class av 2015

80
Introduction to Astronomy & Astrophysics Or What Astrophysicists do? Monday 27 April 2015

Upload: rahul-ganguly

Post on 07-Nov-2015

218 views

Category:

Documents


2 download

DESCRIPTION

astro

TRANSCRIPT

  • Introduction to Astronomy & Astrophysics

    OrWhat Astrophysicists do?

    Monday 27 April 2015

  • The constellation Orion

    What is the universe made up of?

    % by mass

    Monday 27 April 2015

  • Astronomy : Most ancient science

    Jantar Mantar in JaipurIndias legacy in astronomy

    Monday 27 April 2015

  • The windows to the universe

    Electromagnetic radiation Neutrinos Gravitational waves

    Monday 27 April 2015

  • molecular, atomic excitations & ionizations

    (a) O3 : UV(b) H2O : IR(c) ionosphere reflection : Radio(d) photoelectric absorption : Xray

    Monday 27 April 2015

  • Two windows to do astronomy from earth

    1.Optical (and some IR)

    2.Radio

    The rest of the EM spectrum from space

    Monday 27 April 2015

  • Mauna Kea, Hawaiisee http://www.ifa.hawaii.edu/mko/

    A dormant volcano, 4.2km above sea level

    Monday 27 April 2015

  • 2m Himalayan Chandra Telescope (HCT) at Hanle, Leh, Ladak

    Monday 27 April 2015

  • Thirty meter telescope(artist impression)

    Planned to be constructed

    Monday 27 April 2015

  • The sizes of various telescope mirrors

    Monday 27 April 2015

  • Hubble Space Telescope

    Monday 27 April 2015

  • a planetary nebula

    a spiral galaxy

    a cluster of galaxies

    Many forms of wonders

    Monday 27 April 2015

  • Very Large Arrayradio telescope,

    New Mexico, USA

    Monday 27 April 2015

  • Indias GMRT

    30 dishes, 45m diameter each

    Monday 27 April 2015

  • Radio observations (left) of galaxy M 87 in comparison with its optical observations (above)

    Monday 27 April 2015

  • The center of our Galaxy,viewed in radio wavelength (VLA, 90cm)

    Monday 27 April 2015

  • Xray Astronomy

    The Chandra xray telescope orbits the earth while looking at the high energy sky

    Monday 27 April 2015

  • Chandra image of an elliptical galaxy

    Monday 27 April 2015

  • Galaxy M 10623.5 Million

    Light year away from us

    Multiwavelength Astronomy

    This image is a composite of images taken in multiple wavelengths (optical+xray+radio). You can see the spiral arms of this spiral galaxy in red & white shades (also some blue stars are visible). That is the optical image. Notice the diffuse structure in blue & purple. Blue is x-ray and purple is radio. This structure is not visible in optical. Views through multiple observational windows are required to build up complete picture of an astronomical object.

    Monday 27 April 2015

  • RCW 86, SNR.

    In 185 AD the Chinese Astronomers seem to have observed this explosion. This is the remnant of the explosion visible even now. This is another composite image of different wavelengths. Blue and green colors are from the x-ray image. Yellow & red are part of the infrared image.

    Multiwavelength Astronomy

    ps : Images in both previous slide and this are false-colored.

    Monday 27 April 2015

  • Locations in the sky

    Celestial sphere : Imaginary sphere with earth as centre

    Monday 27 April 2015

  • Monday 27 April 2015

  • Coordinate system

    Celestial (a.k.a Equatorial) coordinate system

    Monday 27 April 2015

  • Its all about angles

    smaller angles are measured in arcminutes ()and arcseconds ()

    Monday 27 April 2015

  • Monday 27 April 2015

  • Convince yourself by checking how long does sun take to cross your fingers...

    Or whether you can block moon with your little finger...

    Monday 27 April 2015

  • Why do we have total solar eclipse?

    Total solar eclipse is possible only because the angular sizes of Sun and moon are same.

    Moon 3.8x105 km away from earth

    Diameter : 3474 km

    Sun 1.5x108 km away from earth

    Diameter : 1. 4 x106 km

    Monday 27 April 2015

  • Angular ResolutionAbility to see distinctly

    Eyes : 1

    What decides the limiting angular resolution ?

    Diffraction introduces a certain fuzziness in the image.

