chemical kinetics - biofizika · 2018. 11. 21. · basic terms # chemical kinetics find the rate of...
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Chemical kinetics
BASIC TERMS
# CHEMICAL KINETICS
FIND THE RATE OF A CHEMICAL REACTION
FIND THE RATE LAW
It INSTANTANEOUS CONCENTRATION OF THE REACTANTS / PRODUCTS
Act ) FUNCTION
# RATE OF A CHEMICAL REACTION
RATE OF CHANGE IN THE CONCENTRATION OF THE REACTANTS/ PRODUCTS
DERIVATIVE OF THE CONCENTRATION (A) WITH RESPECT TO TIME ( t )
RATE =
DAHL= V DERIVATIVE
dt
# RATE LAW
RELATES THE RATE OF A REACTION TO THE INSTANTANEOUS CONCENTRATION
OF THE REACTANTS / PRODUCTS
d Act )RATE LAW - N Alt )
,. . .
DIFFERENTIAL EQUATIONIt
- p → IRREVERSIBLE ( only A → P )
REACTANT PRODUCTT REVERSIBLE ( A - p and p - A )
-4=0Act - o ) -_ Ao -
tzAct ) LAO I [ A ]
P ( t = o ) = Po = O p ( t ) > Po T CONCENTRATION
.
.'
.
.
RATE OF THE REACTION ( v )
Alta ) - Act)= OAK ) P ( ta ) -
Pete)
=
0pct)
v =
-- soVa=
--
70AVERAGE tz - t, of tz - t
, Of
Lot -0 At Lot → o PT
v = time )=dAcow
, =othigo =EE > o
INSTANTANEOUS ot→o OtIt It
DERIVATIVE -DAHL
= t ddPft) (
←¥YN→My )dt TIME
I t r→
→ gsTOCTHOMETRY :(HOW MANY MOLECULES )
0.0061 - 0.02 -5
Nz 05 v = -
=L. TOFF 2Nz0g 2. no -5
700 -2--100.0278 - O - 5Noz v= - =
4 - to -51g 4h02 4-41=10-5700
Oz ✓ = = 10-51 -5
TooS 102 ¥= 10-5
DIFFERENT ? Ok 'O
GENERALLY
AAt BB→ c C t DD. STOCTHOMETRY
f p INSTANTANEOUS CONCENTRATION
DA
RATE = it = - at # = - f- I = tf # = the ÷
RATE LAW
= PARTIAL ORDER ORDER = [ PARTIAL ORDERd Act ) i
- n Act )dt
~ k = RATE CONSTANT
DA ( t )- = - k A ( t ) DIFFERENTIAL EQUATION
dtI
M of REACTANT CONVERTED TO PRODUCT IN 1g↳ F →
hesGENERALLY ( M )
' - r
x ( s )- 1
GOAL : A ( t ) = ?
MONOMOLECULAR
A → P v = - hat r=0
v= - KA"
r=1
Bl
MOLECULARATA - P it = - WA'
r=2
ATB → AB we = - ha'
B'
r= 1+1=2TRIMOLECULARA t At A - P v= -
has r =3
At ATB - P v= - KALB"
r=21-1=3At Btc → Pw =
- LIBI r -- 1+11-1=3
PLATINUM
a he1 Nz O - Nd g)
theOz ( g ) A - P r= O →
~ 57500
> to ( s ) Enzo ] ( M ) h( I ) CA] = Enzo ]b- - O 0.4 = Ao 2. to
-3
I k =
2.10-3140.2-3 g
2 2. to
0.1 - 3 ↳ 2. to-3
M A Is CONVERTED INTO2. to
p WITHIN ISEnzo ] t k -_ CONSTANT
RATE LAW : d%t = - he A°( t ) = - k INITIAL CONDITION : t -- O Act ) = Ao
② SEPARABLE DEGOAL i Alt ) = ?
Function dA( t ) = - kdt① m
JdA dt = ) - bolt fi.dACt)=S - kdt
DEWITTEf - gdx!- Gt to f Act )= - kdttc-
INTEGRAL f1dx=XtC GENERAL solution( t ) = - htt C
c= ?
