class 5 - integral theorems
TRANSCRIPT
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7/27/2019 Class 5 - Integral Theorems
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AOE 5104 Class 5 9/9/08
Online presentations for next class:
Equations of Motion 1
Homework 2 due 9/11 (w. recitations, thisevenings is in Whitemore 349 at 5)
Office hours tomorrow will start at 4:30-
4:45pm (and I will stay late)
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7/27/2019 Class 5 - Integral Theorems
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Review
S
0 dS.
1Lim nVV
div
Divergence
For velocity: proportionate
rate of change of volume
of a fluid particle
S
0 dS
1Limgrad n
Gradient
Magnitude and direction
of the slope in the scalar
field at a point
S
0 dS
1Lim nVV
curl
Curl
For velocity: twice the
circumferentially averaged
angular velocity of a fluid
particle= Vorticity
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Differential Forms of the
Divergence
A.r
e+
r
e+
re
A.z
e+r
e+
re
A.
z
k+
y
j+
x
i
A
r
1+
A
r
1+
r
Ar
r
1
z
A+
A
r
1+
r
rA
r
1
z
A+
y
A+
x
A
A.=Adiv
r
zr
r2
2
zr
zyx
sinsin
sin
sin
Cartesian
Cylindrical
Spherical
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a
vav
acurl
curl
hsh
curl
h
curl
curl
curl
aa
020
Ce0
C
0
S
0
S
0
S
0
S
0
2Lim21
Lim.
Limd.1
Lim.
d.1
Lim.
dS.1
Lim.
dS.
1Lim.
dS1Lim
e
Ve
sVVe
neVVe
neVVe
nVeVe
nVV dS
n
Curle
n
Perimeter Ce
ds
h
dS=dsh
Area
radius a
v avg. tangential
velocity= twice the avg. angular velocity
about e
Elemental volume
with surface S
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7/27/2019 Class 5 - Integral Theorems
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Review
S
0 dS.
1Lim nVV
div
Divergence
For velocity: proportionate
rate of change of volume
of a fluid particle
S
0 dS
1Limgrad n
Gradient
Magnitude and direction
of the slope in the scalar
field at a point
S
0 dS
1Lim nVV
curl
Curl
For velocity: twice the
circumferentially averaged
angular velocity of a fluid
particle= Vorticity
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Integral Theorems and
Second Order Operators
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George Gabriel Stokes1819-1903
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1st Order Integral Theorems
Gradient theorem
Divergence theorem
Curl theorem
Stokes theorem
R S
dSd n
R S
dSd nAA ..
R S
dSd nAA
Volume R
with Surface S
d
ndS
C
SSd sAnA d..
Open Surface S
with Perimeter CndS
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The Gradient Theorem
S
0 dS
1Limgrad n
Finite Volume R
Surface S
d
Begin with the definition of grad:
Sum over all the d in R:
R SR i dSgrad nid
di
di+1nidS
ni+1dS
We note that contributions to the
RHS from internal surfaces between
elements cancel, and so:
SRdSgrad nd
Recognizing that the summations
are actually infinite:
SR
d dSgrad n
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Assumptions in Gradient Theorem
A pure math result, applies to all flows
However, S must be chosen so that isdefined throughout R
SR d dSgrad n
S
Submarine
surface
SR
d dSgrad n
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Flow over a
finite wing
S1
S2
SR
pdp dSn
S = S1 + S2
R is the volume of fluid
enclosed between S1and S2
S1
p is not defined inside the
wing so the wing itself
must be excluded from the
integral
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1st Order Integral Theorems
Gradient theorem
Divergence theorem
Curl theorem
Stokes theorem
R S
dSd n
R S
dSd nAA ..
R S
dSd nAA
Volume R
with Surface S
d
ndS
C
SSd sAnA d..
Open Surface S
with Perimeter CndS
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Ce0
C
0 Limd.1
Lim.
e
sAAe curl
Alternative Definition of the Curl
e
Perimeter Ce
ds
Area
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Stokes TheoremFinite Surface S
With Perimeter C
d
Begin with the alternative definition of curl, choosing the
direction e to be the outward normal to the surface n:
Sum over all the d in S:
Note that contributions to the RHS
from internal boundaries between
elements cancel, and so:
Since the summations are actually infinite, and
replacing with the more normal area symbol S:
eC
0 d.1
Lim. sAAn
di
SSid
eC
d.. sAAn
n
dsi
dsi+1
di+1 CS
d sAAn d..
CS Sd sAnA d..
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Stokes Theorem and Velocity
Apply Stokes Theorem to a velocity field
Or, in terms of vorticity and circulation
What about a closed surface?
CS Sd sVnV d..
CC
S
Sd
sVn d..
0.
dS
S
n
CS Sd sAnA d..
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Assumptions of Stokes Theorem
A pure math result, applies to all flows
However, C must be chosen so that A is
defined over all S
CS
Sd sAnA d..
2D flow over airfoil with =0
C
?d..
CS
Sd sVn
The vorticity doesnt
imply anything about the
circulation around C
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Flow over a
finite wing
CS
Sd sVnV d..
C
S
Wing with circulation must trail vorticity.Always.
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Vector Operators of Vector
Products
B).A(-)A.(B-A).B(+)B.(A=)BA(
B.A-A.B=)BA.(
)A(B+)B(A+)A.B(+)B.A(=)B.A(
A+A=)A(
A.+A.=)A.(
+=)(
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Convective Operator
)]A.(B-.B)(A+)BA(-
)A(B-)B(A-)B.A([=
B
z
A
y
A
x
A=B).A(
).(A
zA
yA
xA=
).A(
zyx
zyx
21
.V= change in density in direction ofV, multiplied by magnitude ofV
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Second Order Operators
2
2
2
2
2
22.
zyx
The Laplacian, may also be
applied to a vector field.
0.
0
).(
).(
2
A
AAA
A
So, any vector differential equation of the form B=0
can be solved identically by writing B=.
We say B is i r rotat ional. We refer to as the scalar po tent ial.
So, any vector differential equation of the form .B=0
can be solved identically by writing B=A. We say B is solenoidalorincompress ib le.
We refer to A as the vector po tent ial.
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Class Exercise
1. Make up the most complex irrotational 3D velocityfield you can.
2223sin /3)2cos( zyxxyxe x kjiV ?
We can generate an irrotational field by taking the gradient ofany
scalar field, since 0
I got this one by randomly choosing
zyxe x /132sin And computing
kjiVzyx
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2nd Order Integral Theorems
Greens theorem (1st form)
Greens theorem (2nd form)
Volume R
with Surface S
d
ndS
S
RSd d
n
2
S
RSd d
n-
n
22
These are both re-expressions of the divergence theorem.