    A telescope mirror of D diameter

    ~ /DMonday 27 April 2015

  • Constellation Gemini

    CastorAlpha gemenorium

    a visual binaryin fact 4 stars!

    Monday 27 April 2015

  • Angular resolution

    The spatial resolution of a telescope depends on

    (i) the size of its lenses or mirrors and (ii) the size of the pixels in its detectors (iii) and by the smoothness of a telescope's mirrors or lenses.(iv) the resolution is also limited by air turbulence (for ground based observatories)

    Andromeda : (a)10 (b)1 (c)5 (d)1

    A simulation of the same region, how it will be viewed through three different Infrared telescopes. From left to right IRAS, ISO and

    Spitzer telescopes.

    Monday 27 April 2015

  • Stars rise & set

    Monday 27 April 2015

  • Stars rise & set

    Monday 27 April 2015

  • Monday 27 April 2015

  • Local sky

    Monday 27 April 2015

  • Local sky

    Monday 27 April 2015

  • Arches national park, Utah, USA

    Monday 27 April 2015

  • Local sky

    Monday 27 April 2015

  • Distance in Astronomy1. Parallax

    d = 1/pAssumed :-1. sun is fixed2. stars are fixed

    In arcseconds, the parallax angle,p = 1 AU . (180/pi) . 3600

    Monday 27 April 2015

  • Luminosity, Flux, Stellar Spectra, HR diagram

    Monday 27 April 2015

  • Luminosity, L(power)

    dE/dt

    Flux, F(energy/time/unit-area)

    dE/(dt dA)

    d

    L/4.Pi.d2

    Monday 27 April 2015

  • basicastro4 October 26, 2006

    12 CHAPTER 2

    Figure 2.1 Flux per wavelength interval emitted by different types of stars, at their sur-

    faces, compared to blackbody curves of various temperatures. Each black-

    bodys temperature is chosen to match the total power (integrated over all wave-

    lengths) under the the corresponding stellar spectrum. The wavelength range

    shown is from the ultraviolet (1000 A= 0.1 m), through the optical range(3200-10,000 A), and to the mid-infrared (105 A= 10 m). Data credit: R.Kurucz.

    (since the solid angle of a full sphere is 4pi steradians). The intensity of blackbodyradiation is therefore

    I =c

    4piu =

    2h3

    c21

    eh/kT 1 B . (2.4)

    In cgs, one can see the units now are erg s1 cm2 Hz1 steradian1. We have keptthe product of units, s1 Hz1, even though they formally cancel out, to recall theirdifferent physical origins: one is the time interval over which we are measuring

    the amount of energy that flows through a unit area; and the other is the photon

    frequency interval over which we bin the spectral distribution. I of a blackbody isoften designated B.Now, let us find the net flow of energy that emerges from a unit area (small

    enough so that it can be presumed to be flat) on the outer surface of a blackbody

    (see Fig. 2.2). This is obtained by integrating I over solid angle on the half spherefacing outwards, with each I weighted by the cosine of the angle between theintensity and the perpendicular to the area. This flux, which is generally what one

    actually observes from stars and other astronomical sources, is thus

    f = pi/2=0

    I cos d = I2pi12= piI =

    c

    4u =

    2pih3

    c21

    eh/kT 1 . (2.5)

    Blackbody spectrum. x-axis is wavelength, y-axis is the power emitted per unit wavelength per unit area of the blackbody. The body emits in all wavelengths. But in a given wavelength, it always emits more if its temperature is more. In other words, Temperature is the only quantity that determines the power/area (== flux) of a blackbody.

    Stellar spectrum. Spectra of different stars are plotted. x-axis is wavelength, y-axis is the power emitted per unit wavelength per unit area of the star. Solid curves are fits to the spectrum using blackbody models (of various temperatures). We can see how it is remarkably similar to the blackbody spectrum at the right side.

    Stellar Spectrum & Blackbody Spectrum

    Power, L = 4R2 T4

    Energy/area/time = surface flux = T4

    max T = constMonday 27 April 2015

  • Hertzsprung-Russell Diagrams

    Hertzsprug & Russell

    When total luminosity (==power) emitted by stars are plotted vs their surface temperature, the plot didnt look random. Instead some patterns started appearing.

