ/kg.K). The overall U = 300 W/m2.K and the area A = 15.0 m2. Calculate the heat-transfer rate and the exit water temperature.
1T
2T
hiTK 833
hoT
K 308ciT
coT
kg/s 85.2 oil, m
kg/s 677.0 water, m
2
2
m 15
.K W/m300
kJ/kg.K 187.4
kJ/kg.K 89.1
A
U
c
c
waterp
oilp
W/K5387)1890(85.2
W/K7.2792)4187(667.0
max
min
oil
water
p
CC
CC
cmC
5.05387
7.2792
max
min C
C
6.12792
)15(300 NTU
min
C
UA
0.71 7a-4.9 Fig. Using
W148900
)308383)(2792(71.0 min
ichiactual TTCq
k 3.361
)308)(4187(667.0148900
max
co
co
waterp
T
T
Tcmq
coho TTq , , determine To
NTU &/ Calculate 1. maxmin CC
graph from Obtain 2.
q Calculate 3.
cp
cico
hphiho
cm
qTT
cm
qTT
Calculate 4.
Calculate 1.
, if (i) min cCC
cihic
hohih
TTC
TTC
, if (ii) min hCC
cihih
cicoc
TTC
TTC
maxmin / Calculate 2. CC
U
CA minNTU
.4
:A determine To
NTUObtain 3.
Example
1T
2T
hiTC 09 o
C 40 ohoT
C 19 ociT
coTC 90 o
kg/s 85.2 oil, m
kg/s 677.0 water, m
?
.K W/m502
kJ/kg.K 180.4
kJ/kg.K 1.2
2
A
U
c
c
waterp
oilp
ExchangerHeat 42
min
max
W/K3150)2100(5.1
W/K4180)4180(1
CC
CC
cmC
h
c
p
75.03150
4180
max
min C
C
7.0
)1990(3150
)4090(3150
cihic
hohih
TTC
TTC
2NTU 7-4.9 Fig. Using
2
min
m 2.25
3150
2502
NTU
A
A
C
UA
Surface not clean – additional resistances
fofiiwalloiii RRRRRARA
U
11
odoidiii
io
ooi
i
AhAhAhkL
rr
AhA
U111
2
)/ln(1
1
tube theof inside for thet coefficien fouling where dih
tube theof outside for thet coefficien fouling doh
)( when0 iowall rrR << small & wallk >> large.
Example – Fouling Factors
Stainless steel double-pipe heat exchanger
W/m.K1.15k
? t,coefficienfer heat trans overall Determine
1.K/Wm 0.0001de)side(outsi shellfactor Fouling
1.K/Wm 0.0004e)side(insid efactor tub Fouling
.KW/m1200
.K W/m800
m 1
cm 2.3
cm 9.1
cm 5.1
2
2
2
2
outer tube
oi
do
di
o
i
o
i
& UU
h
h
h
h
L
D
D
D
.K W/m1200 2oh
m 1
cm 1.9
cm 3.2.K W/m800 2ihcm 1.5
22
22
m 0597.0)1)(109.1(
m 0470.0)1)(105.1(
LDA
LDA
oo
ii
053157.0
0597.0
0001.0
0471.0
0004.0
)0471.0(800
1
)1)(1.15(2
)5.1/9.1ln(
)0597.0(1200
1
111
2
)/ln(1
odoidiii
io
oo
fofiiwallo
AhAhAhkL
rr
Ah
RRRRRR
.K W/m4.399
)053157.0(0471.0
1
1
1
2
RA
RRRRRAU
i
fofiiwalloii
.K W/m11.315
)053157.0(0597.0
1
1
2
RAU
oo