GENERAL solution c= ?
Alt ) t
fl.dA(t ) -_ f - kdt Alt )^
Ao to -_ O
[ Act ) ]aY"
= ← ht ] !Ao -
LINEAR
V = SLOPE = - he
Act ) - Ao = - ht EL - Alt ) - t
A ( t ) = Ao - ht PARTICULAR SOLUTIONV
T> t
112
HALF LIFE ( Tye ) t = Tye Alt -- Tye ) = Aofz
A ( Tye ) = -20= Ao - kTyz
kTyz= Ae2
Ao
Tmz = -
2k
- ht Act )Act ) = Ao C PARTICULAR n
SOLUTION
AO -
EXPONENTIAL F.
112"
- tT Act ) ~ e
A ( t -_ Tye ) --
HE-
Ate-
he" '
azoµUtz = la e-
k Tk
v > t- lnz = - k T T' 12 " 12
T ln2yz=k
k3 A → P
r=2→
dA( t ) 2
RATE LAW :
y= - k A ( to ) INITIAL CONDITION it =D A ( t ) = Ao
GOAL : Act ) = ? k =
21MS
SEPARABLE DE
Alt ) t
f 1- DAH )=/ - kdtAZ C t )
[ Ao to -_ o If1dx=-
I t C f -
3dx=-
3×+0×2X
EIn?"
=L- at ] !- IT , -1at = - ht
1 AoAct ) = -
÷
-1kt=IktAo
T aAct )
112
KoHoAo -
A ( t = Tye ) =
2-= - - A ( t ) - I
1tktyzAo t
^ +ht 'll Ao = 2
,Azo µTry = -
k Ao
> tT
1/2
h4 At B → AB r= 2 →
a ) b )
.A B
-.
'
- . .
DAB ( t ) . . . .
- = th Act ) Bct )dt I I
.AB
kn .- . . . .
5 At B RT AB → . .
d. ABLE )- = t k
,Act )B( t ) - kz ABLE )
dt
ABT ABIASSOCIATION DISSOCIATION
ATB AB
ATB AB→ . . . -
→
. .
F- 2 re I
REACTIONr DIFFERENTIAL INTEGRAL The k
SCHEMEFORM FORM
A → p O DAHL= - h Act ) -_ Ao - ht ALMdt 2h S
- kt
A → p 1 dIt)= - KAH ) Act ) -_ Aoe tf Idt
A → p 2 DAHL= - halt ) Act )=÷µ Atop 1-
dt MS
ATB → AB 2
dAB#=hACt)BCt)out
ATB TAB DABA )- = -1k , Act )B( t ) - kzAB( t )
dt
Alt ) A → p r=o act ) A- → P r=1^
a
Ao
b-Ao
to-
-
52 - 5- . \Ao/4 2.5
- 2.5- .
↳ If 1.25 . 1.25 .
t I
I V V > IV N
St^ ① ② ③ i ② ③
55 7.55 8.755 35 Gs 95
Tin ① 55 ① 3s
② 7.5g - 55=2.55 ② Gs - 35=35
③ 8.755-7.55=1.255 ③ 95-65=35
Tried Tyz = A 'LL.
Act )^
Ao he-
A → p r=2
µ , §IDon-
,
Ao/8 I IAtin① ② ③ t
s 3s 75
Tyre ① Is
② 3 s - Is = 25
③ 7 s - 3s=4s
Tye T
PHARMACOKINETICS
CHANGE IN Act ) = t IN - OUT
O①
( Nfu IT
METABOLISMd Act)= +5 - 1 Act )
Act ) EXCRETION . . .
-
i IN , - Act ,dt t
singleI Out
'fgfqdacts-fdtk.net) *
O
k -_ 1h510
- luc 5- act ) ) -1 in (5-0) = t
lnc 5- Act ) ) =- ttln5
- t tln5
5- Act ) = C
- t
Act ) - 5- 5in
*
J ¥ DX = f -1 ←a) du =- t law = - in ( 5 - x )
re
5 - X = u
5- u = X
- die = DX