    Both the plots are same. HR diagram is a plot of Luminosity vs surface Temperature of stars. Ignore the right y-axis and bottom x-axis of the plot above.

    Monday 27 April 2015

  • M(r)

    P+dP

    P

    r+dr r

    What makes stars stable?

    Monday 27 April 2015

  • M(r)

    P+dP

    P

    r+dr r

    Gravitational force on the cylinder

    What makes stars stable?

    Monday 27 April 2015

  • M(r)

    P+dP

    P

    r+dr r

    Gravitational force on the cylinder

    What makes stars stable?

    Monday 27 April 2015

  • M(r)

    P+dP

    P

    r+dr r

    Gravitational force on the cylinder

    To be equal & opposite to the diff. in pressure

    What makes stars stable?

    Monday 27 April 2015

  • M(r)

    P+dP

    P

    r+dr r

    Gravitational force on the cylinder

    To be equal & opposite to the diff. in pressure

    What makes stars stable?

    Monday 27 April 2015

  • Equation of hydrostatic equilibrium

    Stellar matter ideal gas

    Boyles law : P = kB T (2/mH)Special cases where P = P() alone

    An order of magnitude estimate : Solar core temperature

    What energizes the Sun?

    Monday 27 April 2015

  • Replace with averages

    Substitute for Ms and Rs, Pc ~ 6 x 1014 N/m2 And use Pc = n kB Tc to get Tc ~ 107K

    Monday 27 April 2015

  • Main sequence star

    big gas cloud of hydrogen gets heated up to ~107K by gravitational contraction

    Nuclear fusion reaction (hydrogen to helium) starts

    Thus a main sequence star (stars that burn H to He) is formed. Its luminosity is a sole function of its mass

    Monday 27 April 2015

  • Stellar Evolution in a Nutshell

    Monday 27 April 2015

  • How to produce huge amount of energy?

    Mass & energy are not two separate entities.One could be traded for the other.

    How to practically achieve this?

    Binding energy per nucleon curve.

    See that the curve has a maximum around A=60. Most stable element is the one with maximum BE/nucleon. To disrupt it, relatively more energy has to be provided. On both sides of this element, BE is lesser (ignore some fluctuations in between, like for 4He).

    Monday 27 April 2015

  • If you have Z protons and (A-Z) neutrons forming a nucleus, the mass of the nucleus

    mnuc < Z mp + (A-Z) mn

    ie., There is a mass deficit. Energy equivalent of this mass deficit is the BE. (noted as negative conventionally)

    BE = [ Z mp + (A-Z) mn - mnuc ] c2

    So if you fuse nucleons and get a nucleus, this energy can be released.

    4 protons 4He : releases energy of 0.007 mp c2

    Hence if we have 2x1030kg of hydrogen, we can get ~1047 J of energy. Sun can shine for 1011 years!

    While going from a lower BE/nucleon state to a higher BE/nucleon state energy can be released.Because the curve in the previous page has a maximum, this can happen in two ways : either from A > 60 side (fission) or from A< 60 side (fusion).

    Monday 27 April 2015

  • Coulomb BarrierBefore two protons to be able to collide, they have to overcome their electrostatic repulsion

    10-15 mkinetic energy of the colliding nucleons are required to overcome this barrier

    Hence, nuclear fusion can happen only at high temperatures.

    Classically not possible to tunnel through this barrier.

    Monday 27 April 2015

  • After hydrogen burning

    If the core temp is high enough He -> C -> O -> Fe (stops)

    Stars like sun never reach such high temperatures. They are left with CO core where no fusion happens (white dwarf).

    Red giant : H burns in an outer shell. Blue super giant : CO burning core, He shell, H envelope White dwarf, CO core resist gravity due to degeneracy

    pressure (pressure arising in fermions due to Paulis exclusion principle)

    Monday 27 April 2015

  • Mass increases, radius decreases If mass increases beyond a limit, the

    degeneracy pressure of free electrons can not support the gravity.

    This is the Chandrasekar limit Initial mass of the star is 1.4M_sun White dwarfs small luminosity (note

    that it occupies the left bottom corner of the HR diagram, it has very low luminosity) originates from its residual heat

    Chandrasekhar and White dwarf mass limit

    Monday 27 April 2015

  • Higher mass stars

    Monday 27 April 2015

  • Neutron stars & Supernovae

    Higher mass stars have an Fe core.

