chemical reaction engineering chapter 4, part 1: applying the algorithm to a cstr
TRANSCRIPT
![Page 1: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/1.jpg)
Chemical Reaction Engineering
Chapter 4, Part 1:
Applying the Algorithm to a CSTR
![Page 2: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/2.jpg)
Summary
At the start of the chapter we saw we needed -rA=f(X). This result is achieved in two steps.
1. Rate Laws
– -rA=k f(Ci)
– 1st order A--> B or 1st order
– 2nd order A+B --> C
– Rate laws are found by experiment
2. Stoichiometry
– Liquid:
– Gas:
-rA=kCA
rA k C A C B
KC
-rA=kACACB
C A CA 0 1 X
C A CA 0 1 X
1 X PP0
T0
T
C A CT 0
FT
FT 0
PP0
T0
T
![Page 3: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/3.jpg)
Algorithm for Isothermal Reactor Design
1. Mole Balance and Design Equation
2. Rate Law
3. Stoichiometry
4. Combine
5. Evaluate
![Page 4: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/4.jpg)
Algorithm for Isothermal Reactor Design
1. Mole Balance and Design Equation
2. Rate Law
3. Stoichiometry
4. Combine
5. Evaluate
The Evaluate step can be carried out:
![Page 5: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/5.jpg)
Algorithm for Isothermal Reactor Design
1. Mole Balance and Design Equation
2. Rate Law
3. Stoichiometry
4. Combine
5. Evaluate
The Evaluate step can be carried out:1. Graphically (Chapter 2 plots)
![Page 6: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/6.jpg)
Algorithm for Isothermal Reactor Design
1. Mole Balance and Design Equation
2. Rate Law
3. Stoichiometry
4. Combine
5. Evaluate
The Evaluate step can be carried out:1. Graphically (Chapter 2 plots)
2. Numerically (Quadrature formulas: Chapter 2 and Appendices)
![Page 7: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/7.jpg)
Algorithm for Isothermal Reactor Design
1. Mole Balance and Design Equation
2. Rate Law
3. Stoichiometry
4. Combine
5. Evaluate
The Evaluate step can be carried out:1. Graphically (Chapter 2 plots)
2. Numerically (Quadrature formulas: Chapter 2 and Appendices)
3. Analytically (Integral tables in Appendix)
![Page 8: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/8.jpg)
Algorithm for Isothermal Reactor Design
1. Mole Balance and Design Equation
2. Rate Law
3. Stoichiometry
4. Combine
5. Evaluate
The Evaluate step can be carried out:1. Graphically (Chapter 2 plots)
2. Numerically (Quadrature formulas: Chapter 2 and Appendices)
3. Analytically (Integral tables in Appendix)
4. Software packages (Appendix - Polymath)
![Page 9: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/9.jpg)
French Menu Analogy
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French Menu Analogy
![Page 11: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/11.jpg)
French Menu Analogy
![Page 12: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/12.jpg)
French Menu Analogy
![Page 13: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/13.jpg)
French Menu Analogy
![Page 14: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/14.jpg)
French Menu Analogy
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French Menu Analogy
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French Menu Analogy
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French Menu Analogy
Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B.
![Page 18: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/18.jpg)
French Menu Analogy
Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B.
Mole Balance:
![Page 19: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/19.jpg)
French Menu Analogy
Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B.
Mole Balance:
Rate Law:
![Page 20: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/20.jpg)
Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B.
Mole Balance:
Rate Law:
Stoichiometry: gas phase, isothermal (T=T0), no pressure drop (P=P0)
French Menu Analogy
![Page 21: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/21.jpg)
French Menu Analogy
Remember the French Menu reaction:
For a gas phase system:
Deriving CA and CB:
![Page 22: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/22.jpg)
French Menu Analogy
Remember the French Menu reaction:
For a gas phase system:
If the conditions are isothermal (T = T0) and isobaric (P =P0):
Deriving CA and CB:
![Page 23: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/23.jpg)
French Menu Analogy
Remember the French Menu reaction:
For a gas phase system:
If the conditions are isothermal (T = T0) and isobaric (P =P0):
We must divide by the stoichiometric coefficient of our basis of calculation yielding:
Deriving CA and CB:
![Page 24: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/24.jpg)
French Menu Analogy
Remember the French Menu reaction:
For a gas phase system:
If the conditions are isothermal (T = T0) and isobaric (P =P0):
We must divide by the stoichiometric coefficient of our basis of calculation yielding:
And if the feed is equal molar, then:
Deriving CA and CB:
![Page 25: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/25.jpg)
French Menu Analogy
This leaves us with CA as a function of conversion alone:
Deriving CA and CB:
![Page 26: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/26.jpg)
French Menu Analogy
This leaves us with CA as a function of conversion alone:
Similarly for CB:
FB0 FA0
Therefore, B 1
Deriving CA and CB:
![Page 27: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/27.jpg)
Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B.
Mole Balance:
Rate Law:
Stoichiometry: gas phase, isothermal (T=T0), no pressure drop (P=P0)
[Why do you think CB is constant, when B is consumed?]
French Menu Analogy
![Page 28: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/28.jpg)
Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B.
Mole Balance:
Rate Law:
Stoichiometry: gas phase, isothermal (T=T0), no pressure drop (P=P0)
[Why do you think CB is constant, when B is consumed?]
French Menu Analogy
![Page 29: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/29.jpg)
Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B.
Mole Balance:
Rate Law:
Stoichiometry: gas phase, isothermal (T=T0), no pressure drop (P=P0)
[Why do you think CB is constant, when B is consumed?]
Combine:
French Menu Analogy
![Page 30: Chemical Reaction Engineering Chapter 4, Part 1: Applying the Algorithm to a CSTR](https://reader030.vdocument.in/reader030/viewer/2022032415/56649f065503460f94c1be6b/html5/thumbnails/30.jpg)
Example: The elementary gas phase reaction takes place in a CSTR at constant temperature (500 K) and constant pressure (16.4 atm). The feed is equal molar in A and B.
Mole Balance:
Rate Law:
Stoichiometry: gas phase, isothermal (T=T0), no pressure drop (P=P0)
[Why do you think CB is constant, when B is consumed?]
Combine:
Evaluate:
French Menu Analogy