    No more fusion (Fe of A~60 is the most stable element -- remember the BE/nucleon curve). Core collapses to become a neutron star.

    Lot of gravitational potential energy is released. Causing an SN explosion

    Above : (perhaps) An ancient SN happened in Milkyway seen by our ancestors in the American southwest.

    Below : A modern SN, happened at the edge of a far away galaxy.

    Monday 27 April 2015

  • Pulsars

    Monday 27 April 2015

  • Pulsars

    Monday 27 April 2015

  • Pulsars

    Monday 27 April 2015

  • Pulsars

    Monday 27 April 2015

  • Type Ia Supernovae

    Monday 27 April 2015

  • Keplers laws & Astrophysics

    stellar mass from binaries planetary orbits dark matter

    Monday 27 April 2015

  • Keplers laws Orbit of a planet is an ellipse. Sun at one of the focii

    Equal areas at equal time

    P2 = k a3 (P is period of the planet, a is semi-major axis of its orbit, k is a constant.)

    k(M), where M is the mass of Sun

    Monday 27 April 2015

  • Monday 27 April 2015

  • Keplers 3rd law in solar system

    Note : this plot is in log-scale. Hence it is linear

    Monday 27 April 2015

  • Binary stars

    -Algol (the Demon)-Alpha-centauri-Beta-Lyrae-Rigel-Sirius-Spica

    Some examples

    Monday 27 April 2015

  • Binary stars

    -Algol (the Demon)-Alpha-centauri-Beta-Lyrae-Rigel-Sirius-Spica

    Some examples

    Monday 27 April 2015

  • Mass measurement in binaries

    Only from binary stars can we accurately determine masses of individual stars

    M1 a1 = M2 a2

    a = a1 + a2

    a2 = M1 a /(M1+M2)

    P = 2 pi/;

    2 = G(M1+M2)/a3If we can map each orbits & if we know distance & if we know P, we get M1 & M2

    We assumed circular orbits in the above calculation.a1 and a2 are the distances of the two masses M1 and M2 respectively from the center of mass (magenta point). In the circular orbit, of both stars are the same. You can convince yourself of this by looking at the animations at http://en.wikipedia.org/wiki/Barycentric_coordinates_(astronomy)

    Monday 27 April 2015

  • Milkyway : Our home

    Artists image

    Monday 27 April 2015

  • What is a galaxy?

    Stars Diffuse matter

    (gas & solid particles that do not self-gravitate)

    Dark Matter

    Monday 27 April 2015

  • Diffuse gas & solid particles : Nebulae

    Monday 27 April 2015

  • And what about dark matter?

    We need to understand a bit more before getting into that.

    Monday 27 April 2015

  • Rotation curve of spiral galaxies

    Vera Rubin. Pioneer of galaxy spectrum studies. Thanks to her, world realized there may be matter that can not be seen (because it does not interact with photons, ie., it does not interact via electromagnetic forces*). Matter that is Dark. Presence of such material can only be inferred via its gravitational interactions.

    * There are 4 known type of forces in the nature. Electromagnetic, Weak, Strong, and Gravitational.

    Monday 27 April 2015

  • How does galaxy spectrum studies help in knowing the presence of Dark Matter?

    spectral lines can tell the velocity with which material is moving in the galaxy. [How? : see next section on doppler shift]

    velocity of the material carries information of the gravitational potential in which the material moves.

    Monday 27 April 2015

  • Velocity of light source from doppler shift

    Monday 27 April 2015

  • Velocity of light source from doppler shift

    Monday 27 April 2015

  • The background(blue) is the sketch of a galaxy. Concentric circles are drawn to represent different radii (from the galactic center). At different radii, the material has different rotational velocities.

    The red curve is the velocity of material vs its distance from the galactic center.

    Such a curve is called Rotation Curve

    Monday 27 April 2015

  • Rotation curve of spiral galaxies

    Both M33 galaxy and our galaxy rotation curves show that velocity is much larger than expected at large distances from the centre. At these large distances, there is very less visible matter. Velocities should behave like in our solar system (like in slide-51), because all the mass is concentrated at smaller radii. Velocity should fall off with distance. That doesnt happen implies that there is matter that is not emitting light.

    Our galaxy rotation curve

    Monday 27 April 2015